JSON to Parse: http://www.dota2.com/jsfeed/heropickerdata?v=18874723138974056&l=english
Hero Class and JSON Serialization
case class Hero(
var id:Option[Int],
name: String,
bio: String,
var trueName:Option[String]
){}
implicit val modelReader: Reads[Hero] = Json.reads[Hero]
Reading Data
val future: Future[play.api.libs.ws.Response] = WS.url("http://www.dota2.com/jsfeed/heropickerdata?v=18874723138974056&l=english").get()
val json = Json.parse(Await.result(future,5 seconds).body).as[Map[String, Hero]]
var i = 1
json.foreach(p => {
p._2.trueName = Some(p._1)
p._2.id = Some(i)
p._2.commitToDatabase
i += 1
})
I need to get the id of each hero. The order of heros in the json matches their id. Obviously a map is unordered and wont work. Does anyone have any other ideas?
I have tried to use a LinkedHashMap. I even tried to make an implicit Reads for LinkedHashMap but I've failed. If anyone thinks that this is the answer then would you please give me some guidance?
It keeps just saying "No Json deserializer found for type scala.collection.mutable.LinkedHashMap[String,models.Hero]. Try to implement an implicit Reads or Format for this type.". I have the trait imported into the file i'm trying to read from. I have a funny feeling that the last line in my Reads is the problem. i think I can't just do the asInstanceOf, however I have no other ideas of how to do this reads.
LinkedHashMap Implicit Reads Code: http://pastebin.com/cf5NpSCX
You can try extracting data in order from the JsObject returned by Json.parse directly, possibly like this:
val json = Json.parse(Await.result(future,5 seconds).body)
val heroes: Map[String, Hero] = json match {
case obj: JsObject =>
obj.fields.zipWithIndex.map{ case ((name: String, heroJson: JsValue), id) =>
heroJson.asOpt[Hero].map{ _.copy(id = Some(id)) }
}.flatten.toMap
case _ = > Seq.empty
}
I don't believe you'll need an order-preserving map anymore since the ids are generated and fixed.
Related
override def accessToken(): ServiceCall[RequestTokenLogIn, Done] = {
request=>
val a=request.oauth_token.get
val b=request.oauth_verifier.get
val url=s"https://api.twitter.com/oauth/access_token?oauth_token=$a&oauth_verifier=$b"
ws.url(url).withMethod("POST").get().map{
res=>
println(res.body)
}
The output which I am getting on terminal is
oauth_token=xxxxxxxxx&oauth_token_secret=xxxxxxx&user_id=xxxxxxxxx&screen_name=xxxxx
I want to convert this response in json format.like
{
oauth_token:"",
token_secret:"",
}
When Calling res.json.toString its not converting into jsValue.
Is there any other way or am I missing something?
According to the documentation twitter publishes, it seems that the response is not a valid json. Therefore you cannot convert it automagically.
As I see it you have 2 options, which you are not going to like. In both options you have to do string manipulations.
The first option, which I like less, is actually building the json:
print(s"""{ \n\t"${res.body.replace("=", "\": \"").replace("&", "\"\n\t\"")}" \n}""")
The second option, is to extract the variables into a case class, and let play-json build the json string for you:
case class TwitterAuthToken(oauth_token: String, oauth_token_secret: String, user_id: Long, screen_name: String)
object TwitterAuthToken {
implicit val format: OFormat[TwitterAuthToken] = Json.format[TwitterAuthToken]
}
val splitResponse = res.body.split('&').map(_.split('=')).map(pair => (pair(0), pair(1))).toMap
val twitterAuthToken = TwitterAuthToken(
oauth_token = splitResponse("oauth_token"),
oauth_token_secret = splitResponse("oauth_token_secret"),
user_id = splitResponse("user_id").toLong,
screen_name = splitResponse("screen_name")
)
print(Json.toJsObject(twitterAuthToken))
I'll note that Json.toJsObject(twitterAuthToken) returns JsObject, which you can serialize, and deserialize.
I am not familiar with any option to modify the delimiters of the json being parsed by play-json. Given an existing json you can manipulate the paths from the json into the case class. But that is not what you are seeking for.
I am not sure if it is requires, but in the second option you can define user_id as long, which is harder in the first option.
Im trying to parse this file with Klaxon, generally its going well, except I am totally not succeeding in parsing that subarray of features/[Number]/properties/
So my thought is to get the raw string of properties and to parse it seperately with Klaxon, though I dont succeed in that either. Apart from that I took many other approaches as well.
My code so far:
class Haltestelle(val type: String?, val totalFeatures: Int?, val features: Array<Any>?)
fun main(args: Array<String>) { // Main-Routine
val haltejsonurl = URL("http://online-service.kvb-koeln.de/geoserver/OPENDATA/ows?service=WFS&version=1.0.0&request=GetFeature&typeName=ODENDATA%3Ahaltestellenbereiche&outputFormat=application/json")
val haltestringurl = haltejsonurl.readText()
val halteklx = Klaxon().parse<Haltestelle>(haltestringurl)
println(halteklx?.type)
println(halteklx?.totalFeatures)
println(halteklx?.features)
halteklx?.features!!.forEach {
println(it)
}
I am aware that I am invoking features as an Array of Any, so the Output is just printing me java.lang.Object#blabla everytime. Though, using Array failes either.
Really spend hours in this, how would you go on this?
Regards of newbie
Here's how I did something similar in Kotlin. You can parse the response as a Klaxon JsonObject, then access the "features" element to parse all the array objects into a JsonArray of JsonObjects. This can be iterated over and cast with parseFromJsonObject<Haltestelle> in your example:
import com.beust.klaxon.JsonArray
import com.beust.klaxon.JsonObject
import com.beust.klaxon.Parser
import com.github.aivancioglo.resttest.*
val response : Response = RestTest.get("http://anyurlwithJSONresponse")
val myParser = Parser()
val data : JsonObject = myParser.parse(response.getBody()) as JsonObject
val allFeatures : JsonArray<JsonObject>? = response["features"] as JsonArray<JsonObject>?
for((index,obj) in allFeatures.withIndex()) {
println("Loop Iteration $index on each object")
val yourObj = Klaxon().parseFromJsonObject<Haltestelle>(obj)
}
I have made a small app using json and reactiveMongo which inserts
Students Information.
object Applications extends Controller{
val studentDao = StudentDaoAndEntity
val studentqueryReader: Reads[JsObject] = implicitly[Reads[JsObject]]
def saveStudent = Action.async(parse.json) { request =>
request.body.validate[StudentInfo].map {
k => studentDao.insertStudent(k).map {
l => Ok("Successfully inserted")
}
}.getOrElse(Future.successful(BadRequest("Invalid Json"))
In databse
object StudentDaoAndEntity {
val sreader: Reads[StudentInfo] = Json.reads[StudentInfo]
val swriter: Writes[StudentInfo] = Json.writes[StudentInfo]
val studentqueryReader: Reads[JsObject] = implicitly[Reads[JsObject]]
def db = ReactiveMongoPlugin.db
def collection: JSONCollection = db[JSONCollection]("student")
def insertStudent(student: StudentInfo): Future[JsObject]= {
val modelToJsObj = swriter.writes(student).as[JsObject]
collection.insert(modelToJsObj) map (_ => modelToJsObj)
}
This works fine. Now I need to get all data I have inserted. How can I
do that? I am not asking for code but for Idea.
First of all: it seems that you are using Play-ReactiveMongo (as far as i know, JSONCollection is not part of ReactiveMongo itself). If this is the case, then your code is unnecessarily complex. Instead of doing the JSON conversions manually, you just can pass your StudentInfo objects directly to insert. Minimal example:
val studentInfo: StudentInfo = ...
def collection: JSONCollection = db[JSONCollection]("student")
collection.insert(studentInfo)
That's the elegant part of the Play plugin. Yes, MongoDB persists data as JSON (or BSON, to be more precise), but you don't have do deal with it. Just make sure the implicit Writes (or Reads, in case of querying) is in scope, as well as other necessary imports (e.g. play.modules.reactivemongo.json._).
Now I need to get all data I have inserted. How can I do that? I am
not asking for code but for Idea.
Well, you want to have a look at the documentation (scroll down for examples), it's quite simple and there is not more to it. In your case, it could look like this:
// perform query via cursor
val cursor: Cursor[StudentInfo] =
collection.find(Json.obj("lastName" -> "Regmi")).cursor[StudentInfo]
// gather results as list
val futureStudents: Future[List[StudentInfo]] = cursor.collect[List]()
In this case, you get all students with the last name Regmi. If you really want to retrieve all students, then you probably need to pass an empty JsObject as your query. Again, it's not necessary to deal with JSON conversions, as long as the implicit Reads is in scope.
Here is the Complete Answer of my own Question
package controllers
def findAll=Action.async {
val cursor = Json.obj()
StudentDaoAndEntity.findAllStudent(cursor) map {
case Nil => Ok("Student Not Found")
case l:Seq[JsObject] => Ok(Json.toJson(l))
}
}
def findAllStudent(allStd: JsObject): Future[Seq[JsObject]] = {
// gather all the JsObjects in a list
collection.find(allStd).cursor[JsObject].collect[List]()
}
I am trying to display json data from database using scala/anorm of Play(2.2.x), If I give the following trial, I am getting the error like: type mismatch; found : scala.collection.immutable.Stream[String] required: String, but If I write like: sql().map(row => rowString).toString - is giving Stream type json data(i don't need it), so how can I get my normal json data for it ? Please help me and thank in advance.
contorller:
class Test extends Controller {
def getTest = Action {
var sql: SqlQuery = SQL("select name::TEXT from test");
def values: String = DB.withConnection { implicit connection =>
sql().map(row => row[String]("name"))//giving error: type mismatch; found : scala.collection.immutable.Stream[String] required: String
}
Ok(values)
}
It looks like you are using Anorm for database access. As noted in the comments above, executing the Anorm query returns a Stream rather than just a value. When you map the value, it is again returning a Stream of String so that the results can be processed as a stream. This is very useful for large result sets where it makes more sense to process the stream incrementally and stream the result to the client. It looks like you are just getting started so you probably don't want to worry about that right now.
You can covert the result from a stream into a conventional list by simply using toList:
val resList = sql().map(row => row[String]("name")).toList
Now, you also need to unescape the string and return it as a JSON result. That can be done by using string interpolations. To do this, you just need to surround the String in a StringContext and call the s method with no arguments.
val newResList = resList.map(s => StringContext(s).s())
Finally, you should actually be converting the String into a PlayJson JsValue type so that your controller is actually returning the right type.
Json.parse(newResList.mkString("[",",","]")
The mkString method is used to convert the list into a valid JSON string. You will need to import play.api.libs.json.Json for this to work. Passing a JsValue to Ok ensures that the mime type of the response is set to "application/json". You can learn more about using JSON with play here. This will be important if you intend to build JSON services.
Putting it together, you get the following:
class Test extends Controller {
def getTest = Action {
var sql: SqlQuery = SQL("select name::TEXT from test");
def values: JsValue = DB.withConnection { implicit connection =>
val resList = sql().map(row => row[String]("name")).toList
val newResList = resList.map(s => StringContext(s).s())
Json.parse(newResList.mkString("[",",","]")
}
Ok(values)
}
You could also use the following alternate structure to simplify and get rid of the rather sloppy mkString call.
class Test extends Controller {
def getTest = Action {
var sql: SqlQuery = SQL("select name::TEXT from test");
def values: JsValue = DB.withConnection { implicit connection =>
val resList = sql().map(row => row[String]("name")).toList
Json.toJson(resList.map(s => Json.parse(StringContext(s).s())))
}
Ok(values)
}
This parses each of the JSON strings in the list and then converts the list into JsArray again using the capabilities of Play's built in JSON library.
I am new to Scala and play 2 and haven't found a way to return a Json request from the database using Anorm. This is my simple code
def locations = Action {implicit c=>
import play.api.libs.json._
implicit val readLocations = SQL("select city,state from zips limit 1")
Ok(Json.toJson(readLocations))
}
The method is a post I simply want to return via Json 1 record from the database table there but I get this error
Error:(57, 21) Play 2 Compiler:
.scala:57: No Json serializer found for type anorm.SqlQuery. Try to implement an implicit Writes or Format for this type.
Ok(Json.toJson(readLocations))
Any suggestions would be welcomed, I have been switching the code above some but nothing is working. I know I need to do a Write or Format but can't seem to find out how.
^**
Looks like you are trying to send a List of Locations. You could do:
def locations = Action {implicit c=>
import play.api.libs.json._
implicit val locationFmt = Json.format[Location]
case class Location(city: String, state: String)
//Send Multiple Locations if you want
val readLocations = SQL("select city,state from zips").list.map{case Row(city: String, state: String) =>
Location(city, state)
}
// Send a single Location
val readLocation = SQL("select city,state from zips limit 1").list.headOption.map{case Row(city: String, state: String) =>
Location(city, state)
}.getOrElse(throw new NoSuchElementException)
Ok(Json.toJson(readLocation))
}