I need to select a different column from a database based on a value in a different field.
Players:
ID EVENT_ID NAME TEAM
--------------------------------
1 1 Ann 1
2 1 Bob 2
3 2 Claire 1
Events:
ID EVENT_NAME TEAM_1 TEAM_2
----------------------------------------------
1 Football All Stars Tornadoes
2 Tennis Dynamos Best Team
Based on my tables I want to be able to search for player ID 2 and get their team name depending on the players.team value.
so something like this:
SELECT players.*,
(SELECT team+"players.team" AS team_name FROM events WHERE players.event_id = events.id)
WHERE players.id = '2'
that gets the result:
Player.ID: 1
Player.Name: Bob
Team_Name: Tornadoes
You can use CASE for that:
SELECT p.id, p.name,
CASE WHEN p.team = 1 THEN e.team_1 ELSE e.team_2 END AS Team_Name
FROM Players p
LEFT JOIN Events e
ON e.id = p.event_id
WHERE p.id = 2
SELECT p.id,p.name, IF(p.team = 1,e.team_1,e.team_2)
FROM players p
LEFT JOIN events e ON (p.event_id = e.id)
WHERE p.id = 2;
Related
Employee List (List 1)
USER ID NAME
1 John
2 Jane
3 Rob
4 Bill
5 Sally
Enrolled Students (List 1)
ID PID USER_ID
1 1 1
2 1 2
3 2 1
4 2 2
5 2 3
I am trying to find a way to determine if I want to look up who is not enrolled in x course.
So if I wanted to know which employees were not enrolled in Course 1 the result would be
USER_ID
3
4
5
Then if I wanted to know who is not enrolled in course 2
USER_ID
4
5
I tried this however it returns all students enrolled in the course. Where if the student has not been enrolled there is no NULL pid.
SELECT e.user_id, e.full_name, es.student
FROM employees e LEFT OUTER JOIN
enrolled_students es
ON e.user_id = es.student AND es.pid = 40
WHERE e.level = 3 AND es.student IS NULL ;
First we have to check who does enrolled in the course, then we have to get the list of names containing the other names except the ones returned in the first part of the query. Something like this can be done for this purpose:
SELECT
e1.*
FROM
employee e1
LEFT JOIN
(SELECT
e.user_id
FROM
employee e
JOIN enrolled_student es ON e.user_id = es.user_id
WHERE
es.pid = 1) t ON e1.user_id = t.user_id
WHERE
t.user_id IS NULL;
Try this:
select id from users where id not in (select user_id from enrolled where pid = 1)
Selects all users, which are not enrolled to course 1.
Any SQL Guru's out there I could use some help! I am creating a stored procedure that I believe needs a Union so that all the results are brought back with 1 SELECT statement.
I have simplified my problem to the tables below:
user
user_id username name DOB
------------------------------------------------------
1 JohnSmith1 John Smith 01/01/1990
2 LisaGreen17 Lisa Green 03/07/1986
3 BarneyB Barney Brown 09/12/1960
user_team
user_team_id user_id team_id total_score
-------------------------------------------------------------
1 1 1 29
2 2 7 37
3 3 2 15
private_league
priv_league_id league_name host_user league_password
-------------------------------------------------------------------------
1 Lisa's League 2 CSUASH429d9
2 Barney's Bonanza 3 Jkap89f5I01
user_team_private_league_M2M
id priv_league_id user_team_id
----------------------------------------
1 1 1
2 1 2
3 1 3
4 2 1
5 2 3
I would like to run a stored procedure with an input of a user_id which will bring back all leagues entered by the user, the host of each of those leagues, how many total players have entered in each league and what position the user is in for each of those leagues(sorted by total score).
At the moment I have:
CREATE DEFINER=`root`#`localhost` PROCEDURE `user_private_leagues`(IN v_user_id INT)
BEGIN
DECLARE userteamid INT;
# Retrieve user team from a user_id
SELECT user_team_id INTO userteamid
FROM user_team
WHERE user_id = v_user_id;
# Retrieve private league name and host user (for a userteam)
SELECT private_league.league_name, private_league.host_user
FROM user_team_private_league_M2M
INNER JOIN privateleague
ON user_team_private_league_M2M.priv_league_id=private_league.priv_league_id
WHERE user_team_id = userteamid;
END
This query does not include the total number of players for each league and the current position of the user
I have created a query to bring back the total users for each private league, with no user filter like so:
SELECT private_league_id, COUNT(*) AS total_users
FROM classicseasonmodel_classicseasonuserteamprivateleague
GROUP BY private_league_id;
A query for the user's current position can be worked out by using the answer to this question and using total_score.
I am extremely stuck with this at the moment - the perfect result from the SP will be as follows:
CALL user_private_leagues(3); (user id of BarneyB)
priv_league_name current_position total_users host_user
-----------------------------------------------------------------------
Lisa's League 3 3 LisaGreen17
Barney's Bonanza 2 2 BarneyB
Thanks!
Sorry but I didn't create the DB to test the SQL below. But you can start from there. No need for UNION. I didn't understand the business rule to compute the user's position in the league, since it may come from the team or the user.
select priv_league_id, league_name, host_user_name, count(*) as total_users
from (
select A.priv_league_id, A.league_name, D.name as host_user_name, B.user_team_id, C.user_id, D.
from private_league A
join user_team_private_league_M2M B
on A.priv_league_id = B. priv_league_id
join user_team C
on B.user_team_id = C. user_team_id
join user D
on A.host_user = D.user_id
) D
group by priv_league_id
Let take it step by step....
First ID, Count for pleague
SELECT private_league_id, COUNT(*) AS total_users
FROM classicseasonmodel_classicseasonuserteamprivateleague
GROUP BY private_league_id;
Now add in Name and host user
SELECT PL.league_name, LC.uCNT, PL.host_user
FROM (SELECT private_league_id AS pID, COUNT(*) AS uCNT
FROM classicseasonmodel_classicseasonuserteamprivateleague
GROUP BY private_league_id ) AS LC
LEFT JOIN private_league PL ON PL.priv_league_id = LC.pID
Now add in host user name
SELECT PL.league_name, LC.uCNT as total_users, hu.name as host_user
FROM (SELECT private_league_id AS pID, COUNT(*) AS uCNT
FROM classicseasonmodel_classicseasonuserteamprivateleague
GROUP BY private_league_id ) AS LC
LEFT JOIN private_league PL ON PL.priv_league_id = LC.pID
LEFT JOIN user hu ON PL.host_user = hu.user_id
Don't know where current position is.
This query will give users and position for each team, join to this and limit by user id to get one users position for each team:
select UT.user_id,
UT.team_id,
ROW_NUMBER() OVER (PARTITION BY team_id ORDER BY total_score DESC) AS team_position
from private_league L
join user_team_private_league_M2M LJ ON L.priv_league_id = LJ.priv_league_id
join user_team UT ON LJ.user_team_id = UT.user_team_id
I'm stuck for hours on an issue that might be pretty simple to solve but I'm just so lost...
I got 3 tables :
user
id name
----------
1 jack
2 john
...
car
id name
----------
1 ford
2 fiat
3 alfa
4 lada
...
user_car
id_user id_car
-----------------
1 2
1 4
2 1
2 2
2 3
For example, i want to get all users with cars which have id 1 AND 2 in the user_car table so I should get the id_user 2 only and I can't find the proper way to do it.
try this untested query:
select * from user join user_car car1 on id =car1.user_id
join user_car car2 on id =car2.user_id where car1.id_car=1 and car2.id_car=2
I would use UNION for this matter:
SELECT id as id_user from user where id in(1, 2)
UNION
SELECT id as id_car from car where id in (1, 2)
You can use COUNT to do this:-
SELECT user.name
FROM user
INNER JOIN user_car ON user.id = user_car.id_user
INNER JOIN car ON user_car.id_car = car.id
WHERE car.id IN (1,2)
GROUP BY user.name
HAVING COUNT(DISTINCT car.id) = 2
Note that this could be simplified to remove the need for the car table when you are just using the id of the car.
May be you want this
SELECT *
FROM USER
WHERE id IN
(SELECT id_user
FROM user_car
WHERE id_car=1 OR id_car=2);
I have 3 tables like this
soft_id soft_name
1 Office
pu_id soft_id pu_quantity
1 1 10
2 1 20
3 1 30
own_id soft_id owner
1 1 Peter
2 1 Tommy
3 1 David
How can I have a result like this in one single mysql query
soft_id soft_name sum(pu_quantity) count(owner)
1 Office 60 3
Try this:
SELECT a.soft_id,
a.soft_name,
b.p_cnt AS quantity,
c.o_cnt AS owner_count
FROM soft a
INNER JOIN
(SELECT soft_id, SUM(pu_quantity) AS p_cnt FROM product GROUP BY soft_id
) b
ON a.soft_id = b.soft_id
INNER JOIN
(SELECT soft_id, COUNT(*) AS o_cnt FROM owner GROUP BY soft_id
) c
ON b.soft_id = c.soft_id
GROUP BY a.soft_id,
a.soft_name
SQLFiddle
Note: assuming that the table names are soft, product and owner respectively.
Try this
SELECT S.soft_id,S.soft_name,P.sum(pu_quantity),O.count(owner)
FROM Soft S INNER JOIN Product P ON S.soft_id = P.soft_id
Inner JOIN Owner O = P.soft_id = O.soft_id
Group By S.soft_id,P.soft_id,O.soft_id,S.soft_name
I have a table called user_scores as below:
id | af_id | uid | level | record_date
----------------------------------------
1 | 1.1 | 1 | 3 | 2012-01-01
2 | 1.1 | 1 | 4 | 2012-02-01
3 | 1.2 | 1 | 3 | 2012-01-01
4 | 1.2 | 1 | 5 | 2012-03-01
...
I have another table call user_info as below:
uid | forename | surname | gender
-----------------------------------
1 | Homer | Simpson | M
2 | Marge | Simpson | F
3 | Bart | Simpson | M
4 | Lisa | Simpson | F
...
In user scores uid is the user id of a registered user on the system, af_id identifies a particular test a user submits. A user scores a level between 1 - 5 for each test, which can be submitted every month.
My problem is I need to produce an analysis at the end of the year to COUNT the number of users that have achieved each level for a particular test. The analysis is to show a gender split for male and female.
So for example an administrator would select test 1.1 and the system would generate stats based that would COUNT of the total MAX level achieved by each user in the year, with a gender split.
Any help is much appreciated. Thank you in advance.
-
I think I need to clarify myself a bit. Because a user can complete the test multiple times throughout the year, there will be multiple scores for the same test. The query should take the highest level achieved and include this in the count. An example result would be:
Male Results:
level1 | level2 | level3 | level4 | level5
------------------------------------------
2 | 5 | 10 | 8 | 1
I am not certain I get exactly what you mean, but as always I'll have a go. As I understand it you want to know how many people from each gender reached each level in a certain year.
SELECT MaxLevel,
COUNT(CASE WHEN ui.Gender = 'M' THEN 1 END) AS Males,
COUNT(CASE WHEN ui.Gender = 'F' THEN 1 END) AS Females
FROM User_Info ui
INNER JOIN
( SELECT MAX(Level) AS MaxLevel,
UID
FROM User_Scores us
WHERE af_ID = '1.1'
AND YEAR(Record_Date) = 2012
GROUP BY UID
) AS MaxUs
ON MaxUs.uid = ui.UID
GROUP BY MaxLevel
I've put some sample data on SQL Fiddle so you see if it is what you were after.
EDIT
To transpose the data so levels are along the top and Gender in the rows the following will work:
SELECT Gender,
COUNT(CASE WHEN MaxLevel = 1 THEN 1 END) AS Level1,
COUNT(CASE WHEN MaxLevel = 2 THEN 1 END) AS Level2,
COUNT(CASE WHEN MaxLevel = 3 THEN 1 END) AS Level3,
COUNT(CASE WHEN MaxLevel = 4 THEN 1 END) AS Level4,
COUNT(CASE WHEN MaxLevel = 5 THEN 1 END) AS Level5
FROM User_Info ui
INNER JOIN
( SELECT MAX(Level) AS MaxLevel,
UID
FROM User_Scores us
WHERE af_ID = '1.1'
AND YEAR(Record_Date) = 2012
GROUP BY UID
) AS MaxUs
ON MaxUs.uid = ui.UID
GROUP BY Gender
Note, that if there are ever more than 5 levels you will need to add more to the select statement, or start building dynamic SQL.
Assuming record_date holds only dates (without time parts):
SELECT
s.maxlevel,
COUNT(NULLIF(gender, 'F')) AS M,
COUNT(NULLIF(gender, 'M')) AS F
FROM user_info u
INNER JOIN (
SELECT
uid,
MAX(level) AS maxlevel
FROM user_scores
WHERE record_date > DATE_SUB(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) DAY)
AND af_id = '1.1'
GROUP BY
uid
) s ON s.uid = u.uid
GROUP BY
s.maxlevel
That will show you only the maximum levels found in the user_scores table. If you have a Levels table where all possible levels (1 to 5) are listed, you could use that table to get a complete list of levels. If some levels are not present in the requested subset of data, the corresponding rows will show 0s in both columns.
Here's the above script with minor changes to show the complete chart of levels:
SELECT
l.level AS maxlevel,
COUNT(NULLIF(gender, 'F')) AS M,
COUNT(NULLIF(gender, 'M')) AS F
FROM user_info u
INNER JOIN (
SELECT
uid, MAX(level) AS maxlevel
FROM user_scores
WHERE record_date > DATE_SUB(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) DAY)
AND af_id = '1.1'
GROUP BY
uid
) s ON s.uid = u.uid
RIGHT JOIN Levels l ON s.maxlevel = l.level
GROUP BY
l.level
Hope this is what your looking for!
Show number of records group by userid and gender of the max score for af_id '1.1'.
select count(*), info.uid, info.gender, max(score.level)
from user_info as info
join user_scores as score
on info.uid = score.uid
where score.af_id = '1.1'
group by info.uid, info.gender;
EDITED based on your edit.
select sum(if(a.gender="M",1,0)) Male_users, sum(if(a.gender="F",1,0)) Female_users
from myTable a where
a.level = (select max(b.level) from myTable b where a.uid=b.uid)
group by af_id.
I typed this in a rush. But it should work or at least get you where you need to go. E.G. if you need to specify time frame, add that.
You need something like
SELECT
uid,
MAX(level)
WHERE
record_date BETWEEN '2012-01-01' AND '2012-12-31'
AND af_id='1.1'
GROUP BY uid
If you need the gender splits then depending on what stat you need per gender you can either add a JOIN on the user_info table into this query (to get the MAX per gender) to wrap this as a sub-query and JOIN on the whole thing.