How would I go about retrieving records from the last three months of the previous year? I was thinking it would be:
Date_add(curdate() , interval '-1 2' year_month)
Try this:
WHERE my_date_column BETWEEN
SUBDATE(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) + 91 DAY) AND
SUBDATE(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) DAY)
91 is one less than 31 + 30 + 31, because BETWEEN is inclusive.
Note that if your column is a datetime type, you'll need the end value to be the last second of the day:
SUBDATE(SUBDATE(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) - 1 DAY), INTERVAL 1 SECOND)
See SQLFiddle of these expressions generating correct values.
Assuming you date column is named "date", something like:
SELECT
*
FROM
table
WHERE
YEAR(date) = YEAR(DATE_SUB(CURDATE(), INTERVAL 1 YEAR))
AND
MONTH(date) BETWEEN 10 AND 12
Related
How to select all data from last month (or 30 days)?
I already found some answers, and mostly gives this solution
SELECT *
FROM gigs
WHERE date > DATE_SUB(CURDATE(), INTERVAL 3 MONTH)
ORDER BY date DESC
But this gives me also the dates from the future
I am only interested in the days from last month or 30 days (not next month and beyond)
Is this what you want?
WHERE date > DATE_SUB(CURDATE(), INTERVAL 1 MONTH) AND date <= CURRENT_DATE
I added a condition so the query filters on date not greater than today. I also modified your code so the date range starts one month ago (you had 3 months).
try this code
SELECT * FROM gigs
WHERE date BETWEEN CURDATE() - INTERVAL 30 DAY AND CURDATE()
ORDER BY date DESC
You are asking for two separate things.
The last 30 days is easy.
date between now() - interval 30 day and now()
Data this month is like this:
date between (last_day(Now() - INTERVAL 1 MONTH) + INTERVAL 1 DAY) and last_day(Now())
Data a few months ago is like this:
date between (last_day(Now() - INTERVAL 4 MONTH) + INTERVAL 1 DAY)
and
(last_day(Now() - INTERVAL 3 MONTH) + INTERVAL 1 DAY)
I am trying to get records from last one year and upto last date of provious month i.e. not including the current month. Here's my query:
SELECT `customer_id`, `customer_name`, `customer_date`
FROM `customers`
WHERE DATE(`customer_date`) <= (CURDATE() - INTERVAL 1 MONTH)
AND DATE(customer_date) >= (CURDATE() - INTERVAL 12 MONTH)
This query fetches records from 1 May, 2018 to 8 April 2019.
INTERVAL 1 MONTH fetches records 30 days ago. What I need to do something here?
I want to exclude current month records, so query should return records upto 30 April 2019. How do we do that?
You must correctly calculate the first and last days of range with help LAST_DAY() function. For example:
Calculate the first day of the range
SELECT LAST_DAY(CURDATE() - INTERVAL 13 MONTH) + INTERVAL 1 DAY
Output:
2018-05-01
Calculate last day of the range
SELECT LAST_DAY(CURDATE() - INTERVAL 1 MONTH)
Output:
2019-04-30
The full query might look like:
SELECT `customer_id`, `customer_name`, `customer_date`
FROM `customers`
WHERE `customer_date` >= LAST_DAY(CURDATE() - INTERVAL 13 MONTH) + INTERVAL 1 DAY
AND `customer_date` <= SELECT LAST_DAY(CURDATE() - INTERVAL 1 MONTH)
To get data up to the previous month:
where customer_date < curdate() + interval (1 - day(curdate()) day
Why? First note that there is no function call on the customer_date. So, this expression is index-compatible and can use an index.
Second, this structure works both for dates and date/times. That is very handy, because it may not always be obvious if a column has a time component (people are not very good about naming columns to capture this information).
You claim that the "12 months" ago portion works. That doesn't look correct to me. For the complete logic:
where customer_date < curdate() + interval (1 - day(curdate()) day and
customer_date >= (curdate() + interval (1 - day(curdate()) day) - interval 1 year)
SELECT `customer_id`, `customer_name`, `customer_date` FROM `customers` WHERE
MONTH(`customer_date`) <= (CURDATE() - INTERVAL 1 MONTH) AND
MONTH(customer_date) >= (CURDATE() - INTERVAL 12 MONTH)
hope this help
I'm doing a review of existing code and have found the following SQL query which is used to get a selection of records last month.
Is there a more concise way of writing SQL to do what this date based clause does in MySQL?
SELECT foo
FROM some_table
WHERE some_date
BETWEEN
DATE_FORMAT(LAST_DAY((NOW() - INTERVAL 1 MONTH) - INTERVAL 1 SECOND), '%Y-%m-01 00:00:00')
AND
DATE_FORMAT(LAST_DAY((NOW() - INTERVAL 1 MONTH) - INTERVAL 1 SECOND), '%Y-%m-%d 23:59:59')
It works, but I just twitch a little every time I see it.
Can anyone else write it better?
Thank you in advance.
There's no need to format the dates, they default to YYYY-MM-DD 00:00:00.
This is a little bit simpler:
SELECT foo
FROM some_table
WHERE some_date >= LAST_DAY(CURDATE() - INTERVAL 2 MONTH) + INTERVAL 1 DAY
AND some_date < LAST_DAY(CURDATE() - INTERVAL 1 MONTH) + INTERVAL 1 DAY
So if CURDATE() is today, 2019-02-06, then:
- INTERVAL 2 MONTH is 2018-12-06
LAST_DAY() of that date is 2018-12-31
+ INTERVAL 1 DAY is 2019-01-01
Then the upper bound is:
- INTERVAL 1 MONTH is 2019-1-06
LAST_DAY() of that date is 2019-1-31
+ INTERVAL 1 DAY is 2019-02-01
The dates should be strictly less than 2019-02-01.
Using less than accounts for timestamps in the last second of the month, between 23:59:59.000 and 23:59:59.999.
I need to print previous three month name with this function
SELECT MonthName(CURRENT_DATE()) as month
With this query, I am getting the following :
month
September
I need to show like this it is possible
month
September
August
July
June
Use DATE_SUB to subtract date with the help of interval
SELECT MONTHNAME(DATE_SUB(curdate(), INTERVAL 1 MONTH)) as first, MONTHNAME(DATE_SUB(curdate(), INTERVAL 2 MONTH)) as second, MONTHNAME(DATE_SUB(curdate(), INTERVAL 3 MONTH)) as third
Use DATE_ADD function with MONTH interval -1 thrice to get previous 3 months name. And then use UNION ALL.
Query
select MonthName(CURRENT_DATE()) as month
union all
select MonthName(DATE_ADD(CURRENT_DATE(), INTERVAL -1 MONTH))
union all
select MonthName(DATE_ADD(CURRENT_DATE(), INTERVAL -2 MONTH))
union all
select MonthName(DATE_ADD(CURRENT_DATE(), INTERVAL -3 MONTH));
I have a table with a timestamp field. How do I get data from the last 3 months?
In particular, March is my current month let say, 03/2012. I need to return records from the months March, February, and January only.
3 months before today:
select * from table where timestamp >= now()-interval 3 month;
Start with first of month:
select * from table where timestamp >= last_day(now()) + interval 1 day - interval 3 month;
To get the first day of the current month, you could use this:
DATE_FORMAT(CURDATE(), '%Y-%m-01')
if current date is 2013-03-13, it will return 2013-03-01, and we can just substract 2 months from this date to obtain 2013-01-01. Your query could be like this:
SELECT *
FROM yourtable
WHERE data >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH
I know this is an old question, but to possibly save others time and to sum the above answers up for the case of needing (1) dates from current month and (2) dates from the prior 2 months (common when displaying data statistics):
WHERE ((timestamp >= NOW() - DATE_FORMAT(CURDATE(), '%Y-%m-01'))
OR (timestamp >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH))
Assuming you're using SQL Server (Oracle, MySQL and others have similar date functions), you can use the dateadd function to add or subtract an interval to the current date.
If you want a full three months, you can subtract 3 months from today : DATEADD(m,-3,getdate())
But, as you state, you only want data from January, February and March. You have to make some calculation based on today's date: dateadd(m,-2, CONVERT(datetime, CONVERT(VARCHAR(2), MONTH(getdate())) + '/01/' + CONVERT(VARCHAR(4), YEAR(getdate()))))
And in the end, get a query like
SELECT fields
FROM table
WHERE timestampfield > DATEADD(m,-2, CONVERT(datetime, CONVERT(VARCHAR(2), MONTH(getdate())) + '/01/' + CONVERT(VARCHAR(4), YEAR(getdate()))))
--- edit ---
erf, I just noticed the "mysql" tag... you can get more information on MySQL date functions here : https://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
Another possibility would be:
SELECT * WHERE your_date_column > LAST_DAY(CURRENT_DATE - INTERVAL 3 MONTH);
Use this code here to get the previous 3 months from a certain date
SELECT * FROM table WHERE date_column>= DATE_FORMAT(current_date(), '%Y-%m-01') - INTERVAL 3 MONTH and date_column< DATE_FORMAT(current_date(), '%Y-%m-01')
WHERE ((timestamp >= NOW() - DATE_FORMAT(CURDATE(), '%Y-%m-01'))
OR (timestamp >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH))