How to select from data with variable Database and Table - mysql

Question

Is there any way to select from a variable table name database name and value?
I'm trying to a check the column value is exist from the below way. I forced do this way because the table name and column names and values are variable...
This is used in a Stored Procedure File.
I want something like:
SELECT 1
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA= 'database1'
AND TABLE_NAME= 'table1'
AND COLUMN_NAME = 'clmn_id_fk'
AND 'database1.table1.clmn_id_fk'=2218
I am not able to find a result.

Answer 1

You can take inspiration from a stored procedure as shown below. Change all that is necessary to achieve the solution you want, it is very important to include all the relevant restrictions and validations.
/* CODE FOR DEMONSTRATION PURPOSES */
DELIMITER $$
DROP PROCEDURE IF EXISTS `sp_check`$$
CREATE PROCEDURE `sp_check`(`p_table_schema` VARCHAR(64), `p_table_name` VARCHAR(64), `p_column_name` VARCHAR(64), `p_value` INT)
BEGIN
IF EXISTS (SELECT NULL
FROM `information_schema`.`columns`
WHERE `table_schema` = `p_table_schema` AND
`table_name` = `p_table_name` AND
`column_name` = `p_column_name`) THEN
SET #qry := CONCAT('SELECT IF(COUNT(`', `p_column_name`, '`), 1, 0) AS `EXISTS` FROM `', `p_table_schema`, '`.`', `p_table_name`, '` WHERE `', `p_column_name`, '` = ', `p_value`);
PREPARE stmt FROM #qry;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
ELSE
SELECT 0 AS `EXISTS`;
END IF;
END$$
DELIMITER ;
CALL `sp_check`('database1', 'table1', 'clmn_id_fk', 2218);