regexp.test() returns boolean but not on 'if' statement - always evaluates to - google-apps-script

Question

I am working on a standalone interface.
I have several text boxes, and all have Names and IDs.
If I run this code:
var re = /someregexp/g;
var k ="sometext";
textBoxOne.setText(re.test(k)); //textBoxOne was selected first
The correct result 'true' or 'false' is displayed.
asking for a 'typeof(re.test(k))' correctly returns boolean.
However this code:
if (re.test(k)) {
textBoxTwo.setText("matched.");
} else {
textBoxTwo.setText("NOT matched.");
}
Always goes into the 'else' branch. if (re.test(k) == true) renders the same result.
Looks like a bug to me, anyone else also found this?

Answer 1

Edit: AdamL has pointed out (thanks Adam), in his comments below, that there is more to this than I supposed. I leave my original code below for reference.
The myFunction2() below follows the "matched" branch as you would expect a correctly working regex (so perhaps this can be used to work around the bug):
function myFunction2() {
var k ="sometext";
Logger.log( /ome/g.test(k) );
if ( /ome/g.test(k) ) {
Logger.log("matched.");
} else {
Logger.log("NOT matched.");
}
}
Conversely, as you have observed, the myFunction() below unexpectedly follows through to the "NOT matched" branch.
function myFunction() {
var re = /ome/g;
var k ="sometext";
Logger.log(re.test(k));
if (re.test(k)) {
Logger.log("matched.");
} else {
Logger.log("NOT matched.");
}
}