Mysql Update, 2 databases - mysql

I have 2 MYSQL tables and when I pick up dates from table A which contains only 1 column and lets say 10 rows with dates
$result = mysql_query("SELECT * FROM A");
$row = mysql_fetch_assoc($result);
And after I want to UPDATE another table B with using this dates from table A mysql_query("UPDATE B SET something='1' WHERE name='".$row['name']."'")
So i need to update the second table, but its updating just once with first date from table A, and other 9 its ignoring. So my question is, how to make updating of second table with each date from 1 table?

You need to run a the updates in a loop. After executing your query
$result = mysql_query("SELECT * FROM A");
and verifying that it has succeeded (make sure $result is not null), instead of fetching one row, use a loop:
while($row = mysql_fetch_assoc($result)){
// perform calculations & assignments with the $row elements
$result2 = mysql_query("UPDATE B SET something='1'
WHERE name='".$row['name']."'");
if(! $result2){
echo "update failed";
}
// Any other stuff you need to do
}
Alternatively:
If the something in the update is the same for all the rows, you can change your first query to give you a coma-separated string of names:
$result = mysql_query("SELECT CONCAT("'",GROUP_CONCAT(name SEPARATOR "','"),"'")
AS all_names FROM A");
This way, you receive only one row, and you can then use it in your second query:
$result2 = mysql_query("UPDATE B SET something='1'
WHERE name IN (".$row['name'].")");

Related

Updating Multiple Column on MySQL

I want to update members_roosevelt table ACCOUNT column starting with 3000+ value I also want to update ACCOUNT column on loan_roosevelt table that is related to my member_roosevelt. What's wrong with my query? Thank you!
$query1 = "SELECT ACCOUNT
FROM
`members_roosevelt`";
$result_q1 = $link->query($query1) or die($link->error);
while ($obj = $result_q1->fetch_object()) {
$members[] = $obj->ACCOUNT;
}
$ids = implode(',', $members);
$sql = "UPDATE `members_roosevelt` as `memb`
JOIN `loan_roosevelt` as `loan`
ON `memb`.`ACCOUNT` = `loan`.`ACCOUNT`
SET
(`memb`.`ACCOUNT`,
`loan`.`ACCOUNT`) = CASE ACCOUNT";
foreach ($members as $id => $ordinal) {
$sql .= sprintf("WHEN %d THEN %d ", $ordinal, (3000+$id));
}
$sql .= "END WHERE memb.ACCOUNT IN ($ids)";
$link->query($sql) or die($link->error);
SET (`memb`.`ACCOUNT`, `loan`.`ACCOUNT`) = CASE ACCOUNT...
This is simply not part of SQL syntax. You can't set two columns at a time like this. The left side of an assignment operator must be one column.
A better solution is to use a session variable.
SET #acct = 3000;
UPDATE members_roosevelt as memb
JOIN loan_roosevelt as loan
ON memb.ACCOUNT = loan.ACCOUNT
SET memb.ACCOUNT = (#acct:=#acct+1),
loan.ACCOUNT = (#acct);
This way you don't have to run the SELECT query at all, and you don't have to create a huge UPDATE statement with potentially thousands of WHEN clauses.
Demo: SQLFiddle

Select a value from table and reserve it

Low level question but, I understand that you can select elements from a table using:
$sql = "SELECT blah FROM TABLE WHERE this = 'something' ";
But when I try to select a specific value from my table, where let's say a user has no tries left so if I try to grab how many tries they have left with:
$sql = "SELECT tries FROM table WHERE user = 'something'";
How would I grab that value specifically if it was 5 or 9? I tried setting a variable equal to something I $sql off my table but it doesn't grab the value.
Edit
I have a database that has a table called Item which contains: id, name, value, and stock of a particular item. If a user wants to order that item I will first check it if's in stock with a function, to see if it is not in stock then a error message is printed, otherwise accept the order.
Extremely primitive since I'm just trying to get grab the stock value first.
$query = $_GET['query']; //id I get from the specified item
echo 'the id is: ' .$query.''; //test purposes
$mysql_handle = mysql_connect($dbhost, $dbuser, $dbpass)
or die("Error connecting to database server");
mysql_select_db($dbname, $mysql_handle)
or die("Error selecting database: $dbname");
$sql1 = "SELECT item_stock FROM chat-db.Item WHERE id = '".$query."'";
echo '' .$sql2. ''; //test purposes
whats the correct way to assign the value from that specific stock to a variable?
If you want to grab rows with a set of possible values you can use 'IN' such as:
Get all columns from users table where users have 5 or 9 tries:
SELECT * FROM users WHERE tries IN('5', '9'); or
If you want to select where the user has no tries left, assuming the tries column is a numeric type you can look for rows with 0 tries:
Get all columns from Item table where stock is 0:
SELECT * FROM db_inv.Item WHERE stock = '0';
Get all columns from users table where tries is 0:
SELECT * FROM users WHERE tries = '0';
As for your php code you should be able to do the following:
$query = $_GET['query']; //id I get from the specified item
echo 'the id is: ' . $query; //test purposes
$mysql_handle = mysqli_connect($dbhost, $dbuser, $dbpass) or die("Error connecting to database server");
$sql1 = "SELECT item_stock FROM chat-db.Item WHERE id = '".$query."'";
$results = mysqli_query($mysql_handle, $sql1);
if (!empty($results) && mysqli_num_rows($results) > 0) {
while($rec = mysqli_fetch_array($results)) {
echo $rec['item_stock'];
}
}

mysql: get affected row record after update

I recently use two sql queries to get row record after update like this, for example:
Step 1: I update point for user test#gmail.com
$sql = "UPDATE user SET point=point-:point WHERE email=:email";
$result = $conn->prepare($sql);
$result->bindValue(':point', 2);
$result->bindValue(':email', 'test#gmail.com');
$result->execute();
Step 2: I have to use another sql query to get row['point'] after it is updated
$sql = "SELECT point FROM user WHERE email=:email";
$result = $conn->prepare($sql);
$result->bindValue(':email', 'test#gmail.com');
$result->execute();
$row = $result->fetch(PDO::FETCH_ASSOC);
echo $row['point'];
So, my question is, is ther a shortcut for this? such as 1 single query to achieve this?
Many thanks

How to get the next highest record but not the highest record?

This is what i have right now
What need to happen is that when the query run it should get a record where id will equal next id but if the record does not exist it should grab the next one but when i try and run the query below it runs and gets the last record which is the highest record
To make it clear:
Records in database:
1
5
6
7
8
10
So if the query checks for a record 2 (which is not there) it should get the next highest which is 5 not 10 how would i do that?
$query = "SELECT * FROM images where images >= '$nextid'";
$sql = mysqli_query($conn,$query) or die(mysqli_error($conn));
while($row = mysqli_fetch_array($sql)){
$forwardid = $row['images_id'];
$picname = $row['image_name'];
}
Try this
$query = "SELECT * FROM images where images >= '$nextid' ORDER BY
images_id ASC LIMIT 0 , 1";
Try this:
SELECT *
FROM images
WHERE images_id >= 2
ORDER BY images_id
LIMIT 1;
You can add another iteration that converts your resource into an array and also includes the next ID
$result = mysql_query(" your query ");
$recordset = array(); $i = 0;
while ($row = mysql_fetch_assoc($result))
{
$recordset[$i] = $row;
if ($i > 0) { $recordset[$i-1]['nextid'] = $row['id']; }
$i++;
}
Get the next record
you can try like following. i think it will help you.
select * from images where images_id=
(select Min(images_id) from images where images_id>=2)
N.B: here 2 is your given 'images_id'
You can use this
SELECT MAX(records) FROM images WHERE records < (SELECT MAX(records) FROM images)
take a look at this and run and let me know if you need something different.

how can I connect these two tables in sql?

i need to take only the items from the table "__sobi2_item" that are in the same country of the user.And use this results for the rest of the function Showupdatelisting. This is my php script:
<?php
function showUpdatedListing()
{
//i found the user country field value...
global $database;
$user =& JFactory::getUser();
$userId = $user->get( 'id' );
$sql = "SELECT (id) FROM #__community_fields WHERE fieldcode= 'FIELD_COUNTRY'";
$database->setQuery( $sql );
$fieldID = $database->loadResult();
$sql = "SELECT (value) FROM #__community_fields_values WHERE field_id= {$fieldID} && user_id= {$userId}";
$database->setQuery( $sql );
$usercountry = $database->loadResult();
// From all the entries i take only ones that have country field like the user has...
$query = "SELECT `data_txt`, `itemid`, `fieldid` FROM `#__sobi2_fields_data` WHERE (`fieldid` = 6) AND ('data_txt' = {$usercountry})";
$database->setQuery($query);
$ResultsArray = $database->loadObjectList();
// We need something here like a Query to load only the entries from $ResultsArray... ??
//....instead of this...
$config =& sobi2Config::getInstance();
$database = $config->getDb();
$now = $config->getTimeAndDate();
$query = "SELECT itemid FROM #__sobi2_item WHERE (published = 1 AND publish_down > '{$now}' OR publish_down = '{$config->nullDate}') ORDER BY last_update DESC LIMIT 0, 30";
$database->setQuery($query);
$sids = $database->loadResultArray();
// ......... show update function goes on...
?>
can anyone help me to connect and adjust these query? thanks.
NB:with the last query (4) i need to filter items of the $ResultsArray taking only ones published and ordering them by last_update. i know it is wrong and now there is no connection with the query before. This is how i have tables in mysql:
_sobi2_fields_data:
itemid
fieldid
data_txt --->(is a description column for each field)
_sobi2_item:
itemid
published --->( 1 if true, 0 if false )
last_update --->(date of the last update for the item, also equal to the publication date if there are no changes)
thanks.
I don't know what you are trying to ask as well. Your last query (number 4) doesn't make sense to me, how is it linked to the above queries?
[EDIT] I've linked your 4th table above assuming itemid is the primary key for the items in sobi2_item table and that the value is linked to the sobi_fields_data table via itemid.
SELECT
cf.id,
sfd.data_txt,
sfd.itemid,
sfd.fieldid
FROM #__community_fields cf
INNER JOIN #__community_fields_values cfv ON cf.id=cfv.field_id
INNER JOIN #__sobi2_fields_data sfd ON cfv.value=sfd.data_txt
INNER JOIN #__sobi2_item si ON sfd.itemid=si.itemid
WHERE cf.fieldcode='FIELD_COUNTRY'
AND cfv.user_id=$userId
AND sfd.fieldid=6
AND si.published=1
AND (si.publish_down > '{$now}' OR si.publish_down = '{$config->nullDate}')
ORDER BY si.last_update DESC LIMIT 0, 30
Good luck!