SQL Query to get the total sales per seller by month - mysql

Question

I try this:
SELECT
profile.user_id,
profile.name,
total_month.total as month10
FROM profile
LEFT OUTER JOIN (SELECT
order.seller_id,
COUNT(*) AS total
FROM order
WHERE MONTH(order.data_hora) = 10
GROUP BY order.seller_id) AS total_month
ON total_month.seller_id= profile.user_id;
The result was this:
-------------------------
|user_id| name |month10|
-------------------------
| 5 |user1 | 73 |
| 1 |user2 | 1 |
-------------------------
But I need more months like this:
-------------------------------------------------
| user_id | name | month10 | month11 | month12 |
-------------------------------------------------
| 5 | user1 | 73 | 52 | 65 |
| 1 | user2 | 67 | 56 | 78 |
-------------------------------------------------
How could I do this without creating a function?

Answer 1

You can extend your query to do what you want. Just be more flexible in the subquery:
SELECT p.user_id, p.name,
tm.month10, tm.month11, tm.month12
FROM profile p LEFT OUTER JOIN
(SELECT o.seller_id,
sum(o.data_hora = 10) as month10,
sum(o.data_hora = 11) as month11,
sum(o.data_hora = 12) as month12
FROM order o
WHERE MONTH(order.data_hora) in (10, 11, 12)
GROUP BY order.seller_id
) tm
ON tm.seller_id = p.user_id;

Answer 2

Well as I said in the comments supporting the #Schalk comment, in order to get this working as you want you will need a function to get a DYNAMIC PIVOT TABLE or TRANSPOSE ROWS TO COLUMNS google it if you prefer.
For your solution I've created a query that gives you all months/values like this:
user_id name jan feb mar apr may jun jul aug sep oct nov dec
1 a 0 0 1 10 0 0 1 2 7 2 3 0
2 b 1 0 0 0 2 0 0 0 3 1 1 0
If it fits to your problem this is your query:
select
profile.user_id,
profile.name,
sum(if( MONTH(orderr.data_hora) = 1, 1, 0 )) as Jan,
sum(if( MONTH(orderr.data_hora) = 2, 1, 0 )) as Feb,
sum(if( MONTH(orderr.data_hora) = 3, 1, 0 )) as Mar,
sum(if( MONTH(orderr.data_hora) = 4, 1, 0 )) as Apr,
sum(if( MONTH(orderr.data_hora) = 5, 1, 0 )) as May,
sum(if( MONTH(orderr.data_hora) = 6, 1, 0 )) as Jun,
sum(if( MONTH(orderr.data_hora) = 7, 1, 0 )) as Jul,
sum(if( MONTH(orderr.data_hora) = 8, 1, 0 )) as Aug,
sum(if( MONTH(orderr.data_hora) = 9, 1, 0 )) as Sep,
sum(if( MONTH(orderr.data_hora) = 10, 1, 0 )) as Oct,
sum(if( MONTH(orderr.data_hora) = 11, 1, 0 )) as Nov,
sum(if( MONTH(orderr.data_hora) = 12, 1, 0 )) as Dece
from
profile left join orderr
on profile.user_id = orderr.seller_id
group by profile.user_id,
profile.name
I've created a fiddle to it (but the data_hora column I created as integer to make it quickly to do it, it is for understanding).
http://sqlfiddle.com/#!2/4a1a2e/5

Answer 3

It was perfect!
The field type 'data_hora' is datetime, so I made a small change.
SELECT p.user_id,
p.name,
tm.month10,
tm.month11,
tm.month12,
(tm.month10+tm.month11+tm.month12) AS final_total
FROM profile p
LEFT OUTER JOIN
(SELECT o.seller_id,
sum(month(o.data_hora) = 10) AS month10,
sum(month(o.data_hora) = 11) AS month11,
sum(month(o.data_hora) = 12) AS month12
FROM order o
WHERE MONTH(ORDER.data_hora) IN (10, 11, 12)
GROUP BY ORDER.seller_id ) tm
ON tm.seller_id = p.user_id
ORDER BY final_total DESC;
How could I optimize the field "final_total"?