Mysql Query to find distinct characters in a string - mysql

Is there a way to write recursive query in mysql. Equivalent of connect by (level or Prior) in oracle. I searched google as well as stackoverflow and there is no direct eqivalent. But is there any work around to get it.
I have a string, i have to iterate through individual characters in the string and print only the distinct characters of the string.
Input:
recursive
Output:
recusiv

I came up with this "simple" solution.
Functions used:
GROUP_CONCAT: http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat
SUBSTRING http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_substring
Live demo: http://www.sqlfiddle.com/#!2/d41d8/19186
SELECT
GROUP_CONCAT( chars.c SEPARATOR '') AS allchars
FROM (
SELECT DISTINCT
SUBSTRING( str.str, pos.pos, 1 ) AS c
FROM
( SELECT x1.x + x2.x*10 AS pos
FROM
( SELECT 0 AS x UNION ALL
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6 UNION ALL
SELECT 7 UNION ALL
SELECT 8 UNION ALL
SELECT 9
) AS x1
INNER JOIN
( SELECT 0 AS x UNION ALL
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6 UNION ALL
SELECT 7 UNION ALL
SELECT 8 UNION ALL
SELECT 9
) AS x2
) AS pos
INNER JOIN
( SELECT 'recursive' AS str UNION ALL
SELECT 'XYZ'
) AS str
) AS chars

Related

Insert unique random number with recursive MySQL

I want to populate a table with unique random numbers without using a procedure.
I've tried using this reply to do it but not success.
What I'm trying to do is something like this but validating that numbers are not repeated:
INSERT into table (row1,row2)
WITH RECURSIVE
cte AS ( SELECT 0 num, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
UNION ALL
SELECT num+1, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
FROM cte WHERE num < 100000-1)
SELECT random_num, null
FROM cte;
In the example above, I am able to generate random values and insert them but without validating that the numbers are not repeated.
I have tried to do this:
INSERT into table (row1,row2)
WITH RECURSIVE
cte AS ( SELECT 0 num, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
UNION ALL
SELECT num+1, LPAD(FLOOR(RAND() * 99999999),8,0) random_num
FROM cte WHERE num < 100000-1 AND random_num NOT IN (SELECT random_num FROM cte WHERE random_num IS NOT NULL))
SELECT random_num, null
FROM cte;
but the condition AND random_num NOT IN (SELECT random_num FROM cte WHERE random_num IS NOT NULL) in the where case, causes an SQL Error [4008] [HY000]: Restrictions imposed on recursive definitions are violated for table 'cte'
Any suggestions of how to do it? thank you!.
This could be an option. Generate all possible values, sort randomly and take desired number of entries.
CREATE TABLE random_data (
row1 INT PRIMARY KEY AUTO_INCREMENT,
row2 VARCHAR(10) NOT NULL,
UNIQUE KEY _Idx1 ( row2 )
);
INSERT INTO random_data (row2)
SELECT LPAD(num, 8, 0)
FROM (
SELECT h * 10000000 + g * 1000000 + f * 100000 + e * 10000 + d * 1000 + c * 100 + b * 10 + a AS num
FROM (SELECT 0 a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) ta
JOIN (SELECT 0 b UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tb
JOIN (SELECT 0 c UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tc
JOIN (SELECT 0 d UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) td
JOIN (SELECT 0 e UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) te
JOIN (SELECT 0 f UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tf
JOIN (SELECT 0 g UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) tg
JOIN (SELECT 0 h UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) th
) n
ORDER BY RAND()
LIMIT 100000;
If you have a table - any table - with e.g. 100 rows then you can generate million distinct random numbers between 0 and 99999999 as follows:
select distinct floor(rand() * 100000000)
from t as t0, t as t1, t as t2
limit 1000000
Note that because of distinct you will need to generate a bigger number of rows so that you get desired number of rows after distinct.

Fetching Only Unique Results From Sql Database

Database Table
ID Post Tags
1 Range rover range-rover,cars
2 Lamborghini lamborghini,cars
3 Kawasaki kawasaki,bikes
4 Yamaha R1 yamaha,r1,bikes
I Want to Remove Duplicate Values from Result sql
What i Get When i fetch tags (tags are in ,) from Database
SELECT Tags from posts;
Resut:
range-rover,cars lamborghini,cars kawasaki,bikes yamaha,r1,bikes
What I Need is not to show same result again.
range-rover,cars lamborghini kawasaki,bikes yamaha,r1
You can split your text using tally table and SUBSTRING_INDEX:
SELECT DISTINCT SUBSTRING_INDEX(SUBSTRING_INDEX(t.tags, ',', n.n), ',', -1) AS val
FROM posts t
CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
) n
WHERE n.n <= 1 + (LENGTH(t.tags) - LENGTH(REPLACE(t.tags, ',', '')))
SqlFiddleDemo
If you need one row add GROUP_CONCAT:
SELECT GROUP_CONCAT(DISTINCT SUBSTRING_INDEX(SUBSTRING_INDEX(t.tags, ',', n.n), ',', -1)) AS val
...
SqlFiddleDemo2

Find elements in a set that are not in another set using native MySQL functions

I have two variables having comma separated IDs.
SET #Set1 = '1,2,3,4';
SET #Set2 = '3,2,5,6';
I want to get all elements in Set1 that are not in Set2 using just MySQL functions. In the above case,
the answer is: '1,4'.
Please note that I want to use only native MySQL functions.
the easiest way would be to normalize your set you want to find the results in and then use FIND_IN_SET() on the second set like so
SET #Set1 = '1,2,3,4';
SET #Set2 = '3,2,5,6';
SELECT col
FROM
( SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(#Set1, ',', n.digit+1), ',', -1) col
FROM (SELECT #set1) temp
JOIN(SELECT 0 digit UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3) n
ON LENGTH(REPLACE(#Set1, ',' , '')) <= LENGTH(#Set1)-n.digit
ORDER BY n.digit
) t
WHERE NOT FIND_IN_SET(col, #set2);
if you want to capture as many comma separated digits as you can then just do this
SELECT col
FROM
( SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(#Set1, ',', n.digit+1), ',', -1) col
FROM (SELECT #set1) temp
JOIN
( SELECT
SEQ.SeqValue as digit
FROM
( SELECT (HUNDREDS.SeqValue + TENS.SeqValue + ONES.SeqValue) SeqValue
FROM(SELECT 0 SeqValue UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) ONES
CROSS JOIN(SELECT 0 SeqValue UNION ALL SELECT 10 UNION ALL SELECT 20 UNION ALL SELECT 30 UNION ALL SELECT 40 UNION ALL SELECT 50 UNION ALL SELECT 60 UNION ALL SELECT 70 UNION ALL SELECT 80 UNION ALL SELECT 90) TENS
CROSS JOIN(SELECT 0 SeqValue UNION ALL SELECT 100 UNION ALL SELECT 200 UNION ALL SELECT 300 UNION ALL SELECT 400 UNION ALL SELECT 500 UNION ALL SELECT 600 UNION ALL SELECT 700 UNION ALL SELECT 800 UNION ALL SELECT 900) HUNDREDS
) SEQ
) n
ON LENGTH(REPLACE(#Set1, ',' , '')) <= LENGTH(#Set1)-n.digit
ORDER BY n.digit
) t
WHERE NOT FIND_IN_SET(col, #set2);
which will return up to 1000 items in a single comma separated list

How can I update a column with a value from a list of values for a set of records

I do an update in a table row by row:
UPDATE table
SET col = $value
WHERE id = $id
Now if I update e.g. 10000 records each record gets the $value but it does not really matter which $id gets which $value. The only requirement I have is that all the records I am updating end up with a $value.
So how could I convert this update to something like
UPDATE table
SET col ?????? what here from a $value_list???
WHERE id IN ($id_list)
I.e. pass the list ids and somehow the values and that range of ids get a value
Let's assume you've got two comma separated lists of your ids and your values with the same count of items. Then you could do your update with statements like those:
-- the list of the ids
SET #ids = '2,4,5,6';
-- the list of the values
SET #vals = '17, 73,55, 12';
UPDATE yourtable
INNER JOIN (
SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(t.ids, ',', n.n), ',', -1) id,
SUBSTRING_INDEX(SUBSTRING_INDEX(t.vals, ',', n.n), ',', -1) val
FROM (SELECT #ids as ids, #vals as vals) t
CROSS JOIN (
-- build for up to 1000 separated values
SELECT
1 + a.N + b.N * 10 + c.N * 100 AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) c
ORDER BY n
) n
WHERE n <= (1 + LENGTH(t.ids) - LENGTH(REPLACE(t.ids, ',', '')))
) t1
ON
yourtable.id = t1.id
SET
yourtable.val = t1.val;
Explanation
The inner series of UNIONs builds a table with the numbers from 1 to 1000. You should be able to expand this mechanism to your needs:
-- build for up to 1000 separated values
SELECT
a.N + b.N * 10 + c.N * 100 + 1 AS n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) c
ORDER BY n
We use this numbers to get the items out of our lists with the nested SUBSTRING_INDEX call
SUBSTRING_INDEX(SUBSTRING_INDEX(t.ids, ',', n.n), ',', -1) id,
SUBSTRING_INDEX(SUBSTRING_INDEX(t.vals, ',', n.n), ',', -1) val
The WHERE clause get the number of items in (ok only one of the two) lists:
WHERE n <= (1 + LENGTH(t.ids) - LENGTH(REPLACE(t.ids, ',', '')))
Because we've got one occurence of the separator less, we add 1 to the difference in length of the list with the separator and the length of the list without all occurrences of the separator.
Then we do the UPDATE with a JOIN operation on the id values in the outer UPDATE statement.
See it working in this fiddle.
Believe me: This is much faster than agonizing row-by-row update.

Rewrite to not include subquery in FROM?

A great fellow helped me with developing the following statement. However, in mySQL - I cannot save a view with a subquery in the FROM clause. Any suggestions o nhow to rewrite this so that it can be saved into a mySQL server?
SELECT t.idPatternMetadata, SUBSTRING_INDEX(SUBSTRING_INDEX(t.sKeywords, ',', n.n), ',', -1) color , count(*) as counts
FROM tblPatternMetadata t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(t.sKeywords) - LENGTH(REPLACE(t.sKeywords, ',', '')))
group by color
THANKS in advance!
One option is to create a table that contains the 100 integer values, and reference that table in the query.
CREATE TABLE n (n INT UNSIGNED PRIMARY KEY);
INSERT INTO n (n)
SELECT a.n + b.n * 10 + 1 n
FROM ( SELECT 0 AS n UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3
UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6
UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9
) a
CROSS
JOIN ( SELECT 0 AS n UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3
UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6
UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9
) b
ORDER BY 1;
Then rewrite your query to reference the table in place of the inline view:
SELECT t.idPatternMetadata, SUBSTRING_INDEX(SUBSTRING_INDEX(t.sKeywords, ',', n.n), ',', -1) AS color
, count(*) AS counts
FROM tblPatternMetadata t
JOIN n
ON n.n <= 1 + (LENGTH(t.sKeywords) - LENGTH(REPLACE(t.sKeywords, ',', '')))
GROUP BY color