I want to find all rows form one table where one field is contained into another field.
For example:
It seems simple:
SELECT * FROM MyTable WHERE name LIKE CONCAT('%', parent_names, '%')
I need 1-st and 3-rd row from this query, but the above doesn't work!
Use INSTR()
SELECT * FROM MyTable
WHERE instr(parent_names, name) > 0
interchange the columns,
WHERE parent_names LIKE CONCAT('%', name, '%')
Related
I have created a subquery that searches for a particular string from one table, using the SQL LIKE condition. I would like to use this subquery's result as the string to search for in my main SQL query also using the LIKE condition. I tried the below code but I get syntax errors, although it seems to be the way it should be done...sadly I am not an SQL expert and just trying to feel this out.
SELECT * FROM `allcesseries`
WHERE series_id LIKE '%'+(SELECT industry_code FROM `ceindustry` WHERE industry_name LIKE '%Technical and trade schools%')+'%'
SELECT * FROM `allcesseries`
WHERE series_id LIKE concat('%',
(SELECT industry_code FROM `ceindustry`
WHERE industry_name LIKE '%Technical and trade schools%'),
'%')
I would suggest that you use exists in this case:
SELECT *
FROM `allcesseries` a
WHERE EXISTS (SELECT 1
FROM `ceindustry` c
WHERE c.industry_name LIKE '%Technical and trade schools%' AND
a.series_id LIKE CONCAT('%', c.industry_code, '%')
);
If you have multiple matches, then this will work as expected.
You can also phrase this directly as a join, if you want:
SELECT a.*
FROM `allcesseries` a JOIN
ceindustry c
ON c.industry_name LIKE '%Technical and trade schools%' AND
a.series_id LIKE CONCAT('%', c.industry_code, '%')
But if there are multiple rows that satisfy the conditions in ceindustry, you will get duplicates.
This is my users table:
http://ezinfotec.com/Capture.PNG
I need to select all rows those are not contain 2 in except column. How to write a query for this using php & Mysql.
The result i expect for this query is only return last row only.
Thank you.
Don't store comma separated values in your table, it's very bad practice, nevertheless you can use FIND_IN_SET
SELECT
*
FROM
users
WHERE
NOT FIND_IN_SET('2', except)
Try this:
SELECT *
FROM users
WHERE CONCAT(',', except, ',') NOT LIKE '%,2,%'
this should work for you
SELECT *
FROM table
WHERE table.except NOT LIKE '%,2%'
OR table.except NOT LIKE '%2,%';
I have a table in which one column is filled with data like 32;3;13;33;43
so
SELECT * FROM table;
gives something like
name ids
vegetables 13;3;63
fruits 37;73;333
When I'm querying MySQL like
SELECT * FROM table WHERE ids LIKE '%3%'
it gives me both records but obviously I want only this containing 3.
How to query MySQL correctly?
Try to use:
SELECT * FROM table WHERE CONCAT(';',ids,';') LIKE '%;3;%'
You will need to cover the case where it's the first in the list and the last.
SELECT * FROM table WHERE ids LIKE '%;3;%' OR LIKE '%;3' OR LIKE '3;%'
You can use FIND_IN_SET, if you replace the ; with a , before checking the value:0
SELECT *
FROM table
WHERE FIND_IN_SET('3', REPLACE(ids, ';', ','))
I have a mysql 5 table with a char field holding
DOG
DOUG
CAT
MOUSE
Now I want to SELECT on this field, finding any rows where that field exist within a string, like "DOGGY". (This is opposite of how you normally use a wildcard). So I want a select something like:
SELECT FROM TABLE WHERE FIELD IS SUBSTRING OF "DOGGY"
Is this possible?
select * from mytable where 'doggy' like concat('%',mycol,'%')
You should be able to use LOCATE() to achieve this:
SELECT * FROM MyTable WHERE LOCATE(MyField, 'DOGGY') != 0;
I'm trying do something like this:
SELECT * FROM table WHERE column IN (1,2,3)
but in place of 1,2,3 I want to use a column from another table that contains a comma-delimited list just like "1,2,3" above.
I have tried to do this:
SELECT
GROUP_CONCAT(a.eating_area SEPARATOR ', ')
FROM table_areas a
WHERE a.eating_area_id IN (
SELECT
o.eating_area_ids
FROM table_offers o WHERE o.rid=1
)
however this only returns the value associated with 1, and not 2 or 3. Can this be done or is there another way to do this?
Many thanks
SELECT * FROM table t
WHERE IF(FIND_IN_SET(column,(SELECT "1,2,3" FROM otherTable WHERE 1))>=1,1,0)
-- FIND_IN_SET will return the position.
I don't know if it's the best way to do it but... i think it could work.
Source: Find_in_set