Always return 1 even when there is no table related object - mysql

I query my database for a table with joined related table
Example: I want to show all styles and join mixes with that style but show 0 mixes if thst style don't have mixes related.
Here is my 2 tables:
First The Mixes table
CREATE TABLE `mixes` (
`mixes_id` int(11) NOT NULL AUTO_INCREMENT,
`datePublic` date DEFAULT NULL ,
`timeLenght` time DEFAULT NULL ,
`Title` varchar(255) DEFAULT 'No-Title-Yet' ,
`dwnlSize` varchar(45) DEFAULT '? MegaBytes',
`Quality` char(10) DEFAULT '? kbits/s',
`style_id` int(3) unsigned zerofill DEFAULT NULL,
`collection_id` int(3) unsigned zerofill DEFAULT '001',
`lienDwnld` varchar(255) DEFAULT NULL,
`VidLink` varchar(255) DEFAULT NULL,
`ArtisteFeat` varchar(255) DEFAULT NULL,
`slugMixTitle` varchar(100) DEFAULT NULL,
`cache` enum('0','1') DEFAULT NULL,
PRIMARY KEY (`mixes_id`),
UNIQUE KEY `Title_UNIQUE` (`Title`),
UNIQUE KEY `lienDwnld_UNIQUE` (`lienDwnld`),
UNIQUE KEY `slugMixTitle` (`slugMixTitle`),
KEY `style_index` (`style_id`),
KEY `collection_index` (`collection_id`)
)
ENGINE=InnoDB DEFAULT CHARSET=latin1 ;
ALTER TABLE `mixes`
ADD CONSTRAINT `collectionMustExist` FOREIGN KEY (`collection_id`) REFERENCES `collection` (`collection_id`),
ADD CONSTRAINT `styleMustExist` FOREIGN KEY (`style_id`) REFERENCES `style` (`style_id`);
Then the style Table
CREATE TABLE `style` (
`style_id` int(3) unsigned zerofill NOT NULL AUTO_INCREMENT,
`imgMixCat` varchar(255) DEFAULT NULL,
`nameMixCat` varchar(45) DEFAULT NULL,
`descMixCat` varchar(255) DEFAULT NULL,
`slugMixCat` varchar(45) DEFAULT NULL,
`hideMixCat` int(11) NOT NULL DEFAULT '0',
PRIMARY KEY (`style_id`),
UNIQUE KEY `nameMixCat_UNIQUE` (`nameMixCat`),
UNIQUE KEY `slugMixCat` (`slugMixCat`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;
And this is my current Query:
SELECT
count(style.style_id) AS count,
nameMixCat,
style.style_id,
descMixCat,
hideMixCat,
slugMixCat,
imgMixCat
FROM style as style
LEFT JOIN mixes as mixes ON style.style_id = mixes.style_id
GROUP BY style.style_id
ORDER BY style.style_id ASC
So what make return 1 when there is no mixes related to a style?

Related

Cant create a relation in mysql - Error creating foreign key on id_produk (check data types)

here is my table :
CREATE TABLE `pesanan` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`ref_number` varchar(50) NOT NULL DEFAULT '',
`id_produk` int(11) NOT NULL,
`id_user` int(11) NOT NULL,
`qty` int(11) NOT NULL,
`total` varchar(50) NOT NULL DEFAULT '',
`tanggal` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=10 DEFAULT CHARSET=latin1;
i want to create a relation of id_produk to table produk.id and id_user to user.id, here is the other table :
CREATE TABLE `produk` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`id_kategori` int(11) NOT NULL,
`status` varchar(10) NOT NULL DEFAULT '',
`slug` varchar(100) NOT NULL DEFAULT '',
`judul` varchar(100) NOT NULL DEFAULT '',
`harga` varchar(10) DEFAULT '',
`target` int(11) DEFAULT NULL,
`desc` text,
`cover` varchar(100) DEFAULT NULL,
`tanggal` timestamp NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=latin1;
and user table
CREATE TABLE `user` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`suspended` int(11) DEFAULT NULL,
`level` varchar(11) DEFAULT NULL,
`nama` varchar(100) DEFAULT NULL,
`email` varchar(100) DEFAULT NULL,
`password` varchar(100) DEFAULT NULL,
`alamat` text,
PRIMARY KEY (`id`),
UNIQUE KEY `email` (`email`)
) ENGINE=InnoDB AUTO_INCREMENT=23 DEFAULT CHARSET=latin1;
when i try to relation it , it give me this error :
Error creating foreign key on id_produk (check data types)
The columns should have the exact same data type in both tables. In your case in the "produk" and "user" tables they are unsigned, which means they go from 0 to 4294967295 but in the "pesanan" table they are signed which means they go from -2147483648 to 2147483647. See more here.
If the server allowed you to create such foreign keys, it would possibly create situations where, for example, a user is added with and ID of 2147483648 that cannot ever be referenced in the "pesanan" table.
You should change the "id_produk" and "id_user" columns in the "pesanan" table to be unsigned.

MySQL: Optimizing JOINs to find non-matching records

We have a host management system (let's call it CMDB), and a DNS system, each using different tables. The former syncs to the latter, but manual changes cause them to get out of sync. I would like to craft a query to find aliases in CMDB that do NOT have a matching entry in DNS (either no entry, or the name/IP is different)
Because of the large size of the tables, and the need for this query to run frequently, optimizing the query is very important.
Here's what the tables look like:
cmdb_record: id, ipaddr
cmdb_alias: record_id, host_alias
dns_entry: name, ipaddr
cmdb_alias.record_id is a foreign key from cmdb_record.id, so that one IP address can have multiple aliases.
So far, here's what I've come up with:
SELECT cmdb_alias.host_alias, cmdb_record.ipaddr
FROM cmdb_record
INNER JOIN cmdb_alias ON cmdb_alias.record_id = cmdb_record.id
LEFT JOIN dns_entry
ON dns_entry.ipaddr = cmdb_record.ipaddr
AND dns_entry.name = cmdb_alias.host_alias
WHERE dns_entry.ipaddr IS NULL OR dns_entry.name IS NULL
This seems to work, but takes a very long time to run. Is there a better way to do this? Thanks!
EDIT: As requested, here are the SHOW CREATE TABLEs. There are lots of extra fields that aren't particularly relevant, but included for completeness.
Create Table: CREATE TABLE `cmdb_record` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`ip_version` int(11) DEFAULT NULL,
`ipaddr` varchar(40) DEFAULT NULL,
`ipaddr_numeric` decimal(40,0) DEFAULT NULL,
`block_id` int(11) NOT NULL,
`record_commented` tinyint(1) NOT NULL,
`mod_time` datetime NOT NULL,
`deleted` tinyint(1) NOT NULL,
`deleted_date` datetime DEFAULT NULL,
`record_owner` varchar(50) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `ipaddr` (`ipaddr`),
KEY `cmdb_record_fe30f0f7` (`ipaddr`),
KEY `cmdb_record_2b8b575` (`ipaddr_numeric`),
KEY `cmdb_record_45897ef2` (`block_id`),
CONSTRAINT `block_id_refs_id_ed6ed320` FOREIGN KEY (`block_id`) REFERENCES `cmdb_block` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=104427 DEFAULT CHARSET=latin1
Create Table: CREATE TABLE `cmdb_alias` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`host_alias` varchar(255) COLLATE latin1_general_cs NOT NULL,
`record_id` int(11) NOT NULL,
`record_order` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `cmdb_alias_fcffc3bb` (`record_id`),
KEY `alias_lookup` (`host_alias`),
CONSTRAINT `record_id_refs_id_8169fc71` FOREIGN KEY (`record_id`) REFERENCES `cmdb_record` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=155433 DEFAULT CHARSET=latin1 COLLATE=latin1_general_cs
Create Table: CREATE TABLE `dns_entry` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`rec_grp_id` varchar(40) NOT NULL,
`parent_id` int(11) NOT NULL,
`domain_id` int(11) DEFAULT NULL,
`name` varchar(255) DEFAULT NULL,
`type` varchar(6) DEFAULT NULL,
`ipaddr` varchar(255) DEFAULT NULL,
`ttl` int(11) DEFAULT NULL,
`prio` int(11) DEFAULT NULL,
`status` varchar(20) NOT NULL,
`op` varchar(20) NOT NULL,
`mod_time` datetime NOT NULL,
`whodunit` varchar(50) NOT NULL,
`comments` longtext NOT NULL,
PRIMARY KEY (`id`),
KEY `dns_entry_a2431ea` (`domain_id`),
KEY `dns_entry_52094d6e` (`name`)
) ENGINE=InnoDB AUTO_INCREMENT=49437 DEFAULT CHARSET=utf8
If you don't have one already, create an index on dns_entry(ipaddr, name). This might be all you need to speed the query.

How to add foreign key in table using existing column, without losing data?

I have a table in which I need to add foreign key on an existing column. Following is create table:
CREATE TABLE `itemtx` (
`itemTxid` int(11) NOT NULL AUTO_INCREMENT,
`itemcode` varchar(1) NOT NULL,
`weight` decimal(7,3) DEFAULT NULL,
`txtype` varchar(10) DEFAULT 'Pickup',
`tripstopid` int(11) NOT NULL,
`barcode` varchar(25) DEFAULT NULL,
`bagcount` int(11) DEFAULT '1',
PRIMARY KEY (`itemTxid`)
) ENGINE=InnoDB AUTO_INCREMENT=33524 DEFAULT CHARSET=latin1
I need to add foreign key on tripstopid column. I cannot drop or empty table as it contains data. Following is the referenced table:
CREATE TABLE `tripstop` (
`tripstopid` int(11) NOT NULL AUTO_INCREMENT,
`tripid` int(11) DEFAULT NULL,
`locationName` varchar(100) DEFAULT NULL,
`userName` varchar(100) DEFAULT NULL,
`locationid` int(11) DEFAULT NULL,
`datetime` varchar(20) DEFAULT NULL,
`createts` varchar(20) DEFAULT NULL,
`latitude` double DEFAULT NULL,
`longitude` double DEFAULT NULL,
`userid` int(11) DEFAULT NULL,
`tid` int(11) DEFAULT NULL,
PRIMARY KEY (`tripstopid`)
) ENGINE=InnoDB AUTO_INCREMENT=4691 DEFAULT CHARSET=latin1
How can I do this without losing my data?
You can achieve this by following:
ALTER TABLE itemtx
ADD FOREIGN KEY (tripstopid) REFERENCES tripstop(tripstopid);
Verified by creating tables, inserting data in them and then updating table for foreign key, previously entered data is not lost.

cannot add second FK : got error can't create table'.jobstatus\#sql-32c_12f2f.frm' (errno:150)

CREATE TABLE `job` (
`jobId` int(11) NOT NULL auto_increment,
`jobcode` varchar(25) default NULL,
`jobname` varchar(255) default NULL,
`location` varchar(255) default NULL,
`budget` int(10) unsigned default NULL,
`year_type` varchar(100) default NULL,
`worklineId` int(11) default NULL,
PRIMARY KEY (`jobId`),
KEY `NewIndex` (`worklineId`),
FOREIGN KEY (`worklineId`) REFERENCES `workline` (`worklineId`)
) TYPE=InnoDB;
CREATE TABLE `subjob` (
`subjobId` int(11) NOT NULL auto_increment,
`subjobcode` varchar(25) default NULL,
`subjobname` varchar(255) default NULL,
`subjobbudget` int(11) unsigned default NULL,
`jobgoal_date` date default '0000-00-00',
`jobId` int(11) default NULL,
PRIMARY KEY (`subjobId`),
KEY `NewIndex` (`jobId`),
FOREIGN KEY (`jobId`) REFERENCES `job` (`jobId`)
) TYPE=InnoDB;
CREATE TABLE `contract` (
`contractId` int(11) NOT NULL auto_increment,
`contractcode` varchar(25) default NULL,
`price` int(11) unsigned default NULL,
`contractprice` int(11) unsigned default NULL,
`company` varchar(50) default NULL,
`signdate` date default '0000-00-00',
`begindate` date default '0000-00-00',
`enddateplan` date default '0000-00-00',
`note` text,
PRIMARY KEY (`contractId`)
) TYPE=InnoDB;
CREATE TABLE `subjob_contract` (
`subjobcontractId` int(11) NOT NULL auto_increment,
`status` varchar(11) default NULL,
`contractId` int(11) default NULL,
`subjobId` int(11) default NULL,
PRIMARY KEY (`subjobcontractId`),
KEY `NewIndex` (`contractId`),
KEY `NewIndex2` (`subjobId`),
FOREIGN KEY (`contractId`) REFERENCES `contract` (`contractId`)
) TYPE=InnoDB
I m using mysql front 3.2 to manage database,I can add first fk but when i add second fk i got an error following this :
sql execution error #1005. response from the database: can't create table'.jobstatus#sql-32c_12f2f.frm' (errno:150). i already define the new index for fk subjobId reference to subjob table what could be the possibility of this error? thank you
Check the datatype and size of the subjobId column on primary table and referenced table. both must be same than it will allow you to create foreign key.
Answer is: You can not refer that column/table which is not created yet. Try to execute tables having foreign keys after the referenced tables.
Obviously you should have consistency in datatypes of foreign key and referenced column as well
Correct Execution Demo. Also You should use Engine=InnoDB instead of Type=InnoDB

MySQL count from one table while joining another

I don't know if it's just been a long day or what, but I cannot figure out the query that I need to run here. We have two tables - One for leads generated and one for reports. The leads table has basic lead info, along with the Source (Campaign) of the lead. However, we need to know the number of leads that an ACCOUNT has received within a date range. Here is the relevant table structure:
client_leads:
id
source
date
client_reports:
account
campaign
date
The 'source' column contains the same values as the 'campaign' column. So, how would I achieve the following:
Say there are 10 leads in the leads table, each with the campaign that generated the lead. There are 10 accounts in the reports table, each with hundreds of campaigns. I need to list each account and how many leads it has in the leads table.
I just can't get the logic straight in my head. I've tried everything that I can think of and it's just not working out for me. If you need further explanation, let me know. I'm trying to describe the problem to the best of my ability.
Edit:
CREATE TABLE `client_leads` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`site_id` int(10) DEFAULT NULL,
`ip` varchar(255) DEFAULT NULL,
`source` varchar(255) DEFAULT NULL,
`kw` varchar(255) DEFAULT NULL,
`adgroup` varchar(255) DEFAULT NULL,
`time` time DEFAULT NULL,
`date` date DEFAULT NULL,
`dayweek` varchar(255) DEFAULT NULL,
`first_name` varchar(255) DEFAULT NULL,
`last_name` varchar(255) DEFAULT NULL,
`address` varchar(255) DEFAULT NULL,
`city` varchar(255) DEFAULT NULL,
`postal_code` char(5) DEFAULT NULL,
`state` char(2) DEFAULT NULL,
`email` varchar(255) DEFAULT NULL,
`preferred_phone` varchar(10) DEFAULT NULL,
`alternate_phone` varchar(10) DEFAULT NULL,
`level_of_education` varchar(255) DEFAULT NULL,
`program_of_interest` varchar(255) DEFAULT NULL,
`organic` tinyint(1) NOT NULL DEFAULT '0',
PRIMARY KEY (`id`),
KEY `site_id` (`site_id`),
KEY `date_indeces` (`time`,`date`,`dayweek`) USING BTREE,
CONSTRAINT `site_id` FOREIGN KEY (`site_id`) REFERENCES `client_sites` (`id`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=32 DEFAULT CHARSET=utf8
CREATE TABLE `client_reports` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`account` varchar(255) DEFAULT NULL,
`friendly_name` varchar(255) DEFAULT NULL,
`sites_id` int(10) DEFAULT NULL,
`service` varchar(255) DEFAULT NULL,
`date` date DEFAULT NULL,
`campaign` varchar(255) DEFAULT NULL,
`adgroup` varchar(255) DEFAULT NULL,
`keyword` varchar(255) DEFAULT NULL,
`impressions` int(10) DEFAULT NULL,
`clicks` int(10) DEFAULT NULL,
`cost` float DEFAULT NULL,
`max_cpc` float DEFAULT NULL,
`avg_pos` float DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `stats` (`impressions`,`clicks`,`cost`),
KEY `date` (`date`),
KEY `campaign` (`campaign`),
KEY `adgroup` (`adgroup`),
KEY `keyword` (`keyword`),
KEY `service` (`service`),
KEY `sites_id` (`sites_id`),
CONSTRAINT `sites_id` FOREIGN KEY (`sites_id`) REFERENCES `client_sites` (`id`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=109167 DEFAULT CHARSET=utf8
Edit Again:
client_reports table data viewable at http://pastebin.com/T532W3Eq
client_leads table data viewable at http://pastebin.com/9cjWEvck
SELECT cr.account, cr.campaign, cr.date, COUNT(cl.id) AS number_of_leads
FROM client_reports cr
LEFT JOIN client_leads cl
ON cl.source = cr.campaign
GROUP BY cl.source