Find customers with more than 1 order grouped by day - mysql

Question

I want to know how many customers placed more than 1 order, grouped by day.
But I want to exclude orders that have been cancelled.
I have a customer table with customers
I have a customer_order table with orders (when an order is cancelled
it stays in the customer_order table)
I have an order_item table (where original orders are, and also
cancelled orders, cancelled orders get a new credit order, and the
original order id appears in the id_credit_order row of the credit
order)
I want something like this:
date | no of customers with 1 order | no of customers with 2 orders | no of customers with 3 order | etc.
But I want no count if the original order has been cancelled!
I have now this query, but its definitely not enough, does someone know how to get my result? thanks!
SELECT DATE(co.date_order), COUNT(co.id_customer)
FROM customer_order co
GROUP BY DATE(co.date_order)
ORDER BY DATE(co.date_order) DESC;

Answer 1

The question is slightly misleading, as you first ask for the number of customers with more than one order, then you ask for the number of customer with each of 1, 2, 3... orders.
Here's something that will give you the numbers, but unpivoted. You'll need to put the right column name in for o.id
Select -- outer query takes each order count and counts how many customers have that many
co.date_order,
co.customer_order_count,
count(*) as customer_count
From (
Select -- inner query counts how many valid orders each customer has
o.date_order,
o.id_customer,
count(*) as customer_order_count
From
customer_order o
Where
o.id_credit_order is null and -- rule out credit orders
not exists ( -- rule out orders with related credit orders
select
'x'
from
customer_order c
where
c.id_credit_order = o.id -- column name isn't mentioned in the question
)
Group By
o.date_order,
o.id_customer
) co
Group By
co.date_order,
co.customer_order_count
Order By
co.date_order desc,
co.customer_order_count

Answer 2

Try using a HAVING clause.
SELECT DATE(co.date_order), COUNT(co.id_customer)
FROM customer_order co
WHERE co.Cancelled = 0
GROUP BY DATE(co.date_order)
HAVING COUNT(co.id_customer) >= 1
ORDER BY DATE(co.date_order) DESC;

Answer 3

Give this a try. Change the WHERE to reflect how you cancel orders.
SELECT DATE(co.date_order), COUNT(co.id_customer)
FROM customer_order co
WHERE co.cancelled = 0
GROUP BY DATE(co.date_order)
HAVING COUNT(co.id_customer) > 0
ORDER BY DATE(co.date_order) DESC;