Problem: I have a form
<form action="validate.asp" method="post" ENCTYPE="multipart/form-data">
which has a file field input type= "file"
now I need to retrieve the file name in the validate.asp, here I cannot use request.form(filename) since it uses multipart/form-data .
What is the solution?
Re-edit:
this is my form
<form action="validate.asp" method="post" ENCTYPE="multipart/form-data">
<input name="ename" type="text" />
<input name="file" type="file" />
<input name="Add" type="Submit"/>
</form>
now when the submit button is pressed i want the validate page to hold the name of the file ... for example dim fileName contains the name of the file just the name.... how to do this. this doesnot work Set fileName= Upload.Form("file") how to solve this problem.
The proper way to do this is by using upload script that will handle the raw data. Most upload scripts will give easy access to the form elements, so basic sample code would be:
Dim objUpload, strFileName
'Initialize upload:
Set objUpload = New Uploader
'Get form element value:
strFileName = objUpload.Form("file")
You can find many free upload scripts by Googling and you can also use this one I posted here, originally meant for images but can also be used for ordinary upload.
Related
I have successfully hosted an .onion website but I don't have much experience in HTML codes. I need someone to tell me how to create a form + be able to input the submitted stuff inside the form (raw) into a text file + output the contents of a text file. Thanks :) Any help is greatly appreciated.
As per my understanding regarding your requirement, try below stuffs.
In view page(page for input form) use the below HTML code.
<html>
<body>
<form action="" method="POST">
<input name="field1" type="text" />
<input name="field2" type="text" />
<button type="submit">Save</button>
</form>
<button><a href='file_data.php'>Get file data</a></button>
</body>
</html>
Below the above HTML code use the PHP code below for processing submitted form inputs and to add the submitted form data to a text file(data.txt). The text file will be automatically created if it's not existing.
NB: You can also use a PHP file for this, for eg: form.php. In that case use <form action="form.php" method="POST"> in the above HTML code.
Create a file file_data.php and use below code.
$myFile = "data.txt";
$lines = file($myFile);//file in to an array
foreach($lines as $line)
{
echo $line.'<br>';
}
Now, if you click on Get file data button in view page, data added to the text file will be printed.
I'm currently doing some web development work and my assignment requires me to upload a file to a server. I have the following code:
<form id = "uploadbanner" method = "post">
<input id = "fileupload" type = "file" />
</form>
I don't have a submit button, since there's already one at the bottom of the page. Whenever I test out the code and input a file x, it tells me that it cannot find x. I've tried seeing if I could obtain the path name from the client to see if this was the issue, but that isn't allowed due to security reasons. Any help would be appreciated; thanks!
This could help:
<form action="upload.php" method="post" enctype="multipart/form-data">
Select file to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload File" name="submit">
</form>
In order to achieve the upload, you must:
add an action to your form
use name instead of id in order to read the file, check this: HTML input - name vs. id
Don't forget to link your submit button to the form and you're good to go.
I am looking for a one-click solution that will call up a file open dialog and from that dialog, send the file name to the next page. I stole this code, but it requires 2 clicks to get to the next page:
<form enctype="multipart/form-data" action="ImportTOA.php" method="POST" accept="text/csv">
<!-- MAX_FILE_SIZE must precede the file input field -->
<input type="hidden" name="MAX_FILE_SIZE" value="30000" />
<!-- Name of input element determines name in $_FILES array -->
Upload Daily TOA Logs: <br /><input name="userfile" type="file" />
<input type="submit" value="Send File" />
</form>
I don't need to upload the file, I just need to pass the file name that the user chooses.
If you don't need to upload the file, just remove the enctype. The file name should get passed without the upload. Then you could submit the form on the change event on the file. I'll need to double check the documentation, but I think change fires on the file input.
Looks like IE might be a bit different: Jquery: change event to input file on IE
You don't even really need to "submit" the form, just grab the file name via javascript and do whatever you need to do.
OK. With a sufficiently narrow Google query, I found the answer. Should anyone come along to read this thread, here's the code I borrowed that worked:
<form enctype="multipart/form-data" action="ImportTOA.php" method="POST" accept="text/csv">
<!-- MAX_FILE_SIZE must precede the file input field -->
<input type="hidden" name="MAX_FILE_SIZE" value="30000" />
<!-- Name of input element determines name in $_FILES array -->
Upload Daily TOA Logs: <br /><input name="userfile" type="file" onChange = "this.form.submit()" />
</form>
Ok I really didn't know how else to sum it up for the title. I need to create a form where a user can specify an existing file, but I don't need to upload it (it's on a shared server already accessible) -- I just need to grab the filename and save it in the database so it's linked to other data.
I thought about the input tag as it provides a convenient already done interface to the user's filesystem, but I don't know if it's possible to use it without the acutal upload (leaving out enctype="multipart/form-data" doesn't seem to work). Can I tweak this to make it work, or is there any way to do it other than writing a custom mini file browser?
EDIT: I need the full path name of the file, asking the users to enter it is out of the question...
You could place the <input type="file"> outside your HTML form, and then use the onChange event to fill an <input type="hidden"> within the form that gets posted:
<input type="file"
onchange="document.getElementById('hidden_file').value = this.value;" />
<form method="POST">
<input type="hidden" id="hidden_file" value="" />
<input type="submit" />
</form>
I have a trouble with file-uploding. Here is my part of the form:
<input type="file" name="image_file" />
<input type="submit" name="add_new" value="Upload" />
And in script i have a code:
print_r($_FILES);
After image choosing and sending form, I have an empty array $_FILES. Why?
The form must be set like this:
<form action="myuploadpage.php" method="post" enctype="multipart/form-data">
...
</form>
So that the browser knows to send the image along with the data.
Have you set the form method to POST data to the PHP script and set the action to point to it? If so then you should be able to get something like $_FILES['image_file']['name']