My table
+------+-------+--------+
| NAME | MARKS | POINTS |
+------+-------+--------+
| S1 | 53 | (null) |
| S2 | 55 | (null) |
| S3 | 56 | (null) |
| S4 | 55 | (null) |
| S5 | 52 | (null) |
| S6 | 51 | (null) |
| S7 | 53 | (null) |
+------+-------+--------+
Refer : http://www.sqlfiddle.com/#!2/5d046/1
I would like to add 3,2,1 points to the highest Marks. Here S3 goes to 3 points, S2,S4 goes to 2 points and S1,S7 goes to 1 points.
Final outputs looks,
+------+-------+--------+
| NAME | MARKS | POINTS |
+------+-------+--------+
| S1 | 53 | 1 |
| S2 | 55 | 2 |
| S3 | 56 | 3 |
| S4 | 55 | 2 |
| S5 | 52 | 0 |
| S6 | 51 | 0 |
| S7 | 53 | 1 |
+------+-------+--------+
Plz help
My suggestion is that you first calculate the ranking of each mark, and then use that in a case statement in an update.
The following query shows one way to calculate the ranking:
select t.*,
#rn := if(#marks = marks, #rn, #rn + 1) as ranking,
#marks := marks
from myTable t cross join
(select #rn := 0, #marks := -1) const
order by t.marks desc;
(As a note: I am a bit uncomfortable with this method, because MySQL does not guarantee the order of evaluation of the two expressions with constants. If #marks were set before #rn, then it wouldn't work. In practice, that does not seem to happen. And, this is more efficient that the equivalent with a correlated subquery.)
You can then put this into an update using join:
update myTable join
(select t.*,
#rn := if(#marks = marks, #rn, #rn + 1) as ranking,
#marks := marks
from myTable t cross join
(select #rn := 0, #marks := -1) const
order by t.marks desc
) mr
on myTable.Name = mr.Name
set myTable.Points := (case when mr.ranking = 1 then 3
when mr.ranking = 2 then 2
when mr.ranking = 3 then 1
else 0
end);
This has been tested on your SQL Fiddle.
You can do it via variables (see samples in other answers), or via case:
select
myTable.*,
case
when max1.marks is not null then 3
when max2.marks is not null then 2
when max3.marks is not null then 1
else 0
end as score
from
myTable
LEFT JOIN
(select marks from myTable order by marks desc limit 1) AS max1
ON myTable.marks=max1.marks
LEFT JOIN
(select marks from myTable order by marks desc limit 2,1) AS max2
ON myTable.marks=max2.marks
LEFT JOIN
(select marks from myTable order by marks desc limit 3,1) AS max3
ON myTable.marks=max3.marks;
the demo can be found here.
UPDATE myTable t1
INNER JOIN
(
SELECT #row:=#row-1 AS RowPoints, Marks
FROM (
SELECT Marks
FROM myTable
GROUP BY Marks
ORDER BY Marks DESC
LIMIT 3
) AS TopMarks
INNER JOIN (SELECT #row:=4) AS RowInit
) AS AddPoints ON t1.Marks = AddPoints.Marks
SET Points = COALESCE(Points, 0) + AddPoints.RowPoints;
This should work just fine. You should and and index on the Marks column.
The simplest way to do this:
SELECT t.Name Name, t.Marks Marks,
(CASE WHEN Marks = (Select max(marks) from mytable) THEN 3 ELSE 0 END+
CASE WHEN Marks = (Select min(marks) from (Select distinct marks
from mytable order by marks desc limit 2) a) THEN 2 ELSE 0 END+
CASE WHEN Marks = (Select min(marks) from (Select distinct marks
from mytable order by marks desc limit 3) b) THEN 1 ELSE 0 END)
AS `Points`
FROM mytable t;
SQL Fiddle
Related
I want to find a user's position in a leaderboard and return the 4 users above and 4 users below their position.
My table, 'predictions', looks something like this:
+----+---------+--------+-------+---------+
| id | userId | score | rank | gameId |
+----+---------+--------+-------+---------+
| 1 | 12 | 11 | 1 | 18 |
| 2 | 1 | 6 | 4 | 18 |
| 3 | 43 | 7 | 3 | 12 |
| 4 | 4 | 9 | 2 | 18 |
| 5 | 98 | 2 | 5 | 19 |
| 6 | 3 | 0 | 6 | 18 |
+----+---------+--------+-------+---------+
Obviously this isn't properly ordered, so I run this:
SELECT l.userId,
l.rank,
l.score,
l.createdAt,
#curRow := #curRow + 1 AS row_number
FROM (SELECT * FROM `predictions` WHERE gameId = 18) l
JOIN (SELECT #curRow := 0) r
ORDER BY rank ASC
which gets me a nice table with each entry numbered.
I then want to search this generated table, find the row_number where userId = X, and then return the values 'around' that result.
I think I have the logic of the query down, I just can't work out how to reference the table 'generated' by the above query.
It would be something like this:
SELECT *
FROM (
SELECT l.userId,
l.rank,
l.score,
l.createdAt,
#curRow := #curRow + 1 AS row_number
FROM (SELECT * FROM `predictions` WHERE gameId = 18) l
JOIN (SELECT #curRow := 0) r
ORDER BY rank ASC) generated_ordered_table
WHERE row_number < (SELECT row_number FROM generated_ordered_table WHERE userId = 1)
ORDER BY row_number DESC
LIMIT 0,5
This fails. What I'm trying to do is to generate my first table with the correct query, give it an alias of generated_ordered_table, and then reference this 'table' later on in this query.
How do I do this?
MySQL version 8+ could have allowed the usage of Window functions, and Common Table Expressions (CTEs); which would have simplified the query quite a bit.
Now, in the older versions (your case), the "Generated Rank Table" (Derived Table) cannot be referenced again in a subquery inside the WHERE clause. One way would be to do the same thing twice (select clause to get generated table) again inside the subquery, but that would be relatively inefficient.
So, another approach can be to use Temporary Tables. We create a temp table first storing the ranks. And, then reference that temp table to get results accordingly:
CREATE TEMPORARY TABLE IF NOT EXISTS gen_rank_tbl AS
(SELECT l.userId,
l.rank,
l.score,
l.createdAt,
#curRow := #curRow + 1 AS row_number
FROM (SELECT * FROM `predictions` WHERE gameId = 18) l
JOIN (SELECT #curRow := 0) r
ORDER BY rank ASC)
Now, you can reference this temp table to get the desired results:
SELECT *
FROM gen_rank_tbl
WHERE row_number < (SELECT row_number FROM gen_rank_tbl WHERE userId = 1)
ORDER BY row_number DESC
LIMIT 0,5
You could use a bunch of unions
select userid,rank,'eq'
from t where gameid = 18 and userid = 1
union
(
select userid,rank,'lt'
from t
where gameid = 18 and rank < (select rank from t t1 where t1.userid = 1 and t1.gameid = t.gameid)
order by rank desc limit 4
)
union
(
select userid,rank,'gt'
from t
where gameid = 18 and rank > (select rank from t t1 where t1.userid = 1 and t1.gameid = t.gameid)
order by rank desc limit 4
);
+--------+------+----+
| userid | rank | eq |
+--------+------+----+
| 1 | 4 | eq |
| 4 | 2 | lt |
| 12 | 1 | lt |
| 3 | 6 | gt |
+--------+------+----+
4 rows in set (0.04 sec)
But it's not pretty
You can use two derived tables:
SELECT p.*,
(#user_curRow = CASE WHEN user_id = #x THEN rn END) as user_rn
FROM (SELECT p.*, #curRow := #curRow + 1 AS rn
FROM (SELECT p.*
FROM predictions p
WHERE p.gameId = 18
ORDER BY rank ASC
) p CROSS JOIN
(SELECT #curRow := 0, #user_curRow := -1) params
) p
HAVING rn BETWEEN #user_curRow - 4 AND #user_currow + 4;
Let's assume I have two columns: letters and numbers in a table called tbl;
letters numbers
a 1
b 2
c 3
d 4
Doing a cartesian product will lead to :
a 1
a 2
a 3
a 4
b 1
b 2
b 3
b 4
c 1
c 2
c 3
c 4
d 1
d 2
d 3
d 4
Write a query that reverts the cartesian product of these two columns back to the original table.
I tried multiple methods from using ROWNUM to selecting distinct values and joining them (which leads me back to the cartesian product)
SELECT DISTINCT *
FROM (SELECT DISTINCT NUMBERS
FROM TBL
ORDER BY NUMBERS) AS NB
JOIN (SELECT DISTINCT LETTERS
FROM TBL
ORDER BY LETTERS) AS LT1
which led me back to the cartesian product....
This is a version that works with 5.7.
SELECT `numbers`,`letters` FROM
(SELECT `numbers`,
#curRank := #curRank + 1 AS rank
FROM Table1 t, (SELECT #curRank := 0) r
GROUP By `numbers`
ORDER BY `numbers`) NB1
INNER JOIN
(SELECT `letters`,
#curRank1 := #curRank1 + 1 AS rank
FROM (
Select `letters` FROM Table1 t
GROUP By `letters`) t2, (SELECT #curRank1 := 0) r
ORDER BY `letters`) LT1 ON NB1.rank = LT1.rank;
https://dbfiddle.uk/?rdbms=mysql_5.7&fiddle=cc17c2cfeff049edc73e437e5e4fd892
As Raymond and Ankit pointed out you have to know which order have the letters and even the order of the numbers has to be defined prior or else you never get a correct answer.
Another way of writing this:
SELECT numbers
, letters
FROM
( SELECT DISTINCT numbers
, #curRank := #curRank + 1 rank
FROM Table1 t
, (SELECT #curRank := 0) r
ORDER
BY numbers
) NB1
JOIN
( SELECT letters
, #curRank1 := #curRank1 + 1 rank
FROM
( SELECT DISTINCT letters
FROM Table1 t
) t2
, (SELECT #curRank1 := 0) r
ORDER
BY letters
) LT1
ON NB1.rank = LT1.rank;
If you are sure that the order will never be destroyed and is deterministic, You can use dense_rank() analytic function to achieve it back -
SELECT LT1.LETTERS, NB.NUMBERS
FROM (SELECT DISTINCT NUMBERS
FROM TBL
ORDER BY NUMBERS) AS NB
JOIN (SELECT DISTINCT LETTERS, RN
FROM (SELECT LETTERS, DENSE_RANK() OVER (ORDER BY LETTERS) RN
FROM TBL
ORDER BY LETTERS) T) AS LT1
ON NB.NUMBERS = LT1.RN
Here is the fiddle
Perhaps this is oversimplifying the problem, but it should be seen that this, or some variation of it, would suffice...
SELECT * FROM my_table;
+---------+---------+
| letters | numbers |
+---------+---------+
| a | 1 |
| a | 2 |
| a | 3 |
| a | 4 |
| b | 1 |
| b | 2 |
| b | 3 |
| b | 4 |
| c | 1 |
| c | 2 |
| c | 3 |
| c | 4 |
| d | 1 |
| d | 2 |
| d | 3 |
| d | 4 |
+---------+---------+
16 rows in set (0.00 sec)
SELECT x.*
, #i:=#i+1 numbers
FROM
( SELECT DISTINCT letters
FROM my_table
) x
, (SELECT #i:=0) vars
ORDER
BY letters;
+---------+---------+
| letters | numbers |
+---------+---------+
| a | 1 |
| b | 2 |
| c | 3 |
| d | 4 |
+---------+---------+
I have a feeling this is a very simple question but maybe i'm having brain fart right now and just can't seem to figure out how to go about it.
I have a MySQL table structure like below
+---------------------------------------------------+
| id | date | score | speed | user_id |
+---------------------------------------------------+
| 1 | 2016-11-17 | 2 | 133291 | 17 |
| 2 | 2016-11-17 | 6 | 82247 | 17 |
| 3 | 2016-11-17 | 6 | 21852 | 17 |
| 4 | 2016-11-17 | 1 | 109338 | 17 |
| 5 | 2016-11-17 | 7 | 64762 | 61 |
| 6 | 2016-11-17 | 8 | 49434 | 61 |
Now i can get a particular user's best performance by doing this
SELECT *
FROM performance
WHERE user_id = 17 AND date = '2016-11-17'
ORDER BY score desc,speed asc LIMIT 1
This should return the row with ID = 3. Now what I want is a single query to run to be able to return that 1 such row for each unique user_id in the table. So the resulting result would be something like this
+---------------------------------------------------+
| id | date | score | speed | user_id |
+---------------------------------------------------+
| 3 | 2016-11-17 | 6 | 21852 | 17 |
| 6 | 2016-11-17 | 8 | 49434 | 61 |
Also further more, can I have another question within this same query that would further sort this eventual resulting table by the same criteria of sort (score desc, speed asc). Thanks
A simple method uses a correlated subquery:
select p.*
from performance p
where p.date = '2016-11-17' and
p.id = (select p2.id
from performance p2
where p2.user_id = p.user_id and p2.date = p.date
order by score desc, speed asc
limit 1
);
This should be able to take advantage of an index on performance(date, user_id, score, speed).
Is easy using variable to emulate row_number() over (partition by Order by)
Explanation:
First create two variables in the subquery.
Order by user_id so when user change the #rn reset to 1
Order by score desc, speed asc so each row will have a row_number, and the one you want always will have rn = 1
#rn := you change #rn for each row
if you have a new user_id then #rn is set to 1
otherwise #rn is set to #rn+1
SQL Fiddle Demo
SELECT `id`, `date`, `score`, `speed`, `user_id`
FROM (
SELECT *,
#rn := if(#user_id = `user_id`,
#rn + 1 ,
if(#user_id := `user_id`,1,1)
) as rn
FROM Table1
CROSS JOIN (SELECT #user_id := 0, #rn := 0) as param
WHERE date = '2016-11-17'
ORDER BY `user_id`, `score` desc, `speed` asc
) T
where T.rn =1
OUTPUT
For mysql
You can try with a double in subselect and group by
select * from performance
where (user_id, score,speed ) in (
SELECT user_id, max_score, max(speed)
FROM performance
WHERE (user_id, score) in (select user_id, max(score) max_score
from performance
group by user_id)
group by user_id, max_score
);
I need an sql that will give the position of the student ranked in order of marks scored in a specific examtyp e.g. CAT! only.the sql below gives the position of the student but does not distinguish the examtyp.it ranks without considering the examtyp.
res_id admNo stream examtyp termId marks grade points year
1 2129 0 CAT1 1 525 C 62 2013
2 4093 0 CAT1 1 569 B+ 69 2013
3 2129 0 CAT2 1 550 B+ 67 2013
4 4093 0 CAT2 1 556 B+ 68 2013
6 2129 0 FINAL 1 559 B+ 68 2013
7 2129 0 AVERAGE 1 545 B 66 2013
7 4093 0 FINAL 1 581 B+ 70 2013
8 4093 0 AVERAGE 1 569 B+ 69 2013
$sql = "SELECT 1 + (SELECT count(*) FROM $table a
WHERE a.total_marks > b.total_marks ) AS rank
FROM $table b WHERE admNo=? AND examCategory=? AND termId=? AND year=?
ORDER BY rank LIMIT 1";
$res = $this->db->query($sql, array($admNo, $examCategory, $term, $year));
This should work for you:
SELECT res_ID,
admNo,
stream,
examtyp,
termId,
grade,
points,
`year`,
Position
FROM ( SELECT #r:= CASE WHEN #e = examtyp THEN #r + CASE WHEN #p = points THEN 0 ELSE #i END ELSE 1 END Position,
#i:= CASE WHEN #p = points THEN #i + 1 ELSE 1 END incr,
#e:= Examtyp,
#p:= points,
res_ID,
admNo,
stream,
examtyp,
termId,
grade,
points,
`year`
FROM T,
(SELECT #e:= '') e,
(SELECT #r:= 0) r,
(SELECT #p:= 0) p,
(SELECT #i:= 0) i
ORDER BY examtyp, points
) T
WHERE T.admNo = 4093
AND T.Examtyp = 'CAT1'
It uses the same principle of using variables that has been suggested, however also partitions by examtyp, resetting the position to 0 for each new exam type, it also records the previous points to deal with ties, so if 3 people get the same mark they all get the same position.
Example on SQL Fiddle
Note in the bottom pane of the fiddle the results for AVERAGE are equal so both get position = 1
Try the Query
SET #rank=0;
select
#rank := #rank+1 AS rank
result_id,
marks_scored,
admNo,
Aggregate_points,
year
from tale_name
order by marks_scored DESC
Try this query
Query 1:
select
#rn:=if(#prv=examtyp, #rn+1, 1) as rId,
admNo,
#prv:=examtyp as exmtyp,
marks
from table1
join
(select #rn:=0,#prv:='') tmp
order by exmtyp, marks desc
SQL FIDDLE:
| RID | ADMNO | EXMTYP | MARKS |
---------------------------------
| 1 | 4093 | AVERAGE | 569 |
| 2 | 2129 | AVERAGE | 545 |
| 1 | 4093 | CAT1 | 569 |
| 2 | 2129 | CAT1 | 525 |
| 1 | 4093 | CAT2 | 556 |
| 2 | 2129 | CAT2 | 550 |
| 1 | 4093 | FINAL | 581 |
| 2 | 2129 | FINAL | 559 |
EDIT
Query 1:
select * from (
select
#rn:= #rn+1 as rId,
admNo,
examtyp,
marks
from table1
join
(select #rn:=0) tmp
where examtyp='CAT1'
order by examtyp, marks desc
) tmp where tmp.admNo=2129
SQL FIDDLE:
| RID | ADMNO | EXAMTYP | MARKS |
---------------------------------
| 2 | 2129 | CAT1 | 525 |
try this -
SELECT q1.rownum
FROM
(
SELECT *, #rownum:=#rownum + 1 AS rownum
FROM $table t, (SELECT #rownum:=0) r
WHERE examtyp = 'CAT1'
ORDER BY marks
) q1
WHERE q1.admNo=?
2) Since you modified the requirement to get equal ranks for same marks, u might need to do something like this -
SELECT q1.rownum
FROM
(
SELECT *, #rownum:=#rownum + 1 AS rownum
FROM
(SELECT DISTINCT marks FROM table1 t WHERE t.examtyp = 'CAT1' ORDER BY t.marks) q2,
(SELECT #rownum:=0) r
) q1,
table1 t2
WHERE
t2.examtyp = 'CAT1'
AND t2.marks=q1.marks
AND t2.admNo=?;
Above, you need to change examCategory at two places.
This is not the most optimized query..but it will do ur work.
3) as per your third requirement to get incremented count of next student, this might do the trick -
SELECT ROWNUM
FROM
(
SELECT q1.marks, min(q1.rownum) AS rownum
FROM
(
SELECT t1.marks, #rownum:=#rownum + 1 AS rownum
FROM
table1 t1,
(SELECT #rownum:=0) r
WHERE
t1.examtyp='CAT1'
ORDER BY t1.marks asc
) q1
GROUP BY q1.marks
) q2,
table1 t2
WHERE
t2.examtyp = 'CAT1'
AND t2.marks=q2.marks;
AND t2.admNo=?;
I wnat to draw a pie chart with MySQL data. I need to retrieve the first n rows and group the rest.
The problem is that the first query is already grouped.
SELECT name AS especie, SUM(superficie) AS superficie
FROM ciclos
JOIN cultivos ON id_cultivo = idcultivo
JOIN tbl_especies ON id_especie = idespecie
WHERE fecha_cierre IS NULL
GROUP BY id_especie
ORDER BY superficie DESC
This is what I get:
+------------+------------+
| Especie | Superficie |
+------------+------------+
| Avena | 50.0000 |
| Centeno | 32.4000 |
| Trigo | 18.0000 |
| Almendros | 5.1100 |
| Olivos | 4.7000 |
| Vid | 1.8300 |
| Nogal | 0.3500 |
| Cerezo | 0.2500 |
+------------+------------+
And this is what I need:
+------------+------------+
| Especie | Superficie |
+------------+------------+
| Avena | 50.0000 |
| Centeno | 32.4000 |
| Trigo | 18.0000 |
| Almendros | 5.1100 |
| Rest | 7.1300 |
+------------+------------+
In this case, I need to retrieve the first 4 rows and group the rest.
Is there any way to solve this with one query?
SOLVED:
I took the #Gordon Linoff concept and mixed it with this.
The problem with the #Gordon Linoff solution, was that the row number were added during the order.
SELECT #rn := #rn + 1 AS rn, SUM(superficie) AS superficie, (CASE WHEN #rn <= 4 THEN name ELSE "Other" END) AS especie
FROM (
SELECT name, SUM(superficie) AS superficie
FROM ciclos
JOIN cultivos ON id_cultivo = idcultivo
JOIN tbl_especies ON id_especie = idespecie
WHERE fecha_cierre IS NULL
GROUP BY id_especie
ORDER BY superficie DESC
) AS temp
CROSS JOIN (SELECT #rn := 0) AS const
GROUP BY (CASE WHEN #rn <= 4 THEN name ELSE "Other" END)
ORDER BY superficie DESC
Hope this helps someone. Thanks for the help.
You can do this with one query, but it requires a subquery (in the end, somehow, you have to group already grouped data). Here is one, MySQL-specific way. It adds a sequence number on the rows using a variable, and then uses that for the grouping:
select (case when rn <= 4 then especie else 'otros' end) as grouping,
sum(superficie) as superficie
from (SELECT name AS especie, SUM(superficie) AS superficie, #rn := #rn + 1 as rn
FROM ciclos
JOIN cultivos ON id_cultivo = idcultivo
JOIN tbl_especies ON id_especie = idespecie
cross join (select #rn := 0) const
WHERE fecha_cierre IS NULL
GROUP BY id_especie
ORDER BY superficie DESC
) t
group by (case when rn <= 4 then especie else 'otros' end)