Issue related to Background-Position for Image in HTML in CSS - html

I have following CSS class :
.acceptRejectAll a, .acceptRejectAll a:visited{
background-image: url("../images/view-patient.png");
background-position: left top;
background-repeat: no-repeat;
color: #4B555C;
float: left;
height: 35px;
padding-top: 12px;
text-align: center;
text-decoration: none;
width: 100px;
}
and following HTML :
<div style="float: none; display: inline-table" class="acceptRejectAll">
<a style="display:inline-block;height:25px;" href="#" class="fontBlack" id="ctl00_ContentPlaceHolder1_btnAcceptAll">Accept All</a>
</div>
this is display as follows :
when i decrease the size of in css class like : width : 85px
it displays as follows :
it cuts image from right side:
i tried to set background-Position in css class : but either left side or right side, image is not display correctly
wht is solution ?
Thanks

You will need to use background-size for this. Example:
background-size: 100% 100%;
Please note that this setting can scale your image to fill parent.

As the image is 100px (at least the visible part is about 92px so I guess the size is 100px) if you change the size of the button you need to scale the background image rather than change the position.
background-size:85px 35px;

Gradient and Border radius
Another way to approach this — considering the kind of button style you are using — is to go the gradient and border radius route. Whilst the code to use a css gradient looks rather messy, it is dynamically generated so you wont end up with stretched curved corners like you will using background-size.
Everything used below is pretty well supported now by most browsers. For anything that doesn't support the gradient you will get a solid blue background with curved corners instead, and it almost isn't worth worrying about non-support for border radius any more.
markup:
<div class="acceptRejectAll">
Accept All
</div>
css:
.acceptRejectAll {
display: inline-table;
border-radius: 20px;
text-align: center;
padding: 10px;
width: 100px; /* You can change the width as you like */
background: #c3e5fe; /* Old browsers */
background: -moz-linear-gradient(top, #c3e5fe 0%, #98d1fd 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#c3e5fe), color-stop(100%,#98d1fd)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #c3e5fe 0%,#98d1fd 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #c3e5fe 0%,#98d1fd 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #c3e5fe 0%,#98d1fd 100%); /* IE10+ */
background: linear-gradient(to bottom, #c3e5fe 0%,#98d1fd 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#c3e5fe', endColorstr='#98d1fd',GradientType=0 );
}
.fontBlack {
font-family: sans-serif;
font-size: 10pt;
color: black;
text-decoration: none;
}
The gradient was generated using:
http://www.colorzilla.com/gradient-editor/#c3e5fe+0,98d1fd+100;Custom
You end up with:
http://jsfiddle.net/NDHtn/
Or as a preview:
When you must use an image
If there is no other choice but to use an image as a background for a button — say, the graphics are too complicated to replicate using css effects — rather than use one image stretched and distorted to fit, you can use something like the following. There are many ways to essentially achieve the same result, I prefer to keep my mark-up simple and my css more complicated (rather than the other way around). However, to make things more supportive of the wider browser community you can break your mark-up into three parts, rather than make use of ::before and ::after:
markup:
<a class="button" href="#">
<span>Round Button with lots of text and then some</span>
</a>
css:
.button:before {
position: absolute;
content: '';
background: url('image.png') left top;
top: 0;
left: -50px;
width: 50px;
height: 99px;
}
.button:after {
position: absolute;
content: '';
background: url('image.png') right top;
top: 0;
right: -50px;
width: 50px;
height: 99px;
}
.button {
background: url('image.png') center -99px;
height: 99px;
margin: 0 50px;
position: relative;
display: inline-block;
color: white;
text-decoration: none;
}
.button span { display: block; padding: 35px 0px; }
image.png, hacked together using this original image and pixlr.com:
Which will give:
http://jsfiddle.net/2K5Kg/1/
Example mark-up without use of psuedo elements:
<a class="button" href="#">
<span class="before"></span>
<span class="after"></span>
<span>Round Button with lots of text and then some</span>
</a>
Then in the css just replace the .button:before with .button .before and the same for :after.

Related

how to add a color overlay to a background image [duplicate]

I have panel which I colored blue if this panel is being selected (clicked on it). Additionally, I add a small sign (.png image) to that panel, which indicates that the selected panel has been already selected before.
So if the user sees for example 10 panels and 4 of them have this small sign, he knows that he has already clicked on those panels before. This work fine so far. The problem is now that I can't display the small sign and make the panel blue at the same time.
I set the panel to blue with the css background: #6DB3F2; and the background image with background-image: url('images/checked.png'). But it seems that the background color is above the image so you cannot see the sign.
Is it therefore possible to set z-indexes for the background color and the background image?
You need to use the full property name for each:
background-color: #6DB3F2;
background-image: url('images/checked.png');
Or, you can use the background shorthand and specify it all in one line:
background: url('images/checked.png'), #6DB3F2;
For me this solution didn't work out:
background-color: #6DB3F2;
background-image: url('images/checked.png');
But instead it worked the other way:
<div class="block">
<span>
...
</span>
</div>
the css:
.block{
background-image: url('img.jpg') no-repeat;
position: relative;
}
.block::before{
background-color: rgba(0, 0, 0, 0.37);
content: '';
display: block;
height: 100%;
position: absolute;
width: 100%;
}
Based on MDN Web Docs you can set multiple background using shorthand background property or individual properties except for background-color. In your case, you can do a trick using linear-gradient like this:
background-image: url('images/checked.png'), linear-gradient(to right, #6DB3F2, #6DB3F2);
The first item (image) in the parameter will be put on top. The second item (color background) will be put underneath the first. You can also set other properties individually. For example, to set the image size and position.
background-size: 30px 30px;
background-position: bottom right;
background-repeat: no-repeat;
Benefit of this method is you can implement it for other cases easily, for example, you want to make the blue color overlaying the image with certain opacity.
background-image: linear-gradient(to right, rgba(109, 179, 242, .6), rgba(109, 179, 242, .6)), url('images/checked.png');
background-size: cover, contain;
background-position: center, right bottom;
background-repeat: no-repeat, no-repeat;
Individual property parameters are set respectively. Because the image is put underneath the color overlay, its property parameters are also placed after color overlay parameters.
And if you want Generate a Black Shadow in the background, you can use
the following:
background:linear-gradient( rgba(0, 0, 0, 0.5) 100%, rgba(0, 0, 0, 0.5)100%),url("logo/header-background.png");
You can also use short trick to use image and color both like this :-
body {
background:#000 url('images/checked.png');
}
really interesting problem, haven't seen it yet. this code works fine for me. tested it in chrome and IE9
<html>
<head>
<style>
body{
background-image: url('img.jpg');
background-color: #6DB3F2;
}
</style>
</head>
<body>
</body>
</html>
The next syntax can be used as well.
background: <background-color>
url('../assets/icons/my-icon.svg')
<background-position-x background-position-y>
<background-repeat>;
It allows you combining background-color, background-image, background-position and background-repeat properties.
Example
background: #696969 url('../assets/icons/my-icon.svg') center center no-repeat;
This actually works for me:
background-color: #6DB3F2;
background-image: url('images/checked.png');
You can also drop a solid shadow and set the background image:
background-image: url('images/checked.png');
box-shadow: inset 0 0 100% #6DB3F2;
If the first option is not working for some reason and you don't want to use the box shadow you can always use a pseudo element for the image without any extra HTML:
.btn{
position: relative;
background-color: #6DB3F2;
}
.btn:before{
content: "";
display: block;
width: 100%;
height: 100%;
position:absolute;
top:0;
left:0;
background-image: url('images/checked.png');
}
Here is how I styled my colored buttons with an icon in the background
I used "background-color" property for the color and "background" property for the image.
<style>
.btn {
display: inline-block;
line-height: 1em;
padding: .1em .3em .15em 2em
border-radius: .2em;
border: 1px solid #d8d8d8;
background-color: #cccccc;
}
.thumb-up {
background: url('/icons/thumb-up.png') no-repeat 3px center;
}
.thumb-down {
background: url('/icons/thumb-down.png') no-repeat 3px center;
}
</style>
<span class="btn thumb-up">Thumb up</span>
<span class="btn thumb-down">Thumb down</span>
Assuming you want an icon on the right (or left) then this should work best:
.show-hide-button::after {
content:"";
background-repeat: no-repeat;
background-size: contain;
display: inline-block;
background-size: 1em;
width: 1em;
height: 1em;
background-position: 0 2px;
margin-left: .5em;
}
.show-hide-button.shown::after {
background-image: url(img/eye.svg);
}
You could also do background-size: contain;, but that should be mostly the same. the background-position will depened on your image.
Then you can easily do an alternative state on hover:
.show-hide-button.shown:hover::after {
background-image: url(img/eye-no.svg);
}
You can try with box shadow: inset
.second_info_block {
background: url('imageURL');
box-shadow: inset 0 0 0 1000px rgba(0,0,0,.4);
}
<li style="background-color: #ffffff;"><img border="0" style="border-radius:5px;background: url(images/picture.jpg') 50% 50% no-repeat;width:150px;height:80px;" src="images/clearpixel.gif"/></li>
Other Sample Box Center Image and Background Color
1.First clearpixel fix image area
2.style center image area box
3.li background or div color style
body
{
background-image:url('image/img2.jpg');
margin: 0px;
padding: 0px;
}

Get two color effect into round img

I am working on this project
https://www.frontendmentor.io/challenges/todo-app-Su1_KokOW
I am having problem to get the mixed color into the round img for checking the note as in the picturecheck
Maybe there is some kind of properties that I miss ??
Can please anyone give me some advice?
.circle-image {
display: inline-block;
border-radius: 50%;
overflow: hidden;
width: 100px;
height: 100px;
background-color: hsl(237, 14%, 26%);
margin-left: 6%;
margin-top: 20%;
background-color: ??????;
border-color: white;
border: .1px white solid;
}
.circle-image img {
width: 100%;
height: 100%;
object-fit: none;
}
<a href="#" id="check"> <span class="circle-image"> <img id="img" src="data:image/gif;base64,R0lGODlhAQABAAD/ACwAAAAAAQABAAACADs=" width="0" height="0" alt="" /> </span>
You can use CSS gradient. It can generated in any "CSS Gradinet Generator" in Google. You don't need a image for this task.
Its look like this:
background: rgb(255,255,255);
background: linear-gradient(45deg, rgba(255,255,255,1) 0%, rgba(0,0,0,0) 100%);
Probably the easiest and best solution here is to use a background gradient.
I'm probably not spot on with your colors, but if you change background-color in your CSS to be a gradient, it will work:
background: linear-gradient(45deg, #9d78e5 0%, #7eb8ef 100%);
I think you're looking for gradient background.
You can add background with linear-gradient property:
background-image: linear-gradient(direction, color-stop1, color-stop2, ...);
Here you play with it:
https://cssgradient.io/

How to add an edge highlight to a CSS shape?

Hi I am trying to create a highlight on a CSS shape as shown below.
There will also be content inside of the hexagon including image and text,
The highlight I am referring to is the part in the top left.
the code I currently have for creating the hexagon is:
HTML
<div class="hexagon-big"></div>
CSS
.hexagon-big {
position: relative;
width: 200px;
height: 115.47px;
background-color: #343434;
}
.hexagon-big:before,
.hexagon-big:after {
content: "";
position: absolute;
width: 0;
border-left: 100px solid transparent;
border-right: 100px solid transparent;
}
.hexagon-big:before {
bottom: 100%;
border-bottom: 57.74px solid #343434;
}
.hexagon-big:after {
top: 100%;
width: 0;
border-top: 57.74px solid #343434;
}
There is other code for the content but i left it out because I don't think it is necessary
Do the hexagon shape differently and you can rely on gradient to create that highlight effect:
.hex {
width: 200px;
display: inline-flex;
margin:0 5px;
background:
conic-gradient(at top,#000 230deg, #0000 0),
linear-gradient(to bottom left,#fff , #000 60%);
clip-path: polygon(0% 25%,0% 75%,50% 100%,100% 75%,100% 25%,50% 0%);
}
.hex::before {
content: "";
padding-top: 115%; /* 100%/cos(30) */
}
<div class="hex"></div>
The solution in this answer is heavily based on the previous answer. To use clip-path and stacked gradients is by far the smartest thing to do here, but I still wanted to post this in order to show, how this solution could be improved and adjusted for your use case (text box, coloring, variables for maintenance, etc.).
.hexagon-big {
/* define box and text space */
width: 200px;
height: 230px;
padding: 10.8% 5px; /* adjust text box padding here; mind that top/bottom tip are part of the box */
box-sizing: border-box; /* width/height should include padding */
/* text formatting (optional) */
color: white;
text-align: center;
/* hex shape */
--hex-col: hsl(0deg 0% 20%); /* just your #343434 as a HSL color */
--hex-shadow: hsl(0deg 0% 50%); /* increased lightness by 15% to define highlight root color; 100% would be fully white */
background:
conic-gradient(at top, var(--hex-col) 232deg, transparent 0), /* change the angle of the shadow at "232deg": increase → narrower, decrease → wider */
linear-gradient(to bottom left, var(--hex-shadow), var(--hex-col) 55%);
clip-path: polygon(0% 25%,0% 75%,50% 100%,100% 75%,100% 25%,50% 0%);
}
<div class="hexagon-big">
Lorem ipsum dolor sit amet...
</div>
It should also be mentioned that your current way of using border is well better supported by older browsers than clip-path and conic-gradient (same with var()).
If this should be a problem, you might have to add another HTML tag and work out a way with transform: matrix(...) and box-shadow: inset ... (for example).

How to select a button beside the gradient filter

I met a project that set the gradient filter to whole web page.
So I have implemented the filter like this.jsfiddle
HTML
<div class="container">
<button class="tag">Featured</button>
<div id="grad1">
</div>
CSS
#grad1 {
height: 200px;
background: red; /* For browsers that do not support gradients */
background: -webkit-linear-gradient(red, yellow); /* For Safari 5.1 to 6.0 */
background: -o-linear-gradient(red, yellow); /* For Opera 11.1 to 12.0 */
background: -moz-linear-gradient(red, yellow); /* For Firefox 3.6 to 15 */
background: linear-gradient(red, yellow); /* Standard syntax (must be last) */
opacity: 0.5;
}
.container {
border: 1px solid #DDDDDD;
width: 200px;
height: 200px;
position: relative;
}
.tag {
float: left;
position: absolute;
left: 0px;
top: 0px;
background-color: #92AD40;
padding: 5px;
color: #FFFFFF;
font-weight: bold;
}
But the problem is button is not selectable in this case.
I have no sense how to make the button work.
How can I make button selectable and also show gradient above the button?
Finally UI should look like this.
its seems you are looking for pointer-events: none;
Demo http://jsfiddle.net/r6tdc3Lh/5/
a </div> tag is missing.
At the end of ur code.
Ur container isnt closing, so your button cant‘t be clicked.
Try to add just another closing tag.
Check the fiddle. You have two issue 1. set button attribute type="button" and 2. .tag z-index should be 1. Because your button is absolute position.
UPDATE
I Update the fiddle. I think it will help you.

Easier way to create circle div than using an image?

I'm wondering if there's an easier way to create circular divs than what I'm doing now.
Currently, I am just making an image for each different size, but it's annoying to do this.
Is there anyway using CSS to make divs which are circular and I can specify the radius?
Here's a demo: http://jsfiddle.net/thirtydot/JJytE/1170/
CSS:
.circleBase {
border-radius: 50%;
behavior: url(PIE.htc); /* remove if you don't care about IE8 */
}
.type1 {
width: 100px;
height: 100px;
background: yellow;
border: 3px solid red;
}
.type2 {
width: 50px;
height: 50px;
background: #ccc;
border: 3px solid #000;
}
.type3 {
width: 500px;
height: 500px;
background: aqua;
border: 30px solid blue;
}
HTML:
<div class="circleBase type1"></div>
<div class="circleBase type2"></div><div class="circleBase type2"></div>
<div class="circleBase type3"></div>
To make this work in IE8 and older, you must download and use CSS3 PIE. My demo above won't work in IE8, but that's only because jsFiddle doesn't host PIE.htc.
My demo looks like this:
Setting the border-radius of each side of an element to 50% will create the circle display at any size:
.circle {
border-radius: 50%;
width: 200px;
height: 200px;
/* width and height can be anything, as long as they're equal */
}
Try this
.iphonebadge {
border-radius:99px;
-moz-border-radius:99px;
-webkit-border-radius:99px;
background:red;
color:#fff;
border:3px #fff solid;
background-color: #e7676d;
background-image: -webkit-gradient(linear, left top, left bottom, from(#e7676d), to(#b7070a)); /* Saf4+, Chrome */
background-image: -webkit-linear-gradient(top, #e7676d, #b7070a); /* Chrome 10+, Saf5.1+, iOS 5+ */
background-image: -moz-linear-gradient(top, #e7676d, #b7070a); /* FF3.6 */
background-image: -ms-linear-gradient(top, #e7676d, #b7070a); /* IE10 */
background-image: -o-linear-gradient(top, #e7676d, #b7070a); /* Opera 11.10+ */
background-image: linear-gradient(top, #e7676d, #b7070a);
filter: progid:DXImageTransform.Microsoft.gradient(startColorStr='#e7676d', EndColorStr='#b7070a');
-webkit-box-shadow: 0px 2px 4px #000000; /* Saf3-4 */
-moz-box-shadow: 0px 2px 4px #000000; /* FF3.5 - 3.6 */
box-shadow: 0px 2px 4px #000000; /* Opera 10.5, IE9, FF4+, Chrome 10+ */
display:inline-block;
padding:2px 2px 2px 2px ;
margin:3px;
font-family:arial;
font-weight:bold;
}
It is actually possible.
See: CSS Tip: How to Make Circles Without Images. See demo.
But be warned, It has serious disadvantages in terms of compatibility basically, you are making a cat bark.
See it working here
As you will see you just have to set up the height and width to half the border-radius
Good luck!
I have 4 solution to finish this task:
border-radius
clip-path
pseudo elements
radial-gradient
#circle1 {
background-color: #B90136;
width: 100px;
height: 100px;
border-radius: 50px;/* specify the radius */
}
#circle2 {
background-color: #B90136;
width: 100px;/* specify the radius */
height: 100px;/* specify the radius */
clip-path: circle();
}
#circle3::before {
content: "";
display: block;
width: 100px;
height: 100px;
border-radius: 50px;/* specify the radius */
background-color: #B90136;
}
#circle4 {
background-image: radial-gradient(#B90136 70%, transparent 30%);
height: 100px;/* specify the radius */
width: 100px;/* specify the radius */
}
<h3>1 border-radius</h3>
<div id="circle1"></div>
<hr/>
<h3>2 clip-path</h3>
<div id="circle2"></div>
<hr/>
<h3>3 pseudo element</h3>
<div id="circle3"></div>
<hr/>
<h3>4 radial-gradient</h3>
<div id="circle4"></div>
Let's say you have this image:
to make a circle out of this you only need to add
.circle {
border-radius: 50%;
width: 100px;
height: 100px;
}
So if you have a div you can do the same thing.
Check the example below:
.circle {
border-radius: 50%;
width: 100px;
height: 100px;
animation: stackoverflow-example infinite 20s linear;
pointer-events: none;
}
#keyframes stackoverflow-example {
from {
transform: rotate(0deg);
}
to {
transform: rotate(360deg);
}
}
<div>
<img class="circle" src="https://www.sitepoint.com/wp-content/themes/sitepoint/assets/images/icon.javascript.png">
</div>
There's also [the bad idea of] using several (20+) horizontal or vertical 1px divs to construct a circle. This jQuery plugin uses this method to construct different shapes.
Give width and height depending on the size but,keep both equal
.circle {
background-color: gray;
height: 400px;
width: 400px;
border-radius: 100%;
}
<div class="circle">
</div>
.fa-circle{
color: tomato;
}
div{
font-size: 100px;
}
<link href="https://maxcdn.bootstrapcdn.com/font-awesome/4.7.0/css/font-awesome.min.css" rel="stylesheet"/>
<div><i class="fa fa-circle" aria-hidden="true"></i></div>
Just wanted to mention another solution which answers the question of "Easier way to create circle div than using an image?" which is to use FontAwesome.
You import the fontawesome css file or from the CDN here
and then you just:
<div><i class="fa fa-circle" aria-hidden="true"></i></div>
and you can give it any color you want any font size.
You can try the radial-gradient CSS function:
.circle {
width: 500px;
height: 500px;
border-radius: 50%;
background: #ffffff; /* Old browsers */
background: -moz-radial-gradient(center, ellipse cover, #ffffff 17%, #ff0a0a 19%, #ff2828 40%, #000000 41%); /* FF3.6-15 */
background: -webkit-radial-gradient(center, ellipse cover, #ffffff 17%,#ff0a0a 19%,#ff2828 40%,#000000 41%); /* Chrome10-25,Safari5.1-6 */
background: radial-gradient(ellipse at center, #ffffff 17%,#ff0a0a 19%,#ff2828 40%,#000000 41%); /* W3C, IE10+, FF16+, Chrome26+, Opera12+, Safari7+ */
}
Apply it to a div layer:
<div class="circle"></div>
.circle {
height: 20rem;
width: 20rem;
border-radius: 50%;
background-color: #EF6A6A;
}
<div class="circle"></div>
You can use radius but it will not work on IE: border-radius: 5px 5px;.
basically this uses div's position absolute to place a character at the given coordinates. so using the parametric equation for a circle, you can draw a circle. if you were to change div's position to relative, it'll result in a sine wave...
in essence we are graphing equations by abusing the position property. i'm not versed well in css, so someone can surely make this more elegant. enjoy.
this works on all browsers and mobile devices (that i'm aware of). i use it on my own website to draw sine waves of text (www.cpixel.com). the original source of this code is found here: www.mathopenref.com/coordcirclealgorithm.html
<html>
<head></head>
<body>
<script language="Javascript">
var x_center = 50; //0 in both x_center and y_center will place the center
var y_center = 50; // at the top left of the browser
var resolution_step = 360; //how many times to stop along the circle to plot your character.
var radius = 50; //how big ya want your circle?
var plot_character = "·"; //could use any character here, try letters/words for cool effects
var div_top_offset=10;
var div_left_offset=10;
var x,y;
for ( var angle_theta = 0; angle_theta < 2 * Math.PI; angle_theta += 2 * Math.PI/resolution_step ){
x = x_center + radius * Math.cos(angle_theta);
y = y_center - radius * Math.sin(angle_theta);
document.write("<div style='position:absolute;top:" + (y+div_top_offset) + ";left:"+ (x+div_left_offset) + "'>" + plot_character + "</div>");
}
</script>
</body>
</html>
Adding the css property of:
border-radius: 50%;
to any div makes it circular.
For circle, create a div element and then enter width = 2 times of the border radius = 2 times padding. Also line-height = 0
For example, with 50px as radii of the circle, the below code works well:
width: 100px;
padding: 50px 0;
border: solid;
line-height: 0px;
border-radius: 50px;