I have a db with a table called sections. In that is a field called head that has a full text index with 3 entries each a string. 2 entries have the word motorcycle and one has motorcycles. I can't seem to find a way to return all 3 if the term "motorcycles" is search.
I have tried
SELECT * FROM sections
WHERE MATCH (head) AGAINST ('Motorcycles')
but it only returns the plural entry. I have also tried.
SELECT * FROM sections
WHERE head like '%motorcycles%'
but that also only returns the plural entry. Is there a way to return all three rows based on "motorcycles"?
Have you tried boolean mode?
where match (head) against ('+ Motorcycle*' in Boolean mode)
More information is here.
Your where clause has an extra "s":
SELECT * FROM sections WHERE head like '%motorcycle%'
Assuming your question is more general than the specific motorcylce example you've given...I'm not aware of a way that you can relax the contraints directly in the SQL (without a stored proc to pre process the input). I'd suggest pre processing your input with a regex to remove/replace the chars that make the word plural. Then use like in the way that you have shown on the singular version of the word.
If i have got your Questions correctly I think you want something like this:
if (SELECT count(1) FROM sections WHERE head like '%motorcycles%')>1
begin
select * FROM selections
WHERE head like '%motorcycle%'
end
Related
I am working on a search function, where the matches are weighted based on certain conditions. One of the conditions I want to add weight to is matches where the character length of the query string in a LIKE match is longer than 4.
This is what I want to the query to look like, roughly. %s is meant to represent the actual match found by LIKE, but I don't think it does. I'm wondering if there is a special variable in MySQL that does represent the precise character match found by LIKE.
SELECT help.*,
IF(CHAR_LENGTH(%s) > 4, 2, 0) w
FROM help
WHERE (
(title LIKE '%this%' OR title LIKE '%testy%' OR title LIKE '%test%') OR
(content LIKE '%this%' OR content LIKE '%testy%' OR content LIKE '%test%')
) LIMIT 1000
edit: I could in the PHP split the search string array into two arrays based on the character length of the elements, with two separate queries that return different values for 'w', then combine the results, but I'd rather not do that, as it seems to me that would be awkward, messy, and slow.
Check out FULLTEXT as another way to discover rows. It will be faster, but won't address your question.
This probably has the effect you want.
SELECT ....
IF ( (title LIKE '%testy%' OR
content LIKE '%testy%'), 2, 0)
....
Note that the "match" in your LIKEs includes the %, so it is the entire length of the string. I don't think that is what you wanted.
REGEXP "(this|testy|that)" will match either 4 or 5 characters (in this example). It may be possible to do something with REGEXP_REPLACE to replace that with the empty string, then see how much it shrank.
I think the answer to my question is that what I wanted to do isn't possible. There is no special variable in MySQL representing the core character match in a WHERE condtional where LIKE is the operator. The match is the contents of the returned data row.
What I did to reach my objective was took the original dynamic list of search tokens, iterated through that list, and performed a search on each token, with the SQL tailored to the conditions that matched each token.
As I did this I built an array of the search results, using the id for the database row as the index for the array. This allowed me to perform calculations with the array elements, while avoiding duplicates.
I'm not posting the PHP code because the original question was about the SQL.
In Sphinx (using mysql connection), how can I match for a term and also get, let's say 5 characters before and after the match?
For example: a row contains this is a word in a sentence.
When I query: SELECT term FROM table WHERE MATCH('"word*"')
I would want to see is a word in a s returned. Is this possible?
Edit Using #barryhunter's helpful answer below, now trying to figure out how to fit this into my query:
SELECT field1,field2,SPHINX_SNIPPETS(field3,indexName, "word") as snippet FROM tableName
Thats what CALL SNIPPETS is designed for. Although its counted in words, not charactors.
http://sphinxsearch.com/docs/current/sphinxql-call-snippets.html
CALL SNIPPETS('this is a word in a sentance','index1','word', 2 AS around, 5 as limit_words);
would get back
... is a word in a ...
add '' as chunk_separator is dont want the ellipsis
Edit To add: then if want to build the snippet during the search query (not as a seperate CALL query), can use SNIPPET() function in the intial select
http://sphinxsearch.com/docs/current.html#sphinxql-select
I have the following query :
SELECT * FROM `user`
WHERE MATCH (user_login) AGAINST ('supriya*' IN BOOLEAN MODE)
Which outputs all the records starting with 'supriya'.
Now I want something that will find all the records ending with e.g. 'abc'.
I know that * cannot be preappended and it doesn't work either and I have searched a lot but couldn't find anything regarding this.
If I give query the string priya ..it should return all records ending with priya.
How do I do this?
Match doesn't work with starting wildcards, so matching with *abc* won't work. You will have to use LIKE to achieve this:
SELECT * FROM user WHERE user_login LIKE '%abc';
This will be very slow however.
If you really need to match for the ending of the string, and you have to do this often while the performance is killing you, a solution would be to create a separate column in which you reverse the strings, so you got:
user_login user_login_rev
xyzabc cbazyx
Then, instead of looking for '%abc', you can look for 'cba%' which is much faster if the column is indexed. And you can again use MATCH if you like to search for 'cba*'. You will just have to reverse the search string as well.
I believe the selection of FULL-TEXT Searching isn't relevant here. If you are interested in searching some fields based on wildcards like:
%word% ( word anywhere in the string)
word% ( starting with word)
%word ( ending with word)
best option is to use LIKE clause as GolezTrol has mentioned.
However, if you are interested in advanced/text based searching, FULL-TEXT search is the option.
Limitations with LIKE:
There are some limitations with this clause. Let suppose you use something like '%good' (anything ending with good). It may return irrelevant results like goods, goody.
So make sure you understand what you are doing and what is required.
I've to ask your help to solve this problem.
My website has a search field, let's say user writes in "Korg X 50"
In my database in table "products" i have a filed "name" that holds "X50" and a field "brand" that hold "Korg". Is there a way to use the UNION option to get the correct record ?
And if the user enters "Korg X-50" ?
Thank you very much !
Matteo
May be you should use full-text search
SELECT brand, name, MATCH (brand,name) AGAINST ('Korg X 50') AS score
FROM products WHERE MATCH (brand,name) AGAINST ('Korg X 50')
As far as I understand you don't need UNION but something like
SELECT * FROM table1
WHERE CONCAT(field1, field2) LIKE '%your_string%'
On client side you get rid of all characters (like space, hyphen, etc) in your_string that appears in user input and cannot be in field1 or field2.
So, user input Korg X 50 as well as Korg X-50 becomes KorgX50.
you will need to get some form of searchable text.
either parse out the input for multiple key words and match each separately, or perhaps try to append them all together and match to the columns appended in the same way.
you will also need either a regex, or maybe a simpler search and replace to get rid of spaces and dashes after the append before the comparison.
in general, allowing users to search for open ended text strings is more complicated than 'what union do i use'... you will ideally also be worried about slight misspellings and capitalization, and keyword order.
you may consider pulling all keywords out from your normal record into a separate keyword list associated with each product, then use that list to perform your searches.
If you do not want to parse user input and use as it is, then you will need to use a query like this
select * from products where concat_ws(' ',brand,name) = user_input -- or
select * from products where concat_ws(' ',brand,name) like %user_input%
However, this query won't return result if user enters name "Korg X-50" and your table contains "Korg" and "X50", then you need to do some other thing to achive this. You may look at http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_soundex however it won't be a complete solution. Look for text indexing libraries for that ex: lucene
I'm trying to use a regular expression to match a user entered search string to a title of an entry in my MySQL database.
For example I have the following rows in a table in my databse:
id title
1 IM2 - Article 3 Funky Business
2 IM2 - Article 4 There's no Business That's not Show Business
3 IM2 - There's no Business That's not Show Business
4 CO4 - Life's a business
When a user searches for "IM Article Business", the following query will be executed (spaces are replaced by "(.*)" using str_replace):
SELECT * FROM mytable WHERE title REGEXP 'IM(.*)Article(.*)Business'
This will return the first 2 rows.
Now, I want it to show the same results when a user uses the same words, but in another order, for example: "Business IM Article". The results MUST contain all words entered, only the order of how the words are entered shouldn't matter.
I couldn't figure out how to do it in any way and hoped regular expressions would be the answer. I've never used them before, so does anybody know how to do this?
Thanks,
Pascal
This isn't something regular expressions are great at. Fortunately, it's something SQL is pretty good at. (I'm going to not use mysql's regexp keyword, which I didn't even knew existed, and instead use the SQL standard "%" glob matching.)
select * from mytable where title like '%IM%' and title like '%Article%' and title like '%Business%'
Now title has to contain all three strings, but you haven't specified an order. Exactly what you want.