Cannot resolve table name close to - mysql

I want to create a references to foreign table. but i'm getting the following error:
query:
CREATE TABLE category_ids (id INT, post_id INT,
INDEX par_ind (post_id),
FOREIGN KEY (post_id) REFERENCES post(id)
ON DELETE CASCADE
) ENGINE=INNODB;
SHOW ENGINE INNODB STATUS\G:
------------------------
LATEST FOREIGN KEY ERROR
------------------------
2013-08-23 00:11:06 7f6f49e7b700 Error in foreign key constraint of table fun/category_ids:
FOREIGN KEY (post_id) REFERENCES post(id)
ON DELETE CASCADE
) ENGINE=INNODB:
Cannot resolve table name close to:
(id)
ON DELETE CASCADE
) ENGINE=INNODB
posts table structure
mysql> describe post;
+-------------+-----------------------+------+-----+---------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+-----------------------+------+-----+---------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
...
+-------------+-----------------------+------+-----+---------------------+----------------+
22 rows in set (0.00 sec)

Only InnoDB supports Foreign keys, MyISAM doesn't.
Even if it would, you cannot create relations between tables of different type.
Therefore you need to convert the table post into InnoDB. ALTER TABLE post ENGINE = InnoDB;

This error can also come when parent table is partitioned. Removing partitioning from the parent table allows foreign constraint to be created without any problem.

For me works with this.
CREATE TABLE category_ids (id INT, post_id INT references post(id),
INDEX par_ind (post_id)
) ENGINE=INNODB;

Related

How to add a relation if parent deleted then child should automatically delete in mysql [duplicate]

I want to use foreign keys to keep the integrity and avoid orphans (I already use innoDB).
How do I make a SQL statment that DELETE ON CASCADE?
If I delete a category then how do I make sure that it would not delete products that also are related to other categories.
The pivot table "categories_products" creates a many-to-many relationship between the two other tables.
categories
- id (INT)
- name (VARCHAR 255)
products
- id
- name
- price
categories_products
- categories_id
- products_id
If your cascading deletes nuke a product because it was a member of a category that was killed, then you've set up your foreign keys improperly. Given your example tables, you should have the following table setup:
CREATE TABLE categories (
id int unsigned not null primary key,
name VARCHAR(255) default null
)Engine=InnoDB;
CREATE TABLE products (
id int unsigned not null primary key,
name VARCHAR(255) default null
)Engine=InnoDB;
CREATE TABLE categories_products (
category_id int unsigned not null,
product_id int unsigned not null,
PRIMARY KEY (category_id, product_id),
KEY pkey (product_id),
FOREIGN KEY (category_id) REFERENCES categories (id)
ON DELETE CASCADE
ON UPDATE CASCADE,
FOREIGN KEY (product_id) REFERENCES products (id)
ON DELETE CASCADE
ON UPDATE CASCADE
)Engine=InnoDB;
This way, you can delete a product OR a category, and only the associated records in categories_products will die alongside. The cascade won't travel farther up the tree and delete the parent product/category table.
e.g.
products: boots, mittens, hats, coats
categories: red, green, blue, white, black
prod/cats: red boots, green mittens, red coats, black hats
If you delete the 'red' category, then only the 'red' entry in the categories table dies, as well as the two entries prod/cats: 'red boots' and 'red coats'.
The delete will not cascade any farther and will not take out the 'boots' and 'coats' categories.
comment followup:
you're still misunderstanding how cascaded deletes work. They only affect the tables in which the "on delete cascade" is defined. In this case, the cascade is set in the "categories_products" table. If you delete the 'red' category, the only records that will cascade delete in categories_products are those where category_id = red. It won't touch any records where 'category_id = blue', and it would not travel onwards to the "products" table, because there's no foreign key defined in that table.
Here's a more concrete example:
categories: products:
+----+------+ +----+---------+
| id | name | | id | name |
+----+------+ +----+---------+
| 1 | red | | 1 | mittens |
| 2 | blue | | 2 | boots |
+---++------+ +----+---------+
products_categories:
+------------+-------------+
| product_id | category_id |
+------------+-------------+
| 1 | 1 | // red mittens
| 1 | 2 | // blue mittens
| 2 | 1 | // red boots
| 2 | 2 | // blue boots
+------------+-------------+
Let's say you delete category #2 (blue):
DELETE FROM categories WHERE (id = 2);
the DBMS will look at all the tables which have a foreign key pointing at the 'categories' table, and delete the records where the matching id is 2. Since we only defined the foreign key relationship in products_categories, you end up with this table once the delete completes:
+------------+-------------+
| product_id | category_id |
+------------+-------------+
| 1 | 1 | // red mittens
| 2 | 1 | // red boots
+------------+-------------+
There's no foreign key defined in the products table, so the cascade will not work there, so you've still got boots and mittens listed. There's just no 'blue boots' and no 'blue mittens' anymore.
I got confused by the answer to this question, so I created a test case in MySQL, hope this helps
-- Schema
CREATE TABLE T1 (
`ID` int not null auto_increment,
`Label` varchar(50),
primary key (`ID`)
);
CREATE TABLE T2 (
`ID` int not null auto_increment,
`Label` varchar(50),
primary key (`ID`)
);
CREATE TABLE TT (
`IDT1` int not null,
`IDT2` int not null,
primary key (`IDT1`,`IDT2`)
);
ALTER TABLE `TT`
ADD CONSTRAINT `fk_tt_t1` FOREIGN KEY (`IDT1`) REFERENCES `T1`(`ID`) ON DELETE CASCADE,
ADD CONSTRAINT `fk_tt_t2` FOREIGN KEY (`IDT2`) REFERENCES `T2`(`ID`) ON DELETE CASCADE;
-- Data
INSERT INTO `T1` (`Label`) VALUES ('T1V1'),('T1V2'),('T1V3'),('T1V4');
INSERT INTO `T2` (`Label`) VALUES ('T2V1'),('T2V2'),('T2V3'),('T2V4');
INSERT INTO `TT` (`IDT1`,`IDT2`) VALUES
(1,1),(1,2),(1,3),(1,4),
(2,1),(2,2),(2,3),(2,4),
(3,1),(3,2),(3,3),(3,4),
(4,1),(4,2),(4,3),(4,4);
-- Delete
DELETE FROM `T2` WHERE `ID`=4; -- Delete one field, all the associated fields on tt, will be deleted, no change in T1
TRUNCATE `T2`; -- Can't truncate a table with a referenced field
DELETE FROM `T2`; -- This will do the job, delete all fields from T2, and all associations from TT, no change in T1
I think (I'm not certain) that foreign key constraints won't do precisely what you want given your table design. Perhaps the best thing to do is to define a stored procedure that will delete a category the way you want, and then call that procedure whenever you want to delete a category.
CREATE PROCEDURE `DeleteCategory` (IN category_ID INT)
LANGUAGE SQL
NOT DETERMINISTIC
MODIFIES SQL DATA
SQL SECURITY DEFINER
BEGIN
DELETE FROM
`products`
WHERE
`id` IN (
SELECT `products_id`
FROM `categories_products`
WHERE `categories_id` = category_ID
)
;
DELETE FROM `categories`
WHERE `id` = category_ID;
END
You also need to add the following foreign key constraints to the linking table:
ALTER TABLE `categories_products` ADD
CONSTRAINT `Constr_categoriesproducts_categories_fk`
FOREIGN KEY `categories_fk` (`categories_id`) REFERENCES `categories` (`id`)
ON DELETE CASCADE ON UPDATE CASCADE,
CONSTRAINT `Constr_categoriesproducts_products_fk`
FOREIGN KEY `products_fk` (`products_id`) REFERENCES `products` (`id`)
ON DELETE CASCADE ON UPDATE CASCADE
The CONSTRAINT clause can, of course, also appear in the CREATE TABLE statement.
Having created these schema objects, you can delete a category and get the behaviour you want by issuing CALL DeleteCategory(category_ID) (where category_ID is the category to be deleted), and it will behave how you want. But don't issue a normal DELETE FROM query, unless you want more standard behaviour (i.e. delete from the linking table only, and leave the products table alone).

How delete cascade with mysql [duplicate]

I want to use foreign keys to keep the integrity and avoid orphans (I already use innoDB).
How do I make a SQL statment that DELETE ON CASCADE?
If I delete a category then how do I make sure that it would not delete products that also are related to other categories.
The pivot table "categories_products" creates a many-to-many relationship between the two other tables.
categories
- id (INT)
- name (VARCHAR 255)
products
- id
- name
- price
categories_products
- categories_id
- products_id
If your cascading deletes nuke a product because it was a member of a category that was killed, then you've set up your foreign keys improperly. Given your example tables, you should have the following table setup:
CREATE TABLE categories (
id int unsigned not null primary key,
name VARCHAR(255) default null
)Engine=InnoDB;
CREATE TABLE products (
id int unsigned not null primary key,
name VARCHAR(255) default null
)Engine=InnoDB;
CREATE TABLE categories_products (
category_id int unsigned not null,
product_id int unsigned not null,
PRIMARY KEY (category_id, product_id),
KEY pkey (product_id),
FOREIGN KEY (category_id) REFERENCES categories (id)
ON DELETE CASCADE
ON UPDATE CASCADE,
FOREIGN KEY (product_id) REFERENCES products (id)
ON DELETE CASCADE
ON UPDATE CASCADE
)Engine=InnoDB;
This way, you can delete a product OR a category, and only the associated records in categories_products will die alongside. The cascade won't travel farther up the tree and delete the parent product/category table.
e.g.
products: boots, mittens, hats, coats
categories: red, green, blue, white, black
prod/cats: red boots, green mittens, red coats, black hats
If you delete the 'red' category, then only the 'red' entry in the categories table dies, as well as the two entries prod/cats: 'red boots' and 'red coats'.
The delete will not cascade any farther and will not take out the 'boots' and 'coats' categories.
comment followup:
you're still misunderstanding how cascaded deletes work. They only affect the tables in which the "on delete cascade" is defined. In this case, the cascade is set in the "categories_products" table. If you delete the 'red' category, the only records that will cascade delete in categories_products are those where category_id = red. It won't touch any records where 'category_id = blue', and it would not travel onwards to the "products" table, because there's no foreign key defined in that table.
Here's a more concrete example:
categories: products:
+----+------+ +----+---------+
| id | name | | id | name |
+----+------+ +----+---------+
| 1 | red | | 1 | mittens |
| 2 | blue | | 2 | boots |
+---++------+ +----+---------+
products_categories:
+------------+-------------+
| product_id | category_id |
+------------+-------------+
| 1 | 1 | // red mittens
| 1 | 2 | // blue mittens
| 2 | 1 | // red boots
| 2 | 2 | // blue boots
+------------+-------------+
Let's say you delete category #2 (blue):
DELETE FROM categories WHERE (id = 2);
the DBMS will look at all the tables which have a foreign key pointing at the 'categories' table, and delete the records where the matching id is 2. Since we only defined the foreign key relationship in products_categories, you end up with this table once the delete completes:
+------------+-------------+
| product_id | category_id |
+------------+-------------+
| 1 | 1 | // red mittens
| 2 | 1 | // red boots
+------------+-------------+
There's no foreign key defined in the products table, so the cascade will not work there, so you've still got boots and mittens listed. There's just no 'blue boots' and no 'blue mittens' anymore.
I got confused by the answer to this question, so I created a test case in MySQL, hope this helps
-- Schema
CREATE TABLE T1 (
`ID` int not null auto_increment,
`Label` varchar(50),
primary key (`ID`)
);
CREATE TABLE T2 (
`ID` int not null auto_increment,
`Label` varchar(50),
primary key (`ID`)
);
CREATE TABLE TT (
`IDT1` int not null,
`IDT2` int not null,
primary key (`IDT1`,`IDT2`)
);
ALTER TABLE `TT`
ADD CONSTRAINT `fk_tt_t1` FOREIGN KEY (`IDT1`) REFERENCES `T1`(`ID`) ON DELETE CASCADE,
ADD CONSTRAINT `fk_tt_t2` FOREIGN KEY (`IDT2`) REFERENCES `T2`(`ID`) ON DELETE CASCADE;
-- Data
INSERT INTO `T1` (`Label`) VALUES ('T1V1'),('T1V2'),('T1V3'),('T1V4');
INSERT INTO `T2` (`Label`) VALUES ('T2V1'),('T2V2'),('T2V3'),('T2V4');
INSERT INTO `TT` (`IDT1`,`IDT2`) VALUES
(1,1),(1,2),(1,3),(1,4),
(2,1),(2,2),(2,3),(2,4),
(3,1),(3,2),(3,3),(3,4),
(4,1),(4,2),(4,3),(4,4);
-- Delete
DELETE FROM `T2` WHERE `ID`=4; -- Delete one field, all the associated fields on tt, will be deleted, no change in T1
TRUNCATE `T2`; -- Can't truncate a table with a referenced field
DELETE FROM `T2`; -- This will do the job, delete all fields from T2, and all associations from TT, no change in T1
I think (I'm not certain) that foreign key constraints won't do precisely what you want given your table design. Perhaps the best thing to do is to define a stored procedure that will delete a category the way you want, and then call that procedure whenever you want to delete a category.
CREATE PROCEDURE `DeleteCategory` (IN category_ID INT)
LANGUAGE SQL
NOT DETERMINISTIC
MODIFIES SQL DATA
SQL SECURITY DEFINER
BEGIN
DELETE FROM
`products`
WHERE
`id` IN (
SELECT `products_id`
FROM `categories_products`
WHERE `categories_id` = category_ID
)
;
DELETE FROM `categories`
WHERE `id` = category_ID;
END
You also need to add the following foreign key constraints to the linking table:
ALTER TABLE `categories_products` ADD
CONSTRAINT `Constr_categoriesproducts_categories_fk`
FOREIGN KEY `categories_fk` (`categories_id`) REFERENCES `categories` (`id`)
ON DELETE CASCADE ON UPDATE CASCADE,
CONSTRAINT `Constr_categoriesproducts_products_fk`
FOREIGN KEY `products_fk` (`products_id`) REFERENCES `products` (`id`)
ON DELETE CASCADE ON UPDATE CASCADE
The CONSTRAINT clause can, of course, also appear in the CREATE TABLE statement.
Having created these schema objects, you can delete a category and get the behaviour you want by issuing CALL DeleteCategory(category_ID) (where category_ID is the category to be deleted), and it will behave how you want. But don't issue a normal DELETE FROM query, unless you want more standard behaviour (i.e. delete from the linking table only, and leave the products table alone).

mysql foreign key error #1452

ALTER TABLE `groups` ADD FOREIGN KEY ( `company_id` ) REFERENCES `summaries`.`companies` (
`id`
) ON DELETE CASCADE ;
MySQL said:
#1452 - Cannot add or update a child row: a foreign key constraint fails (`summaries/#sql-164a_33c`, CONSTRAINT `#sql-164a_33c_ibfk_1` FOREIGN KEY (`company_id`) REFERENCES `companies` (`id`) ON DELETE CASCADE)
companies.id is primary auto increment int(11)
company_id is index int(11)
I don't understand the error message. Can anyone shed some light on this?
That means you have at least one row in the child table that references a non-existent row in the parent table.
If you are absolutely sure that you are okay with having a data integrity issue like that, you can add the foreign key by disabling foreign key checks before you run the ALTER TABLE command:
SET FOREIGN_KEY_CHECKS = 0;
I just had this problem, although in a somewhat more specific scenario.
In my case, I had added, to an existing table, a column that I needed to be both nullable and act as a foreign key (i.e., for non-null entries to be bound by a foreign key constraint).
The referenced column looked like this:
+-------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+-------------+------+-----+---------+----------------+
| id | int(10) | NO | PRI | NULL | auto_increment |
+-------------+-------------+------+-----+---------+----------------+
and the referencing one like this:
+-------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+-------------+------+-----+---------+----------------+
| bed_id | int(10) | YES | | NULL | |
+-------------+-------------+------+-----+---------+----------------+
Turned out that I had forgotten to specify DEFAULT NULL when adding the referencing column to the existing table and so it was automatically filled with zeros, which failed the foreign key constraint.
I changed them to NULL:
update devices set bed_id = NULL where bed_id = 0;
and then successfully added the foreign key constraint. Hope this helps someone
It looks like it tried to copy the groups table to a temp table in the summaries database.
MySQL tried to put the requested constraints on the temp table first. There may possibly be one or more rows in the groups table (hence the temp table also) whose company_id is no longer present in the summaries.companies table.
To verfiy : Try running a LEFT JOIN between groups and summaries.companies WHERE companies.id is NULL. If you get back any rows from that LEFT JOIN, you found the bad rows in the groups table.
Give it a Try !!!
Checks that "companies" table is not empty,if is empty and you have no data at moment.
set SET FOREIGN_KEY_CHECKS = 0;
like Ike said you before.

mysql foreign key concept

CREATE TABLE parent (id INT NOT NULL,
PRIMARY KEY (id)
) ENGINE=INNODB;
CREATE TABLE child (id INT, parent_id INT,
INDEX par_ind (parent_id),
FOREIGN KEY (parent_id) REFERENCES parent(id)
ON DELETE CASCADE
) ENGINE=INNODB;
I dont understand the meaning of putting ENGINE = INNODB here, and why do we use ON DELETE CASCADE?
engine=innodb will ensure you get foreign key support. The default MyISAM engine doesn't support foreign keys. On delete cascade will remove the child row if the referenced row in the parent table is removed.
MySQL is the DB engine. It can use multiple storage engines. MyISAM is the default storage engine for MySQL and it does not support foreign keys. InnoDB is another storage engine that does support foreign keys. You must specify ENGINE=InnoDB because MySQL will use MyISAM by default.
ON DELETE CASCADE will delete all rows in a table that have a foreign key that references a key that is deleted. I think it is dangerous and defeats a lot of the purpose of foreign key restriction, so I would avoid using it, but this is just my personal opinion.
Say you have:
+-------+-------+
| ordID | proID |
+-------+-------+
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 2 |
| 5 | 2 |
+-------+-------+
And on OrdersItems it has FOREIGN KEY (proID) REFERENCES Products (proID) ON DELETE CASCADE.
Then if someone runs
DELETE FROM Products WHERE proID = 2
Then rows with ordID 4 and 5 will also be deleted (it cascades).

Working with foreign keys - cannot insert

Doing my first tryouts with foreign keys in a mySQL database and are trying to do a insert, that fails for this reason: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails
Does this mean that foreign keys restrict INSERTS as well as DELETES and/or UPDATES on each table that is enforced with foreign keys relations?
Thanks!
Updated description:
Products
----------------------------
id | type
----------------------------
0 | 0
1 | 3
ProductsToCategories
----------------------------
productid | categoryid
----------------------------
0 | 0
1 | 1
Product table has following structure
CREATE TABLE IF NOT EXISTS `alpha`.`products` (
`id` MEDIUMINT UNSIGNED NOT NULL AUTO_INCREMENT ,
`type` TINYINT(2) UNSIGNED NOT NULL DEFAULT 0 ,
PRIMARY KEY (`id`) ,
CONSTRAINT `funkyfunky`
FOREIGN KEY (`id` )
REFERENCES `alpha`.`ProductsToCategories` (`productid` )
ON DELETE CASCADE,
ON UPDATE CASCADE)
ENGINE = InnoDB;
Your insert is failing because the foreign key in the row you are inserting doesn't match a valid key in the constraint table. For example:
Assume you've got these two tables:
Employees
----------------------------
EmpID | Name
----------------------------
0 | John
1 | Jane
OfficeAssignments
----------------------------
OfficeID | EmpID
----------------------------
0 | 0
1 | 1
If you have a foreign key constraint on OfficeAssignments.EmpID -> Employees.EmpID, and you try to execute:
INSERT INTO OfficeAssignments (OfficeID, EmpID) VALUES (2,2)
The statement will fail because there is no entry in the Employees table with an EmpID of 2.
Constraints are designed to ensure that your dependent table always has valid data with regard to the parent table -- in this example, you will never have an office which is listed as assigned to an employee who doesn't exist in the system, either because they never existed (as in this case) or because they've been deleted (because the constraint will prevent the employee record from being deleted until the office assignment record has been deleted first).
Edit: Now that you've posted the constraint, it indeed looks like it might be set up backwards. By placing the constraint in the definition of the Products table, you are making it the child, and ProductsToCategories the parent. The constraint you've written can be read as, "a Product must be assigned to a category before it can be created". I suspect what you meant is the other way around: "a Product must be created before it can be assigned to a category." To get that result, you need to place the constraint on the ProductsToCategories table, setting the foreign key to productid and referencing Products.id.
You cannot delete a row from the parent table while there is a foreign key reference to it from a child table. Also you cannot insert/update in the child table with invalid id's in the foreign key column.
Edit: The "CONSTRAINT funkyfunky FOREIGN KEY (id)" must be declared in the "ProductsToCategories" table not in the "Products" table, because "ProductsToCategories" is referencing "Products" not the opposite as you have did.
Your products table is slightly wrong, as you don't need to reference anything from it. References go in the "other" tables, and point to the main, e.g:
create table products (
id int auto_increment,
type int,
primary key (id)
);
create table categories (
id int auto_increment,
name varchar(128),
primary key (id)
)
create table products_to_categories (
product_id int references products,
category_id int references categories
);
A foreign key enforces a valid relation between the rows in two tables. In order to be able to insert a row into a table containing a foreign key, there must be a row in the referenced table containing that key or the insert will fail. The same with delete, you can't delete the row in the referenced table while there are still rows in the table with the foreign key that still reference it. The prevents ending up with rows in the dependent table that have data, but don't have associated rows in the referenced table, i.e., a violation of referential integrity.