Why do languages have operator precedence? [closed] - operator-precedence

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Closed 9 years ago.
Why not simply evaluate Left to Right? Can someone explain how precedence makes code more readable? To me it seems to require more thought and more possibility for error. Einstein said, "Everything should be made as simple as possible, but no simpler." I guess he wasn't a programmer.

because in Mathematics, before the invention of any computer language, there was operator precedence, e.g.
2 + 5 * 3 = 17 (and not 21)
A language not having a higher precedence for the * operator than for the + operator would generate confusion.
Another example from C++:
std::cout << 7 * 8 << std::endl;
If the * operator did not have precedence over the << operator, this would not compile:
std::cout << 7 would be evaluated first, yielding std::cout as a result (with the side effect that 7 would be printed)
then one would want to evaluate std::cout * 8 which -- unless somebody defines a really weird operator * for multiplying an outputstream by an integer -- is not defined.
Operator precedence allows not having to put unnecessary parentheses 'within common sense' (although I agree that in some cases people introduce bugs because they are not aware of the actual precedences)
Now you might ask: why does Mathematics have operator precedence ? This wikipedia article mentions some historical facts and links to a discussion forum. For me, an imporant argument is the one that when writing polynomials, e.g.
ax^2 + bx + c
without operator precedence, one would have to write them as:
(a(x^2)) + (bx) + c

The purpose of precedence is not to make it more readable, its to (a) standardize and (b) keep with standards set in mathematics, such as PEMDAS.

APL does not have operator precedence (except parentheses); code reads right to left (like Hebrew or Arabic). That said, APL is a niche language and this is one reason why. Most other languages, as other answers already point out, mimic the long-established precedence rules of arithmetic, which in turn appear to me to arise from how typical use cases (i.e., real-world problems) can be modeled with a minimum number of parentheses.

The digital world simply follows the old-school "real" world where the BEDMAS rules: Brackets, Exponents, Division, Multiplication, Addition, Subtraction.
Better to follow the real world, than try to refedefine reality and end up with programmers doing
1 + 2 * 3
as
(1 + 2) * 3 = 9
v.s. a realworlder doing
1 + (2 * 3) = 7
and sending your multimillion dollar probe into an invalid atmospheric descent profile because someone "carried the 1" wrong.

It is possible to do away with precedence rules - or more correctly, have just one such rule - as APL demonstrates.
"It has just one simple, consistent, and recursive precedence rule: the right argument of a function is the result of the entire expression to the right of that function."
For example, in "J" (an APL variant):
1+2*3 => 7 Computed as 1+(2*3)
2*3+1 => 8 Computed as 2*(3+1)
APL (and J) has so many operators, it would be difficult to remember the precedence and associativity rules of each and every one of them.

The reason why there is an operator precedence is because you should see a sum like 2*4 as a WHOLE number.
So you could think of it in a way that 2*4 doesn't exist. It's simply 8.
So what you're basically doing is "simplifying" the sum, like: 2+10*2 This basically says: 2+20.
As in the following sum: 2143+8^2+6^9. You don't want to write out 2143+262144+10077696. (And imagine how this could look like if you have a much larger formula)
It's basically to simplify the look of the sum. And both addition and subtraction are the most basic form of operations. So that's why there is a precedence, it is to increase the readbility of the sum.
And like i said, since the + and - operators are the most basic operators there are, then it makes sense to first solve the more "complicated" operators.

For example, with operator precedence the following evaluates to 14:
2 + 3 * 4
without it would evaluate to 20 which is unexpected, imho.

Take an example , if there were no operator precedence how would you evaluate this expression :
1+2/3
Well , some would say that you want to divide the sum of 1+2 by 3 . Others that you want to add 2/3 to 1 !

Related

How would '1+1' look when just using 1 and 0? [duplicate]

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Is it possible to program in binary?
(6 answers)
Closed 2 years ago.
Is that possible? Can this be done using just 1 and 0 (true/false, on/off ...)?
If so, how would this code look?
If this example is too complex i am open to all other kinds of examples, but would like to have an operation included, because i have no idea how such operations get encoded (i guess they also are just an entry in a conversion chart)
The reason why i ask this, is that i want to give people a concrete example why datatypes and functions/operations are a practical abstraction (easier to read). Im writing a tutorial.
In a 1-bit wide integer = boolean value, carry-out has nowhere to go, so addition simplifies to just XOR.
Fun fact: XOR is add-without-carry. It's part of implementing a single-bit adder out of logic gates, e.g. a "half adder" that has 2 inputs (no carry-in) and produces a sum and carry-out. (sum = a xor b, carry = a AND b). A simple 32-bit adder could be build out of a half adder and 31 "full adders". Or more adders in parallel with tricks to optimize it for lower latency than a simple ripple-carry binary adders.
Carryless multiplication is a thing in some crypo, where summing partial products is done with XOR instead of normal binary addition.
See also What is the best way to add two numbers without using the + operator? for a software use of the same idea.

Computing powers of -1

Is there an established idiom for implementing (-1)^n * a?
The obvious choice of pow(-1,n) * a seems wasteful, and (1-2*(n%2)) * a is ugly and not perfectly efficient either (two multiplications and one addition instead of just setting the sign). I think I will go with n%2 ? -a : a for now, but introducing a conditional seems a bit dubious as well.
Making certain assumptions about your programming language, compiler, and CPU...
To repeat the conventional -- and correct -- wisdom, do not even think about optimizing this sort of thing unless your profiling tool says it is a bottleneck. If so, n % 2 ? -a : a will likely generate very efficient code; namely one AND, one test against zero, one negation, and one conditional move, with the AND+test and negation independent so they can potentially execute simultaneously.
Another option looks something like this:
zero_or_minus_one = (n << 31) >> 31;
return (a ^ zero_or_minus_one) - zero_or_minus_one;
This assumes 32-bit integers, arithmetic right shift, defined behavior on integer overflow, twos-complement representation, etc. It will likely compile into four instructions as well (left shift, right shift, XOR, and subtract), with a dependency between each... But it can be better for certain instruction sets; e.g., if you are vectorizing code using SSE instructions.
Incidentally, your question will get a lot more views -- and probably more useful answers -- if you tag it with a specific language.
As others have written, in most cases, readability is more important than performance and compilers, interpreters and libraries are better at optimizing than most people think. Therfore pow(-1,n) * a is likely to be an efficient solution on your platform.
If you really have a performance issue, your own suggestion n%2 ? -a : a is fine. I don't see a reason to worry about the conditional assignment.
If your language has a bitwise AND operator, you could also use n & 1 ? -a : a which should be very efficient even without any optimization. It is likely that on many platforms, this is what pow(a,b) actually does in the special case of a == -1 and b being an integer.

Why bitwise operators are popular in sport programming

I'm a newbie in one of a sport programming service and found that winning solutions often use bitwise operators.
Here is an example.
Write a function, which finds a difference between two
arrays (consider that they differ by one element).
The solutions are:
let s = x => ~eval(x.join`+`);
let findDiff = (a, b) => s(b) - s(a);
and
let findDiff = (a, b) => eval(a.concat(b).join`^`);
I would like to know:
The explanation of those two examples (bitwise part).
What's the advantage of using bitwise operators on decimal numbers?
Is that faster to operate with bitwise operations rather than normal one?
Update:
I didn't fully understand why my question is marked as a duplicate to ~~ vs parseInt. That's good to know, why this operator replaces parseInt and probably helpful for sport programming. But it doesn't answer on my question.
Code golf isn't focused on bitwise operators, is about code length.
Bitwise operators are not necessary faster, but generally fast enough. They are concise (and usually harder to read, but that's side effect).
~~ is a shorter (and usually more preformant) alternative to parseInt with a considerable number of remarks. In regular (non-golf) code it should be used only if it provides the behaviour that is more desirable than parseInt or in performance-sensitive context.
~a is roughly equal to parseInt(a) * -1 - 1. It can be used as a shorter alternative to ~~a in this particular example, s(b) - s(a), because * -1 - 1 part is eliminated on subtraction (the sign should be taken into account).

Why doesn't the unary plus have the meaning of absolute value? [closed]

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Closed 9 years ago.
Across I have seen many questions of why the unary plus exists in the specific language like:Why does F# have a unary plus operator?
What is the purpose of Java's unary plus operator?
What's the point of unary plus operator in Ruby?
Use of unary plus operator
And they all say that the '+' is only for overloading if you need it,
or it is for performing some rare/unnecessary language-specific task.
But why isn't there any actual use of it?
It would make sense (atleast to me) that a unary '+' should act as an absolute value like:
int x = -5; //x is -5
x = +x; //x is now 5
Is there any specific reason why this hasn't been done?
or is it because this only makes sense to me?
It's not implemented that way because math doesn't work that way.
In math:
note: the following is math on a blackboard, not a programming language
+ -5 = -5
- -5 = 5
Doing it any other way will confuse anyone who's ever finished highschool.
Obviously, the above is fairly weak answer since you can indeed implement the action taken by the ASCII character '+' in the code to work differently from math. In Lisp for example, the + operator does not work like regular highschool math:
;;; Adding two numbers:
+ 1 2
And on TI calculators, it's even reversed:
1 2 +
You could argue that implementing + the way you describe in your programming language makes sense. There are a number of different arguments on why it should not be done including the principle of least surprise, a language should model the problem domain, it's what we've been taught at school etc. All of them are essentially weak arguments because they don't provide a fundamental reason for a machine to treat + the same way as math.
But here's the thing, humans are emotional creatures. We like what's familiar and cringe at something that goes against something we've been taught. And programmers don't like being surprised by + behaving differently from normal. And programmers are the ones who create programming languages so it makes sense that they implement + the way they do.
One programmer may not think like that, or a small group, and they are free to create a programming language that implements + differently. But they'll have a hard time convincing the programming community at large they what they did was right.
So it doesn't matter so much that all the arguments that can be made against + acting as abs() are essentially weak. As long as the majority feels it's right + will behave the same as regular math.

What's the absolute minimum a programmer should know about binary numbers and arithmetic? [closed]

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Although I know the basic concepts of binary representation, I have never really written any code that uses binary arithmetic and operations.
I want to know
What are the basic concepts any
programmer should know about binary
numbers and arithmetic ? , and
In what "practical" ways can binary
operations be used in programming. I
have seen some "cool" uses of shift
operators and XOR etc. but are there
some typical problems where using binary
operations is an obvious choice.
Please give pointers to some good reference material.
If you are developing lower-level code, it is critical that you understand the binary representation of various types. You will find this particularly useful if you are developing embedded applications or if you are dealing with low-level transmission or storage of data.
That being said, I also believe that understanding how things work at a low level is useful even if you are working at much higher levels of abstraction. I have found, for example, that my ability to develop efficient code is improved by understanding how things are represented and manipulated at a low level. I have also found such understanding useful in working with debuggers.
Here is a short-list of binary representation topics for study:
numbering systems (binary, hex, octal, decimal, ...)
binary data organization (bits, nibbles, bytes, words, ...)
binary arithmetic
other binary operations (AND,OR,XOR,NOT,SHL,SHR,ROL,ROR,...)
type representation (boolean,integer,float,struct,...)
bit fields and packed data
Finally...here is a nice set of Bit Twiddling Hacks you might find useful.
Unless you're working with lower level stuff, or are trying to be smart, you never really get to play with binary stuff.
I've been through a computer science degree, and I've never used any of the binary arithmetic stuff we learned since my course ended.
Have a squizz here: http://www.swarthmore.edu/NatSci/echeeve1/Ref/BinaryMath/BinaryMath.html
You must understand bit masks.
Many languages and situations require the use of bit masks, for example flags in arguments or configs.
PHP has its error level which you control with bit masks:
error_reporting = E_ALL & ~E_NOTICE
Or simply checking if an int is odd or even:
isOdd = myInt & 1
I believe basic know-hows on binary operations line AND, OR, XOR, NOT would be handy as most of the programming languages support these operations in the form of bit-wise operators.
These operations are also used in image processing and other areas in graphics.
One important use of XOR operation which I can think of is Parity check. Check this http://www.cs.umd.edu/class/sum2003/cmsc311/Notes/BitOp/xor.html
cheers
The following are things I regularly appreciate knowing in my quite conventional programming work:
Know the powers of 2 up to 2^16, and know that 2^32 is about 4.3 billion. Know them well enough so that if you see the number 2147204921 pop up somewhere your first thought is "hmm, that looks pretty close to 2^31" -- that's a very effective module for your bug radar.
Be able to do simple arithmetic; e.g. convert a hexadecimal digit to a nybble and back.
Have some vague idea of how floating-point numbers are represented in binary.
Understand standard conventions that you might encounter in other people's code related to bit twiddling (flags get ORed together to make composite values and AND checks if one's set, shift operators pack and unpack numbers into different bytes, XOR something twice and you get the same something back, that kind of thing.)
Further knowledge is mostly gravy unless you work with significant performance constraints or do other less common work.
At the absolute bare minimum you should be able to implement a bit mask solution. The tasks associated with bit mask operations should ensure that you at least understand binary at a superficial level.
From the top of my head, here are some examples of where I've used bitwise operators to do useful stuff.
A piece of javascript that needed one of those "check all" boxes was something along these lines:
var check = true;
for(var i = 0; i < elements.length; i++)
check &= elements[i].checked;
checkAll.checked = check;
Calculate the corner points of a cube.
Vec3f m_Corners[8];
void corners(float a_Size){
for(size_t i = 0; i < 8; i++){
m_Corners[i] = a_Size * Vec3f(axis(i, Vec3f::X), axis(i, Vec3f::Y), axis(i, Vec3f::Z));
}
}
float axis(size_t a_Corner, int a_Axis) const{
return ((a_Corner >> a_Axis) & 1) == 1
? -.5f
: +.5f;
}
Draw a Sierpinski triangle
for(int y = 0; y < 512; y++)
for(int x = 0; x < 512; x++)
if(x & y) pixels[x + y * w] = someColor;
else pixels[x + y * w] = someOtherColor;
Finding the next power of two
int next = 1 << ((int)(log(number) / log(2));
Checking if a number is a power of two
bool powerOfTwo = number & (number - 1);
The list can go on and on, but for me these are (except for Sierpinksi) everyday examples. Once you'll understand and work with it though, you'll encounter it in more and more places such as the corners of a cube.
You don't specifically mention (nor rule out!-) floating point binary numbers and arithmetic, so I won't miss the opportunity to flog one of my favorite articles ever (seriously: I sometimes wish I could make passing a strict quiz on it a pre-req of working as a programmer...;-).
The most important thing every programmer should know about binary numbers and arithmetic is : Every number in a computer is represented in some kind of binary encoding, and all arithmetic on a computer is binary arithmetic.
The consequences of this are many:
Floating point "bugs" when doing math with IEEE floating point binary numbers (Which is all numbers in javascript, and quite a few in JAVA, and C)
The upper and lower bounds of representable numbers for each type
The performance cost of multiplication/division/square root etc operations (for embedded systems
Precision loss, and accumulation errors
and more. This is stuff you need to know even if you never do a bitwise xor, or not, or whatever in your life. You'll still run into these things.
This really depends on the language you're using. Recent languages such as C# and Java abstract the binary representation from you -- this makes working with binary difficult and is not usually the best way to do things anyway in these languages.
Middle and low level languages like C and C++, however, require you to understand quite a bit about how the numbers are stored underneath -- especially regarding endianness.
Binary knowledge is also useful when implementing a cross platform protcol of some sort .... for example, on x86 machines, byte order is little endian. but most network protocols want big endian numbers. Therefore you have to realize you need to do the conversion for things to go smoothly. Many RFCs, such as this one -> https://www.rfc-editor.org/rfc/rfc4648 require binary knowledge to understand.
In short, it's completely dependent on what you're trying to do.
Billy3
It's handy to know the numbers 256 and 65536. It's handy to know how two's complement negative numbers work.
Maybe you won't run into a lot of binary. I still use it pretty often, but maybe out of habit.
A good familiarity with bitwise operations should make you more facile with boolean algebra, and I think that's important for every programmer--you want to be able to quickly simplify complex logic expressions.
Absolute minimum is, that "2" is not a binary digit and 10b is smaller than 3.
If you never do low-level programming (like C in embedded systems), never have to use a debugger, and never have to work with real numbers, then I suppose you could get by without knowing binary. But knowing binary will make you a stronger programmer, even if indirectly.
Once you venture into those areas you will need to know binary (and its ``sister'' base, hexadecimal). Without knowing it:
Embedded systems programming would be impossible.
Debugging would be hard because you wouldn't know what you were looking at in memory.
Numerical calculations with decimals would give you answers you don't understand.
I learned to twiddle bits back when c and asm were still used for "mainstream" programming. Although I no longer have much use for that knowledge, I recently used it to solve a real-world business problem.
We use a fax service that posts a message back to us when the fax has been sent or failed after x number of retries. The only way I had to identify the fax was a 15 character field. We wanted to consolidate this into one URL for all of our clients. Before we consolidated, all we had to fit in this field was the FaxID PK (32 bit int) column which we just sent as a string.
Now we had to identify the client (a 4 character code) and the database (32 bit int) underneath the client. I was able to do this using base 64 encoding. Without understanding the binary representation of numbers and characters, I probably would never have even thought of this solution.
Some useful information about the number system.
Binary | base 2
Hexadecimal | base 16
Decimal | base 10
Octal | base 8
These are the most common.
Converting them is faily easy.
112 base 8 = (1 x 8^2) + (2 x 8^1) + (4 x 8^0)
74 base 10 = (7 x 10^1) + (4 x 10^0)
The AND, OR, XOR, and etc. are used in logic gates. Search boolean algebra, something well worth the time knowing.
Say for instance, you have 11001111 base 2 and you want to extract the last four only.
Truth table for AND:
P | Q | R
T | T | T
T | F | F
F | F | F
F | T | F
You can use 11001111 base 2 AND 00111111 base 2 = 00001111 base 2
There are plenty of resources on the internet.