I have an SQL statement :
CREATE TABLE RoomType(
hotelID SMALLINT NOT NULL,
name VARCHAR(20) NOT NULL,
PRIMARY KEY (hotelID, name)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
CREATE TABLE BookingItem(
bookingID SMALLINT NOT NULL,
roomTypeName VARCHAR(20) NOT NULL,
PRIMARY KEY (bookingID, roomTypeName),
FOREIGN KEY (roomTypeName) REFERENCES RoomType(name)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
And it show errors #1215 - Cannot add foreign key constraint.
However when I change the line :
PRIMARY KEY (hotelID, name)
into
PRIMARY KEY (name, hotelID)
it works perfectly fine. I dont know what happens here. Can someone explain to me why this happens. Thank you very much.
FOREIGN KEY should match either several columns from left most part of the PRIMARY KEY or the PRIMARY KEY completely.
So in case of (hotelID, name) PK you can create a foreign key that refers to hotelID or to (hotelID, name), but not to name.
That's what documentation says about that:
However, in the referenced table, there must be an index where the referenced columns are listed as the first columns in the same order.
Related
I am creating the table with this syntax:
CREATE TABLE movies_genres
(
id BIGINT AUTO_INCREMENT,
movie_id INT NOT NULL,
genre_id INT NOT NULL,
PRIMARY KEY (id),
CONSTRAINT `fk_movie_id` FOREIGN KEY (movie_id) REFERENCES movies(id),
CONSTRAINT `fk_genre_id` FOREIGN KEY (genre_id) REFERENCES genres(id),
CONSTRAINT unique_id_pair UNIQUE(movie_id, genre_id)
);
But then I look at the info about the table in MySQL Workbench I see:
CREATE TABLE `movies_genres` (
`id` bigint NOT NULL AUTO_INCREMENT,
`movie_id` int NOT NULL,
`genre_id` int NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `unique_id_pair` (`movie_id`,`genre_id`),
KEY `fk_genre_id` (`genre_id`),
CONSTRAINT `fk_genre_id` FOREIGN KEY (`genre_id`) REFERENCES `genres` (`id`),
CONSTRAINT `fk_movie_id` FOREIGN KEY (`movie_id`) REFERENCES `movies` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci
Why this line of code has generated?
KEY `fk_genre_id` (`genre_id`)
Also I see that extra index was created that I didn't order...
Screenshot with extra index
https://dev.mysql.com/doc/refman/8.0/en/create-table-foreign-keys.html says:
MySQL requires indexes on foreign keys and referenced keys so that
foreign key checks can be fast and not require a table scan. In the
referencing table, there must be an index where the foreign key
columns are listed as the first columns in the same order. Such an
index is created on the referencing table automatically if it does not
exist.
(emphasis mine)
(Bill gave the answer; this is providing another tip.)
Get rid of id from the table and change to these two indexes:
PRIMARY KEY (`movie_id`,`genre_id`),
KEY `fk_genre_id` (`genre_id`),
That will make some of your uses of this many-to-many table run faster. It will also shrink the table size.
If need id
Since you need id for single-row deletion and updating, keep id, but use
PRIMARY KEY (id)
INDEX(`movie_id`, `genre_id`),
INDEX(`genre_id`, `movie_id`),
The PK will continue to make Delete/Update efficient; the other two indexes will make the many-to-many JOIN efficient.
I am facing an error when creating a table between the following two statement
CREATE TABLE SECTION (
cid varchar(10) not null,
sno varchar(3) not null,
primary key (cid, sno),
foreign key (cid) references COURSE (cid)
);
CREATE TABLE ROUND_RELEASE (
cid varchar(10) not null,
sno varchar(3) not null,
rid int not null,
foreign key (cid) references SECTION (cid),
foreign key (sno) references SECTION (sno),
foreign key (rid) references ROUND (rid)
);
Error Code: 1822. Failed to add the foreign key constraint. Missing index for constraint 'round_release_ibfk_2' in the referenced table 'section'
However, when I try to swap the primary key order in SECTION table, I am able to create both table without error
CREATE TABLE SECTION (
cid varchar(10) not null,
sno varchar(3) not null,
primary key (**sno, cid**),
foreign key (cid) references COURSE (cid)
);
CREATE TABLE ROUND_RELEASE (
cid varchar(10) not null,
sno varchar(3) not null,
rid int not null,
foreign key (cid) references SECTION (cid),
foreign key (sno) references SECTION (sno),
foreign key (rid) references ROUND (rid)
);
The follow code above works, and I only swap the attribute, from my knowledge, the order does not matter, thus I am quite puzzled by why is this occurring.
Any guidance on this? Thanks!
Based on the error message, I assume that you are using MySQL.
What you are seeing is a documented behavior:
In the referenced table, there must be an index where the referenced columns are the first columns in the same order.
Let me pinpoint, however, that your code probably does not do what you really want. You probably should be creating a compound foreign key, that references the tuples of columns, rather than one foreign key per column:
create table round_release (
cid varchar(10) not null,
sno varchar(3) not null,
rid int not null,
foreign key (cid, sno) references section(cid, sno),
foreign key (rid) references round(rid)
);
One last thing to note is that your round_release table has no primary key defined; this is not a good practice, and might hurt you in several ways in the future. So, do create a primary key for the table, either as a separate column (possibly auto-incremented), or as a combination of existing columns.
i got these two succesfull queries:
create table Donors (
donor_id int not null auto_increment primary key,
gender varchar(1) not null,
date_of_birth date not null,
first_name varchar(20) not null,
middle_name varchar(20),
last_name varchar(30) not null,
home_phone tinyint(10),
work_phone tinyint(10),
cell_mobile_phone tinyint(10),
medical_condition text,
other_details text );
and
create table Donors_Medical_Condition (
donor_id int not null,
condition_code int not null,
seriousness text,
primary key(donor_id, condition_code),
foreign key(donor_id) references Donors(donor_id) );
but when i try this one:
create table Medical_Conditions (
condition_code int not null,
condition_name varchar(50) not null,
condition_description text,
other_details text,
primary key(condition_code),
foreign key(condition_code) references Donors_Medical_Condition(condition_code) );
i get "Error Code: 1215, cannot add foreign key constraint"
i dont know what am i doing wrong.
In MySql, a foreign key reference needs to reference to an index (including primary key), where the first part of the index matches the foreign key field. If you create an an index on condition_code or change the primary key st that condition_code is first you should be able to create the index.
To define a foreign key, the referenced parent field must have an index defined on it.
As per documentation on foreign key constraints:
REFERENCES tbl_name (index_col_name,...)
Define an INDEX on condition_code in parent table Donors_Medical_Condition and it should be working.
create table Donors_Medical_Condition (
donor_id int not null,
condition_code int not null,
seriousness text,
KEY ( condition_code ), -- <---- this is newly added index key
primary key(donor_id, condition_code),
foreign key(donor_id) references Donors(donor_id) );
But it seems you defined your tables order and references wrongly.
You should have defined foreign key in Donors_Medical_Condition table but not in Donors_Medical_Conditions table. The latter seems to be a parent.
Modify your script accordingly.
They should be written as:
-- create parent table first ( general practice )
create table Medical_Conditions (
condition_code int not null,
condition_name varchar(50) not null,
condition_description text,
other_details text,
primary key(condition_code)
);
-- child table of Medical_Conditions
create table Donors_Medical_Condition (
donor_id int not null,
condition_code int not null,
seriousness text,
primary key(donor_id, condition_code),
foreign key(donor_id) references Donors(donor_id),
foreign key(condition_code)
references Donors_Medical_Condition(condition_code)
);
Refer to:
MySQL Using FOREIGN KEY Constraints
[CONSTRAINT [symbol]] FOREIGN KEY
[index_name] (index_col_name, ...)
REFERENCES tbl_name (index_col_name,...)
[ON DELETE reference_option]
[ON UPDATE reference_option]
reference_option:
RESTRICT | CASCADE | SET NULL | NO ACTION
A workaround for those who need a quick how-to:
FYI: My issue was NOT caused by the inconsistency of the columns’ data types/sizes, collation or InnoDB storage engine.
How to:
Download a MySQL workbench and use it’s GUI to add foreign key. That’s it!
Why:
The error DOES have something to do with indexes. I learned this from the DML script automatically generated by the MySQL workbench. Which also helped me to rule out all those inconsistency possibilities.It applies to one of the conditions to which the foreign key definition subject. That is: “MySQL requires indexes on foreign keys and referenced keys so that foreign key checks can be fast and not require a table scan.” Here is the official statement: http://dev.mysql.com/doc/refman/5.7/en/create-table-foreign-keys.html
I did not get the idea of adding an index ON the foreign key column(in the child table), only paid attention to the referenced TO column(in the parent table).
Here is the auto-generated script(PHONE.PERSON_ID did not have index originally):
ALTER TABLE `netctoss`.`phone`
ADD INDEX `personfk_idx` (`PERSON_ID` ASC);
ALTER TABLE `netctoss`.`phone`
ADD CONSTRAINT `personfk`
FOREIGN KEY (`PERSON_ID`)
REFERENCES `netctoss`.`person` (`ID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION;
I think you've got your tables a bit backwards. I'm assuming that Donors_Medical_Condtion links donors and medical conditions, so you want a foreign key for donors and conditions on that table.
UPDATED
Ok, you're also creating your tables in the wrong order. Here's the entire script:
create table Donors (
donor_id int not null auto_increment primary key,
gender varchar(1) not null,
date_of_birth date not null,
first_name varchar(20) not null,
middle_name varchar(20),
last_name varchar(30) not null,
home_phone tinyint(10),
work_phone tinyint(10),
cell_mobile_phone tinyint(10),
medical_condition text,
other_details text );
create table Medical_Conditions (
condition_code int not null,
condition_name varchar(50) not null,
condition_description text,
other_details text,
primary key(condition_code) );
create table Donors_Medical_Condition (
donor_id int not null,
condition_code int not null,
seriousness text,
primary key(donor_id, condition_code),
foreign key(donor_id) references Donors(donor_id),
foreign key(condition_code) references Medical_Conditions(condition_code) );
I got the same issue and as per given answers, I verified all datatype and reference but every time I recreate my tables I get this error. After spending couple of hours I came to know below command which gave me inside of error-
SHOW ENGINE INNODB STATUS;
LATEST FOREIGN KEY ERROR
------------------------
2015-05-16 00:55:24 12af3b000 Error in foreign key constraint of table letmecall/lmc_service_result_ext:
there is no index in referenced table which would contain
the columns as the first columns, or the data types in the
referenced table do not match the ones in table. Constraint:
,
CONSTRAINT "fk_SERVICE_RESULT_EXT_LMC_SERVICE_RESULT1" FOREIGN KEY ("FK_SERVICE_RESULT") REFERENCES "LMC_SERVICE_RESULT" ("SERVICE_RESULT") ON DELETE NO ACTION ON UPDATE NO ACTION
I removed all relation using mysql workbench but still I see same error. After spending few more minutes, I execute below statement to see all constraint available in DB-
select * from information_schema.table_constraints where
constraint_schema = 'XXXXX'
I was wondering that I have removed all relationship using mysql workbench but still that constraint was there. And the reason was that because this constraint was already created in db.
Since it was my test DB So I dropped DB and when I recreate all table along with this table then it worked. So solution was that this constraint must be deleted from DB before creating new tables.
Check that both fields are the same size and if the referenced field is unsigned then the referencing field should also be unsigned.
im new on mysql workbench, and i tried so many things to put my script working but i simply cant... Ive got these tables:
CREATE TABLE Utilizador (email varchar(40) not null, nome varchar(50)
not null, dataNascimento date, profissao varchar(50) not null,
reputacao double(3,2) unsigned not null, constraint pk_Utilizador
primary key(email))
This is the first table created!
CREATE TABLE POI (email varchar(40) not null, designacaoPOI
varchar(10) not null, coordenadaX int, coordenadaY int,
descricaoPOI varchar(200), constraint pk_POI primary key(email,
designacaoPOI), constraint fk_POI foreign key(email) references
Utilizador(email) on delete cascade)
This is the second table created!
CREATE TABLE Utilizador_POI (email varchar(40) not null, designacaoPOI
varchar(10) not null, constraint pk_Utilizador_POI primary key(email,
designacaoPOI), constraint fk1_Utilizador_POI foreign key(email)
references Utilizador(email) on delete cascade, constraint
fk2_Utilizador_POI foreign key(designacaoPOI) references
POI(designacaoPOI) on delete cascade)
This table gives me the error: Error Code: 1215. Cannot add foreign key constraint
I did some tests and im almost sure that the problem is in the foreign key "designacaoPOI". The other FK ("email") dont give me any error, so maybe the problem is in the Table POI?
Thanks in advanced!
The problem here is twofold:
1/ Use IDs for PRIMARY KEYs
You should be using IDs for primary keys rather than VARCHARs or anything that has any real-world "business meaning". If you want the email to be unique within the Utilizador table, the combination of email and designacaoPOI to be unique in the POI table, and the same combination (email and designacaoPOI) to be unique in Utilizador_POI, you should be using UNIQUE KEY constraints rather than PRIMARY KEY constraints.
2/ You cannot DELETE CASCADE on a FOREIGN KEY that doesn't reference the PRIMARY KEY
In your third table, Utilizador_POI, you have two FOREIGN KEYs references POI. Unfortunately, the PRIMARY KEY on POI is a composite key, so MySQL has no idea how to handle a DELETE CASCADE, as there is not a one-to-one relationship between the FOREIGN KEY in Utilizador_POI and the PRIMARY KEY of POI.
If you change your tables to all have a PRIMARY KEY of ID, as follows:
CREATE TABLE blah (
id INT(9) AUTO_INCREMENT NOT NULL
....
PRIMARY KEY (id)
);
Then you can reference each table by ID, and both your FOREIGN KEYs and DELETE CASCADEs will work.
I think the problem is that Utilizador_POI.email references POI.email, which itself references Utilizador.email. MySQL is probably upset at the double-linking.
Also, since there seems to be a many-to-many relationship between Utilizador and POI, I think the structure of Utilizador_POI isn't what you really want. Instead, Utilizador_POI should reference a primary key from Utilizador, and a matching primary key from POI.
The problem is in your second table. Your primary key is (email,designacaoPOI), when you try to reference that in your table it gives you error because of this:
InnoDB permits a foreign key to reference any index column or group of
columns. However, in the referenced table, there must be an index
where the referenced columns are listed as the first columns in the
same order.
For it to work, either change the order of your second tale PRIMARY KEY :
CREATE TABLE POI (
email VARCHAR(40) NOT NULL,
designacaoPOI VARCHAR(10) NOT NULL,
coordenadaX INT,
coordenadaY INT,
descricaoPOI VARCHAR(200),
CONSTRAINT pk_POI PRIMARY KEY (designacaoPOI,email), -- changed the order
CONSTRAINT fk_POI FOREIGN KEY (email)
REFERENCES Utilizador(email) ON DELETE CASCADE
);
sqlfiddle demo
or add an index for designacaoPOI:
CREATE TABLE POI (
email VARCHAR(40) NOT NULL,
designacaoPOI VARCHAR(10) NOT NULL,
coordenadaX INT,
coordenadaY INT,
descricaoPOI VARCHAR(200),
CONSTRAINT pk_POI PRIMARY KEY (designacaoPOI,email),
KEY key_designacaoPOI(designacaoPOI), -- added index for that column
CONSTRAINT fk_POI FOREIGN KEY (email)
REFERENCES Utilizador(email) ON DELETE CASCADE
);
sqlfiddle demo
Either of these solutions will let you create your third table without errors.
Hey guys getting an Error code 1215, SQL state HY000: Cannot add foreign key constraint for my PERSON_GROUP table and IMAGES table.. Don't know why, is there something wrong with my referencing? I've tried rewriting it but its just not working...
Updated code im now just getting an error for FOREIGN KEY (ID) REFERENCES INSTRUMENT(ID)
You can only create foreign keys that reference either the primary key or a unique key. Since ID is the primary key of PERSON change your foreign keys to point to ID instead of email. You could also make email a unique column, which is probably a good idea to make sure no one reuse the same email address, but it is still less storage to make foreign keys on an integer then a string.
I had this problem. The problem was database engine. Until i added the ENGINE=MyISAM DEFAULT CHARSET=latin1 before it worked. I guess my default was innoDB or something else.
CREATE TABLE LECTURE_NOTE (
ID bigint(20) NOT NULL,
NOTE VARCHAR(1000) NOT NULL,
NOTE_DATE TIMESTAMP NULL DEFAULT NULL,
LECTURE_ID bigint(20) NOT NULL,
PUBLISHER_ID bigint(20) NOT NULL,
PRIMARY KEY (ID),
CONSTRAINT fk_lecture_id FOREIGN KEY (LECTURE_ID) REFERENCES
COURSE_LECTURE (ID),
CONSTRAINT fk_publisher_id FOREIGN KEY (PUBLISHER_ID) REFERENCES
PUBLISHER (ID)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;