Get conversation and last message Query - mysql

Question

i'm tring to get the conversations with the relative last message and order them by time and if is read the message. Let's go to show the my logic.
I created 3 table: inbox_join / inbox_msg / users
On the first table "inbox join" i have the datas about who have a active discussion. In this case we have id_user - "1" and id_user_2 - "4" they have a conversation.
On the inbox_msg table I have the text message, id conversation where the message will shown and other field easy to understand.
Inbox join table
Inbox_msg table
Users table
I made a query that work fine, but the my issue is that i can't have the occured_at on the inbox_msg table. I would like find a better solution for have my desidered result and i can't order how i'm looking for.
This is my query
SELECT DISTINCT (
inbox_join.id_conversation
), user_chat.name AS name_conv, user_chat.surname AS surname_conv, user_chat.username as username_conv, user_chat.id as id_chat, image_upload.name_image, (
SELECT DISTINCT (
message
)
FROM inbox_msg
WHERE inbox_join.id_conversation = inbox_msg.id_conversation
ORDER BY occured_at DESC
LIMIT 1
) AS last_msg, users.name, users.surname
FROM inbox_join
INNER JOIN users ON users.id = inbox_join.id_user
INNER JOIN users AS user_chat ON user_chat.id <> 1 AND (inbox_join.id_user_2 = user_chat.id || inbox_join.id_user = user_chat.id)
INNER JOIN image_upload ON image_upload.id_image = user_chat.profile_image
WHERE inbox_join.id_user = 1
OR inbox_join.id_user_2 = 1
Result desidered selecting the conversation about user 1:
id_conversation | id_user | name | surname | username | last_msg | occured_at_last_msg | read_msg |
1 4 E S E Yes 1380724676 0
4 5 G E K Good 1380724675 0

Answer 1

Query:
SELECT im.id_conversation,
im.id_user,
u.name,
u.surname,
u.username,
im.message AS last_msg,
im.occured_at AS occured_at_last_msg,
im.read_msg
FROM inbox_msg im
JOIN users u
ON u.id_user = im.id_user
JOIN (SELECT id_conversation,
MAX(occured_at) AS occured_at
FROM inbox_msg
GROUP BY id_conversation) im2
ON im2.id_conversation = im.id_conversation
AND im2.occured_at = im.occured_at
ORDER BY im.occured_at DESC

Answer 2

I made this query and should work fine, I would like receive comment about this query.
SELECT DISTINCT (
im.id_conversation
), users.name, users.surname, users.username, image_upload.name_image, im.message as last_msg, im.occured_at, im.read_msg
FROM inbox_join
INNER JOIN (
SELECT sub . *
FROM (
SELECT DISTINCT (
id_conversation
), id_user, message, occured_at, read_msg
FROM inbox_msg
WHERE id_user <> 1
ORDER BY occured_at DESC
) AS sub
GROUP BY sub.id_user
ORDER BY sub.occured_at DESC
) AS im ON im.id_conversation = im.id_conversation
INNER JOIN users ON im.id_user = users.id
INNER JOIN image_upload ON users.profile_image = image_upload.id_image
WHERE inbox_join.id_user = 1 || inbox_join.id_user_2 = 1