How to select an "AS field" in MySql? - mysql

I have a Query which is separated in different parts. (distance, score and rank)
SELECT Entry.*, Address.*,
(6367.41 * SQRT(2 * (1-cos(RADIANS(Entry.latitude)) * cos(0.92640848333131) * (sin(RADIANS(Entry.longitude)) * sin(0.15361853481704) + cos(RADIANS(Entry.longitude)) * cos(0.15361853481704)) - sin(RADIANS(Entry.latitude)) * sin(0.92640848333131))))
AS distance,
(CASE WHEN `Entry`.`title` LIKE '%%' THEN 50 ELSE 0 END +
CASE WHEN `Entry`.`description` LIKE '%%' THEN 30 ELSE 0 END +
CASE WHEN `Entry`.`description_long` LIKE '%%' THEN 10 ELSE 0 END +
CASE WHEN `Entry`.`product_type` = 1 THEN 0 ELSE 0 END +
CASE WHEN `Entry`.`product_type` = 2 THEN 40 ELSE 0 END +
CASE WHEN `Entry`.`product_type` = 3 THEN 50 ELSE 0 END )
AS score,
(CASE WHEN (score > 100 AND distance <= 10) THEN 1 ELSE 0 END)
rank
FROM `usr_web12_1`.`entries` AS `Entry`
inner JOIN `usr_web12_1`.`entrieslocations` AS `Entrieslocation` ON (`Entry`.`id` = `Entrieslocation`.`entry_id`)
inner JOIN `usr_web12_1`.`addresses` AS `Address` ON (`Address`.`id` = `Entry`.`address_id`)
WHERE ((`Entry`.`title` LIKE '%%') OR (`Entry`.`description` LIKE '%%') OR (`Entry`.`description_long` LIKE '%%') OR (`Entry`.`meta_keywords` LIKE '%%') OR (`Entry`.`filter_keywords` LIKE '%%')) AND `Entry`.`status` = 1 AND
`Entry`.`latitude` Between 52.179974594081 AND 53.978617805919 AND `Entry`.`longitude` Between 7.3045938084915 AND 10.298793591508 AND `Entrieslocation`.`category_id` = 1
GROUP BY `Entry`.`id`
ORDER BY `Entry`.`product_type` desc
LIMIT 10
Question: The rank-part doesn't work "Column not found: 1054 Unknown column 'score' in 'field list'", how can I access a dynamic AS-Field???
Same problem with distance...
Thanks a lot!

You can't use an aliased column name in the select or where clause.
You could use it later in the group by, order by, having clause. See the MySQL doc for that.

Related

SQL count when value = 1

I'm doing a select on two tables with this:
SELECT m.torneio, m.deck, m.top, m.lugar, sum( m.quantidade ) AS quantidade, m.formato AS formato, q.quantidade AS qtorneio, t.season AS season, sum( m.top ) AS totaltops, count( m.lugar = '1' ) AS venceu
FROM `metagame` AS m, quantidade AS q, torneios AS t
WHERE m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY m.deck
My problem is that venceu is counting all instances instead of only the ones when lugar = 1. Why is that?
tried with sum() too with no good results too. How can i fix this?
I am surprised that count( m.lugar = '1' ) syntaxs but it does and returns the sames as count(*). You should probably change it to sum(case when lugar = 1 else 0 end) as venceu. You should also look closely at the group by to be sure it works as you expect (i suspect not).
count(x) does not accept an expression.
It's only counting how many times x is returned.
What you should do is check if m.lugar is 1 and yes add one to the counter else do nothing.
Inline checks can be done like so:
case when m.lugar = '1' then 1 else 0 end
Then add all the one you gets :
sum(case when m.lugar = '1' then 1 else 0 end)
Your final query should look like this:
SELECT
m.torneio,
m.deck,
m.top,
m.lugar,
sum( m.quantidade ) AS quantidade,
m.formato AS formato,
q.quantidade AS qtorneio,
t.season AS season,
sum( m.top ) AS totaltops,
sum(case when m.lugar = '1' then 1 else 0 end) AS venceu
FROM
`metagame` AS m,
quantidade AS q,
torneios AS t
WHERE
m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY
m.deck
If I understand your question you can use this:
sum(case when m.lugar = '1' then 1 else 0 end)
or you can try having clause
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);

Multiplying CASE row with different values

I'm creating a rating system. I have two tables hinne (rating) and hinnang (rating multiplier). I need to multiply the rating and then average the rating to know what rating I got out of all ratings by aine(subject).
Example:
All points need to be calculated in 0-100 point system.
So if my first rate is 25 and the rating multiplier is 4 then first rate (25/25)
4*25=100
If the second rate is 30 and multiplier 2 then second rate (30/50)
2*30=60
Now I need to average them like 100+60/2=80.
That should work in my SQL statement, but I got in trouble.
CASE
WHEN aine.nimetus = 'Füüsika I'
THEN hinne.tulemus * hindamine.kaal
ELSE 0
END
,0)
))
So, this is my pivot case statement. hindamine.kaal should be different value for each hinne.tulemus 25*4,50*2 BUT it doesn't work. It just uses multiplier value 4. How can I make this work?
The result of SQL: 150
The expected result: 100
Therefore here is my full SQL:
SELECT
tudeng.m_number,hindamine.kaal, ROUND(AVG(NULLIF(
CASE
WHEN aine.nimetus = 'Füüsika I'
THEN hinne.tulemus * hindamine.kaal
ELSE 0
END
,0)
))
AS FüüsikaI ,ROUND(AVG(NULLIF(
CASE
WHEN aine.nimetus = 'Kõrgem matemaatika I'
THEN hinne.tulemus * hindamine.kaal
ELSE 0
END
,0)
))
AS KõrgemmatemaatikaI ,ROUND(AVG(NULLIF(
CASE
WHEN aine.nimetus = 'Raalprojekteerimine'
THEN hinne.tulemus * hindamine.kaal
ELSE 0
END
,0)
))
AS Raalprojekteerimine ,ROUND(AVG(NULLIF(
CASE
WHEN aine.nimetus = 'Tehniline graafika'
THEN hinne.tulemus * hindamine.kaal
ELSE 0
END
,0)
))
AS Tehnilinegraafika , ROUND(AVG(NULLIF(
CASE
WHEN aine.nimetus = 'Ettevõteluse alused'
THEN hinne.tulemus * hindamine.kaal
ELSE 0
END
,0)
))
AS Ettevõtelusealused
FROM
tudeng
INNER JOIN
aine_tudeng
ON
tudeng.tudeng_id = aine_tudeng.tudeng_id
INNER JOIN
aine
ON
aine.aine_id = aine_tudeng.aine_id
INNER JOIN
hinne
ON
hinne.aine_tudeng_id=aine_tudeng.aine_tudeng_id
INNER JOIN
hindamine
ON
hindamine.hindamine_id=aine_tudeng.aine_id
GROUP BY
tudeng.m_number
I suppose your error is here:
ON hindamine.hindamine_id = aine_tudeng.aine_id
A hindamine (assessment/rating?) is something different from an aine (subject?), so you are mistaken in joining on these IDs.
(I have used Google translator to help me with the meanings.)

MySQL Query Case

This is my code, i have 2 columns - Modem = String, Total = Integer
SELECT `Modem`, `Total`,
CASE `Modem` WHEN 'Yes' THEN
(`Total`+ 50)
ELSE
(`Total`+ 0)
END AS ModemAndTotal
FROM invoices
I need when Modem = "Yes" add 50 to total (Total + 50)
Try something like:
SELECT `Modem`, `Total`, CASE WHEN `Modem` = 'Yes' THEN (`Total`+ 50)
ELSE
`Total`
END AS ModemAndTotal
FROM invoices

how to get SUM() of COUNT() column in MySQL

i have the following query, tried using case statement
SELECT t.inst_id, t.inst_username, tcm.city_name,
SUM(CASE WHEN psb.pms_student_bucket_id IS NULL THEN 1 ELSE 0 END) AS not_assiged,
SUM(CASE WHEN COUNT(psb.pms_student_bucket_id) BETWEEN 1 AND 50 THEN 1 ELSE 0 END) AS '1-50',
SUM(CASE WHEN COUNT(psb.pms_student_bucket_id) > 50 THEN 1 ELSE 0 END) AS ' > 50'
FROM tbl_si_di t
JOIN tbl_city_master tcm ON tcm.city_id = t.city_ref_id
JOIN tbl_si_students tss ON tss.inst_ref_id = t.inst_id
LEFT JOIN pms_student_bucket psb ON psb.user_ref_id = tss.user_ref_id
GROUP BY t.inst_id;
I need SUM of pms_student_bucket_id column when their COUNT is '1-50' and '>50'. Right now this query is saying Invalid use of group function.
How would I SUM on COUNT of "pms_student_bucket_id" equals/between some value in mysql?
you could put it in a subquery
SELECT inst_id, inst_username, city_name,
SUM(pms_student_bucket_id IS NULL ) AS not_assiged,
SUM(num_bucket >=10 AND num_bucket <= 20) AS '10 - 20'
SUM(num_bucket <= 50) AS '1-50',
SUM(num_bucket > 50) AS ' > 50'
FROM
( SELECT t.inst_id, t.inst_username, tcm.city_name,psb.pms_student_bucket_id,
COUNT(psb.pms_student_bucket_id) as num_bucket
FROM tbl_si_di t
JOIN tbl_city_master tcm ON tcm.city_id = t.city_ref_id
JOIN tbl_si_students tss ON tss.inst_ref_id = t.inst_id
LEFT JOIN pms_student_bucket psb ON psb.user_ref_id = tss.user_ref_id
GROUP BY t.inst_id
)t1
GROUP BY inst_id;
note you can use the boolean values returned to do what you want.. aka you don't need a case statement, the boolean value returns a 1 or 0 which can then be summed..

SQL ORDER BY query

I want to have my table,rcarddet, ordered by "SDNO" (not primary key) in ascending order with the exception of "0". So it should turn out to be like:
1
1
2
.
.
10
0
0
My query now is:
SELECT *
FROM `rcarddet`
WHERE `RDATE` = '2011-05-25'
AND `RCNO` = '1'
AND `PLACE` = 'H'
AND `SDNO` != 0
ORDER BY `rcarddet`.`SDNO` ASC;
The easiest way
SELECT * FROM rcarddet
WHERE RDATE = '2011-05-25' and RCNO = '1'and PLACE = 'H'
ORDER BY CASE
WHEN rcarddet.SDNO = 0 THEN [max_number_for_the_type_of_SDNO]
ELSE rcarddet.SDNO
END ASC
SELECT *
FROM `rcarddet`
WHERE `RDATE` = '2011-05-25'
AND `RCNO` = '1'
AND `PLACE` = 'H'
ORDER BY
`SDNO` = 0,
`SDNO`;