MYSQL Group by with the minimum value - mysql

Question

Hi I've been searching for this, and I've found solutions for other sample code, but I can't figure out how to implement for mine.
SELECT `gameDBGames`, `game_id`, MIN(`gamePrice`) AS `gamePrice`
FROM `games`
LEFT JOIN `platforms` ON `gamePlatform` = `platform_id`
LEFT JOIN `bundles` ON `gameBundle` = `bundle_id`
LEFT JOIN `currency` ON `bundleCurrency` = `currency_id`
WHERE `bundleEnd` > CURDATE() AND `bundleType` = "1" AND `gameDBGames` != "0"
GROUP BY `gameDBGames`
Here is my actual query. This returns the minimum price, but do not correspond to the game_id. How could I do that? I believe is doing a inner join like this:
SELECT `gameDBGames`, `game_id`, MIN(`gamePrice`) AS `gamePrice`
FROM `games`
LEFT JOIN `platforms` ON `gamePlatform` = `platform_id`
LEFT JOIN `bundles` ON `gameBundle` = `bundle_id`
INNER JOIN (....)
LEFT JOIN `currency` ON `bundleCurrency` = `currency_id`
WHERE b.`bundleEnd` > CURRDATE() AND b.`bundleType` = "1" AND g.`gameDBGames` != "0"
Thank you.
EDIT: Sorry I don't know what I was thinking not posting the table structure.
The game_id is the unique id (e.g. same game but with different prices) , and gameDBGames is an ID for a game (e.g. gameDBGames = 1, can have price 40 or 30) that's why I'm grouping by gameDBGames. An the aim is getting a unique gameDBGames with the minimum price.
What I have.
+--------------+---------+----+---------+
| table games | | | |
+--------------+---------+----+---------+
| game_id | int | AI | PRIMARY |
| gameDBGames | int | | |
| gamePrice | float | | |
| gamePlatform | tinyint | | |
| gameBundle | int | | |
+--------------+---------+----+---------+
+---------+-------------+-----------+--------------+------------+
| game_id | gameDBGames | gamePrice | gamePlatform | gameBundle |
+---------+-------------+-----------+--------------+------------+
| 1 | 1 | 20 | 1 | 1 |
| 2 | 2 | 20 | 2 | 1 |
| 3 | 2 | 15 | 2 | 1 |
| 4 | 3 | 17 | 1 | 1 |
| 5 | 3 | 20 | 1 | 1 |
| 6 | 3 | 15 | 1 | 1 |
| 7 | 4 | 16 | 2 | 2 |
| 8 | 5 | 18 | 2 | 2 |
| 9 | 5 | 14 | 2 | 2 |
| 10 | 6 | 15 | 1 | 2 |
+---------+-------------+-----------+--------------+------------+
What I get.
+---------+-------------+-----------+--------------+------------+
| game_id | gameDBGames | gamePrice | gamePlatform | gameBundle |
+---------+-------------+-----------+--------------+------------+
| 1 | 1 | 20 | 1 | 1 |
| 2 | 2 | 15 | 2 | 1 |
| 4 | 3 | 15 | 1 | 1 |
| 7 | 4 | 16 | 2 | 2 |
| 8 | 5 | 14 | 2 | 2 |
| 10 | 6 | 15 | 1 | 2 |
+---------+-------------+-----------+--------------+------------+
As you can see the game_id do not correspond to the gamePrice. It should be like this.
+---------+-------------+-----------+--------------+------------+
| game_id | gameDBGames | gamePrice | gamePlatform | gameBundle |
+---------+-------------+-----------+--------------+------------+
| 1 | 1 | 20 | 1 | 1 |
| 3 | 2 | 15 | 2 | 1 |
| 6 | 3 | 15 | 1 | 1 |
| 7 | 4 | 16 | 2 | 2 |
| 9 | 5 | 14 | 2 | 2 |
| 10 | 6 | 15 | 1 | 2 |
+---------+-------------+-----------+--------------+------------+
Hope you understand now, sorry for not been more explained before. If you need something else please ask. Thank you.
EDIT 2 (Mark)
The solution put by Mark gives me this errors.
There are gameDBGames repeated.
Some games are non shown.
I've updated the WHERE clause just in case is needed.

Answer 1

Try:
SELECT g.`gameDBGames`, g.`game_id`, g.`gamePrice`
FROM (SELECT `gameDBGames`, MIN(`gamePrice`) AS `minPrice`
FROM `games`
GROUP BY `gameDBGames`) mn
JOIN `games` g
ON mn.`gameDBGames`=g.`gameDBGames` and mn.`minPrice`=g.`gamePrice`
LEFT JOIN `platforms` p ON g.`gamePlatform` = p.`platform_id`
LEFT JOIN `bundles` b ON g.`gameBundle` = b.`bundle_id`
LEFT JOIN `currency` c ON b.`bundleCurrency` = c.`currency_id`
WHERE ....
The GROUP BY in the main query should not be required, due to the grouping in the subquery - however, more than one game_id will be returned for a given gameDBGames if there is more than one game_id with the same minimum price for a given gameDBGames.