CSS button with slanted bottom right corner - html

Question

I'm trying to achieve a rectangle button with a transparent mask over the bottom right, as per this fiddle:
http://jsfiddle.net/c6gUX/
body {
background: #fff;
padding: 5em;
}
.button {
color: #FFFFFF;
font-family: 'RalewayRegular', Arial,sans-serif;
font-size: 1em;
padding: 0.5em 1.2em 0.5em 0.8em;
position: relative;
text-decoration: none;
}
.button:hover {
background: linear-gradient(to bottom, #FFA13E 0px, #E56204 100%) repeat scroll 0 0 transparent;
color: #FFFFFF;
}
.button:after {
background: url(http://i.imgur.com/8Vvw1Sw.png) no-repeat scroll 0 0 transparent;
bottom: -12px;
content: " ";
height: 38px;
position: absolute;
right: -12px;
width: 36px;
z-index: 99;
}
.orange-grad {
background: #ffa13e; /* Old browsers */
/* IE9 SVG, needs conditional override of 'filter' to 'none' */
background: url(data:image/svg+xml;base64,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);
background: -moz-linear-gradient(top, #ffa13e 0%, #ff7805 100%, #ff7805 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#ffa13e), color-stop(100%,#ff7805), color-stop(100%,#ff7805)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #ffa13e 0%,#ff7805 100%,#ff7805 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #ffa13e 0%,#ff7805 100%,#ff7805 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #ffa13e 0%,#ff7805 100%,#ff7805 100%); /* IE10+ */
background: linear-gradient(to bottom, #ffa13e 0%,#ff7805 100%,#ff7805 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffa13e', endColorstr='#ff7805',GradientType=0 ); /* IE6-8 */
}
As you can see, i've achieved it with a quite hacky way. I've untested this cross-browser and suspect IE to mess it up without a shim for :after, etc.
How can I achieve this cross-browser modern? How can I make it work when overlayed onto an image so it's effectively transparent? (See below image)
From PSD:
My fiddle on an image:
Logically I know that IE6/7 will need an image and i'm kinda OK with that.
Word length. Sometimes the button doesn't have 'Read more', so need a 100% width solution.
Edit
I am thinking of using a Sprite. (http://i.imgur.com/z0UYpTX.png)

Answer 1

This is tricky - particularly with your combination of a gradient with the beveled corner. The closest I could get is this fiddle, which makes use of CSS gradients to achieve the effect you're after, based on Lea Verou's awesome article.
The relevant CSS is:
.button {
background: #ffa13e; /* fallback */
background: -webkit-linear-gradient(135deg, transparent 10px, #ff7805 10px, #ffa13e 100%);
background: -moz-linear-gradient(135deg, transparent 10px, #ff7805 10px, #ffa13e 100%);
background: -o-linear-gradient(135deg, transparent 10px, #ff7805 10px, #ffa13e 100%);
background: linear-gradient(315deg, transparent 10px, #ff7805 10px, #ffa13e 100%);
}
That's the only way to get the background image to show through (that I know of). The drawback is that the gradient is not your linear one from top to bottom, but at an angle. I don't think it's possible to combine multiple gradients to match your visual precisely. But it is pretty close:
I'd suggest that this is the perfect candidate for progressive enhancement - older IE will get a solid background colour but that's perfectly acceptable (i.e. I wouldn't personally bother trying for an image fallback).
Note: there have been numerous changes between the Working Draft and the Candidate Recommendation for the gradient syntax, one of which is the angle of the gradient:
From the IE Blog. Hence the unprefixed version requires a different deg value.

Answer 2

Make use of it..... I think this will help You.. use it with ur image.. this will solve cross-browser issue...
http://jsfiddle.net/Praveen16oct90/2bZAW/1095/
div {
width:200px;
height:80px;
background: red;
top:150px;left:100px;
position: relative;
}
div:before {
content: '';
position: absolute;
top: 40px; right: 0;
border-right: 40px solid white;
border-top: 40px solid red;
width: 20;
}