MySQL: how can I count number of articles by a join table - mysql

Question

I have a table with news items, I have another table with media_types, I want to make one simple query that reads the media_types table and count for each record how many news_items exist.
The result will be turned into a json response that I will use for a chart, this is my SQLstatement
SELECT
gc.country AS "country"
, COUNT(*) AS "online"
FROM default_news_items AS ni
JOIN default_news_item_country AS nic ON (nic.id = ni.country)
JOIN default_country AS c ON (nic.country = c.id)
JOIN default_geo_country AS gc ON (gc.id = c.geo_country)
LEFT JOIN default_medias ON (m.id = ni.media)
WHERE TRUE
AND ni.deleted = 0
AND ni.date_item > '2013-10-23'
AND ni.date_item < '2013-10-29'
AND gc.country <> 'unknown'
AND m.media_type = '14'
GROUP BY gc.country
ORDER BY `online` desc LIMIT 10
This is the json respond I create from the mysql respond
[
{"country":"New Zealand","online":"7"},
{"country":"Switzerland","online":"1"}
]
How do I add print and social data to my output like this
I would like the json respond look like this
[
{"country":"New Zealand","online":"7", "social":"17", "print":"2"},
{"country":"Switzerland","online":"1", "social":"7", "print":"1"}
]
Can I use the count (*) in the select statement to do something like this
COUNT( * ) as online, COUNT( * ) as social, COUNT( * ) as print
Is it possible or do I have to do several SQL statement to get the data I'm looking for?

Answer 1

This is the general structure:
SELECT default_geo_country.country as country,
SUM(default_medias.media_type = 14) as online,
SUM(default_medias.media_type = XX) as social,
SUM(default_medias.media_type = YY) as print
FROM ...
JOIN ...
WHERE ...
GROUP BY country

Answer 2

I think you want conditional aggregation. Your question, however, only shows the online media type.
Your query would be more readable by using table aliases and removing the back quotes. Also, if media_type is an integer, then you should not enclose the constant for comparison in single quotes -- I, for one, find it misleading to compare a string constant to an integer column.
I suspect this is the way you want to go. Where the . . . is, you want to fill in with the counts for the other media types.
SELECT default_geo_country.country as country,
sum(media_type = '14') as online,
sum(default_medias.media_type = XX) as social,
sum(default_medias.media_type = YY) as print
. . .
FROM default_news_items ni JOIN
default_news_item_country nic
ON nic.id = ni.country JOIN
default_country dc
ON nic.country = dc.id JOIN
default_geo_country gc
ON gc.id = dc.geo_country LEFT JOIN
default_medias dm
ON dm.id = dni.media
WHERE ni.deleted = '0'
AND ni.date_item > '2013-10-23'
AND ni.date_item < '2013-10-29'
AND gc.country <> 'unknown'
GROUP BY gc.country
ORDER BY online desc
LIMIT 10