I'm trying to write the following statement:
WHERE field LIKE 'Pandora' AND field Not Like 'radio', 'digital', 'internet';
Translation: Select where field is like Pandora and not like radio, digital, or internet.
Is there a way to write this statement without writing Not Like 3 times with ANDs in between?
Thank you
If "field" is not just single words, you would need to do something like this:
SELECT * FROM table WHERE field LIKE '%Pandora%' AND field NOT LIKE '%radio%' AND field NOT LIKE '%internet%' and field NOT LIKE '%digital%';
First of all, your query is redundant, in that if field is LIKE 'pandora', then the other conditions will by default return false.
There is no possible way that field can be equal to 'Pandora', 'radio', 'digital', and 'internet'.
As a result, you can simplify your query using the following example:
SELECT *
FROM example
WHERE field = 'Pandora';
If the two conditions represent two separate fields, then you can use the REGEXP operator to enforce the DRY principle while still allowing for further pattern matching:
SELECT *
FROM example
WHERE field_1 = 'Pandora'
AND field_2 NOT REGEXP '^(radio|digital|internet)$';
If you're searching for specific words, you can use NOT IN()
WHERE field LIKE 'Pandora' AND field NOT IN('radio', 'digital', 'internet');
If you need the wildcard % in your search you'll need to use multiple LIKEs.
Related
I have two use cases.
For all the columns in my table I am allowing user to search for contains. My query will be
Select * from table where column like "%value%";
When it comes to boolean columns and if they are searching for t/tr/tru/true I should be showing the results with
Select * from table where column is true;
Currently I am checking the entered string with a regular expression and hard coding the query. Is there a better way to achieve this ?
When the user query for equals to and the string contains special characters
Select * from table where column = "string with backslash escaped";
This query does not work but if I use like instead of = it works.
But like doesn't work for boolean columns.
You can use something like this to match against a boolean expression:
SELECT *
FROM my_table
WHERE IF(boolean_column, 'true', 'false') LIKE '%tr%';
The Like clause can be used only on text type of data (i.e VARCHAR, CHAR etc). Your logic should be more of finding out column name being searched and based on that define which operators to use.
If you have option to use a view in place of this table, you can create a view on this table and convert Boolean column to text based column which would allow you to search that column like all others.
I am trying to write a Query to find if a string contains part of the value in Column (Not to confuse with the query to find if a column contains part of a string).
Say for example I have a column in a table with values
ABC,XYZ
If I give search string
ABCDEFG
then I want the row with ABC to be displayed.
If my search string is XYZDSDS then the row with value XYZ should be displayed
The answer would be "use LIKE".
See the documentation: https://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html
You can do WHERE 'string' LIKE CONCAT(column , '%')
Thus the query becomes:
select * from t1 where 'ABCDEFG' LIKE CONCAT(column1,'%');
If you need to match anywhere in the string:
select * from t1 where 'ABCDEFG' LIKE CONCAT('%',column1,'%');
Here you can see it working in a fiddle:
http://sqlfiddle.com/#!9/d1596/4
Select * from table where #param like '%' + col + '%'
First, you appear to be storing lists of things in a column. This is the wrong approach to storing values in the database. You should have a junction table, with one row per entity and value -- that is, a separate row for ABC and XYZ in your example. SQL has a great data structure for storing lists. It is called a "table", not a "string".
If you are stuck with such a format and using MySQL, there is a function that can help:
where find_in_set('ABC', col)
MySQL treats a comma delimited string as a "set" and offers this function. However, this function cannot use indexes, so it is not particularly efficient. Did I mention that you should use a junction table instead?
What would be the right SQL statement so that when I search two words, like for example 'text field' in a text box, it will return all results that has 'text' and 'field' in it using the LIKE statement? I cant find the right terms to make a search. If possible, I want to make it dynamic. Like if a user search 5 words, all 5 words would be in the Like statement. I am trying to achieve a statement something like this.
SELECT *
FROM TABLE
WHERE SEARCH (LIKE %searchterm1%)
OR (LIKE %searchterm2%)
OR (LIKE %searchterm3%) ....
Try This. http://dev.mysql.com/doc/refman/5.1/en/regexp.html#operator_regexp
SELECT *
FROM TABLE
WHERE SEARCH
REGEXP 'searchterm1|searchterm2|searchterm3'
Here's an example of a SQL SELECT statement that uses the LIKE comparison operator
SELECT t.*
FROM mytable t
WHERE t.col LIKE CONCAT('%','cdef','%')
AND t.col LIKE CONCAT('%','hijk','%')
AND t.col LIKE CONCAT('%','mnop','%')
Only rows that have a value in the col column that contains all of the strings 'cdef', 'hijk', and 'mnop' will be returned.
You specifically asked about the LIKE comparison operator. There's also a REGEXP operator that matches regular expressions. And the Full-Text search feature may be a good fit your use case.
I have a MySQL table column rubrics which contains string value '61,80,112,256'. So I try execute that query:
select * from table where 256 in (rubrics) and 61 in (rubrics)
And no result returns. Any suggestions?
Since your rubrics column is a comma separated list the IN operator will not work.
MySQL does have a function that can find a value in a string list so you should be able to use FIND_IN_SET():
select *
from yourtable
where find_in_set(61, rubrics)
or find_in_set(256, rubrics)
See SQL Fiddle with Demo
Something like WHERE rubrics LIKE '%,256,%' OR rubrics LIKE '256,%' OR rubrics LIKE '%,256'. Using parenthesis you can also filter on the 61, but the resulting query will be come messy. You'd better normalize your data, so you can use subqueries and joins using keys (the real deal).
(see also bluefeet's answer as FIND_IN_SET is a better approach)
Try this
select * from table where rubrics like '%'+'256,'+'%' and rubrics like '%'+'61,'+'%'
IN operator does not work with strings
use correct substring matching operator like LIKE or LOCATE
one advice - update your rubics column to begin and end with , character, that will make your LOCATE(",62,", rubics) operations unambiguous as opposed to LOCATE("62", rubics) which will match also 622 and 262 and other combinations. Locating ,62, wil fail if your rubics has value of 62,blah,foo,bar because it doesn't start with ,
I've a problem and I'm guessing if there's a better way to achieve my goal. I've this query in Mysql to retrieve some rows:
SELECT *
FROM table
WHERE field IN ('V','S','G','B')
What I would like to do is to run a query that retrieve the rows where the field has value LIKE those in the IN list. I know that the trivial way is to use this query:
SELECT *
FROM table
WHERE field LIKE '%V%' OR field LIKE '%S%' OR
field LIKE '%G%' OR field LIKE '%B%'
What I want to know is there's an operator that do this or at least, if that operator does not exist, a better way to write the query.
Thanks to everyone that will help me.
Put the values in a table (Params) then use
SELECT *
FROM table
WHERE EXISTS (
SELECT *
FROM Params
WHERE table.field LIKE '%' + Params.col + '%'
);
Consider also putting the wildcard characters into the values in the Params table.