I have a bit of a problem with an advanced query that I am struggling to get my head around.
Essentally there are votes in a votes table that correspond to a given soundtrack. My query needs to get a rank for a soundtrack based on the votes that it has been awarded.
My approach below works just fine when there are votes in the table but the rank is given a NULL value when there are none in there.
Here's the query:
SELECT soundtrack.*,
(SELECT WrappedQuery.rank
FROM (SELECT #rownum := #rownum + 1 AS rank,
prequery.soundtrack_id
FROM (SELECT #rownum := 0) sqlvars,
(SELECT Count(*),
soundtrack_id
FROM vote
GROUP BY vote.soundtrack_id
ORDER BY Count(*) DESC) prequery) WrappedQuery
WHERE WrappedQuery.soundtrack_id = soundtrack.id) AS rank
FROM soundtrack
WHERE soundtrack.id = 33
AND live = 1
ORDER BY rank ASC
I have a feeling the problem is to do with the (SELECT COUNT(*)) part, but everything I have tried so far isn't working out.
Hoping someone could shed some light on my issue.
EDIT
Here's the SQLFiddle
http://www.sqlfiddle.com/#!2/c8db2/2/0
THAT ONE IS GOOD:
SELECT soundtrack.*,
(SELECT WrappedQuery.rank
FROM (SELECT #rownum := #rownum + 1 AS rank,
prequery.soundtrack_id
FROM (SELECT #rownum := 0) sqlvars,
(
SELECT COALESCE(COUNT(vote.soundtrack_id),0) AS no_rows,
soundtrack.id AS soundtrack_id
FROM soundtrack
LEFT JOIN vote ON soundtrack.id=vote.soundtrack_id
GROUP BY soundtrack.id
ORDER BY 1 DESC
) prequery) WrappedQuery
WHERE WrappedQuery.soundtrack_id = soundtrack.id) AS rank
FROM soundtrack
ORDER BY rank ASC;
SEE: http://www.sqlfiddle.com/#!2/74698/2/0
I've had some luck ranking in my own work using the row_number function. But otherwise, the coalesce function might help you out.
SELECT soundtrack.*, rankquery.rank
FROM (
SELECT row_number() over(partition by prequery.soundtrack_id order by prequery.num_votes) as rank,
prequery.soundtrack_id
FROM (
SELECT COALESCE(COUNT(*),0) as num_votes, soundtrack_id
FROM vote
GROUP BY soundtrack_id
ORDER BY num_votes DESC
) prequery
) rankquery
INNER JOIN soundtrack
rankquery.soundtrack_id = soundtrack.id
WHERE soundtrack.id = 33
AND live = 1
ORDER BY rank
SELECT soundtrack.*, rankquery.rank
FROM(
SELECT prequery.*, #rownum := #rownum + 1 AS rank
(
SELECT COALESCE(Count(*),0) as num_votes,
soundtrack_id
FROM vote
GROUP BY soundtrack_id
ORDER BY num_votes DESC
) as prequery,
(SELECT #rownum := 0) as sqlvars
) rankquery
INNER JOIN soundtrack
rankquery.soundtrack_id = soundtrack.id
WHERE soundtrack.id = 33
AND soundtrack.live = 1
ORDER BY rankquery.rank ASC
Related
I have an issue with a query,
this is my old question that was previously solved
mysql get ranking position grouped with joined table
The problem is that when two players have the same score, the query returns the same ranking position, like 1-1-2-3 ecc. How can I fix this?
In the player's table there are also player_tickets (that is the number of game played) and player_date that is a timestamp.
I thought to get my ranking on base of player_score first, player_tickets then, and finally player_date
This is my older query
SELECT *,
(SELECT 1 + Count(*)
FROM players p2
WHERE p2.`player_game` = p.`player_game`
AND p2.player_score > p.player_score
AND p2.player_status = 0) AS ranking
FROM players p
ORDER BY `player_game`,
player_score DESC
You can simply add more columns to the order by of the window function:
rank() over (
partition by player_game_id
order by player_score desc, player_tickets desc, player_date
) as rank
If you really want to avoid having the same rank twice, you can also use row_number(), which guarantees this - when there are ties, row_number() affects distinct numbers (whose order is hence undefined).
Just add the ranking criteria to your WHERE clause:
SELECT *,
(
SELECT 1 + COUNT(*)
FROM players p2
WHERE p2.player_game = p.player_game
AND
(
(p2.player_score > p.player_score) OR
(p2.player_score = p.player_score AND p2.player_tickets > p.player_tickets) OR
(p2.player_score = p.player_score AND p2.player_tickets = p.player_tickets AND p2.player_date > p.player_date) OR
(p2.player_score = p.player_score AND p2.player_tickets = p.player_tickets AND p2.player_date = p.player_date AND p2.player_id > p.player_id)
)
) AS ranking
FROM players p
ORDER BY player_game, player_score DESC;
You can add additional comparisons in the subquery. Or more easily, use variables:
select p.*,
#rn := if(#g = player_game, #rn + 1,
if(#g := player_game, 1, 1)
) as ranking
from (select p.*
from players p
order by player_game, player_score desc, player_tickets desc, player_date desc
) p cross join
(select #rn := 0, #g := 0) as seqnum;
In newer versions, you would just use row_number() if you don't want ties.
I recently moved to a shared host that has MySQL 5.6.39 instead of MariaDB 10.x, I was wondering what would the equivalent of the following MariaDB statement in MySQL?
SELECT rank,
total
FROM
(SELECT ROW_NUMBER() OVER (
ORDER BY `prestige` DESC, `xp` DESC) AS rank,
(SELECT COUNT(*)
FROM Modular_LS) AS total,
steamid
FROM Modular_LS) sub
WHERE sub.steamid = '%s'
I got as far as this, but now I'm stuck
SELECT rank, total FROM
(SELECT #rank := #rank +1 as rank FROM Modular_LS,
(SELECT COUNT(*) FROM Modular_LS) AS total, steamid FROM Modular_LS) sub,
(SELECT #rank := 0) r ORDER BY `prestige` DESC, `xp` DESC) t;
The table structure contains the column steamid, xp, prestige
My goal is to order by prestige descending first and then xp descending to put it in a ranking like-order, then using WHERE query to find a specific player's ranking. The output of which contains the rank (position) and the total (total amount of records)
Maybe this will get you started:
SELECT #rank := IF(player_id = #prev, #rank + 1, 1), #prev := player_id
FROM ( SELECT #rank := 1, #prev = 0 ) AS init
JOIN ( SELECT player_id
FROM Modular_LS
ORDER BY prestige DESC, SP DESC
) AS x ;
After a few hours, this is what I came up with that solved my problem.
SELECT
sub.rank
,sub.total
FROM
(
SELECT
t.id
,t.steamid
,#rownum : = #rownum + 1 AS rank
,(
SELECT
COUNT (*)
FROM
Modular_LS
) AS total
FROM
Modular_LS t JOIN (
SELECT
#rownum : = 0
) r
ORDER BY
t.prestige DESC
,t.xp DESC
) sub
WHERE
sub.steamid = '%s'
How can I do this in laravel query builder? (this basically gets your current position in a voting system)
SELECT position FROM
(SELECT participant.target_user_id, #rownum := #rownum + 1 as position FROM
(SELECT target_user_id, count(*) as votes FROM contest_participants_votes GROUP BY
target_user_id ORDER BY votes DESC) as participant
JOIN (SELECT #rownum := 0) r) x
WHERE target_user_id = 1
We used a raw statement like this with placeholder
$position = \DB::select(\DB::raw(
'SELECT position FROM
(SELECT participant.target_user_id, #rownum := #rownum + 1 as position FROM
(SELECT target_user_id, count(*) as votes FROM contest_participants_votes GROUP BY
target_user_id ORDER BY votes DESC) as participant
JOIN (SELECT #rownum := 0) r) x
WHERE target_user_id = ?'), [$pid]);
I have following my sql query, I want to take limit start index from the other table, How could I do it?
SELECT std.totalmarks
FROM student as std
WHERE std.status=1
ORDER BY (std.datetime) ASC
LIMIT (
SELECT us.startnum
FROM user AS us
WHERE us.username='abc'
),10
select q.totalmarks from
(
SELECT *,#curRow := #curRow + 1 AS row_number
FROM student as std JOIN (SELECT #curRow := 0) r
WHERE std.status=1
ORDER BY (std.datetime) ASC
) q
where row_number>(
SELECT us.startnum
FROM user AS us
WHERE us.username='abc'
)
limit 10
select * from
(SELECT std.totalmarks, numstart.startnum, #n:=#n+1 as number
FROM student as std,
(SELECT us.startnum
FROM user AS us
WHERE us.username='abc') as numstart,
(SELECT #n:=0) sess_var
WHERE std.status=1
ORDER BY (std.datetime) ASC) res
where number>=startnum
LIMIT 0,10
I have a 1 table database with (in a simplified form) the following fields:
user_id(INT), ref_id(INT), points(INT), pointsgiven(BOOL/TINY_INT)
I want a query that returns the RANK of the user_id I specify based on points, given that pointsgiven is true. The kicker is, I need ties included. I can get a result set for ALL ranks if I want with the following query
SELECT
user_id, ref_id, points, pointsgiven,
CASE
WHEN #points = COALESCE(points, 0) THEN #rownum
ELSE #rownum := #rownum + 1
END AS rank,
#points := COALESCE(points, 0)
FROM users CT
JOIN
(
SELECT #rownum := 0, #points := NULL
) r
WHERE pointsgiven=TRUE ORDER BY points DESC
So, based on that, I thought I could just use that as a subquery to get a certain user_id as follows:
select * from
(
SELECT
user_id, ref_id, points, pointsgiven,
CASE
WHEN #points = COALESCE(points, 0) THEN #rownum
ELSE #rownum := #rownum + 1
END AS rank,
#points := COALESCE(points, 0)
FROM users CT
JOIN
(
SELECT #rownum := 0, #points := NULL
) r
WHERE pointsgiven=TRUE ORDER BY points DESC
) as derived WHERE user_id = 15
But this returns [BLOB - 1 B] as the rank on the correct user_id. What am I doing wrong here?
I have no idea why your query isn't working. For a single user id, though, you can use a correlated subquery:
select user_id, ref_id, points, pointsgiven,
coalesce((select count(distinct user_id)
from users u2
where u2.pointsgiven=TRUE and
u2.points > u.points
) + 1, 1) as rank
from users u
where user_id = 15;
An index on users(pointsgiven, points, user_id) should be used by the query.
To look at just one ranking, this might even be faster than your method.