I've 3 tables below. (sample)(mySql script)
customer
cust_id
cust_name
user_id
user_id_2
user
user_id
em_id
employee
em_id
em_name
How can I call the em_name field for user_id, and em_name field for user_id_2 by crossing user table in the same time with join??
Try this
SELECT q1.* ,
q2.em_name AS 'em_name_2'
FROM (SELECT c.cust_id ,
c.cust_name ,
c.user_id ,
c.user_id_2 ,
e.em_name
FROM dbo.customer AS c
INNER JOIN dbo.[user] AS u ON c.user_id = u.user_id
INNER JOIN dbo.employee AS e ON u.em_id = e.em_id
) q1
CROSS JOIN
( SELECT e.em_id ,
e.em_name
FROM dbo.customer AS c
INNER JOIN dbo.[user] AS u ON c.user_id_2 = u.user_id
INNER JOIN dbo.employee AS e ON u.em_id = e.em_id
) q2
Related
SELECT t.id
, t.department
, t.owner
, t.client
, u.username as owner_name
, c.name as catagery
, d.dept_name as deptname
, t.periority
, t.status
, t.estimate
, cl.takeaway_name
from tbl_task t
JOIN tbl_user u
ON u.id = t.owner
JOIN tbl_task_catagery c
ON c.id = t.catagery
JOIN tbl_department d
ON d.id = t.department
JOIN tbl_clients cl
ON cl.id = t.client
and t.status = 0
and (t.id in (select task_id
from tbl_task_note tn
where tn.user_id = '69'
and tn.id in (select max(id)
from tbl_task_note tt
where tt.task_id = tn.task_id
)
)
)
order by t.id
Note : The above query is used for check users hold tasks. tbl_task_note table is used for check task notes for separate users task.
With this query you will get the task that have the last task_note registered, including the user, departament, client, and some other.
If it is what you need you can just do this.
select
t.id,
t.department,
t.owner,
t.client,
u.username as owner_name,
c.name as catagery,
d.dept_name as ptname,
t.periority,
t.status,
t.estimate,
cl.takeaway_name
from tbl_task t
INNER JOIN tbl_user u ON u.id=t.owner
INNER JOIN tbl_task_catagery c ON c.id=t.catagery
INNER JOIN tbl_department d ON d.id=t.department
INNER JOIN tbl_clients cl ON cl.id=t.client and t.status=0
INNER JOIN (select * from tbl_task_note where id =
(select max(id) from tbl_task_note)
)tb on tb.task_id = t.id
order by t.id
That way you can improve your query.
You shoud also ensure that your keys compared are foreign keys to get faster consults.
I am using Laravel 5.1 in my application. My MySQL query is
"Select * from "
. "(Select u.* from "
. "( "
. "SELECT u2.id as user_id, u2.fname as fname, u2.lname as lname, u2.uname as uname, u2.email as email, u2.address as address, u2.city_id as city_id, u2.website as website FROM users u1, users u2 where u1.city_id = u2.city_id && u1.id = '$this->current_user_id' )
u left join follows f on u.user_id = f.following_id where f.following_id is null
UNION
Select uu.id as user_id, uu.fname as fname, uu.lname as lname, uu.uname as uname, uu.email as email, uu.address as address, uu.city_id as city_id, uu.website as website from users uu where uu.id in (Select u.user_id from (SELECT user_id FROM reviews group by user_id order by count(user_id) desc5
) u left join follows f on u.user_id=f.following_id where f.following_id is null
)
)
T LIMIT 5"
How can I convert it into Laravel Eloquent?
Is that query functionally identical to this one:
SELECT u2.id user_id
, u2.fname
, u2.lname
, u2.uname
, u2.email
, u2.address
, u2.city_id
, u2.website
FROM users u1
JOIN users u2
ON u2.city_id = u1.city_id
LEFT
JOIN follows f
ON f.following_id = u.user_id
WHERE f.following_id is null
UNION
SELECT uu.id user_id
, uu.fname
, uu.lname
, uu.uname
, uu.email
, uu.address
, uu.city_id
, uu.website
FROM users uu
JOIN
( SELECT r.user_id
FROM reviews r
LEFT
JOIN follows f
ON f.following_id = r.user_id
WHERE f.following_id IS NULL
GROUP
BY user_id
ORDER
BY COUNT(user_id) DESC
LIMIT 5
) x
ON x.user_id = uu.id;
?
I have 3 tables "maintenances", "cars", "users" . I want to select all data from table maintenance with a distinct car_id and the last record for each distinct (based on max maintenance_date)
SELECT
m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
FROM
maintenances AS m
LEFT JOIN users AS u ON u.id = m.user_id
LEFT JOIN cars AS c ON c.id = m.car_id
WHERE
maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id)
The problem is that this query returns only one record which has the max date from all records. I want all records (distinct car_id and from records with the same car_id to display only values for max(maintenance_date))
This is your query:
SELECT m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
----------------------------------------------------------------^
FROM maintenances AS m LEFT JOIN
users AS u
ON u.id = m.user_id LEFT JOIN
cars AS c
ON c.id = m.car_id
WHERE maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id);
It is an aggregation query. Without a group by, only one row is returned (all the rows are in one group). So, add the group by:
SELECT m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
FROM maintenances AS m LEFT JOIN
users AS u
ON u.id = m.user_id LEFT JOIN
cars AS c
ON c.id = m.car_id
WHERE maintenance_date = (SELECT MAX(m2.maintenance_date) FROM maintenances m2 WHERE m2.car_id = m.car_id);
GROUP BY c.id
I also fixed the correlation statement, to be clear that it is correlated to the outer query.
add GROUP BY u.username .
WHERE
maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id)
GROUP BY u.username
I've a very nice query that selects friends of the current user. user_id = 2 in the example. His friend is user_id = 4.
I want the same query to fetch the number of words user_id 2 has with selected friends. In this case they have word = love, and this is also word they both have, so I want in_common row to say = 1.
Is it possible without changing too much current query?
Should I start from scratch?
SQL FIDDLE
Assuming that both users would have an entry for 'love' in the words_en table then something like this maybe:-
SELECT b.name_surname,
b.avatar,
b.friend_words,
(b.friend_msg_id) AS friend_msg_id,
words_common.words_in_common,
COUNT(m.id) AS unread_msg
FROM
(
SELECT a.name_surname as name_surname,
a.avatar as avatar,
GROUP_CONCAT(DISTINCT w.word ORDER BY w.word ASC) AS friend_words,
(a.friend_id) AS friend_msg_id
FROM
(
SELECT f1.asked_user_id AS friend_id,
f1.created,
u.name_surname,
u.avatar
FROM friends AS f1
INNER JOIN friends AS f2
ON f1.asked_user_id = f2.asker_user_id
AND f1.asker_user_id = f2.asked_user_id
INNER JOIN users AS u ON f1.asked_user_id = u.id
WHERE f1.status = 1 AND f2.status = 1
AND f1.asker_user_id = 2
) a
LEFT JOIN connections c ON c.user_id = a.friend_id
AND c.invisible <> 1 AND c.deleted <> 1
LEFT JOIN words_en w ON c.word_id = w.id
GROUP BY 1
) b
LEFT JOIN messages m ON m.to_user_id = 2
AND m.from_user_id = b.friend_msg_id
AND m.seen = 0
LEFT OUTER JOIN
(
SELECT b.user_id AS friend_id, GROUP_CONCAT(a.word) AS words_in_common
FROM words_en a
INNER JOIN words_en b
ON a.word = b.word
WHERE a.user_id = 2
GROUP BY b.user_id
) words_common
ON b.friend_msg_id = words_common.friend_id
GROUP BY b.name_surname, b.avatar, b.friend_words, b.friend_msg_id
ORDER BY unread_msg DESC
EDIT - modification to use connections table to find common words:-
SELECT b.name_surname,
b.avatar,
b.friend_words,
(b.friend_msg_id) AS friend_msg_id,
words_common.words_in_common,
COUNT(m.id) AS unread_msg
FROM
(
SELECT a.name_surname as name_surname,
a.avatar as avatar,
GROUP_CONCAT(DISTINCT w.word ORDER BY w.word ASC) AS friend_words,
(a.friend_id) AS friend_msg_id
FROM
(
SELECT f1.asked_user_id AS friend_id,
f1.created,
u.name_surname,
u.avatar
FROM friends AS f1
INNER JOIN friends AS f2
ON f1.asked_user_id = f2.asker_user_id
AND f1.asker_user_id = f2.asked_user_id
INNER JOIN users AS u ON f1.asked_user_id = u.id
WHERE f1.status = 1 AND f2.status = 1
AND f1.asker_user_id = 2
) a
LEFT JOIN connections c ON c.user_id = a.friend_id
AND c.invisible <> 1 AND c.deleted <> 1
LEFT JOIN words_en w ON c.word_id = w.id
GROUP BY 1
) b
LEFT JOIN messages m ON m.to_user_id = 2
AND m.from_user_id = b.friend_msg_id
AND m.seen = 0
LEFT OUTER JOIN
(
SELECT b.user_id AS friend_id, GROUP_CONCAT(c.word) AS words_in_common
FROM connections a
INNER JOIN connections b
ON a.word_id = b.word_id
INNER JOIN words_en c
ON b.word_id = c.id
WHERE a.user_id = 2
GROUP BY b.user_id
) words_common
ON b.friend_msg_id = words_common.friend_id
GROUP BY b.name_surname, b.avatar, b.friend_words, b.friend_msg_id
ORDER BY unread_msg DESC
I have following tables:
Table: user
Columns
- id
- username
- full_name
Table: pet
Columns
- id
- pet_name
Table: results
Columns
- id
- user_id_1
- user_id_2
- user_id_3
- pet_id
- date
- some_text
Can I make an SQL query witch will give me one row with: id, full_name, full_name, full_name, pet_name, date, some_text where the results.id is 3?
select u1.full_name
, u2.full_name
, u3.full_name
, p.pet_name
, r.date
, r.some_text
from Results r
join User u1
on u1.id = r.user_id_1
join User u2
on u2.id = r.user_id_2
join User u3
on u3.id = r.user_id_3
join pet p
on p.id = r.pet_id
where r.id = 3
Try Following query :
SELECT A.id, B.full_name, C.full_name, D.full_name, E.pet_name, A.date, A.some_text
FROM RESULTS AS A
LEFT OUTER JOIN USER AS B ON A.USER_ID1 = B.ID
LEFT OUTER JOIN USER AS C ON A.USER_ID2 = C.ID
LEFT OUTER JOIN USER AS D ON A.USER_ID3 = D.ID
LEFT OUTER JOIN PET AS E ON A.PET_ID = E.ID
WHERE A.id = 3