I am making a Image link to user profile, but it is not working as it should be
this is my code.with this i want to add contoroller,function and id. How i can do it.
<?php
$pic = $User['User']['url'];
if(!$pic){
echo $this->Html->link($this->Html->image('pro.jpg'), array('alt'=>$User['User']['handle'],'title' => $User['User']['handle']),array('escape'=>false) ,array('class'=>'inner_image'));
}else{
echo $this->Html->link($this->Html->image($User['User']['url']),array('alt' => $User['User']['handle']),array('escape'=>false),array('class'=>'inner_image'));
}
?>
This code is making image a link but i can't define a link and it is not accepting the class
.I want to pass this url
$this->Html->link('', array('controller'=>'User','action'=>'view','id'=>$User['User']['id']));
This is how I did it
echo $this->Html->link($this->Html->image($pic, array('class'=>'inner_image')), $url_array, array('alt' => $User['User']['handle'], 'escape'=>false));
What cake version are you using? You don't seem to be following the documentation for Html::link.
HtmlHelper::link(string $title, mixed $url = null, array $options =
array(), string $confirmMessage = false)
alt, escape and class should be indexes in the options array, but you're not defininf the url parameter anywhere.
It should be something like this
if(!$pic){
echo $this->Html->link($this->Html->image('pro.jpg'), $url_array, array('alt'=>$User['User']['handle'],'title' => $User['User']['handle'],'escape'=>false,'class'=>'inner_image'));
} else {
echo $this->Html->link($this->Html->image($User['User']['url']), $url_array, array('alt' => $User['User']['handle'], 'escape'=>false, 'class'=>'inner_image'));
(don't know what url you want to point this at, so replace $url_array to your convenience.
Related
In Yii2 I'm trying to construct hidden input
echo $form->field($model, 'hidden1')->hiddenInput()->label(false);
But I also need it to have some value option, how can I do that ?
Use the following:
echo $form->field($model, 'hidden1')->hiddenInput(['value'=> $value])->label(false);
Changing the value here doesn't make sense, because it's active field. It means value will be synchronized with the model value.
Just change the value of $model->hidden1 to change it. Or it will be changed after receiving data from user after submitting form.
With using non-active hidden input it will be like that:
use yii\helpers\Html;
...
echo Html::hiddenInput('name', $value);
But the latter is more suitable for using outside of model.
simple you can write:
<?= $form->field($model, 'hidden1')->hiddenInput(['value'=>'abc value'])->label(false); ?>
You can do it with the options
echo $form->field($model, 'hidden1',
['options' => ['value'=> 'your value'] ])->hiddenInput()->label(false);
you can also do this
$model->hidden1 = 'your value';// better put it on controller
$form->field($model, 'hidden1')->hiddenInput()->label(false);
this is a better option if you set value on controller
$model = new SomeModelName();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
return $this->redirect(['view', 'id' => $model->group_id]);
} else {
$model->hidden1 = 'your value';
return $this->render('create', [
'model' => $model,
]);
}
Like This:
<?= $form->field($model, 'hidden')->hiddenInput(['class' => 'form-control', 'maxlength' => true,])->label(false) ?>
You can use this code line in view(form)
<?= $form->field($model, 'hidden1')->hiddenInput(['value'=>'your_value'])->label(false) ?>
Please refere this as example
If your need to pass currant date and time as hidden input :
Model attribute is 'created_on' and its value is retrieve from date('Y-m-d H:i:s') ,
just like:"2020-03-10 09:00:00"
<?= $form->field($model, 'created_on')->hiddenInput(['value'=>date('Y-m-d H:i:s')])->label(false) ?>
<?= $form->field($model, 'hidden_Input')->hiddenInput(['id'=>'hidden_Input','class'=>'form-control','value'=>$token_name])->label(false)?>
or
<input type="hidden" name="test" value="1" />
Use This.
You see, the main question while using hidden input is what kind of data you want to pass?
I will assume that you are trying to pass the user ID.
Which is not a really good idea to pass it here because field() method will generate input
and the value will be shown to user as we can't hide html from the users browser. This if you really care about security of your website.
please check this link, and you will see that it's impossible to hide value attribute from users to see.
so what to do then?
See, this is the core of OOP in PHP.
and I quote from Matt Zandstr in his great book PHP Objects, Patterns, and Practice fifth edition
I am still stuck with a great deal of unwanted flexibility, though. I rely on the client coder to change a ShopProduct object’s properties from their default values. This is problematic in two ways. First, it takes five lines to properly initialize a ShopProduct object, and no coder will thank you for that. Second, I have no way of ensuring that any of the properties are set when a ShopProduct object is initialized. What I need is a method that is called automatically when an object is instantiated from a class.
Please check this example of using __construct() method which is mentioned in his book too.
class ShopProduct {
public $title;
public $producerMainName;
public $producerFirstName;
public $price = 0;
public function __construct($title,$firstName,$mainName,$price) {
$this->title = $title;
$this->producerFirstName = $firstName;
$this->producerMainName = $mainName;
$this->price = $price;
}
}
And you can simply do this magic.
$product1 = new ShopProduct("My Antonia","Willa","Cather",5.99 );
print "author: {$product1->getProducer()}\n";
This produces the following:
author: Willa Cather
In your case it will be something semilar to this, every time you create an object just pass the user ID to the user_id property, and save yourself a lot of coding.
Class Car {
private $user_id;
//.. your properties
public function __construct($title,$firstName,$mainName,$price){
$this->user_id = \Yii::$app->user->id;
//..Your magic
}
}
I know it is old post but sometimes HTML is ok :
<input id="model-field" name="Model[field]" type="hidden" value="<?= $model->field ?>">
Please take care
id : lower caps with a - and not a _
name : 1st letter in caps
I am trying to create a form "Movie" as follows and my database accepts movie_id, title, year, and description. When I run the code it tries to store the "array" as the year input. This is the error I get => movie_id, title, year, description) VALUES (NULL, 'Movie1', Array, 'some text')
THE VIEW:
<?php
echo $this->Form->create('Movie'); ?>
<?php echo __('Add Movie'); ?>
<?php
echo $this->Form->hidden('movie_id');
echo $this->Form->input('title');
echo $this->Form->input('year', array(
'type'=>'date',
'dateFormat'=>'Y',
'minYear'=>'1990',
'maxYear'=>date('Y'),
));
echo $this->Form->input('description');
?>
<?php echo $this->Form->end(__('Submit'));
?>
THE CONTROLLER:
public function add() {
if ($this->request->is('post')) {
$this->Movie->create();
if ($this->Movie->save($this->request->data)) {
$this->Session->setFlash(__('The movie has been created'));
$this->redirect (array('action'=>'index'));
}
else {
$this->Session->setFlash(__('The movie could not be created. Please, try again.'));
}
}
}
I believe your problem is here:
$this->Form->input('year', array(
'type'=>'date',
'dateFormat'=>'Y',
'minYear'=>'1990',
'maxYear'=>date('Y'),
));
Instead of it you should use
$this->Form->input('Movie.year', array(
'type'=>'text',
'name' => 'data[Movie][year]',
));
If you don't want to use 'text' type input, then use 'select' with your options array. Here main concern is, Movie.year and overwrite the default CakePHP's naming procedure to 'name' => 'data[Movie][year]'. Check here.
The best thing to do is to debug your $this->request->data.
I'm not sure myself, but I once have this problem. What happen is, when you define an input as a date, it will be behave as an array.
It will become $this->request->data['Movie']['year']['year'];
You can modify the data by doing the following
$this->request->data['Movie']['year'] = $this->request->data['Movie']['year']['year'];
I am developing a REST API using CakePHP and want to implement the Instagram API pagination style which looks something like this:
{
...
"pagination": {
"next_url": "https://api.instagram.com/v1/tags/puppy/media/recent?access_token=fb2e77d.47a0479900504cb3ab4a1f626d174d2d&max_id=13872296",
"next_max_id": "13872296"
}
}
I have not used any authorization or whatever, so the access_token part can be ignored. My main motive is to get the pagination links (jump links preferably) as JSON data, so I can use it in my JSON serialized view. Because the usual code:
echo $this->Paginator->prev('< ' . __('previous'), array(), null, array('class' => 'prev disabled'));
echo $this->Paginator->numbers(array('separator' => ''));
echo $this->Paginator->next(__('next') . ' >', array(), null, array('class' => 'next disabled'));
doesn't work and simply displays the equivalent HTML code.
Is there any way I can get it like the Instagram API?
Thanks to noslone, i have got the answer. here is the final edited code:
$url = 'http://yourapp.com/pages/index/limit:7';
$returnArray = array(
.....
'pagination' => array(
'next_url' => null,
'prev_url' => null
)
);
if($this->Paginator->hasNext()) {
$temp = intval($this->Paginator->current())+1;
$returnArray['pagination']['next_url'] = $url."/page:".$temp;
}
if($this->Paginator->hasPrev()) {
$temp = intval($this->Paginator->current())-1;
$returnArray['pagination']['next_url'] = $url."/page:".$temp;
}
echo json_encode($returnArray);
just two changes : first don't forget to add limit:value" to your url and secondly use intval with the Paginator->current.
Try something as follow
$url = 'http://yourapp.com/pages/index';
$returnArray = array(
.....
'pagination' => array(
'next_url' => null,
'prev_url' => null
)
);
if($this->Paginator->hasNext()) {
$returnArray['pagination']['next_url'] = $url.'/page:'. ($this->Paginator->current()+1);
}
if($this->Paginator->hasPrev()) {
$returnArray['pagination']['prev_url'] = $url.'/page:'. ($this->Paginator->current()-1);
}
echo json_encode($returnArray);
If you want, you can add more named params to the url:
$params['pagination']['next_url'] = $url.'/page:'.$this->Paginator->current()+1.'/order:name/direction:asc';
As far as I know, Paginator helper generates the front-end link, and when you click on it, it will generate next link.
I do not think you can use it directly to form the Instagram alike API.
I am using the Cakephp Google Map V3 Helper. I can get the google map to show up but the markers do not. Here is my view code:
<?php
echo $this->GoogleMapV3->map();
foreach ($allcondos as $condo) {
$options = array(
'lat' => $condo['Unit']['lat'],
'lng' => $condo['Unit']['lon']
);
$this->GoogleMapV3->addMarker($options);
}
?>
I know that if I just tell the app to echo out my $condo['Unit']['lat'] or ['lon'] it will do so in the foreach loop (so it is pulling my data). What I don't know how to do is how to write the code for the $options array. I have also tried this:
foreach ($allcondos as $condo) {
$lat=$condo['Unit']['lat'];
$lon=$condo['Unit']['lon'];
$options = array(
'lat' => $lat,
'lng' => $lon
);
$this->GoogleMapV3->addMarker($options);
}
How do I write this correctly?
A couple easy steps to get this to work:
Download
Download from https://github.com/dereuromark/cakephp-google-map-v3-helper and place the GoogleMapV3Helper.php file in /app/view/helper/GoogleMapV3Helper.php.
Load Helper
Either modify your appcontroller so that the top of it reads like the following:
<?php
class AppController extends Contoller{
public $helpers = array('Html','Javascript','GoogleMapV3');
}
?>
Or load it in a single controller by adding it to the helpers array as such:
<?php
class DemoController extends AppContoller{
function map() {
$this->helpers[] = 'GoogleMapV3';
# rest of your code
}
}
?
Include Scripts
Include Jquery in your header. Include the following as well:
<?php
echo '<script type="text/javascript" src="'.$this->GoogleMapV3->apiUrl().'"></script>';
?>
Create Map Container
Put this in your view where you want your map to appear. Feel free to modify the properties of the div.
<?php echo $this->GoogleMapV3->map(array('div'=>array('id'=>'my_map', 'height'=>'400', 'width'=>'100%'))); ?>
Note: you can change the default position of the map by including more options than just 'div':
<?php echo $this->GoogleMapV3->map(array('map'=>array(
'defaultLat' => 40, # only last fallback, use Configure::write('Google.lat', ...); to define own one
'defaultLng' => -74, # only last fallback, use Configure::write('Google.lng', ...); to define own one
'defaultZoom' => 5,
),'div'=>array('id'=>'my_map', 'height'=>'400', 'width'=>'100%'))); ?>
Add markers
Can be in a loop or whatever, but this is done in the view after your container is created.
<?php
$options = array(
'lat'=>40.770272,
'lng'=>-73.974037,
'title' => 'Some title', # optional
'content' => '<b>HTML</b> Content for the Bubble/InfoWindow' # optional
);
$this->GoogleMapV3->addMarker($options);
?>
note: only set the 'icon' key in the array if you want to use a custom image. Otherwise, they will not show up.
Include the script for the markers
<?php echo $this->GoogleMapV3->script() ?>
All done!
Alternately, you can use finalize() instead of script() if you do not want to echo the javascript right away, but write it to the buffer for later output in your layout:
<?php $this->GoogleMapV3->finalize(); ?>
See http://www.dereuromark.de/2010/12/21/googlemapsv3-cakephp-helper/ for details.
I'm using the WordPress "attachment" feature to allow end users of my theme to upload images that will appear above the post content (not inserted into the post itself).
The only problem I have is that there is not a field to allow the end user to specify the link that should be loaded when the end user clicks on one of the attached images. I'd like to add this field to the post attachment editor (the one that lists the "Gallery" of images attached to the post).
Alternately, and perhaps in addition, I'd like to be able to do the same thing when viewing images via the Media manager listing.
Currently, I'm using the "description" field to store the hyperlink to the image. and retrieving it like so (works perfectly but description is not semantic to link destination):
if ($images = get_children(array('post_parent' => get_the_ID(),'post_type' => 'attachment','post_mime_type' => 'image', 'orderby' => 'menu_order ASC, ID', 'order' => 'DESC' )))
{
foreach( $images as $image ) :
echo "<a href='".$image->post_content."'><img src='".wp_get_attachment_url($image->ID, 'medium')."' /></a>";
endforeach;
}
}
function my_image_attachment_fields_to_edit($form_fields, $post) {
$form_fields["custom1"] = array(
"label" => __("Image Links To"),
"input" => "text", // this is default if "input" is omitted
"value" => get_post_meta($post->ID, "_custom1", true)
);
return $form_fields;
}
function my_image_attachment_fields_to_save($post, $attachment) {
if( isset($attachment['custom1']) ){
update_post_meta($post['ID'], '_custom1', $attachment['custom1']);
}
return $post;
}
add_filter("attachment_fields_to_edit", "my_image_attachment_fields_to_edit", null, 2);
add_filter("attachment_fields_to_save", "my_image_attachment_fields_to_save", null, 2);