How to find duplicate set of mysql ids from bash script - mysql

Question

+---------+-------------+--------------+
|table_uid| group_uid | product_uid |
+---------+-------------+--------------+
| 8901 | 5206 | 184 |
| 8902 | 5206 | 523 |
| 9194 | 5485 | 184 |
| 9195 | 5485 | 523 |
| 7438 | 1885 | 184 |
| 7439 | 1885 | 184 |
+---------+-------------+--------------+
My goal here is to show any group_uids that contain the same exact set of product_uids. So group_uid 5206 and 5485 would end up displaying while 1885 would not since it does not have the same set of product_uids. I have to accomplish this through bash script as I do not have the ability to do this in MySQL 3.23.58 (yes, it's horribly old and I hate it but not my choice). I'm trying to store the table_uid, group_uid and product_uid in an array and then compare each group_uid to see if they contain the same product_uids. Help is appreciated!

Answer 1

How are you displaying the table above?
You might have some success with GROUP_CONCAT Can I concatenate multiple MySQL rows into one field?
SELECT group_uid, GROUP_CONCAT(product_uid,separator ','), count(*)
FROM <tab>
GROUP BY group_uid
HAVING count(*) > 1
I'm not sure how it would order the strings as I don't have mysql at present

Answer 2

Here's a bit of awk to collect the groups that belong to the same set of products:
awk '
NR > 3 && NF == 7 {
prod[$4] = prod[$4] $6 " "
}
END {
for (group in prod)
groups[prod[group]] = groups[prod[group]] group " "
for (key in groups)
print key ":" groups[key]
}
' mysql.out
184 523 :5206 5485
184 184 :1885
If you know which set of product ids you're interested in, you can pass that in:
awk -v prod_ids="184 523" '
NR > 3 && NF == 7 {
prod[$4] = prod[$4] $6 " "
}
END {
for (group in prod)
groups[prod[group]] = groups[prod[group]] group " "
key = prod_ids " "
if (key in groups)
print groups[key]
}
' mysql.out
5206 5485