Can I ask for help on a SQL Statement please, I have to do the calculation inline and cannot declare variables for it
Calculation:
-91000000 / 2700000 = -33.7037037037
I need the remainder (7037037037 - but only up to 6 characters ) to be multiplied by 15000
703703 / 15000 = Final Answer of 49.913533
I thought I could do this:
select cast(ParseName(abs(cast(-91000000 as decimal)/ 2700000 ) %1,1) as numeric(8,8)) / 15000
WITH cte AS
(
SELECT -91000000 AS x, 2700000 AS y
)
SELECT ABS(ROUND((CAST(x AS decimal) / CAST(y AS decimal)) - (x/y), 6)) * 1000000 / 15000 FROM CTE
Related
This question already has answers here:
Surpassing MySQL's TIME value limit of 838:59:59
(7 answers)
Closed 4 years ago.
I am trying to sum time values and have it in the format of hours:minutes:seconds i.e. 100:30:10.
SEC_TO_TIME(SUM(TIME_TO_SEC(ActualHours))) AS Hours
But I'm having a problem because time's max value is 838:59:59.
So if summing the time is over this value it won't show i.e. if it equals 900 hours it will show as 838:59:59 which is wrong.
How do I the display the total hours if it is over 838:59:59?
If I had to do this conversion in SQL, I would do something like this:
SELECT CONCAT( ( _secs_ DIV 3600)
, ':'
, RIGHT(CONCAT('0',( _secs_ DIV 60 ) MOD 60 ),2)
, ':'
, RIGHT(CONCAT('0',( _secs_ MOD 60)),2)
) AS `h:mm:ss`
We can just replace the _secs_ with the expression that returns the number of seconds we want to convert. Using the expression given in the question, we get something like this:
SELECT CONCAT( ( SUM(TIME_TO_SEC(ActualHours)) DIV 3600)
, ':'
, RIGHT(CONCAT('0',( SUM(TIME_TO_SEC(ActualHours)) DIV 60 ) MOD 60 ),2)
, ':'
, RIGHT(CONCAT('0',( SUM(TIME_TO_SEC(ActualHours)) MOD 60)),2)
) AS `h:mm:ss`
DEMONSTRATION
The syntax provided in this answer is valid in MySQL 5.6. As a demonstration, using a user-defined variable #_secs as the expression number of seconds:
Set user-defined variable for demonstration:
SELECT #_secs_ := ( 987 * 3600 ) + ( 5 * 60 ) + 7 ;
returns
#_secs := ( 987 * 3600 ) + ( 5 * 60 ) + 7
-----------------------------------------
3553507
demonstrating the query pattern:
SELECT CONCAT( ( #_secs_ DIV 3600)
, ':'
, RIGHT(CONCAT('0',( #_secs_ DIV 60 ) MOD 60 ),2)
, ':'
, RIGHT(CONCAT('0',( #_secs_ MOD 60)),2)
) AS `hhh:mm:ss`
returns
hhh:mm:ss
---------
987:05:07
Here is one way we can do this:
SELECT
CONCAT(CAST(FLOOR(seconds / 3600) AS CHAR(50)), ':',
CAST(FLOOR(60*((seconds / 3600) - FLOOR(seconds / 3600))) AS CHAR(50)), ':',
CAST(seconds % 60 AS CHAR(50))) AS time
FROM yourTable;
For an input of 10,000,000 (ten million) seconds, this would generate:
2777:46:40
Demo
Use some simple math to concat a time period from seconds,replace 35000 with your column.
SELECT CONCAT(FLOOR(35000/3600),':',FLOOR((35000%3600)/60),':',(35000%3600)%60)
A fiddle to play with
I have the following table:
id (integer, primary key)
amount_low (integer)
amount_high (integer)
fixedprice (decimal 4,2 Null)
percentadjust (decimal 4,2 Null)
itemname (varchar 50)
A record will have a value in either the "fixedprice" or "percentadjust" field, but not both. One will be NULL, and the other will have a value.
I need to get records based on a single input amount, "X":
If the "fixedprice" field has a value, I need to get the record if X is >= (fixedprice * amount_low) AND X is <= (fixedprice * amount_high).
If the "percentadjust" field has a value, I need to get the record if X is >= ((((percentadjust / 100) + 1) * 3.5) * amount_low) AND X is <= ((((percentadjust / 100) + 1) * 3.5) * amount_high).
The "3.5" is a value that changes on occasion and I'm not too concerned about that part.
What is a good way to do this in MySQL?
Sample data: (also see http://sqlfiddle.com/#!9/922a0 )
id amount_low amount_high fixedprice percentadjust itemname
-----------------------------------------------------------------
1 20 25 2.25 NULL A
2 50 75 2.38 NULL B
3 23 32 NULL 9.75 C
4 14 22 NULL 9.12 D
5 96 112 2.58 NULL E
Assuming your X was entered as 111 it would be
select * from tblItems
where (fixedprice is not null and 111>=(fixedprice * amount_low) and 111 <= (fixedprice * amount_high) )
OR (percentadjust is not null and 111>=((((percentadjust / 100) + 1) * 3.5) * amount_low) AND 111<=((((percentadjust / 100) + 1) * 3.5) * amount_high))
Note you can always write it as where xyz between A and B to simplify somethings slightly.
Remember that a lot of time can be wasted debugging logic operators when AND and OR are used and safe wrappers with parentheses are not used. So, if you intermingle AND with OR, wrap things well.
I want to convert feet and inches to centimeters format
Format in my DB is:
4'6" (4 feet, 6 inches)
Formula for converting into centimeters
4*30.48 = 121.92 (convert feet to centimeters = multiply by 30.48)
6*2.54 = 15.24 (convert inches to centimeters = multiply by 2.54)
So Result = 121.92 + 15.24 = 137.16 cm
eg:
Actual Table: inches
SELECT * FROM inches
id height
1 4'6"
2 4'7"
3 5'8"
4 5'9"
I expect the following result as centimeters when I do SQL query
id height
1 137.16
2 139.7
3 172.72
4 175.26
Thanks in advance :)
Probably far easier to do on the application level, but if you really had to, you could do it in SQL like this, using the SUBSTR and INSTR functions, and some basic math:
SET #height = '4''6"';
SELECT
SUBSTR(#height, 1, INSTR(#height, '''') - 1) * 12 * 2.54 +
SUBSTR(#height, INSTR(#height, '''') + 1, INSTR(#height, '"') - INSTR(#height, '''') - 1) * 2.54;
-- yields 137.16
Or, applied to your table structure:
SELECT id,
SUBSTR(height, 1, INSTR(height, '''') - 1) * 12 * 2.54 +
SUBSTR(height, INSTR(height, '''') + 1, INSTR(height, '"') - INSTR(height, '''') - 1) * 2.54 AS height
FROM inches;
Application side process will be better,
However,
SELECT
(CAST(SUBSTR(height,1, LOCATE("'",height)-1) AS UNSIGNED) * 30.48) +
(CAST(SUBSTR(height, LOCATE("'",height)+1) AS UNSIGNED) * 2.54 ) AS cm
FROM
inches;
I am trying to multiply a time with decimal value but not to get it right. That is, when I multiply with any decimal value, it is rounding that value to nearest integer and then doing the multiplication.
For Example: All the below operations are resulting the same value
1. '00:04:18' * 1.7 = '00:08:36'
2. '00:04:18' * 1.8 = '00:08:36'
3. '00:04:18' * 1.9 = '00:08:36'
4. '00:04:18' * 2 = '00:08:36'
Please let me know what change I have to do to get the accurate value without rounding.
Thanks
SEC_TO_TIME( TIME_TO_SEC( '00:04:18' ) * 1.7 ) = '00:07:18.6'
SEC_TO_TIME( TIME_TO_SEC( '00:04:18' ) * 1.7 ) = '00:07:44.4'
Why does the following return .500000 rather than .500?
SELECT 50 / CAST(100 AS decimal(3))
Because you are casting the divisor not the result. And you have not specified precision.
See this for examples:
SELECT 50 / CAST(100 AS decimal(3))
,50 / CAST(100 AS decimal(6,3))
,CAST (50 / CAST(100 AS decimal(3)) AS decimal(3))
,CAST (50 / CAST(100 AS decimal(3)) AS decimal(6,3))
Precision, Scale, and Length (Transact-SQL)
Precision is the number of digits in a number. Scale is the number of
digits to the right of the decimal point in a number. For example, the
number 123.45 has a precision of 5 and a scale of 2.
DECIMAL uses a default precision of 18 and scale of 3.
Therefore when you case to DECIMAL(3) you get a DECIMAL(3,0). Then you use it as a divisor and SQL Server follows its rules for the resultant scale.
Operation Result precision Result scale
e1 / e2 p1 - s1 + s2 + max(6, s1 + p2 + 1) max(6, s1 + p2 + 1)