I have a bunch of regular expressions in a MySQL table. I want to know whether a given string matches a part of any regular expression or not.
Eg:
+----+--------------------------------+
| id | regexps |
+----+--------------------------------+
| 1 | foo-[0-9]*\.example\.com |
| 2 | (bar|tux)-[0-9]*\.example\.com |
+----+--------------------------------+
(The regexps attribute is of VARCHAR type)
foo-11.example.com matches the first regexp.
I want a MySQL query that returns the first row with the given string as foo-11
This should do it on MySql:
select * from table t where 'foo-11.example.com' rlike t.data;
There are other ways in PostGreSQL. Here's the link from where I have referenced this:
http://www.tutorialspoint.com/mysql/mysql-regexps.htm
Match a Query to a Regular Expression in SQL?
PS: Using * is tricky though!
Related
Been struggling for this for awhile.
Is there a way to find all rows in my table where the word in the column 'word' is a part of a search word?
+---------+-----------------+
| id_word | word |
+---------+-----------------+
| 177041 | utvälj |
| 119270 | fonders |
| 39968 | flamländarens |
| 63567 | hänvisningarnas |
| 61244 | hovdansers |
+---------+-----------------+
I want to extract the row 119270, fonders. I want to do this by passing in the word 'plafonders'.
SELECT * FROM words WHERE word REGEXP 'plafonders$'
That query will of course not work in this case, would've been perfect if it had been the other way around.
Does anyone know a solution to this?
SELECT * FROM words WHERE 'plafonders' REGEXP concat(word, '$')
should accomplish what you want. Your regex:
plafonders$
is looking for plafonders at the end of the column. This is looking for everything the column has until its end, e.g. the regexp is fonders$ for 119270.
See https://regex101.com/r/Ytb3kg/1/ compared to https://regex101.com/r/Ytb3kg/2/.
MySQL's REGEXP does not handle accented letters very well. Perhaps it will work OK in your limited situation.
Here's a slightly faster approach (though it still requires a table scan):
SELECT * FROM words
WHERE 'PLAutvälj' =
RIGHT('PLAutvälj', CHAR_LENGTH(word)) = word;
(To check the accents, I picked a different word from your table.)
I have a table that looks like this
+------+------------------------------------+
| id | details |
+------+------------------------------------+
| 1 | {"price":"24.99","currency":"USD"} |
+------+------------------------------------+
Is it possible to, with a single MySQL select statement, obtain the value of price 24.99?
Yes, you can using JSON_EXTRACT
It probably should be like:
SELECT JSON_EXTRACT(details, "$.price")
FROM table_name
or another form:
SELECT details->"$.price"
FROM table_name
(I don't have MySql to test it)
Note that the price in your JSON stored as a string, not a number and you probably would want to cast it to a DECIMAL.
I'm trying to isolate some tables in a mysql database that match a pattern which can be described as
some-name_10-digit timestamp
eg:
| oxseohistory_1381393508 |
| oxseohistory_1382427650 |
| oxseohistory_1382617597 |
Is there a way to use a regular expression which matches everything with 10 digits at the end? Like this one?
\d{10}$
I tried
SHOW TABLES FROM `usrdb_xxxx` WHERE `Tables_in_usrdb_xxxx` RLIKE '\d{10}$';
which did not work (empty set).
As MySQL does not support \d, you can use
[[:digit:]]{10}$
Or
[0-9]{10}$
I have a SQL table with the following values:
+---------+----------+
| post_id | path |
+---------+----------+
| 1 | 1/ |
| 2 | 1/2/ |
| 3 | 1/2/3/ |
| 4 | 1/2/3/4/ |
| 5 | 1/2/5/ |
+---------+----------+
How can I create a query that would get the path with the exact number of values separated by slashes?
For example, if I wanted all post_ids where the path is exactly 1/%/%/ (where each % represents a single number), meaning return anything of the form 1/2/3/, 1/2/5/, but not 1/2/3/4/.
Here's one option using regexp:
select *
from yourtable
where path regexp '1/[0-9]/[0-9]/$'
SQL Fiddle Demo
There are several ways to do that:
MySQL LIKE operator.
The LIKE operator provides two wildcard characters, the percentage % ( match any string of zero or more characters), and underscore _ ( match any single character ).
SELECT * FROM `table` WHERE `path` LIKE '1/_/_/'
SELECT * FROM `table` WHERE `path` LIKE '1/%/%/'
MySQL Regular Expressions.
SELECT * FROM `table` WHERE `path` regexp '^1/[0-9]/[0-9]/$'
Hierarchical Data in MySQL
Since this structure involves hierarchical data maybe you should consider to change the table structure to something that represents actual hierarchy. http://mikehillyer.com/articles/managing-hierarchical-data-in-mysql/ has an excellent tutorial about the subject.
I have a table that has a comma separated list of ids in one of the fields (not my doing). I want to know if I can use LIKE to match a number in this string? The problem is I don't want to get similar numbers. Is there a way to match a number with no numeric charcters on either side?
SELECT * FROM table WHERE activitiesids LIKE 6
| activitiesids |
---+---------------+---
| 3,16,8,6 |
---+---------------+---
| 6 |
---+---------------+---
| 7,560 |
---+---------------+---
Haven't tested but you can try something like this:
SELECT * FROM table WHERE activitiesids REGEXP '[[:<:]][0-9]+[[:>:]]';
Something like that:
WHERE ids LIKE '%,16,%' OR ids LIKE '%,16' OR ids LIKE '16,%';
Postgresql even has pattern matching - I don't know for mysql:
WHERE ids ~ '^(.*,)?16(,.*)?$';