Got a column that keeps strings like such:
{"plan-36";"id-36";}
I want to check each string of this column, and if matches my criteria, it would change a specific character of this string (for example would change number 36 to 99). Here's what i got so far:
SELECT string_column
FROM example_table
WHERE
INSTR(string_column,'plan-36') > 0
OR
INSTR(string_column,'id-36') > 0
This only returns rows that has 'plan-36' or 'id-36' string in them. What i need is - if this row contain such strings, i need to change the 36 value, to let's say 99.
Which sql functions do i need for this?
UPDATE example_table
SET string_column = REPLACE(string_column, "36", "99")
WHERE
INSTR(string_column,'plan-36') > 0
OR
INSTR(string_column,'id-36') > 0
would be the syntax, this will update all instances of 36 to 99, Be careful and test on backup data first.
It may be better to use this
SET string_column = REPLACE(string_column, "-36", "-99")
which includes the dash
Related
I have two mysql query.
SELECT tanulok.nev, tanulok.osztaly, leadasok.idopont, leadasok.mennyiseg
FROM `leadasok`, tanulok
WHERE tanulok.tazon = leadasok.tanulo and osztaly LIKE "1_"
SELECT tanulok.nev, tanulok.osztaly, leadasok.idopont, leadasok.mennyiseg
FROM `leadasok`, tanulok
WHERE tanulok.tazon = leadasok.tanulo and osztaly = 1
They give the same result. Why?
column = 1 and column like "1_" are equivalent?
the values of the osztaly column are "1A", "1B", "2A" ...
Because in MySQL to make a comparison of string and number - the DB engine converts the string into a number. It starts on the left side of the string and takes all number characters and builds a number from it.
"1A" -> 1
"300miles" -> 300
"$3" -> 0 (because the string does NOT start with a number)
That is why the second query returns results as well.
I've used the following SQL query in a MySQL database to replace part of a string in a cell:
UPDATE TEST.database2014 SET together1 = REPLACE(together1, "/1900", "20")
For some reason all the rows (225,000!) have now a value of 0.
This is the message which I got:
/* Affected rows:225,000 Found rows: 0 Warnings: 0 Duration for 1 query: 16,888 sec. */
ADDITIONAL INFORMATION:
data example contained in field together1:
TESTING^^^19/01/2014^^
Is there a known reason for this happening?
I find it strange that if no matches where found it converted all values to 0 anyway.
I think that you must use this:
UPDATE TEST.database2014 SET together1 = REPLACE(together1, "/19", "/20") WHERE togheter1 LIKE '%/19%'
if you want to upate all year 1900 to 2000
I have a csv file that contains phone numbers, some of them have 9 digits and some of them have 10. Is there a command that would allow the transformation of the column such that numbers that have only 9 digits will have a 0 appended in front of the numbers.
For example,
if the column has values "443332332" and "0441223332", I would like to have the value of the one with 9 digits changed to "0443332332"?
Sorry, I should have elaborated.
I was wondering if there was a command to do it in SQLlite easily? I prefer not to use excel to transform the column as if I can get it to working with sqllite it would be so much easier and faster.
A more generic solution would be:
select substr('0000000000'||'1234567', -10, 10) from table_name;
The above query would always return 10 digits and add leading zeroes to the missed out number of digits.
For example, the above query would return : 0001234567
For Update, use
UPDATE TABLE_NAME SET PHONE_NO = substr('0000000000'|| PHONE_NO, -10, 10);
If you're sure that just prepending a zero on strings with length 9 will work for your application, something simple will work:
SELECT CASE WHEN LENGTH(phone_number) = 9 THEN '0'||phone_number
ELSE phone_number
END AS phone_number
FROM your_table
;
You could also update the table, depending on your needs:
UPDATE your_table
SET phone_number = '0'||phone_number
WHERE LENGTH(phone_number) = 9
;
Open the .csv using Excel,
Add a filter to the column,
Sort from A-Z to get all the columns with 9 digits,
Then follow the steps here
http://office.microsoft.com/en-au/excel-help/keep-leading-zeros-in-number-codes-HA010342581.aspx
I have a PolicyNo column in my table in MySQL with a format like this:
XXXX-000000
A four capital-case characters followed by a dash and a six digit number.
The six digit number is incremental, adding 1 for the next row, and the the four characters is always the same for all rows. The PolicyNo column is unique with a type of varchar(11).
If ordered, it will look like this:
XXXX-000001
XXXX-000002
XXXX-000003
...
Now I want to get all PolicyNo whose number is greater than a specified number.
For example: Retrieve all PolicyNo greater than 'XXXX-000100':
XXXX-000101
XXXX-000102
XXXX-000103
...
I test this query and it works fine, but I just didn't know if it is really safe to do such:
SELECT 'XXXX-000099' > 'XXXX-000098'
, 'XXXX-000099' > 'XXXX-000100'
, 'XXXX-000099' > 'XXXX-000101'
Result:
+-------------------------------+-------------------------------+-------------------------------+
| 'XXXX-000099' > 'XXXX-000098' | 'XXXX-000099' > 'XXXX-000100' | 'XXXX-000099' > 'XXXX-000101' |
+-------------------------------+-------------------------------+-------------------------------+
| 1 | 0 | 0 |
+-------------------------------+-------------------------------+-------------------------------+
Is there any other way to do this or is it already OK to use this?
Because your numbers are zero padded, as long as the four letter prefix is the same and always the same length, then this should work as MySQL will do a lexicographical comparison.
Note that one less 0 in the padding will cause this to fail:
SET #policy1 = 'XXXX-00099';
SET #policy2 = 'XXXX-000598';
SELECT #policy1, #policy2, #policy1 > #policy2 AS comparison;
=========================================
> 'XXXX-00099', 'XXXX-000598', 1
If you need to truly compare the numbers at the end, you will need to parse them out and cast them:
SET #policy1 = 'XXXX-00099';
SET #policy2 = 'XXXX-000598';
SELECT #policy1, #policy2,
CONVERT(SUBSTRING(#policy2, INSTR(#policy2, '-')+1), UNSIGNED) >
CONVERT(SUBSTRING(#policy2, INSTR(#policy2, '-')+1), UNSIGNED) AS comparison;
=========================================
> 'XXXX-00099', 'XXXX-000598', 0
You can also use SUBSTRING function provided by MySQL, like the following query.
SELECT count(*) FROM Table1 where substring(policyNo,6)>YOUR_RANGE;
here 6 is passed as the 6 digit number start from 6th position And if you do want to pass initial 4 charecter as well then you can use following query. Here second where clause will take intial 4 letters from the policyNo.
SELECT count(*) FROM Table1 where substring(policyNo,6)>YOUR_RANGE AND substring(policyNo,1,4) = 'ABCD'
Lets say I have these DB rows
id | storage | used | status
1 - 100 - 0 - 1
2 - 1000 - 5000 - 1
I need to compare the rows "storage" and "used"
I want to select rows WHERE status = 1 and Column"storage" > Column"used".
I tried WHERE status = '1' AND storage > used
It should report back row id #1, but it doesnt.
Well, WHERE status=1 AND storage > used is correct. If you tried it and didn't get back the row with id=1 there's something wrong with your data.
Are storage and used numeric columns? Or are they stored as a VARCHAR (or, gasp, TEXT)? If so, you won't be able to compare them quite the way you want, and will first have to convert or cast them to numeric types. It would be better to change the type to actually be numeric (i.e., INT or DECIMAL or whichever other type is appropriate).
SELECT * FROM `table` WHERE status = '1' AND storage > used
should give you the right solution, like VoteyDisciple mentioned, make sure status and used are both of numeric type.
you can use SELECT * FROMtableWHERE status = '1' AND storage > used but the data type of the storage and used must be NUMERIC not VARCHAR.
if Still you didn't get correct ans then it should be problem with your data storage structure.
Thanks!