I have a table "audit" with a "description" column, a "record_id" column and a "record_date" column. I want to select only those records where the description matches one of two possible strings (say, LIKE "NEW%" OR LIKE "ARCH%") where the record_id in each of those two matches each other. I then need to calculate the difference in days between the record_date of each other.
For instance, my table may contain:
id description record_id record_date
1 New Sub 1000 04/14/13
2 Mod 1000 04/14/13
3 Archived 1000 04/15/13
4 New Sub 1001 04/13/13
I would want to select only rows 1 and 3 and then calculate the number of days between 4/15 and 4/14 to determine how long it took to go from New to Archived for that record (1000). Both a New and an Archived entry must be present for any record for it to be counted (I don't care about ones that haven't been archived). Does this make sense and is it possible to calculate this in a SQL query? I don't know much beyond basic SQL.
I am using MySQL Workbench to do this.
The following is untested, but it should work asuming that any given record_id can only show up once with "New Sub" and "Archived"
select n.id as new_id
,a.id as archive_id
,record_id
,n.record_date as new_date
,a.record_date as archive_date
,DateDiff(a.record_date, n.record_date) as days_between
from audit n
join audit a using(record_id)
where n.description = 'New Sub'
and a.description = 'Archieved';
I changed from OR to AND, because I thought you wanted only the nr of days between records that was actually archived.
My test was in SQL Server so the syntax might need to be tweaked slightly for your (especially the DATEDIFF function) but you can select from the same table twice, one side grabbing the 'new' and one grabbing the 'archived' then linking them by record_id...
SELECT
newsub.id,
newsub.description,
newsub.record_date,
arc.id,
arc.description,
arc.record_date,
DATEDIFF(day, newsub.record_date, arc.record_date) AS DaysBetween
FROM
foo1 arc
, foo1 newsub
WHERE
(newsub.description LIKE 'NEW%')
AND
(arc.description LIKE 'ARC%')
AND
(newsub.record_id = arc.record_id)
Related
I am writing an Exception Catching Page using MySQL for catching duplicate billing entries the following scenario.
Items details are entered in a table which has the following two columns (among others).
ItemCode VARCHAR(50), BillEntryDate DATE
It often happens that same item's bill is entered multiple times, but over a period of few days. Like,
"Football","2019-01-02"
"Basketball","2019-01-02"
...
...
"Football","2019-01-05"
"Rugby","2019-01-05"
...
"Handball","2019-01-05"
"Rugby","2019-01-07"
"Rugby","2019-01-10"
In the above example, the item Football is billed twice - first on 2Jan and again on 5Jan. Similarly, item Rugby is billed thrice on 5,7,10Jan.
I am looking to write simple SQL which can pickup each item [say, using distinct(ItemCode) clause], and then display all the records which are duplicates over a period of 30 days.
In the above case, the expected output should be the following 5 records:
"Football","2019-01-02"
"Football","2019-01-05"
"Rugby","2019-01-05"
"Rugby","2019-01-07"
"Rugby","2019-01-10"
I am trying to run the following SQL:
select * from tablen a, tablen b, where a.ItemCode=b.ItemCode and a.BillEntryDate = b.BillEntryDate+30;
However, this seems to be highly inefficient as it is running for long without displaying any records.
Is there any possibility for getting a less complex and faster method?
I did explore existing topics (like How do I find duplicates across multiple columns?), but it is catching duplicates where BOTH columns have same value. My requirement is one column same value, and second column varying over a month-long date range.
You can use:
select t.*
from tablen t
where exists (select 1
from tablen t2
where t2.ItemCode = t.ItemCode and
t2.BillEntryDate <> t.BillEntryDate and
t2.BillEntryDate >= t1.BillEntryDate - interval 30 day and t2.BillEntryDate <= t1.BillEntryDate + interval 30 day
);
This will pick up both duplicates in the pair.
For performance, you want an index on (ItemCode, BillEntryDate).
With EXISTS:
select ItemCode, BillEntryDate
from tablename t
where exists (
select 1 from tablename
where
ItemCode = t.ItemCode
and
abs(datediff(BillEntryDate, t.BillEntryDate)) between 1 and 30
)
Sorry for the title, hard to explain in one line, but I am after a query that can get me all the rows based on the result of the first row - an example will explain:
Table looks like this
id | name | week
1 x 2
2 y 2
3 z 3
So basically without knowing the first week value, I want only those rows where week = 2. In other words, if the next run, the first result is week: 3, then I only want rows where week = 3.
This is all contingent on the correct ordering of the rows - but that is not the purpose of this.
I've thought about doing it in two queries given this be inside some php app, where the first query
select week from table limit 1
And therefore, now we know the week value, can simply
select id, name, week from table where week = '2'
But I figured there was a smarter way to do it in one query, just not sure what that sql function might look like.
Hope that makes sense.
Expanding from your steps and thinking, you could do
SELECT * FROM table WHERE week = (SELECT week FROM table LIMIT 1)
The above should work fine (unless I misunderstood the question).
I've a table with a structure something like this,
Device | paid | time
abc 1 2 days ago
abc 0 1 day ago
abc 0 5 mins ago
Is it possible to write a query that checks the paid column on all the rows where Device = abc and then outputs the most recent two rows that different. Basically, something like an if statement saying if row 1 = 1 and row 2 = 0 output that but only if it's the most recent two columns that are different. For example, in this case, the first and second row. The table is being updated whenever a user changes from a free to paid account etc. It is also updated in different columns for different reasons hence the duplicate 0s for example.
I know this would probably be done better by having another table altogether and updating that every time the user switches account type, but is there any way to make this work?
Thanks
Example:
http://rextester.com/MABU7860 need further testing on edge cases but this seems to work.
SELECT A.*, B.*
FROM SQLfoo A
INNER JOIN SQLFoo B
on A.Device = B.Device
and A.mTime < B.mTime
WHERE A.Paid <> B.Paid
and A.device = 'abc'
ORDER BY B.mTime Desc, A.MTime Desc
LIMIT 1
By performing a self join we on the devices where the time from one table is less than the time from the next table (thus the two records will never matach and we only get the reuslts one way) and we order by those times descending, the highest times appear first in the result since we limit by a single device we don't need to concern ourselves with the devices. We then just need compare the paid from one source to the paid in the 2nd source and return the first result encountered thus limit 1.
Or using user variables
http://rextester.com/TWVEVX7830
in other engines one might accomplish this task by performing the join as in above, assigning a row number partitioned by the device and then simply return all those row_numbers with a value of 1; which would be the earliest date discrepency.
Use LIMIT to limit the number of record on mysql:
http://www.mysqltutorial.org/mysql-limit.aspx
In your case, use LIMIT 2
and then put the 2 record that you just select into an array, then compare the array if the value is different. If they are different then print
Evening folks,
I have a complex MySQL COUNT query I am trying to perform and am looking for the best way to do it.
In our system, we have References. Each Reference can have many (or no) Income Sources, each of which can be validated or not (status). We have a Reference table and an Income table - each row in the Income table points back to Reference with reference_id
On our 'Awaiting' page (the screen that shows each Income that is yet to be validated), we show it grouped by Reference. So you may, for example, see Mr John Smith has 3 Income Sources.
We want it to show something like "2 of 3 Validated" beside each row
My problem is writing the query that figures this out!
What I have been trying to do is this, using a combination of PHP and MySQL to bridge the gap where SQL (or my knowledge) falls short:
First, select a COUNT of the number of incomes associated with each reference:
SELECT `reference_id`, COUNT(status) AS status_count
FROM (`income`)
WHERE `income`.`status` = 0
GROUP BY `reference_id`
Next, having used PHP to generate a WHERE IN clause, proceed to COUNT the number of confirmed references from these:
SELECT `reference_id`, COUNT(status) AS status_count
FROM (`income`)
WHERE `reference_id` IN ('8469', '78969', '126613', ..... etc
AND status = 1
GROUP BY `reference_id`
However this doesn't work. It returns 0 rows.
Any way to achieve what I'm after?
Thanks!
In MySQL, you can SUM() on a boolean expression to get a count of the rows where that expression is true. You can do this because MySQL treats true as the integer 1 and false as the integer 0.
SELECT `reference_id`,
SUM(`status` = 1) AS `validated_count`,
COUNT(*) AS `total_count`
FROM `income`
GROUP BY `reference_id`
I actually don't even know how to call this :P, but...
I have one table, let's call it "uploads"
id owner date
-----------------------------
0 foo 20100101120000
1 bar 20100101120300
2 foo 20100101120400
3 bar 20100101120600
.. .. ..
6 foo 20100101120800
Now, when I'ld do something like:
SELECT id FROM uploads ORDER BY date DESC
This would result in:
id owner date
-----------------------------
6 foo 20100101120800
.. .. ..
3 bar 20100101120600
2 foo 20100101120400
1 bar 20100101120300
0 foo 20100101120000
Question: Nice, but, I want to go even further. Because now, when you would build a timeline (and I did :P), you are 'spammed' by messages saying foo and bar uploaded something. I'ld like to group them and return the first result with a time-limit of '500' at the date-field.
What kind of SQL-command do I need that would result in:
id owner date
-----------------------------
6 foo 20100101120800
3 bar 20100101120600
0 foo 20100101120000
Then, after that, I can perform a call for each record to get the associative records in a timeframe of 5 minutes (this is an exmaple for id=6):
SELECT id FROM uploads WHERE date>=20100101120800-500 ORDER BY date DESC
Does anyone now how I should do the first step? (so limiting/grouping the results)
(btw. I know that when I want to use this, I should convert every date (YmdHis=60) to Unix-time (=100), but I don't need the 5 minutes to be exactly 5 minutes, they may be a minute less sometimes...)
I'm not quite clear on the result you are trying to get, even with your examples. Perhaps something with rounding and group by.
SELECT max(id) max_id,owner, (ROUND(date/500)*500) date_interval, max(date) date
FROM uploads GROUP BY date_interval,owner
You may want to use FLOOR or CEILING instead of ROUND, depending on what you want.
Standard SQL doesn't deal with intervals very well.
You are going to need to do a self-join of the table to compare dates of different tuples.
That way, you can easily find all pairs of tuples of which the dates are no more than 500 apart.
However, you really want to cluster the dates in sets no more than 500 apart - and that can't be expressed in SQL at all, as far as I know.
What you can do is something quite similar: split the total time interval into fixed 500-unit ranges, and then cluster all tuples in the table based on the interval they're in. For that, you first need a table or query result with the start times of the intervals; this can be created using a SQL query on your table and a function that either "rounds off" a timestamp to the starting time in its interval, or computes its interval sequence number. Then as a second step you can join the table with that result to group its timestamps according to their corresponding start time. I can't give the SQL because it's DBMS-dependent, and I certainly can't tell you if this is the best way of accomplishing what you want in your situation.
Use an inline view? e.g. something like
SELECT u1.*
FROM uploads u1,
(SELECT date
FROM uploads u2
WHERE u2.owner='foo') datum_points
WHERE u1.date BETWEEN datum_points.date
AND DATE_ADD(datum_points.date INTERVAL 5 MINUTES)
should return all the posts made within 5 minutes of 'foo' making a post.