Mysql to select rows group by with order by another column - mysql

Question

I am trying to select the rows from a table by 'group by' and ignoring the first row got by sorting the data by date. The sorting should be done by a date field, to ignore the newest entry and returning the old ones for the group.
The table looks like
+----+------------+-------------+-----------+
| id | updated on | group_name | list_name |
+----+------------+----------------+--------+
| 1 | 2013-04-03 | g1 | l1 |
| 2 | 2013-03-21 | g2 | l1 |
| 3 | 2013-02-26 | g2 | l1 |
| 4 | 2013-02-21 | g1 | l1 |
| 5 | 2013-02-20 | g1 | l1 |
| 6 | 2013-01-09 | g2 | l2 |
| 7 | 2013-01-10 | g2 | l2 |
| 8 | 2012-12-11 | g1 | l1 |
+----+------------+-------------+-----------+
http://www.sqlfiddle.com/#!2/cec99/1
So, basically, I just want to return ids (3,4,5,6,8) as those are the oldest in the group_name and list_name. Ignoring the latest entry and returning the old ones by grouping it based on group_name and list_name
I am not able to write sql for this problem. I know order by will not work with group by. Please help me in figuring out a solution.
Thanks
And also, is there a way to do this without using subqueries?

Answer 1

Something like the following to get only the rows that are the minimum date for a specific row:
select a.ID, a.updated_on, a.group_name, list_name
from data a
where
a.updated_on <
(
select max(updated_on)
from data
group by group_name having group_name = a.group_name
);
SQL Fiddle: http://www.sqlfiddle.com/#!2/00d43/10
Update (based on your reqs)
select a.ID, a.updated_on, a.group_name, list_name
from data a
where
a.updated_on <
(
select max(updated_on)
from data
group by group_name, list_name having group_name = a.group_name
and list_name = a.list_name
);
See: http://www.sqlfiddle.com/#!2/cec99/3
Update (To not use Correlated Subquery but Simple subquery)
Decided correlated subquery is too slow based on: Subqueries vs joins
So I changed to joining with a aliased temporary table based on nested query.
select a.ID, a.updated_on, a.group_name, a.list_name
from data a,
(
select group_name, list_name , max(updated_on) as MAX_DATE
from data
group by group_name, list_name
) as MAXDATE
where
a.list_name = MAXDATE.list_name AND
a.group_name = MAXDATE.group_name AND
a.updated_on < MAXDATE.MAX_DATE
;
SQL Fiddle: http://www.sqlfiddle.com/#!2/5df64/8

Answer 2

You could try using the following query (yes, it has a nested join, but maybe it helps).
SELECT ID FROM
(select d1.ID FROM data d1 LEFT JOIN
data d2 ON (d1.group_name = d2.group_name AND d1.list_name=d2.list_name AND
d1.updated_on > d2.updated_on) WHERE d2.ID IS NULL) data_tmp;
CORRECTION:
SELECT DISTINCT(ID) FROM
(select d1.* FROM data d1 LEFT JOIN
data d2 ON (d1.group_name = d2.group_name AND d1.list_name=d2.list_name AND
d1.updated_on < d2.updated_on) WHERE d2.ID IS NOT NULL) date_tmp;

Answer 3

SELECT DISTINCT y.id
FROM data x
JOIN data y
ON y.group_name = x.group_name
AND y.list_name = x.list_name
AND y.updated_on < x.updated_on;