How do I generate a dropdown list with custom item in joomla 3.1. I took a look on couple of examples but I don not get the thing to work. I have been trying the following but the list is not genarated the html works.
public function getInput() {
$jinput = JFactory::getApplication()->input;
$sub_id = $jinput->get('sub_id');
$db = JFactory::getDbo();
$query = $db->getQuery(true)
->select('*')
->from('#__unis_faculties')
->order('faculty_name');
$db->setQuery($query);
$rows = $db->loadObjectList();
//array_unshift($rows, JHtml::_('select.option', '', JText::_('COM_UNIS_FACULTIES'), 'value', 'text'));
return JHTML::_('select.genericlist',$rows,'faculties',array('class'=>'nourritures','option.attr'=>'data'));
}
Your code actually does not look to have problems.
As long as the query returns something you are on the right track.
Change select('*') to select('COL_A as value, COL_B as text').
Make sure you echo the result of the method getInput (not a great name btw, how about getFacultiesDropdown()
Related
I have some code below which demonstrates a hard-coded example of what I would like to accomplish dynamically.
At a high level, I wish to do something like select * from view_data_$app_state and then get all of the data from that views table into my mustache templates dynamically.
The code I currently must use to group multiple rows of data for a specific column along with the views data is:
<?php
error_reporting(E_ALL);
class Example {
function __construct(){
try {
$this->db = new PDO('mysql:host=localhost;dbname=Example', 'root','drowssap');
}
catch (PDOException $e) {
print($e->getMessage());
die();
}
}
function __destruct(){
$this->db = null;
}
function string_to_array($links_string){
return explode(",", $links_string);
}
function get_view_data(){
$q = $this->db->prepare('select *, GROUP_CONCAT(`links`) as "links" from `view_data_global` ');
$q->execute();
$result = $q->fetchAll(PDO::FETCH_ASSOC);
return $result;
}
}
$Example = new Example();
$result = $Example->get_view_data();
$result[0]["links"] = $Example->string_to_array($result[0]["links"]);
echo json_encode($result);
This gives me the perfect object while
GROUP_CONCAT seems to be doing the trick this way, however I MUST know the column name that will contain multiple rows before writing the query. I am trying to figure out an approach for this and wish to make a custom query + code example that will transform cols with multiple rows of null null and not empty data into an array like above - but return the data.. again like the code above.
Below is an output of the actual data:
[{"id":"1","title":"This is the title test","links":["main","about","store"]}];
How can I replicate this process dynamically on each view table?
Thank you so much SO!
You can use PDOStatement::fetch to retrieve your results, with fetch_style set to PDO::FETCH_ASSOC (some other values will also provide the same information). In this case, the result set will be array indexed by column name. You can access this information with foreach (array_expression as $key => $value)
See the documentation for additional information.
I'm coming from codeigniter background. Unlike codeigniter helper directory, i just created helper directory within app directory of Laravel. Just want to know how to execute query within this common function. Here is my codeigniter function.
function show_menu($primary_key_col, $parent_id, $sort_order)
{
$output = "";
$ci =& get_instance();
$ci->db->select("*");
$ci->db->where('is_active', "Y");
$ci->db->where('is_delete', "N");
$ci->db->where('parent_id', $parent_id);
($sort_order!="")?$ci->db->order_by($sort_order, "ASC"):"";
$query = $ci->db->get('tbl_cms_menus');
foreach ($query->result() as $row){
$output .= '<option value="'.$row->$primary_key_col.'">'.$indent.$row->menu_name.'</option>';
}
return $output;
}
I tried something like this in laravel file. but this code did't give me any result. Please tell me where i'm doing wrong in this code. thanks
function databaseTable()
{
$table = DB::table('tbl_cms_menus');
$get_rows = $table->get();
$count_rows = $table->count();
if($count_rows > 0){
foreach ($get_rows as $tbl)
{
echo $tbl->menu_name;
}
}
}
This code will rot so hard that it shipped pre-rotten.
But, if you want to just.. ram it into the app all dry like that.. then add something like this to your base controller class...
$whatever = crazyChainingStuff;
foreach ($whatever ...) { $topMenu .= ... }
View::share('topMenu', $topMenu);
If you want to learn how to write code that will do less damage to your company and your clients then I recommend starting by watching Uncle Bob's "Fundamentals" videos. At least the first 5-6. http://cleancoders.com
It looks like you are trying to generate a drop-down/select with some data from your database, in this case, you should pass the data required for the drop-down/select from your controller to the view where you have written your HTML, for example, in your view, you may have a select like this:
echo Form::select('cms_menu', $cms_menu, Input::old('cms_menu'));
Or this (If you are using Blade):
{{ Form::select('cms_menu', $cms_menu, Input::old('cms_menu')) }}
From your controller you should pass the $cms_menu which should contain the menu-items as an arrtay and to populate that array you may try something like this:
$menuItems = DB::table('tbl_cms_menus')->lists('menu_name','id');
return View::make('your_view_name', array('cms_menu' => $menuItems));
Also, you may use something like this:
// Assumed you have a Page model
$menuItems = Page::lists('menu_name', 'id');
return View::make('your_view_name', array('cms_menu' => $menuItems));
You may also read this article which is about building a menu from database using view composer (More Laravelish way). Read more about Form::select on documentation.
It was too late to give an answer. I was also from CodeIgniter background and when I learnt Laravel then first I try to find how can I write a query in Helper. My Team leader helped me.
I have converted your code in a helper function.
function show_menu($primary_key_col, $parent_id, $sort_order)
{
$query = DB::table('tbl_cms_menus')
->select('*')
->where('is_active', '=', 'Y')
->where('is_delete', '=', 'N')
->where('parent_id', '=', $parent_id);
($sort_order != "")? $query->orderBy($sort_order, "ASC") : "";
$resultData = $query->get()->toArray();
}
Here $resultData will be array format. Now, you can create a foreach loop according to your requirement.
I want to build the below query using joomla inbuilt database class.
SELECT *
FROM table_name
ORDER BY id DESC
LIMIT 1
This is the query I have built up to now.
$db =& JFactory::getDBO();
$query = $db->getQuery(true);
$query->select($db->nameQuote('*'));
$query->from($db->nameQuote(TABLE_PREFIX.'table_name'));
$db->setQuery($query);
$rows = $db->loadObjectList();
I don't know how to add the limit(LIMIT 1) to the query. Can someone please tell me how to do it? Thanks
Older than Joomla 3.0
$db = JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('*')
->from($db->nameQuote('#__table_name'))
->order($db->nameQuote('id').' desc');
$db->setQuery($query,0,1);
$rows = $db->loadObjectList();
$db->setQuery function takes 3 parameters. The first one being the query, then the start, then the limit. We can limit records as shown above.
Newer than Joomla 3.0
setLimit(integer $limit, integer $offset)
If you want just one row
$query->setLimit(1);
Read more
This should work as well:
$query->setLimit(1);
Documentation: http://api.joomla.org/cms-3/classes/JDatabaseQueryLimitable.html
SetLimit doesn't work for me in Joomla 3.4.x, so try:
Within the model:
protected function getListQuery()
{
// Create a new query object.
$db = JFactory::getDBO();
$query = $db->getQuery(true);
// Select some fields
$query->select('*');
$query->from('#__your_table');
$this->setState('list.limit', 0); // 0 = unlimited
return $query;
}
Davids answer: https://joomla.stackexchange.com/questions/4249/model-getlistquery-fetch-all-rows-with-using-jpagination
Run that before the model calls getItems and it will load all the
items for you.
A few caveats with this.
You can also do this outside the model, so if for instance you were in
your view. You could do the following:
$model = $this->getModel(); $model->setState('list.limit', 0);
Sometimes you can do this too early, before the model's state has been
populated, which will cause the model to get rebuilt from the user
state after you have set the limit, basically overriding the limit.
To fix this, you can force the model to populate its state first:
$model = $this->getModel(); $model->getState();
$model->setState('list.limit', 0); The actual populateState method is
protected, so outside the model you can't call it directly, but any
call to getState will make sure that the populateState is called
before returning the current settings in the state.
Update: Just had to revisit this answer, and I can confirm, both the methods
setLimit & order are working if used as below.
$query->order($db->qn($data->sort_column_name) . ' ' . $data->sort_column_order);
$query->setLimit($length,$start);
OLD ANSWER
As of 08/Sept/14 The solutions from #Dasun or #escopecz arent working for me on J3.x
but this old trick is working for me which is nice,
$query->order($db->qn('id') . ' DESC LIMIT 25');
And About your specific requirement of wishing to fetch only 1 row you could use :
$rows = $db->loadObject();
I'm trying to retrieve content using two items in the URL. Here is the php/symfony code that should do it:
$em = $this->getDoctrine()->getEntityManager();
$repository = $this->getDoctrine()
->getRepository('ShoutMainBundle:Content');
$query = $repository->createQueryBuilder('p')
->where('p.slug > :slug')
->andWhere('p.subtocontentid > :parent')
->setParameters(array(
'slug' => $slug,
'parent' => $page
))
->getQuery();
$content = $query->getSingleResult();
However, when this code is executed it returns the following error:
No result was found for query although at least one row was expected.
I have done some tests, and the data held in the $slug and $page variables hold the correct information. I have also tested the MySQL query and the query brings up the desired result, which confuses me further.
Have I missed something?
As it was answered here
You are getting this error because you are using the
getSingleResult() method. it generates an Exception if it can't find
even a single result. you can use the getOneOrNullResult() instead
to get a NULL if there isn't any result from the query.
Query#getSingleResult(): Retrieves a single object. If the result
contains more than one object, an NonUniqueResultException is thrown.
If the result contains no objects, an NoResultException is thrown. The
pure/mixed distinction does not apply.
No result was found for query although at least one row was expected.
Another reason could be:
You did this
$query = $this->getEntityManager()
->createQuery('
SELECT u FROM MyBundle:User u
WHERE u.email = :email')
->setParameter('email', $email);
return $query->getSingleResult();
Instead of this
$query = $this->getEntityManager()
->createQuery('
SELECT u FROM MyBundle:User u
WHERE u.email = :email')
->setParameter('email', $email);
$query->setMaxResults(1);
return $query->getResult();
Don't you want to use "=" instead of ">" ?
If you've got this message because used
$content = $query->getSingleResult();
you can just replace it with the row below
$content = $query->getOneOrNullResult(AbstractQuery::HYDRATE_SINGLE_SCALAR) ?? 0;
I'm having a weird problem.
I have this code
$topic contains "海賊_(ONE_PIECE)" from URI /trends/about/海賊_(ONE_PIECE)
I checked to echo $topic and it prints out 海賊_(ONE_PIECE)
$sql="SELECT wti.redirect_title FROM wikipedia_timelines AS wti WHERE wti.redirect_title = ? LIMIT 1";
$query = $this->db->query($sql,array($topic));
if ($row = $query->result_array())
{
The problem is that this code returns $row to be an empty array
Array
(
[0] => Array
(
[redirect_title] =>
)
)
However, if I use this code (replacing ? with the actual value of $topic, it works perfectly
$sql="SELECT wti.redirect_title FROM wikipedia_timelines AS wti WHERE wti.redirect_title = '海賊_(ONE_PIECE)' LIMIT 1";
$query = $this->db->query($sql,array($topic));
if ($row = $query->result_array())
{
Replacing ? with {$topic} will not make it working too.
This problem only occurs when $topic contains ( ) if it doesn't have () it works fine
I wonder what is the problem.
I suppose there is a problem with URI encoding, but I'm not sure how to fix it.
Please help me.
Thank you
I'm pretty sure your problem is that query binding escapes your input values (im guessing it doesn't like brackets).
try building your sql string with concatenation, like:
$sql = "SELECT wti.redirect_title FROM wikipedia_timelines AS wti WHERE wti.redirect_title = '".$topic."' LIMIT 1";
$query = $this->db->query($sql);
and see if that helps. Or try the active record class, I use it for japanese characters all the time and it seems to work ok.
// EDIT:
To allow brackets in the URI, try and change application/config.config.php and set
$config['permitted_uri_chars'] = 'a-z 0-9~%.:_\-()';
also try urldecode($topic); to get the kanji out.