SQL - CURDATE() + 4 random digits (2013-10-02-0001) - mysql

Question

create table Table1(
DateIdentify CHAR(15),
primary key(DateIdentify)
);
Insert into Table1 (DateIdentify) VALUES('?');
How I want the 'DateIdentify' to look: (20131002-0001) with 0001 being some sort of an auto incrementer that starts at 0001 and goes up every insert and 20131002 coming from CURDATE(), so adding CURDATE() + 4 digits. I'm wondering if this is possible? If so, could anyone please point me in the right direction?
EDIT:
CREATE TABLE Table1(
IdTable1 int auto_increment NOT NULL,
Date1 datetime,
);

Answer 1

You have to separate your datetime and the auto increment field.
Create your table like this using an auto-increment int field, and your datetime.
For example:
CREATE TABLE Table1(
IdTable1 int PRIMARY KEY IDENTITY(1,1) NOT NULL,
Date datetime
)
Then, you don't have to insert anything in IdTable1 because of it is auto-incremented thanks to keyword IDENTITY (SQL do the auto-increment for you)
NOTE : I wrote this for SQLServer, if you use another database, the code can change a little bit.
Which one do you use ?
EDIT :
You can also do some insert like this :
INSERT INTO Table1
(
Date
)
VALUES
(
'2013-10-02'
)

Answer 2

In case a solution is required as, having only one column with values in desired format you can create a function as:
create function dbo.fn_GetDateIdentify ()
returns varchar(15)
as
begin
declare #DateIdentify varchar(15);
select #DateIdentify =
(select convert (varchar(8),GETDATE (),112) +
'-' +
right ('00000' + cast (
(
(
case when Not exists (select ROW_NUMBER() over( order by (select 1)) from Table1 ) then 1
else (select top 1 ROW_NUMBER() over( order by (select 1)) as currentRownumber from Table1 order by currentRownumber desc) + 1
end
)
)
as varchar(4))
,4));
return #DateIdentify;
end
go;
and then use the function in insert statement as :
insert into Table1 (DateIdentify)
select dbo.fn_GetDateIdentify();
Hope this helps!