Data truncated for column? - mysql

After changing the data type of a MySql column in order to store Twilio call ids (34 char strings), I try to manually change the data in that column with:
update calls
set incoming_Cid='CA9321a83241035b4c3d3e7a4f7aa6970d'
where id='1';
However I get an error which doesn't make sense seeing as the column's data type was properly modified?
| Level ||| Code | Message
| Warning | 1265 | Data truncated for column 'incoming_Cid' at row 1

Your problem is that at the moment your incoming_Cid column defined as CHAR(1) when it should be CHAR(34).
To fix this just issue this command to change your columns' length from 1 to 34
ALTER TABLE calls CHANGE incoming_Cid incoming_Cid CHAR(34);
Here is SQLFiddle demo

I had the same problem because of an table column which was defined as ENUM('x','y','z') and later on I was trying to save the value 'a' into this column, thus I got the mentioned error.
Solved by altering the table column definition and added value 'a' into the enum set.

By issuing this statement:
ALTER TABLES call MODIFY incoming_Cid CHAR;
... you omitted the length parameter. Your query was therefore equivalent to:
ALTER TABLE calls MODIFY incoming_Cid CHAR(1);
You must specify the field size for sizes larger than 1:
ALTER TABLE calls MODIFY incoming_Cid CHAR(34);

However I get an error which doesn't make sense seeing as the column's data type was properly modified?
| Level | Code | Msg | Warn | 12 | Data truncated for column 'incoming_Cid' at row 1
You can often get this message when you are doing something like the following:
REPLACE INTO table2 (SELECT * FROM table1);
Resulted in our case in the following error:
SQL Exception: Data truncated for column 'level' at row 1
The problem turned out to be column misalignment that resulted in a tinyint trying to be stored in a datetime field or vice versa.

In my case it was a table with an ENUM that accepts the days of the week as integers (0 to 6). When inserting the value 0 as an integer I got the error message "Data truncated for column ..." so to fix it I had to cast the integer to a string. So instead of:
$item->day = 0;
I had to do;
$item->day = (string) 0;
It looks silly to cast the zero like that but in my case it was in a Laravel factory, and I had to write it like this:
$factory->define(App\Schedule::class, function (Faker $faker) {
return [
'day' => (string) $faker->numberBetween(0, 6),
//
];
});

I had the same problem, with a database field with type "SET" which is an enum type.
I tried to add a value which was not in that list.
The value I tried to add had the decimal value 256, but the enum list only had 8 values.
1: 1 -> A
2: 2 -> B
3: 4 -> C
4: 8 -> D
5: 16 -> E
6: 32 -> F
7: 64 -> G
8: 128 -> H
So I just had to add the additional value to the field.
Reading this documentation entry helped me to understand the problem.
MySQL stores SET values numerically, with the low-order bit of the
stored value corresponding to the first set member. If you retrieve a
SET value in a numeric context, the value retrieved has bits set
corresponding to the set members that make up the column value. For
example, you can retrieve numeric values from a SET column like this:
mysql> SELECT set_col+0 FROM tbl_name; If a number is stored into a
If a number is stored into a SET column, the bits that are set in the
binary representation of the number determine the set members in the
column value. For a column specified as SET('a','b','c','d'), the
members have the following decimal and binary values.
SET Member Decimal Value Binary Value
'a' 1 0001
'b' 2 0010
'c' 4 0100
'd' 8 1000
If you assign a value of 9 to this column, that is 1001 in binary, so
the first and fourth SET value members 'a' and 'd' are selected and
the resulting value is 'a,d'.

when i first tried to import csv into mysql , i got the same error , and then i figured out mysql table i created doesn't have the character length of the importing csv field ,
so if it's the first time importing csv
its a good idea to give more character length .
label all fields as varchar or text , don't blend int or other values.
then you are good to go.

Check whether you are using the 'enum' datatype.If you are using 'enum' datatype then the items inside the enum datatype should be exactly match with the data which you are entering.Ex.
You are taking the enum datatype like this:
enum('book',stationery','others')
then when you are inserting the data into the database you have to do like this:
INSERT INTO database_name.table_name (column1,...columnn) VALUES().
THE value should include same items which you are mentioned within the bracket of enum datatype.

my issue was I used single quote instead of double quotes which add extra words in Boolean column

I Faced the same issue .In my case i was inserting a empty string for a numeric column.But by inserting a numeric value in string form for same column it got resolved e.g '12.56' --> numeric column will work but '' --> numeric column will give the above mentioned error.
Note: For numeric columns in MySql we can pass values in double quotes also .

In some cases this can be result of wrong type of input. For example, you have a column decimal(10,2) and the input isn't sanitized and is 7,7 but should be 7.7.

Related

Replace null values where the datatype is numeric with just a blank

UPDATE kpi.data
SET MetricValue = ''
WHERE (MetricValue IS NULL )
and PeriodDate = '2020-01-02'
and ReportID = 4
I got this error
Msg 8114, Level 16, State 5, Line 4 Error converting data type varchar
to numeric.
What you are trying to do does not make any sense, so it cannot work, and it will not work.
If the data type of a column is numeric then the column can only contain numbers.
If the data type of a column is numeric and nullable the column can contain either a number or null.
There is no other value that a numeric field can receive, either in MySQL or in any other relational database that I have ever heard of.
Perhaps what you want to do is to convert null to blank when selecting, (not when inserting/updating,) in which case you should look at some other Q&A like this one: MySql Query Replace NULL with Empty String in Select

Why is MySQL not converting my data correctly?

I have a column of decimals, but MySQL is reading them as TEXT. I tried this to alter the column by:
ALTER TABLE `engine_type_project`.`weo_data_eu_test`
CHANGE COLUMN `Mean_GDP_all_time` `Mean_GDP_all_time` DECIMAL(6,2) NULL DEFAULT NULL;
An original value is: 3,282.772
But my code returns it as: 3.00
Prior to this, I attempted:
SELECT CAST('Mean_GDP_all_time' AS DECIMAL(6,2))
FROM weo_data_eu_test;
But the entire column returned as 0.00
In casting non-numeric values to numeric, mysql does not expect commas. So it gives up looking for additional parts of the number after the "3".
Before changing the type, remove the commas with:
update weo_data_eu_test set Mean_GDP_all_time=replace(Mean_GDP_all_time,',','')
fiddle

MYSQL, Insert the numeric characters of a string in a column to another column

I am trying to clean the telephone numbers of a database so we can easily search for them. In the column TEL we have rows like:
654-598-5487
654.254.2456
(458)-5458789 e.3
I want to copy all those values to a new column where only the numeric characters are transferred:
6545985487
6542542456
45854587893
The new column (TEL_NO_FORMAT) is a big int and it only allows numbers, but if I execute something like this:
UPDATE CLIENTS set `TEL_NO_FORMAT` = `TEL`
It will only transfer the first numeric characters found and ignore the rest:
654
654
NULL
Easiest way is the REGEXP_REPLACE(MySQL 8.0+):
SELECT *, REGEXP_REPLACE(tel_no_format, '[^0-9]','') AS result
FROM clients
Answering the question in an update query
UPDATE CLIENTS SET TEL_NO_FORMAT = REGEXP_REPLACE(TEL, '[^0-9]','');
You should replace the undesired char before
UPDATE CLIENTS set `TEL_NO_FORMAT` = replace(replace(replace(`TEL`, '.',''),'-',''),')','')
because some char (eg '-') are create problem during conversion ..
anyway rember that a big int can't manage properly eventual tel number 0 prefixed eg:
00453778988

Why * is Inserted in SQL

This happened when I was just testing.
I've created a table as
Create Table Test_Table
(
Field_char char(1)
);
When I want to insert value with code
Insert Into Test_Table(Field_char)
Select 13;
It inserts '*' in the column. For single digits it inserts them as it is. If the length is modified from 1 to 2, similar thing happen for 3 digits input such as 100 etc.
Why is this?
In your create statement you set the length of Field_char to 1 (char(1)). This means that your entries must have a length smaller or equal to 1. valid entries are 1,2 etc. Invalid entries are 12, 13 as they are longer than 1 char -> * is a placeholder to indicate invalid values.
EDIT: (Thanks To Vladimir)
To be more precise take a look here.
Truncating and Rounding Results
[...] Conversions to char, varchar, nchar, nvarchar, binary, and varbinary are truncated, except for the conversions shown in the following table.
There we have the following entry:
From data type int to data type char result *
where * = Result length too short to display
When you are writing
Insert Into Test_Table(Field_char)
Select 13;
The it is converting int to char. So your 13 is converted into *. If you want you can check by writing
select CONVERT(char(1),13)
If you want to see the result as 13 then you need to put that in single inverted comma like this:
Insert Into Test_Table(Field_char)
Select '13';
And also you need to increase the size of column as char(1) can hold only one character.
SQL FIDDLE DEMO
It simply Convert Int to Char
for Example
select CONVERT(char(1),13)
it will give *
Sql Implicitly convert int to char which is you column type..

mysql syntax for populating a column of an existing table and setting a default value for said column

I have a table and I have added a new column to it. I need to populate this new column and also set the default value for it.
The value of the new col is obtained by concatenating two strings based on the values of other columns:
the first string is the sum COL_1 + 10000
the second string is a obtained by stripping everything but the alphanumerics in COL_2
Update TABLE set NEW_COL = CONCAT ((SUM (10000 + COL_1)), (preg_replace('/[\s\W]+/','',COL_2)))
This will be the default value for the column
The reason your update is failing is that preg_replace() is not a valid MySQL function. That's a PHP function. Here's a relevant question that addresses that functionality in MySQL:
How to do a regular expression replace in MySQL?