Query in a SQL table - mysql

Question

I have the following tables:
http://sqlfiddle.com/#!2/1e991/1
But I have a problem! The output of my query is:
DATE SLOT sum(SUCCESSFUL) SUCCESSFUL PERCENTAGE OTA_NAME USERS_SI
July, 02 2013 00:00:00+0000 2 120 120 41.6667 campana 2 50
July, 02 2013 00:00:00+0000 1 200 200 25 campana 2 50
July, 02 2013 00:00:00+0000 1 150 150 53.3333 campana 3 80
July, 01 2013 00:00:00+0000 2 100 100 20 campana 1 20
July, 01 2013 00:00:00+0000 3 440 440 4.5455 campana 1 20
July, 01 2013 00:00:00+0000 1 700 700 2.8571 campana 1 20
And I need a sum of successful with the same date and campaign, for example, I have in July 1 with campaign 1 three rows, then I need sum the successful of the three rows, and with campaign 2 two rows, then I need sum the successful of the two rows, and with campaign 3 one rows, then I need sum the successful of the one row that is the same.
And finally the percentage is the division between sum(SUCCESSFUL) and USERS_SI
The output that I need is:
DATE SLOT sum(SUCCESSFUL) SUCCESSFUL PERCENTAGE OTA_NAME USERS_SI
July, 02 2013 00:00:00+0000 2 320 120 41.6667 campana 2 50
July, 02 2013 00:00:00+0000 1 320 200 25 campana 2 50
July, 02 2013 00:00:00+0000 1 150 150 53.3333 campana 3 80
July, 01 2013 00:00:00+0000 2 1240 100 20 campana 1 20
July, 01 2013 00:00:00+0000 3 1240 440 4.5455 campana 1 20
July, 01 2013 00:00:00+0000 1 1240 700 2.8571 campana 1 20
Can you help me?

Answer 1

sqlfiddle here
SELECT other.date AS date,
other.slot,
other.successful,
calc.sum_successful,
max((case when (rule.tree_si = dms.tree) then dms.numberResponses end))/successful AS percentage,
other.name AS ota_name,
other.successful AS successful,
max((case when (rule.tree_si = dms.tree) then dms.numberResponses end)) AS users_si
FROM aca_ota_other other
join aca_dms_rules rule on other.name = rule.ota_name
join aca_dms dms on dms.date = other.date and rule.tree_si = dms.tree
join (SELECT name, sum(successful) as sum_successful FROM aca_ota_other GROUP BY name) as calc on other.name = calc.name
GROUP BY
other.date,
other.name,
other.successful
ORDER BY other.date desc

Answer 2

I'm not sure but if i understood well, you need something like this:
I'm sorry, I've made some little changes in your query.
SELECT other.date date,
other.slot,
other.name ota_name,
sum(successful) successful,
dms.numberResponses users_si,
SUM(successful)/dms.numberResponses AS percentage
FROM aca_ota_other other
JOIN aca_dms_rules rule ON other.name=rule.ota_name
JOIN aca_dms dms ON dms.date=other.date AND rule.tree_si=dms.tree
GROUP BY other.date,
other.name
ORDER BY other.date DESC
http://sqlfiddle.com/#!2/1e991/22