Give a sequential number for each GROUP BY values - sql-server-2008

Question

I have a temp table with many rows (#TümDATA). I INSERT it's rows into another temp table (#GrupTOT) with GROUP BY clause. But I'm stuck here, I need to give the rows a sequential number after they are GROUPED.
Here is my SQL:
INSERT INTO #GrupTOT(AY, BLK, DRE, TOT)
SELECT J.AY, J.BLK, J.DRE, SUM(J.BORÇ)
FROM #TümDATA J
GROUP BY J.AY, J.BLK, J.DRE

Answer 1

You can try SELECT INTO using an IDENTITY column. This will create the new temporary table #GrupTOT.
Here is a Fiddle example.
SELECT SeqNo = identity(int,1,1), --Identity column
AY = J.AY
BLK = J.BLK,
DRE = J.DRE,
TOT = SUM(J.BORÇ)
INTO #GrupTOT
FROM #TümDATA J
GROUP BY J.AY, J.BLK, J.DRE;
--SELECT * FROM #GrupTOT

Answer 2

You can use ROW_NUMBER to get a number based on an ORDER BY. Or you could add an IDENTITY column to autoincrement a number on insert if that is what you want.
The ROW_NUMBER approach:
WITH CTE AS
(
SELECT Col1, Col2, Col3, Count(*) as [COUNT]
FROM dbo.Table1
GROUP BY Col1, Col2, Col3
)
INSERT INTO dbo.Table2
SELECT RowNum = ROW_NUMBER() OVER ( ORDER BY Col1, Col2, Col3, [COUNT] DESC ),
Col1, Col2, Col3, [COUNT]
FROM CTE

Answer 3

Try this: (Works in Oracle)
WITH ORDERS
AS (SELECT
TO_DATE ( '2013-09-18 00:00:01',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'John' AS NAME
FROM
DUAL
UNION ALL
SELECT
TO_DATE ( '2013-09-19 00:00:01',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'James' AS NAME
FROM
DUAL
UNION ALL
SELECT
TO_DATE ( '2013-09-20 00:00:01',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'John' AS NAME
FROM
DUAL
UNION ALL
SELECT
TO_DATE ( '2013-09-20 00:00:02',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'John' AS NAME
FROM
DUAL
UNION ALL
SELECT
TO_DATE ( '2013-09-20 00:00:03',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'John' AS NAME
FROM
DUAL
UNION ALL
SELECT
TO_DATE ( '2013-09-20 00:00:04',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'John' AS NAME
FROM
DUAL
UNION ALL
SELECT
TO_DATE ( '2013-09-21 16:00:01',
'YYYY-MM-DD HH24:MI:SS' )
AS THE_DATE,
'Jennifer' AS NAME
FROM
DUAL)
SELECT
THE_DATE,
NAME,
ROWNUM
FROM
(SELECT
TRUNC ( THE_DATE ) THE_DATE,
NAME,
COUNT ( 1 )
FROM
ORDERS
GROUP BY
TRUNC ( THE_DATE ),
NAME);
Original Data:
9/18/2013 12:00:01 AM John
9/19/2013 12:00:01 AM James
9/20/2013 12:00:01 AM John
9/20/2013 12:00:02 AM John
9/20/2013 12:00:03 AM John
9/20/2013 12:00:04 AM John
9/21/2013 4:00:01 PM Jennifer
Result:
9/21/2013 Jennifer 1
9/19/2013 James 2
9/20/2013 John 3
9/18/2013 John 4

Answer 4

You can use the ROW_NUMBER() function.
E.g.
WITH q AS (
SELECT field_a
FROM SomeTable
GROUP BY field_a
)
SELECT ROW_NUMBER() OVER(ORDER BY field_a) AS row_num,
field_a
FROM q