I'm not sure if the following can be done using a mere select statement, but I have two tables (truncated with the data necessary to the problem).
Inventory Item
id int (PRIMARY)
quantity int
Stock - Contains changes in the stock of the inventory item (stock history)
id int (PRIMARY)
inventory_item_id int (FOREIGN KEY)
quantity int
created datetime
The quantity in stock is the change in stock, while the quantity in inventory item is the current quantity of that item
EVERYTHING IN THE running COLUMN WILL RETURN 0
SELECT
inventory_item.id,
(inventory_item.quantity - SUM(stock.quantity)) AS running
FROM
stock
JOIN
inventory_item ON stock.inventory_item_id = inventory_item.id
GROUP BY inventory_item.id
THE QUESTION
Now, what I would like to know is: Is it possible to select all of the dates in the stock table where the running quantity of the inventory_item ever becomes zero using a SELECT?
I know this can be done programmatically by simply selecting all of the stock data in one item, and subtracting the stock quantity individually from the current inventory item quantity, which will get the quantity before the change in stock happened. Can I do this with a SELECT?
(Updated) Assuming there will never be more than one record for a given combination of inventory_item_id and created, try:
SELECT i.id,
s.created,
i.quantity - COALESCE(SUM(s2.quantity),0) AS running
FROM inventory_item i
JOIN stock s ON s.inventory_item_id = i.id
LEFT JOIN stock s2 ON s2.inventory_item_id = i.id and s.created < s2.created
GROUP BY i.id, s.created
HAVING running=0
My take on it:
select
inventory_item_id `item`,
created `when`
from
(select
#total := CASE WHEN #curr <> inventory_item_id
THEN quantity
ELSE #total+quantity END as running_total,
inventory_item_id,
created,
#curr := inventory_item_id
from
(select #total := 0) a
(select #curr := -1) b
(select inventory_item_id, created, quantity from stock order by inventory_item_id, created asc) c
) running_total
where running_total.running_total = 0;
This one has the relative advantage of having to give only one pass to the stock table. Depending on the size and the indexes on it that may or may not be a good thing.
The most logical way to do this is with a cumulative sum. But, MySQL doesn't support that.
The clearest approach, in my opinion, is to use a correlated subquery to get the running quantity. Then it is a simple matter of a where clause to select where it is 0:
select i.*
from (select i.*,
(select SUM(i2.inventory)
from inventory i2
where i2.inventory_item_id = i.inventory_item_id and
i2.created <= i.created
) as RunningQuantity
from inventory i
) i
where RunningQuantity = 0;
I had a response similar based on a running total to be flagged found here...
You can do with MySQL #variables, but the data needs to be pre-queried and ordered by the data of activity... then set a flag on each row that causes the negative and keep only those. Something like
select
PreQuery.*
from
( select
s.id,
s.created,
#runBal := if( s.id = #lastID, #runBal - quantity, #i.quantity ) as CurBal,
#lastID := s.id as IDToCompareNextEntry
from
stock s
join inventory_item ii
on s.inventory_item_id = ii.id,
(select #lastID := -1,
#runBal := 0 ) sqlvars
order by
s.id,
s.created DESC ) PreQuery
where
PreQuery.CurBal < 0
This way, for each inventory item, it works backwards by created date (order by the created descending per ID). So, when the inventory ID changes, look to the inventory table "Quantity" field to START the tally of used stock down. If same ID as the last record processed, just use the running balance and subtract out the quantity of that stock entry.
I believe this is a simple approach to this.
SELECT inventory_item.id, stock.created
FROM inventory_item
JOIN stock ON stock.inventory_item_id = inventory_item.id
WHERE (SELECT SUM(quantity) FROM stock WHERE created <= stock.created) = 0
Related
I'm trying in MySql to count the number of users created each day and then get an accumulative figure on a row by row basis. I have followed other suggestions on here, but I cannot seem to get the accumulation to be correct.
The problem is that it keeps counting from the base number of 200 and not taking account of previous rows.
Where was I would expect it to return
My Sql is as follows;
SELECT day(created_at), count(*), (#something := #something+count(*)) as value
FROM myTable
CROSS JOIN (SELECT #something := 200) r
GROUP BY day(created_at);
To create the table and populate it you can use;
CREATE TABLE myTable (
id INT AUTO_INCREMENT,
created_at DATETIME,
PRIMARY KEY (id)
);
INSERT INTO myTable (created_at)
VALUES ('2018-04-01'),
('2018-04-01'),
('2018-04-01'),
('2018-04-01'),
('2018-04-02'),
('2018-04-02'),
('2018-04-02'),
('2018-04-03'),
('2018-04-03');
You can view this on SqlFiddle.
Use a subquery:
SELECT day, cnt, (#s := #s + cnt)
FROM (SELECT day(created_at) as day, count(*) as cnt
FROM myTable
GROUP BY day(created_at)
) d CROSS JOIN
(SELECT #s := 0) r;
GROUP BY and variables have not worked together for a long time. In more recent versions, ORDER BY also needs a subquery.
I have a transactions table which has shows various transactions made by several accounts. Some make only one, others more than that. At the moment the SQL I have prints out the first purchase of each account but i need it to print out the second made by each account
SELECT account_id
, purchase_date as second_purchase
, amount as second_purchase_amount
FROM Transactions t
WHERE purchase_date NOT IN (SELECT MIN(purchase_date)
FROM Transactions m
)
GROUP BY account_id
HAVING purchase_date = MIN(purchase_date);
What needs to change that the second purchase date and amount are chosen? I tried adding in a count for the account_id but it was giving me the wrong value.
You can use variables to assign row numbers and get the 2nd purchase.
SELECT account_id,purchase_Date,amount
FROM (
SELECT account_id
,purchase_date
,amount
--, #rn:=IF(account_id=#a_id and #pdate <> purchase_date,#rn+1,1) as rnum
,case when account_id=#a_id and #pdate <> purchase_date then #rn:=#rn+1
when account_id=#a_id and #pdate=purchase_date then #rn:=#rn
else #rn:=1 end as rnum
, #pdate:=purchase_date
, #a_id:=account_id
FROM Transactions t
CROSS JOIN (SELECT #rn:=0,#a_id:=-1,#pdate:='') r
ORDER BY account_id, purchase_date
) x
WHERE rnum=2
Explanation of how it works:
#rn:=0,#a_id:=-1,#pdate:='' - Declare 3 variables and initialize them, #rn for assigning the row numbers, #a_id to hold the account_id and #pdate to hold the purchase_date.
For the first row (ordered by account_id and purchase_date), account_id and #a_id, #pdate and purchase_date will be compared. As they wouldn't be equal, the when conditions fail and the else part would assign #rn=1. Also, the variable assignment happens after this. #aid and #pdate would be updated to current row's values. For the second row, if they are the same account and on a different date the first when condition will be executed and the #rn will be incremented by 1. If there are ties the second when condition would be executed and the #rn remains the same. You can run the inner query to check how the variables are assigned.
Number the rows and choose RowNumber = 2
select *
from (
select
#rn := case when #account_id = account_id then #rn + 1 else #rn := 1 end as RowNumber,
#account_id := account_id as account_id,
purchase_date
from
(select #rn := 1) x,
(select #acount_id :=account_id as account_id, purchase_date
from Transactions
order by account_id, purchase_date) y
) z
where RowNumber = 2;
I have a MySQL database that includes a table of orders and table of part numbers with available stock.
For example
==Orders Table==
part_number
order_date
qty
==Stock Table==
part_number
stock_qty
Assuming that available stock will be assigned to the most recent orders, how would I select rows from the orders table that don't have stock to cover them.
The orders table could have between 1.5 and 2 million records so reading the whole data set into memory and processing in PHP first is not ideal.
===Update and Final Answer===
Gordon's answer gave me enough information to get the exact result that worked for me. which I have included below.
select * from (
select o.*,s.stock_qty,(#netted_stock := if(#pn = o.part_number,#netted_stock-sumqty,s.stock_qty-sumqty)) as netted_stock
from (select o.*,
(#sumqty := if(#pt = part_number, #sumqty + qty,
if(#pt := part_number, qty, qty)
)
) as sumqty
from orders o cross join
(select #pn := -1, #sumqty := 0, #netted_stock:= 0) params
order by part_number, order_date desc
) o join
stock s
on o.part_number = s.part_number
) s
Here is the result it gives me.
You need a cumulative sum of stock per order. You can get that with variables. The rest is just simple logic:
select o.*
from (select o.*,
(#sumqty := if(#pt = part_number, #sumqty + qty,
if(#pt := part_number, qty, qty)
)
) as sumqty
from orders o cross join
(select #pn := -1, #sumqty := 0) params
order by part_number, order_date desc
) o join
stock s
on o.part_number = s.part_number
where s.stock_qty < o.sumqty;
There is a table with the columns :
USE 'table';
insert into person values
('11','xxx','1976-05-10','p1'),
('11','xxx ','1976-06-11','p1'),
('11','xxx ','1976-07-21','p2'),
('11','xxx ','1976-08-31','p2'),
Can anyone suggest me a query to get the start and the end date of the person with respect to the place he changed chronologically.
The query I wrote
SELECT PId,Name,min(Start_Date) as sdt, max(Start_Date) as edt, place
from **
group by Place;
only gives me the first two rows of my answer. Can anyone suggest the query??
This isn't pretty, and performance might be horrible, but at least it works:
select min(sdt), edt, place
from (
select A.Start_Date sdt, max(B.Start_Date) edt, A.place
from person A
inner join person B on A.place = B.place
and A.Start_Date <= B.Start_Date
left join person C on A.place != C.place
and A.Start_Date < C.Start_Date
and C.Start_Date < B.Start_Date
where C.place is null
group by A.Start_Date, A.place
) X
group by edt, place
The idea is that A and B represent all pairs of rows. C will be any row in between these two which has a different place. So after the C.place is null restriction, we know that A and B belong to the same range, i.e. a group of rows for one place with no other place in between them in chronological order. From all these pairs, we want to identify those with maximal range, those which encompass all others. We do so using two nested group by queries. The inner one will choose the maximal end date for every possible start date, whereas the outer one will choose the minimal start date for every possible end date. The result are maximal ranges of chronologically subsequent rows describing the same place.
This can be achived by:
SELECT Id, PId,
MIN(Start_Date) AS sdt,
MAX(Start_Date) as edt,
IF(`place` <> #var_place_prev, (#var_rank:= #var_rank + 1), #var_rank) AS rank,
(#var_place_prev := `place`) AS `place`
FROM person, (SELECT #var_rank := 0, #var_place_prev := "") dummy
GROUP BY rank, Place;
Example: SQLFiddle
If you want records to be ordered by ID then:
SELECT Id, PId,
MIN(Start_Date) AS sdt,
MAX(Start_Date) as edt,
`place`
FROM(
SELECT Id, PId,
Start_Date
IF(`place` <> #var_place_prev,(#var_rank:= #var_rank + 1),#var_rank) AS rank,
(#var_place_prev := `place`) AS `place`
FROM person, (SELECT #var_rank := 0, #var_place_prev := "") dummy
ORDER BY ID ASC
) a
GROUP BY rank, Place;
My website allows users to record bids. Each bid is saved individually and associated to a user Id. A user can have many bids which are used to add up to one overall bid which is displayed upon the site.
What I am trying to do in sql is return the position a users overall bid is from a result set.
The sql I am using is below but problems arise when I use the group by command - the ordering seems to revert back to the default db order rather than by the sum of a users bid amounts:
SET #rowcount = 0;
SELECT rowCount, userId FROM (
SELECT userId, #rowcount := #rowcount + 1 as rowCount, sum(amount) as amount FROM bids group by userId order by amount desc
) t when product = xxxxx
appreciate if anyone knows if this is possible?
You need to move rowcount incrementation out of subquery. And put your WHERE condition inside, otherwise your subquery will sum bids on all products for a given user.
SET #rowcount = 0;
SELECT #rowCount:=#rowcount+1 as rowcount, userId, amount FROM
(
SELECT userId, sum(amount) as amount
FROM bids
WHERE product = xxxxx
GROUP BY userId
ORDER BY amount DESC
) t
Have you already tried?
SET #rowcount = 0;
SELECT rowCount, userId FROM (
SELECT userId, #rowcount := #rowcount + 1 as rowCount from
(select sum(amount) as amount, userId FROM bids group by userId) s
order by s.amount desc
) t where product = xxxxx
if I understand it correctly you could try something like this:
SELECT #rownum:=#rownum+1 ‘rank’, userId FROM (SELECT product, userId, sum(amount) AS amount FROM bids GROUP BY userId) t, (SELECT #rownum:=0) r WHERE t.product = xxxx ORDER BY t.amount DESC;