Since I put a code AllowBypassKey = false in my program
If I run my code in Access Runtime 2010, automatically gives an Runtime Error and closes my program for no reason. :(
==================
What I did is :
-The first form will show in the program is the LoginForm
-On Load LoginForm
CurrentDB.Properties("AllowBypassKey") = false
-On Click Quit Button in the LoginForm.
If txtpassword = strByPassCode then CurrentDB.Properties("AllowBypassKey") = True
====================
Im not really sure whats happening with my program
but If I run my program in Full Version Ms Access 2010
I didn't encounter any errors with my codes.
But if I remove the AllowByPassKey it will run smoothly. But I need to put
a ByPass Code so that my codes will be protected and also the tables.
I already solve my problem. It was a data problem
from the clients database. I was so d**b I didn't copy
his database.
Thanks for the help :)
Related
I have a DB I created as a sort of real time virtual client check in log. It would be stored on an intranet network drive. In theory, a greeter can send client information back to be picked up by another worker. This is done through a series of forms, tables, and queries. When I test it myself on my own machine, opening both the greeter and reception forms I can enter information on the greeter, click the action button to send it to the table, where a timered query(held in a hidden form opened with an AutoExec macro) picks up the current record, and then displays it on the reception form. Everything works perfectly. The only problem is, when I try to test it on multiple computers, the greeter can send info back, it appears on the table, but the reception form never populates. Any ideas where the disconnect might be?
edit I have decided I want to do away with the hidden initialize form, so I've re-organized the code as follows. It still works when I do it myself on one computer, but opening the reception form on another computer it still fails to populate.
Reception 1
Private Sub Form_Timer()
If gClientID > gNextClientID Then
gblnRNC = True
Else: gblnRNC = False
End If
If gblnRNC = True And gblnRec1Free = True Then
gRec1CL = gNextClientID
MsgBox "There is a new client to be seen.", vbSystemModal, "New Client Warning"
Me.RecordSource = "RecClientIDNum"
End If
End Sub
So forgive my noob question, I sorta jumped into programming procedures without fully understanding how Access works. I declared global variables but didn't realize they were only global within the scope of the local session running on a particular machine.
Moved the variables that establish the interactions between the various forms to a table and everything works perfectly.
I support a LOB application written in MS Access VBA with a SQL Server back end. One feature of the application is the ability to open a second instance of the application, allowing the users to view/modify two records at the same time.
The first time I open the application it connects and everything works fine. However when I attempt to open the second instance I get the following error message:
-2147467259 - Method "OpenConnection" of object _CurrentProject failed.
This is the line of code executing when the error occurs:
CurrentProject.OpenConnection strConnection
I have stepped through the code and verified that strConnection is the same connection string in both the first and second instances of the application
I'm running out of things to look for. Any ideas are greatly appreciated!
UPDATE: It appears that something is not allowing the second MSACCESS.EXE instance to use the same connection string. My connection string is below, with database and server substituted for the actual database and server.
PROVIDER=SQLOLEDB.1;INTEGRATED SECURITY=SSPI;PERSIST SECURITY INFO=FALSE;INITIAL CATALOG=database;DATA SOURCE=server
Try
MultipleActiveResultSets=True
(http://msdn.microsoft.com/en-us/library/h32h3abf(v=vs.110).aspx)
Would it be better to open a new form from the same application?
dim frm as ShowCar_Form
frm.Show
So our corporate IT dept has determined that it is time to force SP1 on everyone's PC's.
Which means I need to get my Access 2003 ADE application working with the stupid ADO incompatibility problem.
I got the ADO portion to work by following KB2517589, but now several of my textboxes say #Name?.
These are bound to code, so, for example, the data field in the textbox is =CalcShippingAddr().
As a test, I replaced the code with the following:
Public Function CalcShippingAddr() As String
msgbox "Func Called"
CalcShippingAddr = "Test"
End Function
This works fine on my dev machine, but as soon as I make an ADE and send it to a PC without SP1, I get #Name? on the textbox. The msgbox nevers pops up.
Any ideas what might be happening?
This is a fault to do with the field calculation, I haven't seen it myself but have heard that clicking in to the relevant text box would then show the value although this is not a solution. I would always recommend using unbound forms as you can control step by step what your fields/objects are doing. As you already have a custom function to calculate the shipping address then it should be simple enough for you to add the code the the forms 'Open' or 'Load' event e.g.
Private Sub Form_Load()
textbox = CalcShippingAddr
End Sub
I am migrating a website over to a new server, its in ASP and uses several Access databases, the site and CMS can read, display the data, and even edit and update existing data entries, but when I want to add a new entry, I get an error...
Microsoft VBScript runtime error '800a0046'
Permission denied: 'CreateObject'
/padp2010d/ads_tradetracker.asp, line 11
There seems to be no passwords on the databases, I have set up and tested the ODBC Data Sources and they are working fine.
The code or line that is causing the problem is...
<%
Dim Mail, strPath, strHost, Upload
Set Upload = CreateObject("Persits.Upload")
Upload.IgnoreNoPost = True
' Generate unique names
Upload.OverwriteFiles = False
' Limit file size to 500000 bytes
Upload.SetMaxSize 500000, True
' capture an upload and save uploaded files (if any) in temp directory
Upload.SaveVirtual "\pa\images\advertenties"
Upload.Save
' Use session ID as the new file name
NewName = Session.SessionID
The line 11 is Set Upload = CreateObject("Persits.Upload")
If anyone could help that would be great. Could it be a Permission setting?
Im a complete novice with ASP and Access!
Thanks
I have tried the answer below but I still get an error...
Server object error ASP 0178 : 80070005
Server.CreateObject Access Error
/padp2010d/ads_tradetracker.asp, line 11
The call to Server.CreateObject failed while checking permissions. Access is denied to this object.
How about:
Server.CreateObject("Persits.Upload")
Try CreateObject("Persits.Upload", "localhost") instead. I've found that in some scenarios the optional argument is required, but have never figured out a pattern as to when.
I have now solved the problem, the script works fine, the problem was permission settings on AspUpload component on the server. Many Thanks for your help.
Some users get the following error when running reports.
• Execution 'iwy2vpzo52pmp555ftfn4455' cannot be found (rsExecutionNotFound)
They run fine in the morning.
Any suggestions?
Thank you
I can help.
The problem is that the ReportViewer control uses Session to store the currently executing report. Once you navigate away from the reports, the item still remains and eventually loses its "execution context", which is the way Report Server caches reports.
Therefore, before browsing a report, you should attempt to clear out the Session of these reports, so that there are NO cached reports in the Session, and the ReportViewer control can work properly.
You will also find that sometimes when accessing Session.Keys.Count, this error can occur, as again, the execution context has failed.
Make sure you do this on the page showing the report!!
The 2 options are:
if (!IsPostBack)
{
HttpContext.Current.Session.Clear();
ReportViewer1.ServerReport.ReportServerUrl = new Uri(ReportServerUrl, System.UriKind.Absolute);
ReportViewer1.ServerReport.ReportPath = ReportPath;
System.Collections.Generic.List<ReportParameter> parameters = new System.Collections.Generic.List<ReportParameter>();
....
ReportViewer1.ServerReport.SetParameters(parameters);
ReportViewer1.ServerReport.Refresh();
}
Or
for (int i = 0; i < HttpContext.Current.Session.Keys.Count; )
{
if (HttpContext.Current.Session[i].ToString() == "Microsoft.Reporting.WebForms.ReportHierarchy")
HttpContext.Current.Session.RemoveAt(i);
else
i++;
}
I am using SSRS 2017 and was running into this issue when trying to load a report into my MVC project using URL Access. The issue for me had to do with session.
To check this for yourself, you can try deleting the RSExecutionSession cookie and reload your report. Unfortunately, this is only a temporarily fix.
If this does work, try adding rs:ClearSession=true to your query string.
You can read about this setting here.
Look for a trailing space on the report path. This was the cause for me.
On the web.config's impersonation, use identity
impersonate="true"
userName="xxxxx"
password="xxxxx"
instead of : !--<identity impersonate="true"
Hope it helps
If you're running SQL Server Express edition, the SQL Server Agent isn't running to clean up your old SSRS sessions. You'll need to run a job on SSRS DB to clean up the old sessions.
My report took 10 seconds to run and 2 seconds to export - so it wasn't to do with the session expiry length.
I'd get the error when exporting a report to excel into my app an hour after I exported the report.
This error was causing my application to display a run time error.
I added this to the Global.asax class to resolve the error. Tried Server.Clear but got nothing. Session.Clear got rid of the error completely.
Sub Application_Error(ByVal sender As Object, ByVal e As EventArgs)
If ex.InnerException IsNot Nothing Then
If ex.InnerException.ToString.Contains("The report execution") AndAlso
ex.InnerException.ToString.Contains("rsExecutionNotFound") Then
Session.Clear()
Return
End If
End If
End Sub
While it may not be 100% applicable to the question above, I haven't been able to find any other resolution.