I'm creating a secondary tile and the only logo I have is quite small (32x32 pixels I think).
This means the logo is scaled for the secondary tile and looks terrible:
Is there any way to prevent the logo from being scaled so it looks more like a normal live tile?
I've tried specifying the tile size as TileSize.Square71x71 in the constructor, but this simply throws an exception.
Any ideas?
Edit
The exception I get is:
{Windows.UI.Xaml.UnhandledExceptionEventArgs}
Exception = {"Value does not fall within the expected range."}
Message = "The parameter is incorrect.\r\n"
But I think that makes sense because I think secondary tiles only accept two sizes in the constructor, TileSize.Square150x150 and TileSize.Wide310x150.
Edit 2
The code that throws the exception is:
var secondaryTile = new SecondaryTile("myId",
"sweet name",
"sweet args",
myLogoUri,
TileSize.Square71x71);
If I change the last line to TileSize.Square150x150); no exception is thrown, but then I'm left with the larger tile.
Ended up going for a work around.
I'm placing the icon on a transparent background which is the right size, thus preventing scaling.
If anyone has cleaner solution I'd be stoked to hear it!
So I am super stoked to start using LibGDX for my first android title for OUYA and PC, but I am running into some snags with LibGDX. (All of my questions can be answered by looking at source, but I am really trying to understand the design choices as well).
To start with, the coordinate system. I created a project using the Project Setup jar, and it creates an OrthographicCamera like so
camera = new OrthographicCamera(1, h/w);
From my reading, I understand that LibGdx uses bottom left corner for 0,0 and yUp. Fine.
I see that it is pretty easy to change to y down if I want to, but I am not understanding the next bit of code that was created.
For the default sprite that gets created the position is set like so.
logoSprite.setOrigin(logoSprite.getWidth()/2, logoSprite.getHeight()/2);
logoSprite.setPosition(-logoSprite.getWidth()/2, -logoSprite.getHeight()/2);
When I run this basic program, I see the logo image I have added is centered on the screen. What I am trying to understand is why the values are negative in set position, and why is it using the sprite width and height instead of the graphics w and h of the view port? If I change to the screen width and height, then the image is drawn in some odd position in the lower right hand side of the screen.
My next question is sprite.setSize vs sprite.setScale. Why is the difference between the two? (They appear to do the same thing, except setScale leaves getWidth and getHeight unchanged).
Since my game will be using a 2D camera heavily for panning, zooming and rotation, I am trying to understand as much as I can about the libgdx framework before I start writing any code.
As a side note, I have a game development and math background and I have made several 2D and 3D games using XNA. I am finding LibGdx a bit frustrating as it does not abstract away OpenGL as much as I was expecting it to, and so far the 2D drawing I have been experimenting with seems to be more confusing than it should be!
I also wanted to note that I am planning to use spine for my animations. Should that change my choice to use y-up or y-down?
If you want to draw a sprite in center of screen, do this in your create method
logosprite.setposition(scrw/2-logosprite.getwidth()/2,scrh/2-logosprite.getheight/2);
here scrw is your viewport's width,
and scrh is your viewport's height,
this way your sprite will be in center of screen
sprite.setsize is used for setting size of the sprite and sprite.setscale is used when we scale a large/small texture so that its quality remains good in all devices(hdpi.mdpi,xhdpi,ldpi)..
no need to worry if you are using spine it works smoothly in libgdx..
You can use just this code if possible
logoSprite.setPosition(Gdx.graphics.getWidth()/2 - image.getWidth()/2,
Gdx.graphics.getHeight()/2 - image.getHeight()/2);
To center the sprite into the middle of the screen Where "image" is the Texture you have loaded/declared initially.
As for why it is coming in a odd position is due to the fact that you are using a camera.
Which changes the view a lot just go through the documentations of libgdx about camera here
In my case, I needed to set position of camera and then call update() method.
Then never forget camera's (0,0) is its center. Everything is being placed that way. My camera code:
private void cameralariUpdateEt() {
cameraGame.position.set(cameraGame.viewportWidth * 0.5f,
cameraGame.viewportHeight * 0.5f, 0);
cameraGame.update();
cameraScore.position.set(cameraScore.viewportWidth * 0.5f,
cameraScore.viewportHeight * 0.5f, 0);
cameraScore.update();
}
Call this method from inside render();
Step 1: Set the sprite origin to the position you would like it to rotate around.
// camera center point is (c.x, c.y)
logoSprite.setOrigin(c.x, c.y);
Step 2: make sure to set your sprite center to origin
logoSprite.setOriginCenter();
Step 3: Rotate your sprite
logoSprite.setRotation(Angle);
Step 4: Set the sprite position, [subtract half the sprites width and height to center the sprite]
logoSprite.setPosition(c.x - logoSprite.getWidth() / 2, c.y - logoSprite.getHeight() / 2)
This page shows some animations in HTML5 canvas. If you look at the source of the scroller, there's a statement to save the context after clearing the rectangle and restoring it after the animation. If I substitute the restore statement with another ctx.clearRect(0, 0, can.width, can.height statement, nothing works. I thought the restore is restoring the cleared rectangle but it seems its restoring more info. What's that extra info that's needed for the next frame?
I am not looking for HTML5 textbook definitions of Save and Restore but I want to understand why they are needed in this specific example.
UPDATE
It's frustrating to get an answer where I specifically already mentioned in the question I don't want to get the definitions of save() and restore(). I already know Save() saves the state of the context and Restor()e restores it. My question is very specific. Why is restore() used in the manner in the example when all the Save did is saved an empty canvas. Why is restoring an empty canvas not the same as clearing it?
Canvas state isn't what's drawn on it. It's a stack of properties which define the current state of the tools which are used to draw the next thing.
Canvas is an immediate-mode bitmap.
Like MS Paint. Once it's there, it's there, so there's no point "saving" the current image data, because that would be like saving the whole JPEG, every time you make a change, every frame...
...no, the state you save is the state which will dictate what coordinate-orientation, dimension-scale, colour, etc, you use to draw the NEXT thing (and all things thereafter, until you change those values by hand).
var canvas = document.createElement("canvas"),
easel = canvas.getContext("2d");
easel.fillStyle = "rgb(80, 80, 120)";
easel.strokeStyle = "rgb(120, 120, 200)";
easel.fillRect(x, y, width, height);
easel.strokeRect(x, y, width, height);
easel.save(); // stores ALL current status properties in the stack
easel.rotate(degrees * Math.PI / 180); // radians
easel.scale(scale_X, scale_Y); // any new coordinates/dimensions will now be multiplied by these
easel.translate(new_X, new_Y); // new origin coordinates, based on rotated orientation, multiplied by the scale-factor
easel.fillStyle = "gold";
easel.fillRect(x, y, width, height); // completely new rectangle
// origin is different, and the rotation is different, because you're in a new coordinate space
easel.clearRect(0, 0, width, height); // not even guaranteed to clear the actual canvas, anymore
easel.strokeRect(width/2, height/2, width, height); // still in the new coordinate space, still with the new colour
easel.restore(); // reassign all of the previous status properties
easel.clearRect(0, 0, width, height);
Assuming that you were only one state-change deep on the stack, that last line, now that your canvas' previous state was restored, should have successfully cleared itself (subpixel shenanigans notwithstanding).
So as you can see, it has very, VERY little to do with erasing the canvas.
In fact, it has nothing to do with erasing it, at all.
It has to do with wanting to draw something, and doing the basic outlining and sweeping colours/styles, and then manually writing in the colours for the smaller details on top, and then manually writing all of the styles back the way they were before, to go back to sweeping strokes for the next object, and on and on...
Instead, save general states that will be reused, create a new state for smaller details, and return to the general state, without having to hard-code it, every time, or write setter functions to set frequently-used values on the canvas over and over (resetting scale/rotation/affine-transforms/colours/fonts/line-widths/baseline-alignment/etc).
In your exact example, then, if you're paying attention, you'll see that the only thing that's changing is the value of step.
They've set the state of a bunch of values for the canvas (colour/font/etc).
And then they save. Well, what did they save?
You're not looking deep enough. They actually saved the default translation (ie: origin=0,0 in original world-space).
But you didn't see them define it?
That's because it's defined as default.
They then increase the step 1 pixel (actually, they do this first, but it doesn't matter after the first loop -- stay with me here).
Then they set a new origin point for 0,0 (ie: from now on, when they type 0,0 that new origin will point to a completely different place on the canvas).
That origin point is equal to x being the exact middle of the canvas, and y being equal to the current step (ie: pixel 1 or pixel 2, etc... and why the difference between starting at 0 and starting at 1 really doesn't matter).
Then what do they do?
They restore.
Well, what have they restored?
...well, what have they changed?
They're restoring the point of origin to 0,0
Why?
Well, what would happen if they didn't?
If the canvas is 500px x 200px, and it starts at 0,0 in our current screen space... ...that's great...
Then they translate it to width/2, 1
Okay, so now when they ask to draw text at 0,0 they'll actually be drawing at 250, 1
Wonderful. But what happens next time?
Now they're translating by width/2, 2
You think, well, that's fine... ...the draw call for 0,0 is going to happen at 250, 2, because they've set it to clear numbers: canvas.width/2, 2
Nope. Because current 0,0 is actually 250,1 according to our screen. And one translation is relative to its previous translation...
...so now you're telling the canvas to start at it's current-coordinates' 0,0 and go left 250, and down 2.
According to the screen (which is like a window, looking at the map, and not the map, itself) we're now 500px to the right, and 3 pixels down from where we started... And only one frame has gone by.
So they restore the map's coordinates to be the same origin as the screen's coordinates (and the rotation to be the same, and the scale, and the skew, etc...), before setting the new one.
And as you might guess, by looking at it, now, you can see that the text should actually move top to bottom. Not right to left, like the page says...
Why do this?
Why go to the trouble of changing the coordinate-system of the drawing-context, when the draw commands give you an x and y right there in the function?
If you want to draw a picture on the canvas, and you know how high and wide it is, and where you'd like the top-left corner to be, why can't you just do this:
easel.drawImage(myImg, x, y, myImg.width, myImg.height);
Well, you can.
You can totally do that. There's nothing stopping you.
In fact, if you wanted to make it zoom around the screen, you could just update the x and y on a timer, and call it a day.
But what about if you were drawing a game character? What if the character had a hat, and had gloved hands, and big boots, and all of those things were drawn separate from the character?
So first you'd say "well, he's standing at x and y in the world, so x plus where his hand is in relation to his body would be x + body.x - hand.x...or was that plus..."
...and now you have draw calls for all of his parts that are all looking like a notebook full of Grade 5 math homework.
Instead, you can say: "He's here. Set my coordinates so that 0,0 is right in the middle of my guy". Now your draw calls are as simple as "My right hand is 6 pixels to the right of the body, my left hand is 3 pixels to the left".
And when you're done drawing your character, you can set your origin back to 0,0 and then the next character can be drawn. Or, if you want to attempt it, you can then translate from there to the origin of the next character, based on the delta from one to the other (this will save you a function call per translation). And then, if you only saved state once the whole time (the original state), at the end, you can return to 0,0 by calling .restore.
The context save() saves stuff like transformation color among other stuff. Then you can change the context and restore it to have the same as when you saved it. It works like a stack so you can push multiple canvas states onto the stack and recover them.
http://html5.litten.com/understanding-save-and-restore-for-the-canvas-context/
First of all, I would like to say that I'm a newbie in Java3D. Please bear with my ignorance.
I have made an application with Java3D and I have the following problems with zooming.
It seems the MouseWheelZoom behaviour of Java3D moves the object along Z-axis. On the scene my Z-axis is not out of plane so by using MouseWheelZoom , the object doesn't get closer but it get out of screen. Is there a way to set the zoom direction to an arbitrary direction?
I have got around the problem by using MouseWheelListener and changing the viewing platform based on zoom steps. But there is another problem now. As the object gets closer than a certain distance, some parts of the object ( usually the corners) start disappearing so I can't zoom as much as I desire.
Could you please help ?
Regards,
Hassan
Question:
I guess you use an OrbitBehavior for MouseControl like:
orbit = new OrbitBehavior(canvas3d, OrbitBehavior.REVERSE_ALL);
If that is the case then try
orbit.setZoomFactor(-1d);
To reverse the zoom direction (the default zoom factor is +1d).
To your 2. Question:
You have to set a BoundingLeaf on your PlatformGeometry to encapsulate your "viewing area".
Try something like this
defaultBounds = new BoundingSphere(new Point3d(radiusGameMap, 0.0, radiusGameMap),
radiusGameMap * 6.0d);
BoundingLeaf boundingLeaf = new BoundingLeaf(defaultBounds);
PlatformGeometry platformGeom = new PlatformGeometry();
platformGeom.addChild(boundingLeaf);
where radiusGameMap is a double defining the radius of your whole map.
I'm using a flip mechanism to navigate through my site (flip file & demo). The problem is, once it's flipped the content been displayed good just like I want it, but there's some offset from the flipped (right) parts en the solid left part (visible when you look closely). Also the right part is now a little blurred (which is the disturbing part of my issue). This all caused by the flip (I think the rotationY is causing the problem).
When I click a button I do the following:
flip=new Flip(currentPage,nextPage,richting);
content.addChild(flip);
currentPage=nextPage;
nextPage = new MovieClip();
there is a fix for it, consider the following:
// store original matrix
var origMatrix:Matrix = box.transform.matrix;
// set initial position
box.rotationY = -180;
// start animation
TweenLite.to(box, 1, {rotationY:0, onComplete:cleanBlur})
// execute after animation complete
function cleanBlur():void {
box.transform.matrix = origMatrix;
}
maybe you can find better results using other 3d library.
EDIT: sorry the "box" object, I was testing in flash, but box would be any of your pages to flip. Just apply the same logic.
Matteo at Flash & Math has an excellent solution for this. He actually found that when you bring an object into native 3D space it expands the object by one pixel in both the width and height. This can be counteracted by scaling your object back and then setting it's z to 0 which will scale it back up. Now the object is ready to play with without the blur.
http://www.flashandmath.com/flashcs4/blursol/index.html
adding: This fixes the scale issue, but not the blurriness. You will still need to use the matrix transformation fix posted above.