I created an SSIS variable, which I want to turn into an expression, so I write this as the Expression:
="\\livprodad1.liv.local\UserProfiles$\mike.jones\Documents\Files"
The actual link that I am referencing is:
\livprodad1.liv.local\UserProfiles$\mike.jones\Documents\Files
But I get this message: Expression can not be evaluated
Attempt to parse the expression failed. The expression might contain an invalid token, an incomplete token, or an invalid element. It might not be well-formed, or might be missing part of a required element such as a parenthesis.
What am I doing wrong? How should it be written?
You need to double all the slashes in an expression so
"\livprodad1.liv.local\UserProfiles$\mike.jones\Documents\Files"
becomes
"\\livprodad1.liv.local\\UserProfiles$\\mike.jones\\Documents\\Files"
And if you were intending to encode
"\\livprodad1.liv.local\UserProfiles$\mike.jones\Documents\Files"
it would become
"\\\\livprodad1.liv.local\\UserProfiles$\\mike.jones\\Documents\\Files"
The leading equals sign might point to a different issue as the only explicit location that I can think of where one assigns a value is in the Expression Task. Everywhere else, there's a separate field where you list the variable you are modifying
And if the double quote is part of the expression itself, then you also escape it with a backslash \" Excellent example of escaping both on What is the escape character for SSIS Expression Builder?
I have this one line JSON text:
{"schemaText":{"fields":[{"name":"AX_SND_TYPE","type":"string"},{"name":"BWORK","type":"int"}],"name":"XXXSchema","type":"record"},"description":"Autogenerated by NiFi"}
As can be seen there is a property called "schemaText" that contains an object, I want to convert it to a string, so the 'only' thing I need to do is add quotes at the beginning and end of the property and escape the quotes inside.
Using the regular expression bellow (not that my regex knowledge is really low), I am able to do the first step:
({"schemaText":)(\{"fields":\[.*)(,"description.*)
Using the substitution
$1"$2"$3
gives the result:
{"schemaText":"{"fields":[{"name":"AX_SND_TYPE","type":"string"},{"name":"BWORK","type":"int"}],"name":"XXXSchema","type":"record"}","description":"Autogenerated by NiFi"}
But still remains to escape the quotes to get this:
{"schemaText":"{\"fields\":[{\"name\":\"AX_SND_TYPE\",\"type\":\"string\"},{\"name\":\"BWORK\",\"type\":\"int\"}],"name":"XXXSchema","type":"record"}","description":"Autogenerated by NiFi"}
That is have valid JSON format.
The question is: is there a way to escape the quotes inside $2 capture group in the same regular expression?
Thanks in advance.
The answer to your question is no, it's not possible. You're really trying to do two different, unrelated substitutions in a single regular expression. This is a feature that no regular expression engine supports.
Think about it: Your first requirement is for the engine to perform a substitution on the whole text (the quotes), and then, for your second requirement, the engine has to somehow backtrack and perform more substitutions on text which may or may not have already changed: e.g.: It would need to perform a new match on the already substituted text, which, depending on what the first substitution did, may not even exist anymore!
If, as you say, you already have an aproach that works, keep that. A single regular expression is simply not a good fit for what you are trying to do.
I'd recommend tackling this problem using code e.g. with vanilla JavaScript:
let json = '{"schemaText":{"fields":[{"name":"AX_SND_TYPE","type":"string"},{"name":"BWORK","type":"int"}],"name":"XXXSchema","type":"record"},"description":"Autogenerated by NiFi"}';
let obj = JSON.parse(json);
let schemaTextAsString = JSON.stringify(obj.schemaText)
obj.schemaText = schemaTextAsString
var result = JSON.stringify(obj)
You can see this working here.
Note that in your desired output you were not escaping the quotes in schemaText's name field, but this code does.
Finally whenever I use regular expressions I always think of this classic article "Regular Expressions: Now You Have Two Problems"!
Just for your information, you can actually match at every position where a substitution should occur, using an expression such as the following:
/({"schemaText":)|}(,"description")(.*)|([^"]*)"/g
The only issue, as others have mentioned, is that you want to do more than match; you want to perform a "conditional replacement" because there does not exist a single catch-all substitution that will cover all 3 cases you're dealing with (insert starting ", insert \ before quotes, and insert ending ").
You can in fact accomplish this with a single replace() call:
var test = "{\"schemaText\":{\"fields\":[{\"name\":\"AX_SND_TYPE\",\"type\":\"string\"},{\"name\":\"BWORK\",\"type\":\"int\"}],\"name\":\"XXXSchema\",\"type\":\"record\"},\"description\":\"Autogenerated by NiFi\"}";
window.alert(test.replace(/({"schemaText":)|}(,"description")(.*)|([^"]*)"/g, function(a,b,c,d,e){ return (b=="{\"schemaText\":"?b+"\"":(c==",\"description\""?"}\""+c+d:e+"\\\"")) })));
So it's technically "the same regex", but the substitution parameter uses an inline function as replacement rather than a static string.
I'm doing a field that will only accept whole numbers. So I did a regex validation like this /^\d{1,3}$/ this is validating whole number entry and does not allow decimal from .1 e.g it will make 1.1 invalid but when I tried to input 1.0 it accepted it. Is there a regex that will also check .0?
^\d{1,3}(\.0)?$ accepts one, two or three digit whole numbers as well as if they end with .0.
I am trying to create a regex to validate usernames which should match the following :
Only one special char (._-) allowed and it must not be at the extremes of the string
The first character cannot be a number
All the other characters allowed are letters and numbers
The total length should be between 3 and 20 chars
This is for an HTML validation pattern, so sadly it must be one big regex.
So far this is what I've got:
^(?=(?![0-9])[A-Za-z0-9]+[._-]?[A-Za-z0-9]+).{3,20}
But the positive lookahead can be repeated more than one time allowing to be more than one special character which is not what I wanted. And I don't know how to correct that.
You should split your regex into two parts (not two Expressions!) to make your life easier:
First, match the format the username needs to have:
^[a-zA-Z][a-zA-Z0-9]*[._-]?[a-zA-Z0-9]+$
Now, we just need to validate the length constraint. In order to not mess around with the already found pattern, you can use a non-consuming match that only validates the number of characters (its literally a hack for creating an and pattern for your regular expression): (?=^.{3,20}$)
The regex will only try to match the valid format if the length constraint is matched. It is non-consuming, so after it is successful, the engine still is at the start of the string.
so, all together:
(?=^.{3,20}$)^[a-zA-Z][a-zA-Z0-9]*[._-]?[a-zA-Z0-9]+$
Debugger Demo
I think you need to use ? instead of +, so the special character is matched only once or not.
^(?=(?![0-9])?[A-Za-z0-9]?[._-]?[A-Za-z0-9]+).{3,20}
I’m trying to use the REST API provided by DeployIt (v3.9) to list all the packages available on a given project.
Thus, I use the GET /repository/query service
So, I’m calling this service with the following URL:
http://[server]/deployit/repository/query?namePattern=my-app&type=udm.DeploymentPackage
Unfortunately, I don’t get anything (just an empty list).
If I remove the namePattern from my URL, then I get a long list of all applications (not only the only I'm interested in).
So it appears that I don’t set correctly the namePattern attribute. In the documentation, they say:
a search pattern for the name. This is like the SQL "LIKE" pattern:
the character '%' represents any string of zero or more characters,
and the character '_' (underscore) represents any single character.
Any literal use of these two characters must be escaped with a
backslash ('\'). Consequently, any literal instance of a backslash
must also be escaped, resulting in a double backslash ('\').
So I tried the following URL:
http://[server]/deployit/repository/query?type=udm.DeploymentPackage&namePattern=my-app : empty list
http://[server]/deployit/repository/query?type=udm.DeploymentPackage&namePattern=%my-app%: error 400
http://[server]/deployit/repository/query?type=udm.DeploymentPackage&namePattern=%25my-app%25 (trying to escape the % character): empty list
http://[server]/deployit/repository/query?type=udm.DeploymentPackage&namePattern=Applications/my-app/2.0.0 (with a real version): error, character ‘/’ not allowed.
http://[server]/deployit/repository/query?type=udm.DeploymentPackage&namePattern=2.0.0 : I get the list of all applications deployed with a version 2.0.0 (including my my-app), but that's not what I'm looking for (I want all versions available on DeployIt for my-app).
So, what is the correct URL to retrieve the list of deployed applications?
I've solved my problem. In fact, the namePattern only applies to the last part of the Application name, i.e. the version.
Thus, I have to use the parent attribute to retrieve the list of my application:
http://[server]/deployit/repository/query?type=udm.DeploymentPackage&parent=Applications%2Fmy-app&resultsPerPage=-1