Related
MyJsonArray
[{"ID":"D29","PersonID":"23616639"},{"ID":"D30","PersonID":"22629626"}]
and I want from sql Function set this array in to my Table but return null value in the variable and not set record in My database
my function:
DELIMITER $$
CREATE DEFINER=`toshiari`#`localhost` FUNCTION `setTitleRecords`(`Title` VARCHAR(166) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci, `List` JSON) RETURNS int(4)
BEGIN
DECLARE Item INT;
DECLARE HolderLENGTH INT;
DECLARE ValidJson INT;
DECLARE ID VARCHAR(166);
DECLARE PersonID VARCHAR(166);
DECLARE S1 VARCHAR(166);
DECLARE S2 VARCHAR(166);
SET ValidJson = (SELECT JSON_VALID(List));
IF ValidJson = 1 THEN
SET HolderLENGTH = (SELECT JSON_LENGTH(List));
SET Item = 0;
WHILE Item < HolderLENGTH DO
SET S1 = CONCAT("'$[",Item, "].ID'");
SET S2 = CONCAT("'$[",Item, "].PersonID'");
SET ID = (SELECT JSON_EXTRACT(List,S1));
SET PersonID = (SELECT JSON_EXTRACT(List,S2));
INSERT INTO `Titles`(`ID`,`PersonID`,`Title`) VALUES (ID, PersonID, Title);
SET Item = Item + 1;
END WHILE;
RETURN 3;
ELSE
RETURN 2;
END IF;
END$$
DELIMITER ;
when I use this command in the Sql commands no problem and return true value
SELECT JSON_EXTRACT('[{"ID":"D29","PersonID":"23616639"},{"ID":"D30","PersonID":"22629626"}]','$[0].ID') return "D29"
return
"D29"
but in when run function from this code
return error and said:
SET #p0='DR'; SET #p1='[{\"ID\":\"D29\",\"PersonID\":\"23616639\"},{\"ID\":\"D30\",\"PersonID\":\"22629626\"}]'; SELECT `setTitleRecords`(#p0, #p1) AS `setTitleRecords`;
#4042 - Syntax error in JSON path in argument 2 to function 'json_extract' at position 1
I created a little test, in order to reproduce your issues. Basically you just need to redeclare S1 and S2, in the following way:
SET S1 = CONCAT('$[',Item,'].ID');
SET S2 = CONCAT('$[',Item,'].PersonID');
And that's it. You can check the test in the following url: https://www.db-fiddle.com/f/2TPgF868snjwcHN3uwoSEA/0
I have some string output which contain alphanumeric value. I want to get only Digits from that string. how can I fetch this by query? which MySql function can I Use?
My query is like :
select DISTINCT SUBSTRING(referrerURL,71,6)
from hotshotsdblog1.annonymoustracking
where advertiserid = 10
limit 10;
Output :
100683
101313
19924&
9072&h
12368&
5888&h
10308&
100664
1&hash
101104
And I Want output like :
100683
101313
19924
9072
12368
5888
10308
100664
1
101104
If the string starts with a number, then contains non-numeric characters, you can use the CAST() function or convert it to a numeric implicitly by adding a 0:
SELECT CAST('1234abc' AS UNSIGNED); -- 1234
SELECT '1234abc'+0; -- 1234
To extract numbers out of an arbitrary string you could add a custom function like this:
DELIMITER $$
CREATE FUNCTION `ExtractNumber`(in_string VARCHAR(50))
RETURNS INT
NO SQL
BEGIN
DECLARE ctrNumber VARCHAR(50);
DECLARE finNumber VARCHAR(50) DEFAULT '';
DECLARE sChar VARCHAR(1);
DECLARE inti INTEGER DEFAULT 1;
IF LENGTH(in_string) > 0 THEN
WHILE(inti <= LENGTH(in_string)) DO
SET sChar = SUBSTRING(in_string, inti, 1);
SET ctrNumber = FIND_IN_SET(sChar, '0,1,2,3,4,5,6,7,8,9');
IF ctrNumber > 0 THEN
SET finNumber = CONCAT(finNumber, sChar);
END IF;
SET inti = inti + 1;
END WHILE;
RETURN CAST(finNumber AS UNSIGNED);
ELSE
RETURN 0;
END IF;
END$$
DELIMITER ;
Once the function is defined, you can use it in your query:
SELECT ExtractNumber("abc1234def") AS number; -- 1234
To whoever is still looking, use regex:
select REGEXP_SUBSTR(name,"[0-9]+") as amount from `subscriptions`
Here I got success with this function:
select REGEXP_REPLACE('abc12.34.56-ghj^-_~##!', '[^0-9]+', '')
output: 123456
Explaining: basically I'm asking for mysql replace all 'not numbers' in interval from 0 to 9 to ''.
Based on Eugene Yarmash Answer. Here is a version of the custom function that extracts a decimal with two decimal places. Good for price extraction.
DELIMITER $$
CREATE FUNCTION `ExtractDecimal`(in_string VARCHAR(255))
RETURNS decimal(15,2)
NO SQL
BEGIN
DECLARE ctrNumber VARCHAR(255);
DECLARE in_string_parsed VARCHAR(255);
DECLARE digitsAndDotsNumber VARCHAR(255) DEFAULT '';
DECLARE finalNumber VARCHAR(255) DEFAULT '';
DECLARE sChar VARCHAR(1);
DECLARE inti INTEGER DEFAULT 1;
DECLARE digitSequenceStarted boolean DEFAULT false;
DECLARE negativeNumber boolean DEFAULT false;
-- FIX FIND_IN_SET cannot find a comma ","
SET in_string_parsed = replace(in_string,',','.');
IF LENGTH(in_string_parsed) > 0 THEN
-- extract digits and dots
WHILE(inti <= LENGTH(in_string_parsed)) DO
SET sChar = SUBSTRING(in_string_parsed, inti, 1);
SET ctrNumber = FIND_IN_SET(sChar, '0,1,2,3,4,5,6,7,8,9,.');
IF ctrNumber > 0 AND (sChar != '.' OR LENGTH(digitsAndDotsNumber) > 0) THEN
-- add first minus if needed
IF digitSequenceStarted = false AND inti > 1 AND SUBSTRING(in_string_parsed, inti-1, 1) = '-' THEN
SET negativeNumber = true;
END IF;
SET digitSequenceStarted = true;
SET digitsAndDotsNumber = CONCAT(digitsAndDotsNumber, sChar);
ELSEIF digitSequenceStarted = true THEN
SET inti = LENGTH(in_string_parsed);
END IF;
SET inti = inti + 1;
END WHILE;
-- remove dots from the end of number list
SET inti = LENGTH(digitsAndDotsNumber);
WHILE(inti > 0) DO
IF(SUBSTRING(digitsAndDotsNumber, inti, 1) = '.') THEN
SET digitsAndDotsNumber = SUBSTRING(digitsAndDotsNumber, 1, inti-1);
SET inti = inti - 1;
ELSE
SET inti = 0;
END IF;
END WHILE;
-- extract decimal
SET inti = 1;
WHILE(inti <= LENGTH(digitsAndDotsNumber)-3) DO
SET sChar = SUBSTRING(digitsAndDotsNumber, inti, 1);
SET ctrNumber = FIND_IN_SET(sChar, '0,1,2,3,4,5,6,7,8,9');
IF ctrNumber > 0 THEN
SET finalNumber = CONCAT(finalNumber, sChar);
END IF;
SET inti = inti + 1;
END WHILE;
SET finalNumber = CONCAT(finalNumber, RIGHT(digitsAndDotsNumber, 3));
IF negativeNumber = true AND LENGTH(finalNumber) > 0 THEN
SET finalNumber = CONCAT('-', finalNumber);
END IF;
IF LENGTH(finalNumber) = 0 THEN
RETURN 0;
END IF;
RETURN CAST(finalNumber AS decimal(15,2));
ELSE
RETURN 0;
END IF;
END$$
DELIMITER ;
Tests:
select ExtractDecimal("1234"); -- 1234.00
select ExtractDecimal("12.34"); -- 12.34
select ExtractDecimal("1.234"); -- 1234.00
select ExtractDecimal("1,234"); -- 1234.00
select ExtractDecimal("1,111,234"); -- 11111234.00
select ExtractDecimal("11,112,34"); -- 11112.34
select ExtractDecimal("11,112,34 and 123123"); -- 11112.34
select ExtractDecimal("-1"); -- -1.00
select ExtractDecimal("hello. price is 123"); -- 123.00
select ExtractDecimal("123,45,-"); -- 123.45
Here is my improvement over ExtractNumber function by Eugene Yarmash.
It strips not only non-digit characters, but also HTML entities like &#[0-9];, which should be considered as non-digit unicode characters too.
Here is the code without UDP on pure MySQL <8.
CREATE DEFINER = 'user'#'host' FUNCTION `extract_number`(
str CHAR(255)
)
RETURNS char(255) CHARSET utf8mb4 COLLATE utf8mb4_unicode_ci
DETERMINISTIC
NO SQL
SQL SECURITY DEFINER
COMMENT ''
BEGIN
DECLARE tmp VARCHAR(255);
DECLARE res VARCHAR(255) DEFAULT "";
DECLARE chr VARCHAR(1);
DECLARE len INTEGER UNSIGNED DEFAULT LENGTH(str);
DECLARE i INTEGER DEFAULT 1;
IF len > 0 THEN
WHILE i <= len DO
SET chr = SUBSTRING(str, i, 1);
/* remove &#...; */
IF "&" = chr AND "#" = SUBSTRING(str, i+1, 1) THEN
WHILE (i <= len) AND (";" != SUBSTRING(str, i, 1)) DO
SET i = i + 1;
END WHILE;
END IF;
SET tmp = FIND_IN_SET(chr, "0,1,2,3,4,5,6,7,8,9");
IF tmp > 0 THEN
SET res = CONCAT(res, chr);
END IF;
SET i = i + 1;
END WHILE;
RETURN res;
END IF;
RETURN 0;
END;
But if you are using UDP's PREG_REPLACE, you can use just following line:
RETURN PREG_REPLACE("/[^0-9]/", "", PREG_REPLACE("/&#[0-9]+;/", "", str));
I have rewritten this for MemSQL Syntax:
DROP FUNCTION IF EXISTS GetNumeric;
DELIMITER //
CREATE FUNCTION GetNumeric(str CHAR(255)) RETURNS CHAR(255) AS
DECLARE i SMALLINT = 1;
DECLARE len SMALLINT = 1;
DECLARE ret CHAR(255) = '';
DECLARE c CHAR(1);
BEGIN
IF str IS NULL
THEN
RETURN "";
END IF;
WHILE i < CHAR_LENGTH( str ) + 1 LOOP
BEGIN
c = SUBSTRING( str, i, 1 );
IF c BETWEEN '0' AND '9' THEN
ret = CONCAT(ret,c);
END IF;
i = i + 1;
END;
END LOOP;
RETURN ret;
END //
DELIMITER ;
SELECT GetNumeric('abc123def456xyz789') as test;
Based on Eugene Yarmash and Martins Balodis answers.
In my case, I didn't know whether the source string contains dot as a decimal separator. Although, I knew how the specific column should be treated. E.g. in case value came up as "10,00" hours but not as "1.00" we know that the last delimiter character should be treated as a dot decimal separator. For this purposes, we can rely on a secondary boolean param that specifies how the last comma separator should behave.
DELIMITER $$
CREATE FUNCTION EXTRACT_DECIMAL(
inString VARCHAR(255)
, treatLastCommaAsDot BOOLEAN
) RETURNS varchar(255) CHARSET utf8mb4
NO SQL
DETERMINISTIC
BEGIN
DECLARE ctrNumber VARCHAR(255);
DECLARE inStringParsed VARCHAR(255);
DECLARE digitsAndDotsNumber VARCHAR(255) DEFAULT '';
DECLARE digitsBeforeDotNumber VARCHAR(255) DEFAULT '';
DECLARE digitsAfterDotNumber VARCHAR(255) DEFAULT '';
DECLARE finalNumber VARCHAR(255) DEFAULT '';
DECLARE separatorChar VARCHAR(1) DEFAULT '_';
DECLARE iterChar VARCHAR(1);
DECLARE inti INT DEFAULT 1;
DECLARE digitSequenceStarted BOOLEAN DEFAULT false;
DECLARE negativeNumber BOOLEAN DEFAULT false;
-- FIX FIND_IN_SET cannot find a comma ","
-- We need to separate entered dot from another delimiter characters.
SET inStringParsed = TRIM(REPLACE(REPLACE(inString, ',', separatorChar), ' ', ''));
IF LENGTH(inStringParsed) > 0 THEN
-- Extract digits, dots and delimiter character.
WHILE(inti <= LENGTH(inStringParsed)) DO
-- Might contain MINUS as the first character.
SET iterChar = SUBSTRING(inStringParsed, inti, 1);
SET ctrNumber = FIND_IN_SET(iterChar, CONCAT('0,1,2,3,4,5,6,7,8,9,.,', separatorChar));
-- In case the first extracted character is not '.' and `digitsAndDotsNumber` is set.
IF ctrNumber > 0 AND (iterChar != '.' OR LENGTH(digitsAndDotsNumber) > 0) THEN
-- Add first minus if needed. Note: `inti` at this point will be higher than 1.
IF digitSequenceStarted = FALSE AND inti > 1 AND SUBSTRING(inStringParsed, inti - 1, 1) = '-' THEN
SET negativeNumber = TRUE;
END IF;
SET digitSequenceStarted = TRUE;
SET digitsAndDotsNumber = CONCAT(digitsAndDotsNumber, iterChar);
ELSEIF digitSequenceStarted = true THEN
SET inti = LENGTH(inStringParsed);
END IF;
SET inti = inti + 1;
END WHILE;
-- Search the left part of string until the separator.
-- https://stackoverflow.com/a/43699586
IF (
-- Calculates the amount of delimiter characters.
CHAR_LENGTH(digitsAndDotsNumber)
- CHAR_LENGTH(REPLACE(digitsAndDotsNumber, separatorChar, SPACE(LENGTH(separatorChar)-1)))
) + (
-- Calculates the amount of dot characters.
CHAR_LENGTH(digitsAndDotsNumber)
- CHAR_LENGTH(REPLACE(digitsAndDotsNumber, '.', SPACE(LENGTH(separatorChar)-1)))
) > 0 THEN
-- If dot is present in the string. It doesn't matter for the other characters.
IF LOCATE('.', digitsAndDotsNumber) != FALSE THEN
-- Replace all special characters before the dot.
SET inti = LOCATE('.', digitsAndDotsNumber) - 1;
-- Return the first half of numbers before the last dot.
SET digitsBeforeDotNumber = SUBSTRING(digitsAndDotsNumber, 1, inti);
SET digitsBeforeDotNumber = REPLACE(digitsBeforeDotNumber, separatorChar, '');
SET digitsAfterDotNumber = SUBSTRING(digitsAndDotsNumber, inti + 2, LENGTH(digitsAndDotsNumber) - LENGTH(digitsBeforeDotNumber));
SET digitsAndDotsNumber = CONCAT(digitsBeforeDotNumber, '.', digitsAfterDotNumber);
ELSE
IF treatLastCommaAsDot = TRUE THEN
-- Find occurence of the last delimiter within the string.
SET inti = CHAR_LENGTH(digitsAndDotsNumber) - LOCATE(separatorChar, REVERSE(digitsAndDotsNumber));
-- Break the string into left part until the last occurrence of separator character.
SET digitsBeforeDotNumber = SUBSTRING(digitsAndDotsNumber, 1, inti);
SET digitsBeforeDotNumber = REPLACE(digitsBeforeDotNumber, separatorChar, '');
SET digitsAfterDotNumber = SUBSTRING(digitsAndDotsNumber, inti + 2, LENGTH(digitsAndDotsNumber) - LENGTH(digitsBeforeDotNumber));
-- Remove any dot occurence from the right part.
SET digitsAndDotsNumber = CONCAT(digitsBeforeDotNumber, '.', REPLACE(digitsAfterDotNumber, '.', ''));
ELSE
SET digitsAndDotsNumber = REPLACE(digitsAndDotsNumber, separatorChar, '');
END IF;
END IF;
END IF;
SET finalNumber = digitsAndDotsNumber;
IF negativeNumber = TRUE AND LENGTH(finalNumber) > 0 THEN
SET finalNumber = CONCAT('-', finalNumber);
END IF;
IF LENGTH(finalNumber) = 0 THEN
RETURN 0;
END IF;
RETURN CAST(finalNumber AS DECIMAL(25,5));
ELSE
RETURN 0;
END IF;
END$$
DELIMITER ;
Here are some examples of usage:
--
-- SELECT EXTRACT_DECIMAL('-711,712,34 and 123123', FALSE); -- -71171234.00000
-- SELECT EXTRACT_DECIMAL('1.234', FALSE); -- 1.23400
-- SELECT EXTRACT_DECIMAL('1,234.00', FALSE); -- 1234.00000
-- SELECT EXTRACT_DECIMAL('14 9999,99', FALSE); -- 14999999.00000
-- SELECT EXTRACT_DECIMAL('-149,999.99', FALSE); -- -149999.99000
-- SELECT EXTRACT_DECIMAL('3 536 500.53', TRUE); -- 3536500.53000
-- SELECT EXTRACT_DECIMAL('3,536,500,53', TRUE); -- 3536500.53000
-- SELECT EXTRACT_DECIMAL("-1"); -- -1.00000
-- SELECT EXTRACT_DECIMAL('2,233,536,50053', TRUE); -- 2233536.50053
-- SELECT EXTRACT_DECIMAL('13.01666667', TRUE); -- 13.01667
-- SELECT EXTRACT_DECIMAL('1,00000000', FALSE); -- 100000000.00000
-- SELECT EXTRACT_DECIMAL('1000', FALSE); -- 1000.00000
-- ==================================================================================
Try,
Query level,
SELECT CAST('1&hash' AS UNSIGNED);
for PHP,
echo intval('13213&hash');
For any newcomers with a similar request this should be exactly what you need.
select DISTINCT CONVERT(SUBSTRING(referrerURL,71,6), SIGNED) as `foo`
from hotshotsdblog1.annonymoustracking
where advertiserid = 10
limit 10;
I suggest using a pivot table (e.g., a table that only contains a vector of ordered numbers from 1 to at least the length of the string) and then doing the following:
SELECT group_concat(c.elem separator '')
from (
select b.elem
from
(
select substr('PAUL123f3211',iter.pos,1) as elem
from (select id as pos from t10) as iter
where iter.pos <= LENGTH('PAUL123f3211')
) b
where b.elem REGEXP '^[0-9]+$') c
It can be done in PHP instead.
foreach ($query_result as &$row) {
$row['column_with_numbers'] = (int) filter_var($query_result['column_with_numbers'], FILTER_SANITIZE_NUMBER_INT);
}
Try this in php
$string = '9072&h';
echo preg_replace("/[^0-9]/", '', $string);// output: 9072
or follow this link to do this in MySql
Refer the link
I need to create a function that I found here: http://vyaskn.tripod.com/code/propercase.txt It converts text to "ProperCase," first letter of every word to uppercase.
CREATE FUNCTION PROPERCASE
(
-- The string to be converted to proper case
#input VARCHAR( 8000 )
)
-- This function returns the proper case string of varchar type
RETURNS VARCHAR( 8000 )
AS
BEGIN
IF #input IS NULL
BEGIN
-- Just return NULL if input string is NULL
RETURN NULL
END
-- Character variable declarations
DECLARE #output VARCHAR( 8000 )
-- Integer variable declarations
DECLARE #ctr INT, #len INT, #found_at INT
-- Constant declarations
DECLARE #LOWER_CASE_a INT, #LOWER_CASE_z INT, #Delimiter CHAR(3), #UPPER_CASE_A INT, #UPPER_CASE_Z INT
-- Variable/Constant initializations
SET #ctr = 1
SET #len = LEN(#input)
SET #output = ''
SET #LOWER_CASE_a = 97
SET #LOWER_CASE_z = 122
SET #Delimiter = ' ,-'
SET #UPPER_CASE_A = 65
SET #UPPER_CASE_Z = 90
WHILE #ctr <= #len
BEGIN
-- This loop will take care of reccuring white spaces
WHILE CHARINDEX(SUBSTRING(#input,#ctr,1), #Delimiter) > 0
BEGIN
SET #output = #output + SUBSTRING(#input,#ctr,1)
SET #ctr = #ctr + 1
END
IF ASCII(SUBSTRING(#input,#ctr,1)) BETWEEN #LOWER_CASE_a AND #LOWER_CASE_z
BEGIN
-- Converting the first character to upper case
SET #output = #output + UPPER(SUBSTRING(#input,#ctr,1))
END
ELSE
BEGIN
SET #output = #output + SUBSTRING(#input,#ctr,1)
END
SET #ctr = #ctr + 1
WHILE CHARINDEX(SUBSTRING(#input,#ctr,1), #Delimiter) = 0 AND (#ctr <= #len)
BEGIN
IF ASCII(SUBSTRING(#input,#ctr,1)) BETWEEN #UPPER_CASE_A AND #UPPER_CASE_Z
BEGIN
SET #output = #output + LOWER(SUBSTRING(#input,#ctr,1))
END
ELSE
BEGIN
SET #output = #output + SUBSTRING(#input,#ctr,1)
END
SET #ctr = #ctr + 1
END
END
RETURN #output
END
I need a function to do that, but it's giving me error...
You are using MySQL, but the syntax you have is for SQL Server. Please read the documentation about MySQL's syntax and convert your procedure to use that syntax. The major constructs are the same, but the syntax is a little different. Here are some things to start with:
Local variables never start with #.
IF is condition followed by THEN followed by any number of lines of code, followed by END IF. The BEGIN...END construct is not used for IF statements in MySQL.
The functions are different. You won't use CHARINDEX but instead INSTR.
Here's the relevant MySQL documentation: http://dev.mysql.com/doc/refman/5.5/en/stored-routines-syntax.html and http://dev.mysql.com/doc/refman/5.5/en/sql-syntax-compound-statements.html.
I have the following table with each row having comma-separated values:
ID
-----------------------------------------------------------------------------
10031,10042
10064,10023,10060,10065,10003,10011,10009,10012,10027,10004,10037,10039
10009
20011,10027,10032,10063,10023,10033,20060,10012,10020,10031,10011,20036,10041
I need to get a count for each ID (a groupby).
I am just trying to avoid cursor implementation and stumped on how to do this without cursors.
Any Help would be appreciated !
You will want to use a split function:
create FUNCTION [dbo].[Split](#String varchar(MAX), #Delimiter char(1))
returns #temptable TABLE (items varchar(MAX))
as
begin
declare #idx int
declare #slice varchar(8000)
select #idx = 1
if len(#String)<1 or #String is null return
while #idx!= 0
begin
set #idx = charindex(#Delimiter,#String)
if #idx!=0
set #slice = left(#String,#idx - 1)
else
set #slice = #String
if(len(#slice)>0)
insert into #temptable(Items) values(#slice)
set #String = right(#String,len(#String) - #idx)
if len(#String) = 0 break
end
return
end;
And then you can query the data in the following manner:
select items, count(items)
from table1 t1
cross apply dbo.split(t1.id, ',')
group by items
See SQL Fiddle With Demo
Well, the solution i always use, and probably there might be a better way, is to use a function that will split everything. No use for cursors, just a while loop.
if OBJECT_ID('splitValueByDelimiter') is not null
begin
drop function splitValueByDelimiter
end
go
create function splitValueByDelimiter (
#inputValue varchar(max)
, #delimiter varchar(1)
)
returns #results table (value varchar(max))
as
begin
declare #delimeterIndex int
, #tempValue varchar(max)
set #delimeterIndex = 1
while #delimeterIndex > 0 and len(isnull(#inputValue, '')) > 0
begin
set #delimeterIndex = charindex(#delimiter, #inputValue)
if #delimeterIndex > 0
set #tempValue = left(#inputValue, #delimeterIndex - 1)
else
set #tempValue = #inputValue
if(len(#tempValue)>0)
begin
insert
into #results
select #tempValue
end
set #inputValue = right(#inputValue, len(#inputValue) - #delimeterIndex)
end
return
end
After that you can call the output like this :
if object_id('test') is not null
begin
drop table test
end
go
create table test (
Id varchar(max)
)
insert
into test
select '10031,10042'
union all select '10064,10023,10060,10065,10003,10011,10009,10012,10027,10004,10037,10039'
union all select '10009'
union all select '20011,10027,10032,10063,10023,10033,20060,10012,10020,10031,10011,20036,10041'
select value
from test
cross apply splitValueByDelimiter(Id, ',')
Hope it helps, although i am still looping through everything
After reiterating the comment above about NOT putting multiple values into a single column (Use a separate child table with one value per row!),
Nevertheless, one possible approach: use a UDF to convert delimited string to a table. Once all the values have been converted to tables, combine all the tables into one table and do a group By on that table.
Create Function dbo.ParseTextString (#S Text, #delim VarChar(5))
Returns #tOut Table
(ValNum Integer Identity Primary Key,
sVal VarChar(8000))
As
Begin
Declare #dlLen TinyInt -- Length of delimiter
Declare #wind VarChar(8000) -- Will Contain Window into text string
Declare #winLen Integer -- Length of Window
Declare #isLastWin TinyInt -- Boolean to indicate processing Last Window
Declare #wPos Integer -- Start Position of Window within Text String
Declare #roVal VarChar(8000)-- String Data to insert into output Table
Declare #BtchSiz Integer -- Maximum Size of Window
Set #BtchSiz = 7900 -- (Reset to smaller values to test routine)
Declare #dlPos Integer -- Position within Window of next Delimiter
Declare #Strt Integer -- Start Position of each data value within Window
-- -------------------------------------------------------------------------
-- ---------------------------
If #delim is Null Set #delim = '|'
If DataLength(#S) = 0 Or
Substring(#S, 1, #BtchSiz) = #delim Return
-- --------------------------------------------
Select #dlLen = DataLength(#delim),
#Strt = 1, #wPos = 1,
#wind = Substring(#S, 1, #BtchSiz)
Select #winLen = DataLength(#wind),
#isLastWin = Case When DataLength(#wind) = #BtchSiz
Then 0 Else 1 End,
#dlPos = CharIndex(#delim, #wind, #Strt)
-- --------------------------------------------
While #Strt <= #winLen
Begin
If #dlPos = 0 Begin -- No More delimiters in window
If #isLastWin = 1 Set #dlPos = #winLen + 1
Else Begin
Set #wPos = #wPos + #Strt - 1
Set #wind = Substring(#S, #wPos, #BtchSiz)
-- ----------------------------------------
Select #winLen = DataLength(#wind), #Strt = 1,
#isLastWin = Case When DataLength(#wind) = #BtchSiz
Then 0 Else 1 End,
#dlPos = CharIndex(#delim, #wind, 1)
If #dlPos = 0 Set #dlPos = #winLen + 1
End
End
-- -------------------------------
Insert #tOut (sVal)
Select LTrim(Substring(#wind,
#Strt, #dlPos - #Strt))
-- -------------------------------
-- Move #Strt to char after last delimiter
Set #Strt = #dlPos + #dlLen
Set #dlPos = CharIndex(#delim, #wind, #Strt)
End
Return
End
Then write, (using your table schema),
Declare #AllVals VarChar(8000)
Select #AllVals = Coalesce(#allVals + ',', '') + ID
From Table Where ID Is Not null
-- -----------------------------------------
Select sVal, Count(*)
From dbo.ParseTextString(#AllVals, ',')
Group By sval
I have a table with two columns: price (int) and price_display (varchar).
price is the actual numerical price, e.g. "9990"
price_display is the visual representation, e.g. "$9.99" or "9.99Fr"
I've been able to confirm the two columns match via regexp:
price_display not regexp
format(price/1000, 2)
But in the case of a mismatch, I want to extract the value from the price_display column and set it into the price column, all within the context of an update statement. I've not been able to figure out how.
Thanks.
This function does the job of only returning the digits 0-9 from the string, which does the job nicely to solve your issue, regardless of what prefixes or postfixes you have.
http://www.artfulsoftware.com/infotree/queries.php?&bw=1280#815
Copied here for reference:
SET GLOBAL log_bin_trust_function_creators=1;
DROP FUNCTION IF EXISTS digits;
DELIMITER |
CREATE FUNCTION digits( str CHAR(32) ) RETURNS CHAR(32)
BEGIN
DECLARE i, len SMALLINT DEFAULT 1;
DECLARE ret CHAR(32) DEFAULT '';
DECLARE c CHAR(1);
IF str IS NULL
THEN
RETURN "";
END IF;
SET len = CHAR_LENGTH( str );
REPEAT
BEGIN
SET c = MID( str, i, 1 );
IF c BETWEEN '0' AND '9' THEN
SET ret=CONCAT(ret,c);
END IF;
SET i = i + 1;
END;
UNTIL i > len END REPEAT;
RETURN ret;
END |
DELIMITER ;
SELECT digits('$10.00Fr');
#returns 1000
One approach would be to use REPLACE() function:
UPDATE my_table
SET price = replace(replace(replace(price_display,'Fr',''),'$',''),'.','')
WHERE price_display not regexp format(price/1000, 2);
This works for the examples data you gave:
'$9.99'
'9.99Fr'
Both result in 999 in my test. With an update like this, it's important to be sure to back up the database first, and be cognizant of the formats of the items. You can see all the "baddies" by doing this query:
SELECT DISTINCT price_display
FROM my_table
WHERE price_display not regexp format(price/1000, 2)
ORDER BY price_display;
For me CASTING the field did the trick:
CAST( price AS UNSIGNED ) // For positive integer
CAST( price AS SIGNED ) // For negative and positive integer
IF(CAST(price AS UNSIGNED)=0,REVERSE(CAST(REVERSE(price) AS UNSIGNED)),CAST(price AS UNSIGNED)) // Fix when price starts with something else then a digit
For more details see:
https://dev.mysql.com/doc/refman/5.0/en/cast-functions.html
This is a "coding horror", relational database schemas should NOT be written like this!
Your having to write complex and unnecessary code to validate the data.
Try something like this:
SELECT CONCAT('$',(price/1000)) AS Price FROM ...
In addition, you can use a float, double or real instead of a integer.
If you need to store currency data, you might consider adding a currency field or use the systems locale functions to display it in the correct format.
I create a procedure that detect the first number in a string and return this, if not return 0.
DROP FUNCTION IF EXISTS extractNumber;
DELIMITER //
CREATE FUNCTION extractNumber (string1 VARCHAR(255)) RETURNS INT(11)
BEGIN
DECLARE position, result, longitude INT(11) DEFAULT 0;
DECLARE string2 VARCHAR(255);
SET longitude = LENGTH(string1);
SET result = CONVERT(string1, SIGNED);
IF result = 0 THEN
IF string1 REGEXP('[0-9]') THEN
SET position = 2;
checkString:WHILE position <= longitude DO
SET string2 = SUBSTR(string1 FROM position);
IF CONVERT(string2, SIGNED) != 0 THEN
SET result = CONVERT(string2, SIGNED);
LEAVE checkString;
END IF;
SET position = position + 1;
END WHILE;
END IF;
END IF;
RETURN result;
END //
DELIMITER ;
Return last number from the string:
CREATE FUNCTION getLastNumber(str VARCHAR(255)) RETURNS INT(11)
DELIMETER //
BEGIN
DECLARE last_number, str_length, position INT(11) DEFAULT 0;
DECLARE temp_char VARCHAR(1);
DECLARE temp_char_before VARCHAR(1);
IF str IS NULL THEN
RETURN -1;
END IF;
SET str_length = LENGTH(str);
WHILE position <= str_length DO
SET temp_char = MID(str, position, 1);
IF position > 0 THEN
SET temp_char_before = MID(str, position - 1, 1);
END IF;
IF temp_char BETWEEN '0' AND '9' THEN
SET last_number = last_number * 10 + temp_char;
END IF;
IF (temp_char_before NOT BETWEEN '0' AND '9') AND
(temp_char BETWEEN '0' AND '9') THEN
SET last_number = temp_char;
END IF;
SET position = position + 1;
END WHILE;
RETURN last_number;
END//
DELIMETER;
Then call this functions:
select getLastNumber("ssss111www222w");
print 222
select getLastNumber("ssss111www222www3332");
print 3332