Where is the problem? i am trying to create the table comparein using the composed primary key from the table Episodi but there should be a problem that i can t see..
the primary key from the table is a combination of "numero" and "titolo_episodio"
create table Autori(
id_autore int auto_increment primary key,
nome varchar(15) not null,
cognome varchar(15) not null,
nome_arte varchar (15)
) ENGINE=InnoDB;
create table Serie(
nome varchar(25) primary key,
id_autore int(6),
descrizione varchar(400),
FOREIGN KEY (id_autore)REFERENCES Autori(id_autore)
) ENGINE=InnoDB;
create table Episodi(
titolo_episodio varchar(25) not null,
numero int not null,
durata time not null,
data_trasmissione date not null,
nome_serie varchar(25),
PRIMARY KEY(titolo_episodio,numero),
FOREIGN KEY (nome_serie)REFERENCES Serie(nome)
) ENGINE=InnoDB;
create table Personaggi(
id_pers int auto_increment primary key,
nome varchar(15) not null,
cognome varchar(15),
nazionalita varchar (15),
nome_serie varchar(25),
FOREIGN KEY (nome_serie)REFERENCES Serie(nome)
) ENGINE=InnoDB;
create table Utenti(
nickname varchar(15) primary key,
nazionalita varchar(15) not null,
mail varchar(25) not null,
pwd varchar(15) not null,
amministratore bool default 0 not null
) ENGINE=InnoDB;
create table Generi(
genere varchar(15) primary key
) ENGINE=InnoDB;
create table comparein(
id_pers int not null,
numero int not null,
titolo_episodio varchar(25),
FOREIGN KEY (id_pers)REFERENCES Personaggi(id_pers),
FOREIGN KEY (numero,titolo_episodio)REFERENCES Episodi(numero,titolo_episodio),
primary key(id_pers,numero,titolo_episodio)
) ENGINE=InnoDB;
I think you need to reference the PK columns in the same order as the primary key was defined. So instead of
FOREIGN KEY (numero,titolo_episodio)REFERENCES Episodi(numero,titolo_episodio)
use
FOREIGN KEY (titolo_episodio, numero) REFERENCES Episodi(titolo_episodio, numero)
SQLFiddle: http://sqlfiddle.com/#!2/363bd
Related
I'm new to sql.
I get this error when I try to create foreign keys:
cannot add foreign key constraint
when I'm trying to create the ORDERS table. here is my code:
drop database if exists Company;
create database Company;
use Company;
create table WORKERS(w_id varchar(4), w_name varchar(20) not null, telephone varchar(12), e_mail varchar(35) unique);
create table CUSTOMERS(customer_id varchar(4), customer_name varchar(20) not null, telephone varchar(12), e_mail varchar(35) unique, credit bool);
create table WAREHOUSE(m_id int unsigned primary key, describes varchar(20) not null, fl char(1));
create table ITEM(p_id int(4) unsigned primary key, p_name varchar(15) not null, p_price float not null);
create table INVENTORY(in_id int auto_increment primary key, m_id int unsigned not null, p_id int(4) unsigned not null, amount int not null,
foreign key (m_id) references WAREHOUSE(m_id),
foreign key (p_id) references ITEM(p_id)
);
create table ORDERS(o_id int auto_increment primary key, customer_id varchar(4),
p_id int(4) unsigned, w_id varchar(4), amount int unsigned not null,
date_of_order date not null,
foreign key (p_id) references ITEM(p_id),
foreign key (w_id) references WORKERS(w_id),
foreign key (customer_id) references CUSTOMERS(customer_id)
);
I put the ORDERS (where I have the problem) on different lines to make it easier to you to read.
I search here for an answer, but didn't found anything specific that answer my question.
anyone got any idea what the problem is? thank you!
The problem is that you are trying to create a FOREIGN KEY relationship to a field in the WORKERS and CUSTOMERS tables that aren't set up as a PRIMARY KEY.
The FOREIGN KEY needs to be pointing to a PRIMARY KEY. Change your create script to the following:
create table WORKERS(w_id varchar(4) primary key, w_name varchar(20) not null, telephone varchar(12), e_mail varchar(35) unique);
create table CUSTOMERS(customer_id varchar(4) primary key, customer_name varchar(20) not null, telephone varchar(12), e_mail varchar(35) unique, credit bool);
A word of caution, though. I would recommend not using VARCHAR (4) as a PRIMARY KEY field. I would recommend using an INT AUTO_INCREMENT instead.
The column of the referenced table should be declared as primary key to assign a foreign key. For your orders table, WORKERS(w_id) and CUSTOMERS(customer_id) are not declared as primary key, hence you get the error.
Modified Statements:
drop database if exists Company;
create database Company;
use Company;
create table WORKERS(w_id varchar(4) primary key, w_name varchar(20) not null, telephone varchar(12), e_mail varchar(35) unique);
create table CUSTOMERS(customer_id varchar(4) primary key, customer_name varchar(20) not null, telephone varchar(12), e_mail varchar(35) unique, credit bool);
create table WAREHOUSE(m_id int unsigned primary key, describes varchar(20) not null, fl char(1));
create table ITEM(p_id int(4) unsigned primary key, p_name varchar(15) not null, p_price float not null);
create table INVENTORY(in_id int auto_increment primary key, m_id int unsigned not null, p_id int(4) unsigned not null, amount int not null,
foreign key (m_id) references WAREHOUSE(m_id),
foreign key (p_id) references ITEM(p_id)
);
create table ORDERS(o_id int auto_increment primary key, customer_id varchar(4),
p_id int(4) unsigned, w_id varchar(4), amount int unsigned not null,
date_of_order date not null,
foreign key (p_id) references ITEM(p_id),
foreign key (w_id) references WORKERS(w_id),
foreign key (customer_id) references CUSTOMERS(customer_id)
);
SQLFiddle Demo
I get this following error for some reason, and I know it has to do with the foreignkey I just added "UsesTruck" However I don't know WHAT it is I did wrong.. I have included only the tables I think are important for this issue.
CREATE TABLE Employee (
EmployeeID INT AUTO_INCREMENT,
Name VARCHAR(90) NOT NULL,
UsesTruck CHAR(20) NULL,
FOREIGN KEY (UsesTruck) REFERENCES Truck(LicensePlate),
PRIMARY KEY (EmployeeID));
CREATE TABLE Truck (
LicensePlate CHAR(20) NULL,
color VARCHAR(45) NULL,
capacity VARCHAR(45) NULL,
PRIMARY KEY (LicensePlate));
CREATE TABLE Shifts (
ShiftTime VARCHAR(15) NOT NULL,
PRIMARY KEY (ShiftTime));
CREATE TABLE Reservation (
ReservNum INT NOT NULL,
ReserveDate VARCHAR(45) NULL,
PickupTime VARCHAR(45) NOT NULL,
NumOfPassengers INT NULL,
sheduledTime VARCHAR(45) NULL,
ActualPickupTime VARCHAR(45),
ActualTime VARCHAR(45),
PricePaid VARCHAR(45),
DriverHourlyRate DECIMAL(7,2) NULL,
PassEmployeeHourlyRate DECIMAL (7,2) NULL,
DriverSalary VARCHAR(10),
PassEmployeeSalary VARCHAR(10),
Customer_CustomerID INT,
Truck_LicensePlate char(20) NULL,
Employee_EmployeeID_Driver INT,
Location_Address_Pickup VARCHAR(100),
Employee_EmployeeID_Passenger INT,
Location_Address_Drop VARCHAR(100),
PRIMARY KEY (ReservNum),
FOREIGN KEY (Customer_CustomerID) REFERENCES Customer (CustomerID),
FOREIGN KEY (Truck_LicensePlate) REFERENCES Truck (LicensePlate),
FOREIGN KEY (Employee_EmployeeID_Driver) REFERENCES Employee (EmployeeID),
FOREIGN KEY (Location_Address_Pickup) REFERENCES Location (Address),
FOREIGN KEY (Employee_EmployeeID_Passenger) REFERENCES Employee (EmployeeID),
FOREIGN KEY (Location_Address_Drop) REFERENCES Location (Address));
Try to run create Truck table firstly.
Here is the code below, I'm not sure what this error means...
All I know is that it has something to do with the employeeshifts table.
Does it have something to do with foreign keys?
(insterting this text as I have nothing else to say, but stack requires a lot of text)
CREATE TABLE Customer (
CustomerID INT AUTO_INCREMENT,
Name VARCHAR(90) NOT NULL,
Phone VARCHAR(45) NULL,
CustomerAddress VARCHAR(45) NOT NULL,
PRIMARY KEY (CustomerID));
CREATE TABLE Location (
Address VARCHAR(100) NOT NULL,
Latitude VARCHAR(45) NULL DEFAULT ' ',
Longitude VARCHAR(45) NULL,
PRIMARY KEY (Address));
CREATE TABLE Employee (
EmployeeID INT AUTO_INCREMENT,
Name VARCHAR(90) NOT NULL,
PRIMARY KEY (EmployeeID));
CREATE TABLE Truck (
LicensePlate CHAR(20) NOT NULL,
color VARCHAR(45) NULL,
capacity VARCHAR(45) NULL,
PRIMARY KEY (LicensePlate));
CREATE TABLE Shifts (
ShiftTime DATETIME NOT NULL,
PRIMARY KEY (ShiftTime));
CREATE TABLE EmployeeShifts (
DesiredShift DATETIME NOT NULL,
EmployeeWorking VARCHAR(90) NOT NULL,
DateOfShift DATE,
PRIMARY KEY(DesiredShift, EmployeeWorking, DateOfShift),
FOREIGN KEY (EmployeeWorking) REFERENCES Employee(Name),
FOREIGN KEY (DesiredShift) REFERENCES Shifts(ShiftTime));
CREATE TABLE Reservation (
ReservNum INT NOT NULL,
ReserveDate DATE NULL,
PickupTime VARCHAR(45) NOT NULL,
NumOfPassengers INT NULL,
sheduledTime VARCHAR(45) NULL,
ActualPickupTime VARCHAR(45),
ActualTime VARCHAR(45),
PricePaid VARCHAR(45),
DriverHourlyRate DECIMAL(7,2) NOT NULL,
PassEmployeeHourlyRate DECIMAL (7,2) NOT NULL,
DriverSalary VARCHAR(10),
PassEmployeeSalary VARCHAR(10),
Customer_CustomerID INT,
Truck_LicensePlate char(20) NOT NULL,
Employee_EmployeeID_Driver INT,
Location_Address_Pickup VARCHAR(100),
Employee_EmployeeID_Passenger INT,
Location_Address_Drop VARCHAR(100),
PRIMARY KEY (ReservNum),
FOREIGN KEY (Customer_CustomerID) REFERENCES Customer (CustomerID),
FOREIGN KEY (Truck_LicensePlate) REFERENCES Truck (LicensePlate),
FOREIGN KEY (Employee_EmployeeID_Driver) REFERENCES Employee (EmployeeID),
FOREIGN KEY (Location_Address_Pickup) REFERENCES Location (Address),
FOREIGN KEY (Employee_EmployeeID_Passenger) REFERENCES Employee (EmployeeID),
FOREIGN KEY (Location_Address_Drop) REFERENCES Location (Address));
You need to reference UNIQUE or PRIMARY KEY column:
CREATE TABLE EmployeeShifts (
DesiredShift DATETIME NOT NULL,
EmployeeWorking VARCHAR(90) NOT NULL,
DateOfShift DATE,
PRIMARY KEY(DesiredShift, EmployeeWorking, DateOfShift),
FOREIGN KEY (EmployeeWorking) REFERENCES Employee(Name), -- name is not UNIQUE/PK
FOREIGN KEY (DesiredShift) REFERENCES Shifts(ShiftTime)
);
to:
CREATE TABLE EmployeeShifts (
DesiredShift DATETIME NOT NULL,
EmployeeID INT NOT NULL, -- here
DateOfShift DATE,
PRIMARY KEY(DesiredShift, EmployeeID, DateOfShift),
FOREIGN KEY (EmployeeID) REFERENCES Employee(EmployeeID),
FOREIGN KEY (DesiredShift) REFERENCES Shifts(ShiftTime)
);
SqlFiddleDemo
I am using Workbench 6.0 and having a frustrating issue I am new to SQl and would like to keep this as simple as possible at this point, I believe my tables are ordered properly to add contraints except for my TICKET table, no idea how to find what foreign key is having problems.
CREATE TABLE IF NOT EXISTS ACTION_TYPE (
ActionCode int primary key,
Description char(50) not null
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS OFFICER (
PersonnelNo int primary key,
OfficerLName char(50) not null,
OfficerFName char(50) not null
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS DRIVER (
DriverLicenseNo int primary key,
DriverLastName char(50) not null,
DriverFirstName char(50) not null,
DriverAddress char(50) not null,
DriverCity char(50) not null,
DriverProv char(50) not null,
DriverPostalCode varchar(6) not null,
DriverGender char(1) not null,
DriverBirthDate Date not null
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS REGISTERED_OWNER (
RegOwnerID int primary key auto_increment,
RegOwnerLName char(50) not null,
RegOwnerFName char(50) not null,
RegOwnerAddress char(50) not null,
RegOwnerCity char(50) not null,
RegOwnerProv char(50) not null,
RegOwnerPostalCode varchar(6) not null
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS VEHICLE_TYPE (
VehicleType int primary key,
VehicleDescription char(50) not null
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS VEHICLE (
VehicleLicense int primary key,
ProvinceIssued char(2) not null,
VehicleYear int not null,
VehicleMake char(10) not null,
VehicleType int not null,
index (VehicleType),
foreign key (VehicleType)
references VEHICLE_TYPE (VehicleType)
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS TICKET ( <-----this table calling the error
TicketNo int primary key auto_increment,
TicketDateTime datetime not null,
TicketLocationCity char(50) not null,
TicketLocationProv char(50) not null,
TicketLocationRoad char(50) not null,
PersonnelNo int not null,
VehicleLicense int not null,
ActionCode int not null,
RegOwnerID int not null,
DriversLicenseNo int not null,
index (PersonnelNo),
foreign key (PersonnelNo)
references OFFICER (PersonnelNo),
index (VehicleLicense),
foreign key (VehicleLicense)
references VEHICLE (VehicleLicense),
index (ActionCode),
foreign key (ActionCode)
references ACTION_TYPE (ActionCode),
index (RegOwnerID),
foreign key (RegOwnerID)
references REGISTERED_OWNER (RegOwnerID),
index (DriversLicenseNo),
foreign key (DriversLicenseNo)
references DRIVER (DriversLicenseNo)
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS VIOLATION_TYPE (
ViolationCode int primary key auto_increment,
ViolationDesc char(50) not null,
ViolationCurrFineAmt int not null
)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS VIOLATION (
ViolationNo int primary key auto_increment,
TicketNo int not null,
ViolationCode int not null,
AppliedFineAmount int not null,
index (TicketNo),
foreign key (TicketNo)
references TICKET (TicketNo),
index (ViolationCode),
foreign key (ViolationCode)
references VIOLATION_TYPE (ViolationCode)
)ENGINE=InnoDB;
Spelling mistake on DriverLicenseNo in TICKET table ane
DriversLicenseNo in DRIVER table
I have an error in my database
Error: Invalid structure on line 18. Refer to our Manual (PHPMYADMIN)
I use (WAMPSERVER 2 32bits)
-PHPMYADMIN
- MYSQL 5.5.6
- PHP 5
Although i need to use InnoDB (ENGINE=InnoDB)
thanks to help me. Take a look at the structure... the variable name meaning is not important.
Here's my code:
DROP TABLE IF EXISTS Adresse;
DROP TABLE IF EXISTS Telephone;
DROP TABLE IF EXISTS Personne;
DROP TABLE IF EXISTS TelPers;
DROP TABLE IF EXISTS Specialiste;
DROP TABLE IF EXISTS Patient;
DROP TABLE IF EXISTS ListePatient;
DROP TABLE IF EXISTS Produit;
DROP TABLE IF EXISTS Medicament;
DROP TABLE IF EXISTS Materiel;
DROP TABLE IF EXISTS Panier;
CREATE TABLE Adresse(
idAdresse INT(100) NOT NULL PRIMARY KEY AUTO_INCREMENT,
num INT(5) NOT NULL,
rue VARCHAR(30) NOT NULL,
ville VARCHAR(15) NOT NULL,
postal VARCHAR(6) NOT NULL
)ENGINE=InnoDB;
CREATE TABLE Telephone(
idTel INT(100) NOT NULL PRIMARY KEY AUTO_INCREMENT,
typeTel VARCHAR(15) NOT NULL,
ind INT(3) NOT NULL,
quartier INT(3) NOT NULL,
num INT(4) NOT NULL,
)ENGINE=InnoDB;
CREATE TABLE Personne(
idPersonne INT(100) PRIMARY KEY NOT NULL AUTO_INCREMENT,
nom VARCHAR(15) NOT NULL,
prenom VARCHAR(15) NOT NULL,
idTel INT(100) NOT NULL,
idAdresse INT(100) NOT NULL,
FOREIGN KEY(idAdresse) REFERENCES Adresse(idAdresse),
FOREIGN KEY(idTel) REFERENCES Telephone(idTel)
)ENGINE=InnoDB;
CREATE TABLE TelPers(
idPersonne INT(100) PRIMARY KEY NOT NULL,
idTel INT(100) PRIMARY KEY NOT NULL,
FOREIGN KEY(idPersonne) REFERENCES Personne(idPersonne),
FOREIGN KEY(idTel) REFERENCES Telephone(idTel)
)ENGINE=InnoDB;
CREATE TABLE Specialiste(
login VARCHAR(10) PRIMARY KEY NOT NULL PRIMARY KEY,
password VARCHAR(10) NOT NULL,
profession VARCHAR(20) NOT NULL,
idListeP INT(5),
idPanier INT(5),
idPersonne INT(100),
FOREIGN KEY(idPersonne) REFERENCES Personne(idPersonne)
)ENGINE=InnoDB;
CREATE TABLE Patient(
idPatient INT(10) NOT NULL PRIMARY KEY AUTO_INCREMENT,
sexe CHAR NOT NULL,
anniv DATE,
assurance INT(3) NOT NULL,
idPersonne INT(100),
FOREIGN KEY(idPersonne) REFERENCES Personne(idPersonne)
)ENGINE=InnoDB;
CREATE TABLE ListePatient(
idListeP INT(5) NOT NULL PRIMARY KEY,
idPatient INT(10)NOT NULL PRIMARY KEY,
FOREIGN KEY(idListeP) REFERENCES Specialiste(idListeP),
FOREIGN KEY(idPatient) REFERENCES Patient(idPatient)
)ENGINE=InnoDB;
CREATE TABLE Produit(
idProduit INT(100) NOT NULL PRIMARY KEY AUTO_INCREMENT,
nom VARCHAR(50) NOT NULL,
descr VARCHAR(255) NOT NULL,
prix DECIMAL(5,2) NOT NULL,
qte INT(100) NOT NULL
)ENGINE=InnoDB;
CREATE TABLE Medicament(
idMedic INT(100)NOT NULL PRIMARY KEY AUTO_INCREMENT,
marque VARCHAR(10) NOT NULL,
typeMed VARCHAR(10) NOT NULL,
idProduit INT(100) NOT NULL,
FOREIGN KEY(idProduit) REFERENCES Produit(idProduit)
)ENGINE=InnoDB;
CREATE TABLE Materiel(
idMateriel INT(100) NOT NULL PRIMARY KEY AUTO_INCREMENT,
rabais INT(99) NOT NULL,
idProduit INT(100) NOT NULL,
FOREIGN KEY(idProduit) REFERENCES Produit(idProduit)
)ENGINE=InnoDB;
CREATE TABLE Panier(
idPanier INT(5) NOT NULL PRIMARY KEY,
idProduit INT(100) NOT NULL PRIMARY KEY,
FOREIGN KEY(idPanier) REFERENCES Specialiste(idPanier),
FOREIGN KEY(idProduit) REFERENCES Produit(idProduit)
)ENGINE=InnoDB;
THANKS FOR YOUR HELP! :D
In Telephone declaration there is a comma (,) before closing )
In TelPers there are two primary keys
In Specialiste there is PRIMARY KEY twice in login column
In ListePatien there are two primary keys
In Panier there are two primary keys
To define a PRIMARY key on two columns use
CREATE TABLE Panier(
idPanier INT(5) NOT NULL,
idProduit INT(100) NOT NULL,
PRIMARY KEY (`idPanier`,`idProduit`),
FOREIGN KEY(idPanier) REFERENCES Specialiste(idPanier),
FOREIGN KEY(idProduit) REFERENCES Produit(idProduit)
)ENGINE=InnoDB;
(same on other tables)