Count value from table column - mysql

Question

first I have a table which is pivot looks like this
pivot_product_Id | productsxx_Id | category_Id | subcategory_Id | color_Id
---------------------------------------------------------------------------
1 | 1 | 1 | 1 | 1
2 | 1 | 1 | 1 | 2
3 | 3 | 1 | 1 | 3
4 | 4 | 1 | 2 | 4
5 | 4 | 1 | 2 | 5
6 | 2 | 2 | 4 | 6
7 | 5 | 2 | 5 | 7
and I have color table like this
color_Id | color | color2
------------------------------------------
1 | black | white
2 | blue | orange
3 | white | black
4 | purple | black
5 | black | green
6 | red | black
and my question is in category ID 1 or 2 ... how many black color exist ? Counting from both color and color2 columns
and I tryed something like this but not geting the result I want and need help to create right query.
if(isset($shoes_post_var) || isset($nightwear_post_var)|| isset($outwear_post_var)){
$query3 = "SELECT count(*)
FROM pivot
JOIN category ON
pivot.category_Id = category.category_Id
JOIN subcategory ON
pivot.subcategory_Id = subcategory.subcategory_Id
JOIN color ON
pivot.color_Id = color.color_Id
JOIN productsxx ON
pivot.productsxx_Id = productsxx.productsxx_Id
WHERE
color IN ('$black')
or
color2 IN ('$black')
AND
category IN ('$shoes_post_var','$nightwear_post_var','$outwear_post_var')
GROUP BY pivot.color_Id ASC ";
$query5 = mysql_query($query3)or die(mysql_errno());
$total = mysql_result($query5, 0);
echo ' '.'('.$total.')';}

Answer 1

A possible solution
SELECT COUNT(*) total
FROM pivot
WHERE category_id IN (1, 2)
AND color_id IN
(
SELECT color_id
FROM color
WHERE color = 'black'
OR color2 = 'black'
)
Here is SQLFiddle demo

Answer 2

You only described two tables and asked about a query based on these two tables. This is a matter of a simple join with a simple selection - and a count - something like this:
SELECT count(1)
FROM pivot
JOIN color ON (pivot.color_id=color.color_id AND 'black' in (color.color, color.color2))
WHERE pivot.category_id = 1
Feel free to change the where clause for other categories.
However your existing code joins 5 tables and uses some other selection criteria. You really do need to ask the right question. Don't try to ask one thing while implying another.