Getting Stratified data from MySQL - mysql

Question

I have two tables. Teams and Players. What I want to do is create a query that tells me some statistical data about the salary of the largest team. Specifically I want a count of how many players make less than 5K. How many make between 5K and 10K ....in increments of 5K to the max player.
Here is the SQL:
CREATE TABLE `formsfiles`.`Teams` (
`ID` INT NOT NULL AUTO_INCREMENT ,
`Name` VARCHAR(45) NULL ,
PRIMARY KEY (`ID`) );
INSERT INTO `Teams` (`Name`) VALUES ('Sharks');
INSERT INTO `Teams` (`Name`) VALUES ('Jets');
INSERT INTO `Teams` (`Name`) VALUES ('Fish');
INSERT INTO `Teams` (`Name`) VALUES ('Dodgers');
CREATE TABLE `Players` (
`ID` INT NOT NULL AUTO_INCREMENT ,
`Name` VARCHAR(45) NULL ,
`Team_ID` INT NULL ,
`Salary` INT NUll ,
PRIMARY KEY (`ID`) );
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Jim', '1', '4800');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Tom', '1', '12000');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Harry', '2', '1230');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Dave', '2', '19870');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Tim', '3', '1540');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Trey', '4','7340');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Jay', '4', '4800');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Steve', '4','6610');
INSERT INTO `Players` (`Name`, `Team_ID`, salary) VALUES ('Chris', '4','17754');
Given this data: The Dodgers are the largest team (ID =4)
We would like an output of:
0-5000 1
5000-10000 2
10000-15000 0
15000-20000 1
If this code looks familiar it is because it is an evolution of a problem of a prior problem I posted here. Kindly don't beat me down!

Answer 1

Here is my attempt at this. It uses joins to satisfy the conditions:
select sr.range,
SUM(case when p.salary >= sr.low and p.salary < sr.high then 1 else 0 end)
from Players p join
(select t.id
from Players p join
Teams t
on p.team_id = t.id
group by t.team_id
order by SUM(p.salary) desc
limit 1
) team
on p.team_id = team.id cross join
(select '0-5000' as range, 0 as low, 5000 as high union all
select '5000-10000', 5000, 10000 union all
select '10000-15000', 10000, 15000 union all
select '15000-20000', 15000, 20000
) sr
group by sr.range
order by min(sr.low)
Notice the use of a separate query for the ranges, to be sure that you get rows with a count of 0.

Answer 2

This code will do almost what you want
SELECT 5000 * FLOOR(Salary / 5000), count(*)
FROM Players
WHERE Team_ID = 4
GROUP BY FLOOR(Salary / 5000)
It returns the low border of the range and the number of entries
0 1
5000 2
15000 1
Note that it does not return empty ranges.