I Have query result like this , Select Type,Jan,FEB From TableName :
+-----------+------+------+
| Type | JAN | FEB |
+-----------+------+------+
| MATIC | 137 | 128 |
| MOPED | 41 | 23 |
| MOPED PRM | 8 | 9 |
| SPORT | 55 | 62 |
+-----------+------+------+
4 rows in set (1.23 sec)
I want to add up the columns jan and columns feb, be like this
+-----------+------+------+------+
| Type | JAN | FEB | TOT |
+-----------+------+------+------+
| MATIC | 137 | 128 | 165 |
| MOPED | 41 | 23 | 64 |
| MOPED PRM | 8 | 9 | 17 |
| SPORT | 55 | 62 | 117 |
+-----------+------+------+------+
4 rows in set (1.23 sec)
is there a command such as
select type, jan, feb, sum (jan) + sum (feb) As TOT
From Table Name
This is my syntax
Select SubTbl2.jenis,
sum(If(Month = 1 and Year = 2013 ,Result,0)) as 'JAN',
sum(If(Month = 2 and Year = 2013,Result,0)) as 'FEB'
From (
select SubTbl1.jenis,month(SubTbl1.TglAmb) as Month,
year(SubTbl1.tglAmb) as Year,
count(SubTbl1.jenis) as Result
From (
select jual_leasing.TglAmb,jual_leasing.NoMsn,typemotor.jenis
,lokasi.lokasi3s
from jual_leasing
left join typeconvert
on jual_leasing.typeK = typeconvert.typesystem
left join typemotor
on typeconvert.typeconv = typemotor.type
left join lokasi
on jual_leasing.kodelok = lokasi.kodelokasi
where
lokasi.lokasi3S = 'YMS PURWODADI 3S'
group by jual_leasing.NoMsn)
as SubTbl1
group by SubTbl1.jenis,Month,Year )
as SubTbl2 group by SubTbl2.jenis;
The result is on Top , i try to add script on line 4 , with
JAN + FEB as TOT
but there is stil warning :
ERROR 1054 (42S22): Unknown column 'JAN' in 'field list'
Tq For advanced
To obtain tour desired output, simply do:
select type, jan, feb, jan + feb As TOT
from TableName
You do not need SUM, that is designed to add the values of different rows.
edit For your actual query, yes you can add two sums. Also, the following should work for you:
sum(If((Month = 1 or Month = 2) and Year = 2013 ,Result,0)) as 'TOT',
The MySQL documentation on arithmetic functions indicates that + is indeed the addition operator.
So, your query would be:
select type, jan, feb, jan + feb from table
Sum works over columns and not rows; you'd use this if you wanted the sum of both columns added together.
P.S. 137 + 128 = 265
I think you will find this question is getting down-voted because it is not really about programming - this is more of a general SQL syntax question. That being said, I think you should just be able to sum your values:
select type, jan, feb, jan + feb As TOT From Table Name
Just change the beginning of your query with this :
Select SubTbl2.jenis,
sum(If(Month = 1 and Year = 2013 ,Result,0)) as 'JAN',
sum(If(Month = 2 and Year = 2013,Result,0)) as 'FEB',
sum(If(Month = 1 and Year = 2013 ,Result,0)) +
sum(If(Month = 2 and Year = 2013,Result,0)) as 'TOT'
From (
Or
Select SubTbl2.jenis,
sum(If(Month = 1 and Year = 2013 ,Result,0)) as 'JAN',
sum(If(Month = 2 and Year = 2013,Result,0)) as 'FEB',
sum(If((Month = 1 or Month = 2) and Year = 2013,Result,0)) as 'TOT'
From (
Related
This question already has answers here:
How can I return pivot table output in MySQL?
(10 answers)
Closed 9 years ago.
i have problem with transposing row to column and column to row.
I can do that if it just transpose row to column or column to row.
This my table with data
UNIT|JAN|FEB|MAR|APR|MEI|JUN
CS-1|100|200|300|400|500|600
CS-2|111|222|333|444|555|666
CS-3|331|123|423|923|918|123
and I would like to get the following output
MONTH|CS-1|CS-2|CS-3
JAN |100 |111 |331
FEB |200 |222 |123
MAR |300 |333 |423
etc..
Anybody know how to do this? Thanks very much!
You can do it this way
SELECT month,
MAX(CASE WHEN unit = 'CS-1' THEN value END) `CS-1`,
MAX(CASE WHEN unit = 'CS-2' THEN value END) `CS-2`,
MAX(CASE WHEN unit = 'CS-3' THEN value END) `CS-3`
FROM
(
SELECT unit, month,
CASE month
WHEN 'JAN' THEN jan
WHEN 'FEB' THEN feb
WHEN 'MAR' THEN mar
WHEN 'APR' THEN apr
WHEN 'MAY' THEN may
WHEN 'JUN' THEN jun
END value
FROM table1 t CROSS JOIN
(
SELECT 'JAN' month UNION ALL
SELECT 'FEB' UNION ALL
SELECT 'MAR' UNION ALL
SELECT 'APR' UNION ALL
SELECT 'MAY' UNION ALL
SELECT 'JUN'
) c
) q
GROUP BY month
ORDER BY FIELD(month, 'JAN', 'FEB', 'MAR', 'APR', 'MAY', 'JUN')
Output:
| MONTH | CS-1 | CS-2 | CS-3 |
|-------|------|------|------|
| JAN | 100 | 111 | 331 |
| FEB | 200 | 222 | 123 |
| MAR | 300 | 333 | 423 |
| APR | 400 | 444 | 923 |
| MAY | 500 | 555 | 918 |
| JUN | 600 | 666 | 123 |
Here is SQLFiddle demo
I need to find the difference between the points grouping by Id column.
Id | Year | Points
---+------+-------
1 | 2017 | 10
1 | 2018 | 20
2 | 2017 | 13
2 | 2018 | 16
3 | 2017 | 25
3 | 2018 | 20
Expected result:
Id | Points
---+-------
1 | 10
2 | 3
3 | -5
do aggregation
select
id,sum(case when year = 2018 then points end) -sum(case when year = 2017 then points end) as diff
from tablename group by id
If you want the difference between the years, you don't need group by:
select t2017.id, t2017.points as points_2017,
t2018.points as points_2018,
(t2018.points - t2017.points) as diff
from t t2017 join
t t2018
on t2017.id = t2018.id and
t2017.year = 2017 and
t2018.year = 2018;
You can do something very similar with conditional aggregation:
select id,
sum(case when year = 2017 then points end) as points_2017,
sum(case when year = 2018 then points end) as points_2018,
(sum(case when year = 2018 then points end) -
sum(case when year = 2017 then points end)
) as diff
from t
group by id;
SELECT *,
points - LAG(points) OVER ( PARTITION BY id
ORDER BY year ) delta_to_prev
FROM sourcetable
PS. Needs MySQL 8+.
I have an small application which was build with CodeIgniter 3 and need to perform a report which will be converted to Chart.js. The report should be in yearly basis but at given specific date every month. The requirement are all data count must be from 4th to 3rd monthly. Like this:
For example January Report would be from 4th January to 3rd February, 4th February to 3rd March,... and so on.
I have created a MySQL query but I'm stuck on how to get the date too date. My Query are as follows:
SELECT DATE_FORMAT(odd_date_created, '%Y') as 'year',
DATE_FORMAT(odd_date_created, '%m') as 'month',
COUNT(odd_id) as 'total', status
FROM odd_data
WHERE status = $id and
GROUP BY DATE_FORMAT(odd_date_created, '%Y%m'), status
I'm new to MySQl. Could somebody help me on this. I'm stuck where should I put the date to date query.
Firstly I want to caution you not to use "between" with the following when you come to join your data, use this method instead data.date >= r.period_start_dt and data.date < r.period_end_dt
Secondly I am assuming your data does have dates or timestamps and that will fall between the calculated ranges that follow:
set #year :=2017;
select
*
from (
select
start_dt + INTERVAL m.n MONTH period_start_dt
, start_dt + INTERVAL m.n + 1 MONTH period_end_dt
from (
select str_to_date(concat(#year,'-01-04'),'%Y-%m-%d') start_dt ) seed
cross join (select 0 n union all
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 8 union all
select 9 union all
select 10 union all
select 11
) m
) r
## LEFT JOIN YOUR DATA
## ON data.date >= r.period_start_dt and data.date < r.period_end_dt
Example ranges: (produce you own at this demo: http://rextester.com/CHTKSA95303 )
nb dd.mm.yyyy (.de format)
+----+---------------------+---------------------+
| | period_start_dt | period_end_dt |
+----+---------------------+---------------------+
| 1 | 04.01.2017 00:00:00 | 04.02.2017 00:00:00 |
| 2 | 04.02.2017 00:00:00 | 04.03.2017 00:00:00 |
| 3 | 04.03.2017 00:00:00 | 04.04.2017 00:00:00 |
| 4 | 04.04.2017 00:00:00 | 04.05.2017 00:00:00 |
| 5 | 04.05.2017 00:00:00 | 04.06.2017 00:00:00 |
| 6 | 04.06.2017 00:00:00 | 04.07.2017 00:00:00 |
| 7 | 04.07.2017 00:00:00 | 04.08.2017 00:00:00 |
| 8 | 04.08.2017 00:00:00 | 04.09.2017 00:00:00 |
| 9 | 04.09.2017 00:00:00 | 04.10.2017 00:00:00 |
| 10 | 04.10.2017 00:00:00 | 04.11.2017 00:00:00 |
| 11 | 04.11.2017 00:00:00 | 04.12.2017 00:00:00 |
| 12 | 04.12.2017 00:00:00 | 04.01.2018 00:00:00 |
+----+---------------------+---------------------+
Given the specification, I think I would tempted to cheat it... subtract 3 days from the date. Doing that, Jan 4 backs up to Jan 1, Feb 3 backs up to Jan 31... so those all end up as January.
SELECT DATE_FORMAT(odd_date_created + INTERVAL -3 DAY, '%Y') AS `year`
, DATE_FORMAT(odd_date_created + INTERVAL -3 DAY, '%m') AS `month`
, ...
FROM ...
GROUP
BY DATE_FORMAT(odd_date_created + INTERVAL -3 DAY, '%Y')
, DATE_FORMAT(odd_date_created + INTERVAL -3 DAY, '%m')
This falls apart if there's oddball ranges... if it's not always the 4th and 3rd.
I have a table that stores the date and price of purchases.
For example
date | price
---------------------
2014-1-12 | 6.50
2014-2-34 | 10.99
2015-1-01 | 3.22
2015-2-14 | 4.12
And so on.
What I want to achieve: A query that outputs the SUM of the purchases grouped per month of the year.
The IMPORTANT thing is, though, that I need to have the different years in COLUMNS to be able to make a graph with a separate line for each year. So the output I need is this:
MONTH | 2014 | 2015
JAN | 123.23 | 99.1
FEB | 457.00 | 122.00
MAR | 299.99 | 789.12
... |
NOV | 333.33 | 10.99
DEC | 100.00 | 20.10
Is this even possible? I searched quite a long time for things like "year on year" query etc. But I could not find anything.
Any help is greatly appreciated!
Just use conditional aggregation:
select monthname(date) as mon,
sum(case when year(date) = 2014 then price else 0 end) as price_2014,
sum(case when year(date) = 2015 then price else 0 end) as price_2015
from table t
group by monthname(date)
order by max(month(date));
This question already has answers here:
How can I return pivot table output in MySQL?
(10 answers)
Closed 9 years ago.
i have problem with transposing row to column and column to row.
I can do that if it just transpose row to column or column to row.
This my table with data
UNIT|JAN|FEB|MAR|APR|MEI|JUN
CS-1|100|200|300|400|500|600
CS-2|111|222|333|444|555|666
CS-3|331|123|423|923|918|123
and I would like to get the following output
MONTH|CS-1|CS-2|CS-3
JAN |100 |111 |331
FEB |200 |222 |123
MAR |300 |333 |423
etc..
Anybody know how to do this? Thanks very much!
You can do it this way
SELECT month,
MAX(CASE WHEN unit = 'CS-1' THEN value END) `CS-1`,
MAX(CASE WHEN unit = 'CS-2' THEN value END) `CS-2`,
MAX(CASE WHEN unit = 'CS-3' THEN value END) `CS-3`
FROM
(
SELECT unit, month,
CASE month
WHEN 'JAN' THEN jan
WHEN 'FEB' THEN feb
WHEN 'MAR' THEN mar
WHEN 'APR' THEN apr
WHEN 'MAY' THEN may
WHEN 'JUN' THEN jun
END value
FROM table1 t CROSS JOIN
(
SELECT 'JAN' month UNION ALL
SELECT 'FEB' UNION ALL
SELECT 'MAR' UNION ALL
SELECT 'APR' UNION ALL
SELECT 'MAY' UNION ALL
SELECT 'JUN'
) c
) q
GROUP BY month
ORDER BY FIELD(month, 'JAN', 'FEB', 'MAR', 'APR', 'MAY', 'JUN')
Output:
| MONTH | CS-1 | CS-2 | CS-3 |
|-------|------|------|------|
| JAN | 100 | 111 | 331 |
| FEB | 200 | 222 | 123 |
| MAR | 300 | 333 | 423 |
| APR | 400 | 444 | 923 |
| MAY | 500 | 555 | 918 |
| JUN | 600 | 666 | 123 |
Here is SQLFiddle demo