Is it possible to have table in table (mysql)? - mysql

Question

Suppose I defined music as a table and gave it 3 columns: album, artist, and track:
CREATE TABLE music (
id int auto_increment primary key,
album varchar(45) not null,
artist varchar(30) not null,
track int(8)
);
Now I want another table releasedy which contains a column:
'Year' and the table music
I suppose for that I have to bind some row from table music with year from table releasedy in another table. So I can know which year contains which musics. If I'm not wrong I have to do that with foreign key. How should I proceed?

Answer 1

You do not want "a table in a table", instead you want to match records from one table with records from another table in a query. You can create a view on top of this query and use the view later as it if were a regular table.
As you guessed, establish a foreign key relationship, then JOIN the two tables.

Answer 2

There is no "table in a table", only tables and relations between them.
Table releasedy will have 2 columns, musicId & year. musicId is the foreign key to your music table.
Join (as you called bind) these two:
SELECT *
FROM music m
INNER JOIN releasedy r ON m.id = r.musicId
WHERE year = ..
Which is all overkill in this example but it illustrates the "binding" you want.

Answer 3

class Functions {
public function getRows($sql){
$result = mysql_query($sql);
while($row = mysql_fetch_assoc($result)){
$data[] = $row;
}
return $data;
}
public function getMusicData(){
$data = $this->getRows("SELECT * FROM music");
return base64_encode(serialize($data));
}
}
$func = new Functions();
$music = $func->getMusicData();
$sql = "insert into releasedy (id,Year) values (NULL,'".$music."')";
mysql_query($sql);
$id = 'your necessary id'; $read = "select * from releasedy where id = ".(int)$id; $data = mysql_query($read); $musics = unserialize(base64_decode($data['Year'])); foreach($musics as $music){ // do something }