Searching a Record from Middle of the Table - mysql

Question

I am facing issue in finding the data from MySql table.
Table A:
+-------+-------------+------+-----+-------------------+-------+
| ID | Table_b_fk |Value | age | name | score |
+-------+-------------+------+-----+-------------------+-------+
| 01 | 01 | 255 | 21 | Tom | 65 |
| 02 | 02 | 36 | 20 | Peter | 95 |
| 03 | 03 | 25 | 22 | John | 65 |
| 04 | 04 | 36 | 20 | Bond | 95 |<<----First
| 05 | 05 | 258 | 22 | Smith | 65 |
| 06 | 06 | 420 | 20 | Robert | 95 |
| 07 | 07 | 258 | 22 | Nisarg Patel | 65 |
| 08 | 08 | 16 | 21 | Peter | 95 |
| 09 | 09 | 25 | 23 | J0k | 65 |
| 10 | 10 | 36 | 22 | Prodigitalson | 95 |
| 11 | 11 | 205 | 22 | Silver | 65 |<<----Next
| 12 | 12 | 37 | 20 | Json | 95 |
| 13 | 13 | 285 | 23 | Villa | 65 |
| 14 | 14 | 36 | 22 | Parker | 95 |
+-------+-------------+------+-----+-------------------+-------+
Table B:
+-------+-------------+------+-----+-------------------+-------+
| ID | Result | M1 | M2 | name | score |
+-------+-------------+------+-----+-------------------+-------+
| 01 | Pass | 30 | 26 | Tom | 65 |
| 02 | Pass | 30 | 20 | Peter | 95 |
| 03 | Pass | 25 | 60 | John | 65 |
| 04 | Pass | 100 | 100 | Bond | 95 |<<----First
| 05 | Pass | 55 | 65 | Smith | 65 |
| 06 | Pass | 80 | 95 | Robert | 95 |
| 07 | Pass | 65 | 75 | Nisarg Patel | 65 |
| 08 | Pass | 56 | 71 | Peter | 95 |
| 09 | Pass | 90 | 96 | J0k | 65 |
| 10 | Pass | 96 | 96 | Prodigitalson | 95 |
| 11 | Pass | 100 | 100 | Silver | 65 |<<----Next
| 12 | Pass | 47 | 92 | Json | 95 |
| 13 | Pass | 82 | 73 | Villa | 65 |
| 14 | Pass | 86 | 72 | Parker | 95 |
+-------+-------------+------+-----+-------------------+-------+
I am joining TableA & TableB, where in TableA Table_b_fk is foreign key to TableB.
I am finding the record which matches the TableB column M1 & M2 = 100.
My Scenario: 1
I know the first occurrence of the match record ID : 04 in TableA. I want to do a search to find the next record with M1 & M2 = 100. (Record Id-11) But the search should not start from 01. It should start from the last found record Id. That is from O4 the search should start to find the next occurrence of the record.
My Try:
I tried to find using Limit but it didn't help me to find. Can some one help me in this?
Edit: 1
My Scenario: 2
In my second case my TableB has repeated Data and the ID was foreign in TableA. How can I fins the record. ? with the matching ID/M1/M2 values: I found a solution for that. I just want to find the Current Record FOREIGN KEY and Check for the next occurrence of the record in the same table and I can get the next record rite?
In this case my TableB record are not as same as TableA records. In other words my TableA records will point to tableA. Many-to-one. Is this rite?
Edit: 2
Thanks for all your efforts and knowledge I found a solution for scenario:2 check it:
CREATE TABLE TableB (
ID Int,
Result VARCHAR(20),
M1 INT,
M2 INT,
name VARCHAR(20),
Score INT);
INSERT INTO TableB VALUES
( 11 , 'Pass' , 30 , 26 , 'Tom' , 65 ),
( 13 , 'Pass' , 30 , 20 , 'Peter' , 95 ),
( 80 , 'Pass' , 25 , 60 , 'John' , 65 ),
( 81 , 'Pass' , 100 , 100 , 'Bond' , 95 ),
( 90 , 'Pass' , 55 , 65 , 'Smith' , 65 ),
( 96 , 'Pass' , 80 , 95 , 'Robert' , 95 ),
( 97 , 'Pass' , 65 , 75 , 'Nisarg Patel' , 65 ),
( 98 , 'Pass' , 56 , 71 , 'Peter' , 95 ),
( 99 , 'Pass' , 90 , 96 , 'J0k' , 65 ),
( 100 , 'Pass' , 96 , 96 , 'Prodigitalson' , 95 ),
( 101 , 'Pass' , 10 , 10 , 'Silver' , 65 ),
( 103 , 'Pass' , 47 , 92 , 'Json' , 95 ),
( 201 , 'Pass' , 82 , 73 , 'Villa' , 65 ),
( 222 , 'Pass' , 86 , 72 , 'Parker' , 95 )
;
CREATE TABLE TableA
(`ID` int, `Table_b_fk` int, `Value` int, `age` int, `name` varchar(13), `score` int)
;
INSERT INTO TableA
(`ID`, `Table_b_fk`, `Value`, `age`, `name`, `score`)
VALUES
(01, 11, 255, 21, 'Tom', 65),
(02, 81, 36, 20, 'Peter', 95),
(03, 80, 25, 22, 'John', 65),
(04, 97, 36, 20, 'Bond', 95),
(05, 81, 258, 22, 'Smith', 65),
(06, 06, 420, 20, 'Robert', 95),
(07, 81, 258, 22, 'Nisarg Patel', 65),
(08, 08, 16, 21, 'Peter', 95),
(09, 96, 25, 23, 'J0k', 65),
(10, 101, 36, 22, 'Prodigitalson', 95),
(11, 222, 205, 22, 'Silver', 65),
(12, 12, 37, 20, 'Json', 95),
(13, 201, 285, 23, 'Villa', 65),
(14, 101, 36, 22, 'Parker', 95)
;
Solution for that is:
SELECT a.id
FROM TableB b
INNER JOIN TableA a
ON a.Table_b_fk = b.id
WHERE M1 = 100 and M2 = 100 AND a.ID>4 limit 1
where the limit just limits the next record.. (answer is 5).
I case of Doctrine 2: Use the below Query code.
$qry = $this->manager()->createQueryBuilder()
->select(array('e', 's'))
->from('YOUR_DOMAIN', 'e')
->Join('e.table_b_k', 's')
->where("s.m1 = ?", $valueone)
->andwhere("s.m2 = ?", $valuetwo)
->andwhere("e.id > ?", $currentrecord)
->setMaxResult(1);
Note: YOUR_DOMAIN here is the TableA. TableA and TableB should be joined through the Mapping so we dont need to Join/Reference int he Query.. directly as TableB. The will be done by the second line Join in the above example. It is not tested as of now.

Answer 1

What about this give it a try
SELECT b.id AS next_id FROM tableb b LEFT JOIN tablea a
ON (b.id =a.Table_b_fk ) WHERE b.M1=100 AND b.M2 =100 AND b.id >4
ORDER BY b.id ASC LIMIT 1
It gives the next occurrence of *M1 =100 and M2 =100 *
See Fiddle Example it returns 11 the next occurrence *M1 =100 and M2 =100 *

Answer 2

If I understand your question correctly, I think you are looking for this:
SET #id:=4;
SELECT *
FROM TableA
WHERE Table_b_fk =
(SELECT MIN(ID)
FROM TableB
WHERE (M1,M2) = (SELECT M1, M2 FROM TableB WHERE ID=#id)
AND ID>#id)
This query will select the second row from TableA that has M1=100 and M2=100 in the second table.

Answer 3

try this
SELECT a.id
FROM TableB b
INNER JOIN TableA a
ON a.Table_b_fk = b.id
WHERE M1 = 100 and M2 = 100 AND b.ID>4
output:
ID
11
demo FIDLLE

Answer 4

I am finding the record which matches the TableB column M1 & M2 = 100.
Assuming you mean:
I am finding the tableA record which matches the TableB column M1 = 100 AND M2 = 100.
SELECT *
FROM table_a a
WHERE EXISTS (
SELECT *
FROM table_b b
WHERE b.id = a.tableb_fk
AND b.m1 = 100 AND b.m2 = 100
);
UPDATE: since the OP appears to want to suppress the first matching record from the result (I assume: the one with the lowest id), one could add an extra EXIST to the WHERE clause to suppress the first match:
SELECT *
FROM table_a a
WHERE EXISTS (
SELECT *
FROM table_b b
WHERE b.id = a.tableb_fk
AND b.m1 = 100 AND b.m2 = 100
AND EXISTS (
SELECT *
FROM table_b bb
WHERE bb.id < b.id
AND bb.m1 = 100 AND bb.m2 = 100
)
);