Google Org Chart - Draw a chart from JSON (mysql) - json

I'm trying to draw an organizational chart (http://goo.gl/wgftfO) from JSON (php - mysql) but it doen'st display well.
Here is my HTML code:
<script type="text/javascript">
google.load('visualization', '1', {packages:['orgchart']});
google.setOnLoadCallback(drawChart);
function json(){
$.ajax({
type: "POST",
url: "function/ver.php",
success: function(datos){
datos = eval(datos);
for (var i=0;i<datos.length;i++){
var id = datos[i].id;
var nombre = datos[i].nombre;
var jefe = datos[i].jefe;
alert(id);
drawChart(id, nombre);
function drawChart(id, nombre) {
//alert("Id: " + id + " | Nombre: " + nombre);
var data = new google.visualization.DataTable();
data.addColumn('string', 'Name');
data.addColumn('string', 'Manager');
data.addColumn('string', 'ToolTip');
data.addRows([
[nombre, jefe, id]
]);
var chart = new google.visualization.OrgChart(document.getElementById('contenido'));
chart.draw(data, {allowHtml:true});
}
}
},
error: function(error){
alert(error);
}
});
}
</script>
</head>
<body onLoad="json()">
<div id="contenido"></div>
</body>
JSON result:
[
{
"id":"1",
"nombre":"Andrey",
"paterno":null,
"foto":"http:\/\/icons.iconarchive.com\/icons\/deleket\/face-avatars\/256\/Male-Face-G1-icon.png",
"jefe":""
},
{
"id":"2",
"nombre":"Enrique",
"paterno":null,
"foto":"http:\/\/icons.iconarchive.com\/icons\/deleket\/face-avatars\/256\/Male-Face-F3-icon.png",
"jefe":"Andrey"
},
{
"id":"3",
"nombre":"Chero",
"paterno":null,
"foto":"http:\/\/icons.iconarchive.com\/icons\/deleket\/face-avatars\/256\/Male-Face-E4-icon.png",
"jefe":"Andrey"
},
{
"id":"4",
"nombre":"Ricardo",
"paterno":null,
"foto":"http:\/\/icons.iconarchive.com\/icons\/deleket\/face-avatars\/256\/Male-Face-F3-icon.png",
"jefe":"Chero"
},
{
"id":"5",
"nombre":"Jhon",
"paterno":null,
"foto":"http:\/\/icons.iconarchive.com\/icons\/deleket\/face-avatars\/256\/Male-Face-H1-icon.png",
"jefe":"Enrique"
}
]
This displays like:
And, if i remove the alert(id) form the HTML code (in ajax), just shows the last object of the JSON:
How can i fix this?
or, is there any other option to do this chart?
Thank your for answers

The bellow code worked for me
index.html
<script type='text/javascript' src='https://www.google.com/jsapi'></script>
<script type='text/javascript' src='js/jquery.min.js'></script>
<script type='text/javascript'>
google.load('visualization', '1', { packages: ['orgchart'] });
google.setOnLoadCallback(drawChart);
function drawChart() {
$.ajax({
type: "POST",
url: "ajax/organization.php",
success: function(result){
var result = JSON.parse(result);
if ((emp_count = result.length) > 0) {
console.log(result);
var data = new google.visualization.DataTable();
data.addColumn('string', 'Name');
data.addColumn('string', 'Manager');
data.addRows(emp_count);
for (i = 0; i < emp_count; i++) {
data.setCell(i, 0, result[i].emp);
data.setCell(i, 1, result[i].manager);
}
var chart = new google.visualization.OrgChart(document.getElementById('chart_div'));
chart.draw(data, { allowHtml: true });
}
}
});
}
</script>
organization.php
define('DB_SERVER', 'localhost');
define('DB_USERNAME', 'USERNAME');
define('DB_PASSWORD', 'PASSWORD');
define('DB_DATABASE', 'DATABASE_NAME');
$connection = mysql_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD) or die(mysql_error());
$database = mysql_select_db(DB_DATABASE) or die(mysql_error());
$query=mysql_query("select emp, manager from employees") or die(mysql_error());
# Collect the results
while($obj = mysql_fetch_object($query)) {
$arr[] = $obj;
}
# JSON-encode the response
$json_response = json_encode($arr);
// # Return the response
echo $json_response;

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You have typo in the for function name loadChart.
The variable declarations and function definitions are needed to be added before being used.
Reduced the length of array to 7 instead of 10.
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In you app.js file on line number 10 :
Gender.push("Gender " + data[i].JenisKelaminID);
you can set an if condition instead of it Like
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